问题


There is a single choice question about elementary mathematics. Answer the question by replying A, B, C or D.
Question: Find 1 over 6 + 1 over 8.
A. 7 over 24
B. 2 over 14
C. 1 over 7
D. 1 over 4
Answer:

答案

模型 模型答案 正确答案
金声玉亮2.0

A. 7 over 24

Explanation:

To add fractions, we need to find a common denominator. The least common multiple (LCM) of 6 and 8 is 24. So, we can rewrite the fractions as:

1/6 = 4/24
1/8 = 3/24

Now, we can add:

4/24 + 3/24 = 7/24

Therefore, the correct answer is A. 7 over 24.
A
deepseekr1

To add the fractions \( \frac{1}{6} \) and \( \frac{1}{8} \), first find their least common denominator (LCD). The multiples of 6 are 6, 12, 18, 24, ..., and the multiples of 8 are 8, 16, 24, 32, ..., so the LCD is 24. Convert both fractions:

\[
\frac{1}{6} = \frac{1 \times 4}{6 \times 4} = \frac{4}{24}, \quad \frac{1}{8} = \frac{1 \times 3}{8 \times 3} = \frac{3}{24}.
\]

Adding them:

\[
\frac{4}{24} + \frac{3}{24} = \frac{4 + 3}{24} = \frac{7}{24}.
\]

The correct answer is **A. 7 over 24**.

Answer: A
A
gpto1 A A
GPT-4o To find \(\frac{1}{6} + \frac{1}{8}\), you need to find a common denominator. The least common multiple of 6 and 8 is 24.

Convert each fraction to have the same denominator:
\[
\frac{1}{6} = \frac{4}{24} \quad \text{(since \(\frac{1 \times 4}{6 \times 4} = \frac{4}{24}\))}
\]
\[
\frac{1}{8} = \frac{3}{24} \quad \text{(since \(\frac{1 \times 3}{8 \times 3} = \frac{3}{24}\))}
\]

Now, add the two fractions:
\[
\frac{4}{24} + \frac{3}{24} = \frac{4 + 3}{24} = \frac{7}{24}
\]

Thus, the answer is:
A. 7 over 24
A
llama3.1-70B-Instruct

To find the sum of 1/6 and 1/8, we need to find a common denominator. The least common multiple of 6 and 8 is 24.

So, we can rewrite the fractions as:

1/6 = 4/24
1/8 = 3/24

Now, we can add the fractions:

4/24 + 3/24 = 7/24

Therefore, the correct answer is:

A. 7 over 24
A
llama3.1-405B-Instruct

A. 7 over 24
A
DeepSeek-Coder-V2 A. 7 over 24 A
Qwen2-72B-Instruct A. 7 over 24 A
baichuan4 A. 7 over 24 A
doubao A. 7 over 24.

1/6 + 1/8 = 4/24 + 3/24 = 7/24.
A
minimax To find \( \frac{1}{6} + \frac{1}{8} \), we need to find a common denominator. The least common multiple of 6 and 8 is 24. So we convert each fraction to have a denominator of 24:

\( \frac{1}{6} = \frac{4}{24} \) (because \( 6 \times 4 = 24 \))

\( \frac{1}{8} = \frac{3}{24} \) (because \( 8 \times 3 = 24 \))

Now we can add them:

\( \frac{4}{24} + \frac{3}{24} = \frac{7}{24} \)

So the answer is:

A. 7 over 24
A
kimi To solve this, we need to find a common denominator for the fractions 1/6 and 1/8. The least common denominator (LCD) of 6 and 8 is 24.

Now, we convert each fraction to have the denominator of 24:
1/6 = 4/24 (because 6 * 4 = 24)
1/8 = 3/24 (because 8 * 3 = 24)

Now, we add the two fractions:
4/24 + 3/24 = 7/24

So the correct answer is:
A. 7 over 24
A
wenxinyiyan A
Explanation:
To add two fractions with different denominators, we need to find a common denominator. In this case, the least common denominator of 6 and 8 is 24.
1/6 + 1/8
= (1 × 4) / (6 × 4) + (1 × 3) / (8 × 3)
= 4/24 + 3/24
= (4 + 3) / 24
= 7/24
So, the answer is A. 7 over 24.
A
zhipu To find \( \frac{1}{6} + \frac{1}{8} \), we need to find a common denominator. The least common multiple of 6 and 8 is 24.

Convert each fraction to have the denominator of 24:

\[ \frac{1}{6} = \frac{1 \times 4}{6 \times 4} = \frac{4}{24} \]

\[ \frac{1}{8} = \frac{1 \times 3}{8 \times 3} = \frac{3}{24} \]

Now add the fractions:

\[ \frac{4}{24} + \frac{3}{24} = \frac{4 + 3}{24} = \frac{7}{24} \]

So, the correct answer is:

A. \(\frac{7}{24}\)
A
gpto1 A A
deepseekv3 To solve \( \frac{1}{6} + \frac{1}{8} \), follow these steps:

1. **Find the Least Common Denominator (LCD):**
The denominators are 6 and 8. The LCD of 6 and 8 is 24.

2. **Convert the fractions to equivalent fractions with the LCD:**
\( \frac{1}{6} = \frac{4}{24} \) (since \( 6 \times 4 = 24 \))
\( \frac{1}{8} = \frac{3}{24} \) (since \( 8 \times 3 = 24 \))

3. **Add the fractions:**
\( \frac{4}{24} + \frac{3}{24} = \frac{7}{24} \)

The correct answer is:
**A. 7 over 24**
A