问题


There is a single choice question about elementary mathematics. Answer the question by replying A, B, C or D.
Question: Sheila has been given 5 minutes to solve 20 arithmetic problems. What is the minimum rate Sheila can work in order to finish in time?
A. 1 problem per minute
B. 2 problems per minute
C. 4 problems per minute
D. 5 problems per minute
Answer:

答案

模型 模型答案 正确答案
金声玉亮2.0

C. 4 problems per minute.

Sheila has 5 minutes to solve 20 problems, so she needs to solve 20/5 = 4 problems per minute to finish in time.
C
deepseekr1

To determine the minimum rate Sheila needs to solve 20 problems in 5 minutes, divide the total problems by the time:
**20 problems ÷ 5 minutes = 4 problems per minute**.

This means Sheila must work at a rate of **4 problems per minute** to finish exactly on time. A slower rate (e.g., 2 problems per minute) would result in incomplete work, while a faster rate (e.g., 5 problems per minute) would finish early but is not the **minimum** required.

**Answer: C**
C
gpto1 C C
GPT-4o C. 4 problems per minute C
llama3.1-70B-Instruct

C
C
llama3.1-405B-Instruct

C. 4 problems per minute
C
DeepSeek-Coder-V2 A. 1 problem per minute C
Qwen2-72B-Instruct B. 2 problems per minute C
baichuan4 B. 2 problems per minute C
doubao C. 4 problems per minute. If she has 5 minutes to solve 20 problems, then 20÷5 = 4 problems per minute. C
minimax To find the minimum rate Sheila can work in order to finish the 20 arithmetic problems in 5 minutes, we divide the total number of problems by the total number of minutes available.

20 problems ÷ 5 minutes = 4 problems per minute

So the minimum rate Sheila can work in order to finish in time is:

C. 4 problems per minute
C
kimi B. 2 problems per minute C
wenxinyiyan C C
zhipu To determine the minimum rate at which Sheila must work to solve 20 arithmetic problems in 5 minutes, we can calculate the number of problems she needs to solve per minute.

Given:
- Total problems = 20
- Total time (in minutes) = 5

Rate of solving problems = Total problems / Total time
= 20 / 5
= 4 problems per minute

Therefore, the minimum rate at which Sheila must work to finish the 20 problems in 5 minutes is 4 problems per minute.

Answer: C. 4 problems per minute
C
gpto1 C C
deepseekv3 To determine the minimum rate Sheila needs to work to solve 20 problems in 5 minutes, we divide the total number of problems by the total time:

\[
\text{Rate} = \frac{\text{Total Problems}}{\text{Total Time}} = \frac{20}{5} = 4 \text{ problems per minute}
\]

Thus, Sheila needs to solve at least 4 problems per minute to finish in time. The correct answer is:

**C. 4 problems per minute**
C