问题


There is a single choice question about elementary mathematics. Answer the question by replying A, B, C or D.
Question: Find 3 over 4 − 1 over 8.
A. 21 over 32
B. 1
C. 5 over 8
D. 11 over 16
Answer:

答案

模型 模型答案 正确答案
金声玉亮2.0

C. 5 over 8
C
deepseekr1

To solve \( \frac{3}{4} - \frac{1}{8} \), first find a common denominator. The least common denominator of 4 and 8 is 8. Convert \( \frac{3}{4} \) to eighths by multiplying numerator and denominator by 2:
\[
\frac{3}{4} = \frac{3 \times 2}{4 \times 2} = \frac{6}{8}.
\]
Now subtract the fractions:
\[
\frac{6}{8} - \frac{1}{8} = \frac{6-1}{8} = \frac{5}{8}.
\]
The correct answer is **C. 5 over 8**.

Answer: C
C
gpto1 C C
GPT-4o To solve the problem \( \frac{3}{4} - \frac{1}{8} \):

1. First, find a common denominator. The denominators are 4 and 8, and the least common multiple is 8.
2. Convert \( \frac{3}{4} \) to a fraction with a denominator of 8: \( \frac{3}{4} = \frac{3 \times 2}{4 \times 2} = \frac{6}{8} \).
3. Now, subtract \( \frac{1}{8} \) from \( \frac{6}{8} \): \( \frac{6}{8} - \frac{1}{8} = \frac{6 - 1}{8} = \frac{5}{8} \).

So, the answer is \( \frac{5}{8} \).

Answer: C
C
llama3.1-70B-Instruct

C
C
llama3.1-405B-Instruct

C
C
DeepSeek-Coder-V2 To solve the problem \( \frac{3}{4} - \frac{1}{8} \), we need to find a common denominator. The denominators are 4 and 8. The least common denominator (LCD) of 4 and 8 is 8.

First, we convert \( \frac{3}{4} \) to a fraction with a denominator of 8:
\[ \frac{3}{4} = \frac{3 \times 2}{4 \times 2} = \frac{6}{8} \]

Now, we can subtract the fractions:
\[ \frac{6}{8} - \frac{1}{8} = \frac{6 - 1}{8} = \frac{5}{8} \]

Thus, the answer is:
\[ \boxed{C} \]
C
Qwen2-72B-Instruct C. 5 over 8 C
baichuan4 To find 3 over 4 minus 1 over 8, we first need to make sure the fractions have the same denominator. Since 4 and 8 are both divisible by 4, we can multiply the numerator of the first fraction by 2 to get the same denominator as the second fraction.

So, 3 over 4 becomes 6 over 8. Now we can subtract the fractions:

6 over 8 - 1 over 8 = 5 over 8.

Answer: C. 5 over 8
C
doubao C. 5 over 8.

3/4 - 1/8 = 6/8 - 1/8 = 5/8.
C
minimax To solve the problem, we need to subtract the fractions:

3/4 - 1/8

First, we need to find a common denominator for the two fractions. The least common multiple of 4 and 8 is 8. So we convert 3/4 to a fraction with a denominator of 8:

3/4 = (3 * 2) / (4 * 2) = 6/8

Now we can subtract the two fractions:

6/8 - 1/8 = (6 - 1) / 8 = 5/8

Therefore, the answer is:

C. 5 over 8
C
kimi To solve this problem, we first need to find a common denominator for the fractions 3/4 and 1/8. The least common denominator for 4 and 8 is 8.

Now, convert 3/4 to a fraction with a denominator of 8:
3/4 = (3 * 2) / (4 * 2) = 6/8

Now, subtract 1/8 from 6/8:
6/8 - 1/8 = (6 - 1) / 8 = 5/8

So the answer is:
C. 5 over 8
C
wenxinyiyan C
Explanation:
To subtract fractions with different denominators, first find a common denominator. In this case, the least common denominator of 4 and 8 is 8.
Then convert each fraction to have the common denominator:
3/4 × 2/2 = 6/8
1/8 is already in terms of 8, so no conversion is necessary.
Now subtract the fractions:
6/8 - 1/8 = 5/8
So, the answer is C. 5 over 8.
C
zhipu To solve the expression \( \frac{3}{4} - \frac{1}{8} \), we need to have a common denominator. The least common denominator (LCD) of 4 and 8 is 8.

First, convert \( \frac{3}{4} \) to a fraction with a denominator of 8:
\[ \frac{3}{4} = \frac{3 \times 2}{4 \times 2} = \frac{6}{8} \]

Now, subtract \( \frac{1}{8} \) from \( \frac{6}{8} \):
\[ \frac{6}{8} - \frac{1}{8} = \frac{6 - 1}{8} = \frac{5}{8} \]

So, the correct answer is:
C. \( \frac{5}{8} \)

Answer: C
C
gpto1 C C
deepseekv3 To solve \( \frac{3}{4} - \frac{1}{8} \), follow these steps:

1. Find a common denominator. The least common denominator of 4 and 8 is 8.
2. Convert \( \frac{3}{4} \) to a fraction with denominator 8:
\[
\frac{3}{4} = \frac{3 \times 2}{4 \times 2} = \frac{6}{8}
\]
3. Subtract \( \frac{1}{8} \) from \( \frac{6}{8} \):
\[
\frac{6}{8} - \frac{1}{8} = \frac{5}{8}
\]

Thus, the correct answer is **C**.

\boxed{C}
C