| 模型 | 模型答案 | 正确答案 |
|---|---|---|
| 金声玉亮2.0 | D. t − 11 = 84; 95°F |
D |
| deepseekr1 | The temperature at 6 P.M. (t) dropped by 11°F to reach 84°F at 10 P.M. This relationship is correctly represented by the equation **t − 11 = 84**, solving which gives **t = 95°F**. While option B also results in the correct temperature, its equation (t − 84 = 11) focuses on the difference rather than the drop itself. The problem explicitly states the temperature "dropped," making **D** the most accurate choice. **Answer:** D |
D |
| gpto1 | D | D |
| GPT-4o | C. 84 − t = 11; 73°F | D |
| llama3.1-70B-Instruct | The correct answer is D. |
D |
| llama3.1-405B-Instruct | D. t − 11 = 84; 95°F |
D |
| DeepSeek-Coder-V2 | D. t − 11 = 84; 95°F | D |
| Qwen2-72B-Instruct | D. t − 11 = 84; 95°F | D |
| baichuan4 | A. 84 − 11 = t; 73°F | D |
| doubao | D. t - 11 = 84; 95°F. If the temperature at 10 P.M. is 84°F and it dropped 11°F from 6 P.M. to 10 P.M., then the temperature at 6 P.M. (t) minus 11 should equal 84, so t - 11 = 84 and t = 95°F. | D |
| minimax | A. 84 − 11 = t; 73°F To find the temperature at 6 P.M., we need to add the temperature drop to the temperature at 10 P.M. since the temperature dropped. So the equation is: 84°F (temperature at 10 P.M.) + 11°F (temperature drop) = t (temperature at 6 P.M.) However, the correct equation should be: t (temperature at 6 P.M.) - 11°F (temperature drop) = 84°F (temperature at 10 P.M.) Therefore, the correct answer is: C. 84 − t = 11; 73°F Solving for t gives us: t = 84°F + 11°F t = 95°F So the correct temperature at 6 P.M. was 95°F. The correct answer is C, but the explanation provided in the question is incorrect. The correct equation should be 84 − t = 11, and solving for t gives us 95°F, not 73°F. |
D |
| kimi | D. t − 11 = 84; 95°F To solve the equation: t - 11 = 84 t = 84 + 11 t = 95°F So the temperature at 6 P.M. was 95°F. |
D |
| wenxinyiyan | D | D |
| zhipu | To find the temperature at 6 P.M., we need to set up an equation based on the information given. We know the temperature dropped 11°F between 6 P.M. and 10 P.M., and it was 84°F at 10 P.M. Let \( t \) be the temperature at 6 P.M. Since the temperature dropped by 11°F, we can write the equation as: \[ t - 11 = 84 \] Now, solve for \( t \): \[ t = 84 + 11 \] \[ t = 95 \] So, the temperature at 6 P.M. was 95°F. The correct choice is: D. \( t - 11 = 84; 95°F \) Answer: D |
D |
| gpto1 | D | D |
| deepseekv3 | To solve the problem, we need to find the temperature at 6 P.M. given that the temperature dropped 11°F by 10 P.M., and the temperature at 10 P.M. was 84°F. Let \( t \) be the temperature at 6 P.M. Since the temperature dropped by 11°F, we can write the equation as: \[ t - 11 = 84 \] To solve for \( t \), add 11 to both sides of the equation: \[ t = 84 + 11 \] \[ t = 95 \] Thus, the temperature at 6 P.M. was 95°F. The correct answer is: **D. \( t - 11 = 84; 95°F \)** |
D |