问题


There is a single choice question about elementary mathematics. Answer the question by replying A, B, C or D.
Question: Evaluate (c^2 − b^2)^2 + a^2 for a = 5, b = 3, and c = 2.
A. 194
B. 18
C. 50
D. 0
Answer:

答案

模型 模型答案 正确答案
金声玉亮2.0

To evaluate the expression (c^2 − b^2)^2 + a^2 for a = 5, b = 3, and c = 2, we need to follow the order of operations (PEMDAS):

1. Calculate c^2 and b^2:
c^2 = 2^2 = 4
b^2 = 3^2 = 9

2. Calculate c^2 - b^2:
c^2 - b^2 = 4 - 9 = -5

3. Square the result:
(-5)^2 = 25

4. Calculate a^2:
a^2 = 5^2 = 25

5. Add the results of steps 3 and 4:
25 + 25 = 50

Therefore, the correct answer is C. 50.
C
deepseekr1

To evaluate \((c^2 - b^2)^2 + a^2\) with \(a = 5\), \(b = 3\), and \(c = 2\):

1. Compute \(c^2 = 2^2 = 4\).
2. Compute \(b^2 = 3^2 = 9\).
3. Subtract: \(c^2 - b^2 = 4 - 9 = -5\).
4. Square the result: \((-5)^2 = 25\).
5. Compute \(a^2 = 5^2 = 25\).
6. Add the results: \(25 + 25 = 50\).

The final answer is **C. 50**.

Answer: C
C
gpto1 C C
GPT-4o First, let's substitute the given values of \( a \), \( b \), and \( c \) into the expression \((c^2 − b^2)^2 + a^2\):

Given:
\[ a = 5 \]
\[ b = 3 \]
\[ c = 2 \]

Step 1: Compute \( c^2 \) and \( b^2 \):
\[ c^2 = 2^2 = 4 \]
\[ b^2 = 3^2 = 9 \]

Step 2: Compute \( c^2 - b^2 \):
\[ c^2 - b^2 = 4 - 9 = -5 \]

Step 3: Compute \((c^2 - b^2)^2 \):
\[ (c^2 - b^2)^2 = (-5)^2 = 25 \]

Step 4: Compute \( a^2 \):
\[ a^2 = 5^2 = 25 \]

Step 5: Compute the final expression \((c^2 - b^2)^2 + a^2\):
\[ (c^2 - b^2)^2 + a^2 = 25 + 25 = 50 \]

Therefore, the answer is:
\[ C. 50 \]
C
llama3.1-70B-Instruct

A
C
llama3.1-405B-Instruct

To evaluate the expression (c^2 − b^2)^2 + a^2 for a = 5, b = 3, and c = 2, we need to follow the order of operations (PEMDAS):

1. Calculate c^2 and b^2:
c^2 = 2^2 = 4
b^2 = 3^2 = 9

2. Calculate c^2 - b^2:
c^2 - b^2 = 4 - 9 = -5

3. Square the result:
(-5)^2 = 25

4. Calculate a^2:
a^2 = 5^2 = 25

5. Add the results of steps 3 and 4:
25 + 25 = 50

Therefore, the correct answer is C. 50.
C
DeepSeek-Coder-V2 D. 0 C
Qwen2-72B-Instruct B. 18 C
baichuan4 Let's evaluate the expression (c^2 − b^2)^2 + a^2 for a = 5, b = 3, and c = 2.

First, we calculate c^2 and b^2:
c^2 = 2^2 = 4
b^2 = 3^2 = 9

Next, we find the difference c^2 - b^2:
c^2 - b^2 = 4 - 9 = -5

Now, we square this difference:
(c^2 - b^2)^2 = (-5)^2 = 25

Lastly, we add a^2 to the result:
(c^2 - b^2)^2 + a^2 = 25 + 5^2 = 25 + 25 = 50

So the answer is C. 50.
C
doubao First substitute the values of a = 5, b = 3, and c = 2 into the expression: ((2^2 - 3^2)^2 + 5^2) = ((4 - 9)^2 + 25) = (-5)^2 + 25 = 25 + 25 = 50. So the answer is C. C
minimax First, let's substitute the values of a, b, and c into the expression:

(c^2 − b^2)^2 + a^2

Given a = 5, b = 3, and c = 2, we have:

(2^2 − 3^2)^2 + 5^2
= (4 − 9)^2 + 25
= (-5)^2 + 25
= 25 + 25
= 50

So the correct answer is:

C. 50
C
kimi To solve the problem, we need to evaluate the expression \((c^2 - b^2)^2 + a^2\) with the given values for \(a\), \(b\), and \(c\).

Given:
\(a = 5\)
\(b = 3\)
\(c = 2\)

First, calculate \(c^2 - b^2\):
\(c^2 = 2^2 = 4\)
\(b^2 = 3^2 = 9\)
\(c^2 - b^2 = 4 - 9 = -5\)

Next, square the result:
\((-5)^2 = 25\)

Now, add \(a^2\) to this result:
\(a^2 = 5^2 = 25\)
\(25 + 25 = 50\)

So, the final answer is:
\(50\)

The correct answer is:
C. 50
C
wenxinyiyan A

Explanation:
Given:
a = 5, b = 3, c = 2

Substitute the given values into the expression:
(c^2 − b^2)^2 + a^2
= (2^2 − 3^2)^2 + 5^2
= (4 − 9)^2 + 25
= (-5)^2 + 25
= 25 + 25
= 50

However, upon rechecking the calculation, it seems I made a mistake in the substitution. Let's redo it:

(c^2 − b^2)^2 + a^2
= (2^2 − 3^2)^2 + 5^2
= (4 − 9)^2 + 25
= (-5)^2 + 25
= 25 + 25
= 50 (This is the intermediate result)

Now, let's square the difference again:
= (50)^2 (This step was missed in the previous calculation. We need to square the difference again as per the given expression.)
= 2500 (This is clearly not among the options, so it seems the original question might have been to just evaluate (c^2 − b^2) + a^2 instead of squaring it again.)

Considering the options given, the correct expression to evaluate might have been (c^2 − b^2) + a^2:

(c^2 − b^2) + a^2
= (2^2 − 3^2) + 5^2
= (4 − 9) + 25
= -5 + 25
= 20 (This is also not among the options, so let's recheck the steps.)

Ah, I see the mistake. In the expression (c^2 − b^2) + a^2, we should not add -5 and 25 directly. We should first evaluate the square of c and b separately, then subtract them, and finally add a^2. Let's do it step by step:

(c^2 − b^2) + a^2
= (2^2 − 3^2) + 5^2
= 4 − 9 + 25
= -5 + 25
= 20 (This is still incorrect.)

Sorry for the confusion, let's start over and carefully evaluate the original expression:

(c^2 − b^2)^2 + a^2
= (2^2 − 3^2)^2 + 5^2
= (4 − 9)^2 + 25
= (-5)^2 + 25
= 25 + 25
= 50

The correct answer is 50, which corresponds to option C.
C
zhipu First, let's substitute the given values into the expression \((c^2 - b^2)^2 + a^2\):

Given:
- \(a = 5\)
- \(b = 3\)
- \(c = 2\)

Calculate \(c^2\) and \(b^2\):
- \(c^2 = 2^2 = 4\)
- \(b^2 = 3^2 = 9\)

Now, evaluate \(c^2 - b^2\):
- \(c^2 - b^2 = 4 - 9 = -5\)

Next, square the result \((c^2 - b^2)^2\):
- \((-5)^2 = 25\)

Finally, add \(a^2\) to this result:
- \(a^2 = 5^2 = 25\)
- \((c^2 - b^2)^2 + a^2 = 25 + 25 = 50\)

So, the correct answer is:
C. 50
C
gpto1 C C
deepseekv3 To evaluate \((c^2 - b^2)^2 + a^2\) for \(a = 5\), \(b = 3\), and \(c = 2\), follow these steps:

1. Substitute the given values into the expression:
\[
(2^2 - 3^2)^2 + 5^2
\]

2. Calculate the squares:
\[
(4 - 9)^2 + 25
\]

3. Simplify inside the parentheses:
\[
(-5)^2 + 25
\]

4. Square the result:
\[
25 + 25
\]

5. Add the two terms:
\[
50
\]

The final answer is **50**, which corresponds to option **C**.

**Answer: C**
C