问题


There is a single choice question about high school mathematics. Answer the question by replying A, B, C or D.
Question: In the equation $|x-4| -10 = 2$, what is the product of all possible values of $x$?
A. -8
B. 128
C. -128
D. 16
Answer:

答案

模型 模型答案 正确答案
金声玉亮2.0

B
C
deepseekr1

To solve the equation \( |x - 4| - 10 = 2 \), first isolate the absolute value term by adding 10 to both sides:

\[
|x - 4| = 12.
\]

This splits into two cases:
1. \( x - 4 = 12 \) → \( x = 16 \),
2. \( x - 4 = -12 \) → \( x = -8 \).

The product of the solutions \( 16 \) and \( -8 \) is:

\[
16 \times (-8) = -128.
\]

Verifying both solutions in the original equation confirms their validity. The correct answer is **C**.

**Answer:** C
C
gpto1 C C
GPT-4o To solve the equation \( |x-4| -10 = 2 \), we first isolate the absolute value term:

\[
|x-4| - 10 = 2
\]

Add 10 to both sides:

\[
|x-4| = 12
\]

The absolute value equation \( |x-4| = 12 \) has two possible solutions:

\[
x - 4 = 12 \quad \text{or} \quad x - 4 = -12
\]

Solve each equation separately:

1. \( x - 4 = 12 \)

\[
x = 12 + 4 = 16
\]

2. \( x - 4 = -12 \)

\[
x = -12 + 4 = -8
\]

The possible values of \( x \) are \( 16 \) and \( -8 \). To find the product of all possible values of \( x \):

\[
16 \times (-8) = -128
\]

Thus, the product of all possible values of \( x \) is:

\[
\boxed{-128}
\]

Therefore, the answer is:
C. -128
C
llama3.1-70B-Instruct

B
The equation $|x-4|-10=2$ is equivalent to $|x-4|=12$. This equation is equivalent to the two equations $x-4=12$ and $x-4=-12$. The first of these two equations has solution $x=16$, and the second has solution $x=-8$. Therefore, the product of all possible values of $x$ is $16\left(-8\right)=-128$.
C
llama3.1-405B-Instruct

To solve the equation $|x-4| - 10 = 2$, we first add 10 to both sides to isolate the absolute value term, getting $|x-4| = 12$.

Now, we split the equation into two cases to solve for $x$:

1. $x - 4 = 12$
2. $x - 4 = -12$

Solving each case:

1. $x = 12 + 4 = 16$
2. $x = -12 + 4 = -8$

The product of all possible values of $x$ is $16 \times -8 = -128$.

The correct answer is C.
C
DeepSeek-Coder-V2 C. -128 C
Qwen2-72B-Instruct First, we solve the equation $|x-4| -10 = 2$ for $x$.

Adding 10 to both sides, we get $|x-4| = 12$.

This absolute value equation splits into two cases:

Case 1: $x-4 = 12$, which gives $x = 16$.

Case 2: $x-4 = -12$, which gives $x = -8$.

So the possible values of $x$ are $16$ and $-8$. The product of these values is $16 \cdot (-8) = -128$.

Answer: C. -128
C
baichuan4 B C
doubao Solve the equation $|x-4|-10=2$.
$|x-4|=12$.
So $x-4=12$ or $x-4=-12$.
When $x-4=12$, $x=12+4=16$.
When $x-4=-12$, $x=-12+4=-8$.
The product of 16 and -8 is $16\times(-8)=-128$.
So the answer is C.
C
minimax First, let's solve the equation $|x-4| -10 = 2$.

Add 10 to both sides to isolate the absolute value:
$|x-4| = 12$

Now, the absolute value equation $|x-4| = 12$ has two possible solutions because the absolute value of a number is the distance from zero on the number line, which can be in either direction (positive or negative). Therefore, we have:

$x - 4 = 12$ or $x - 4 = -12$

Solving each equation for $x$ gives us:

For $x - 4 = 12$:
$x = 12 + 4$
$x = 16$

For $x - 4 = -12$:
$x = -12 + 4$
$x = -8$

So the two possible values of $x$ are 16 and -8. The product of these two values is:

$16 \times (-8) = -128$

Therefore, the correct answer is:

C. -128
C
kimi To solve the equation \( |x-4| - 10 = 2 \), we first isolate the absolute value:

\[ |x-4| = 2 + 10 \]
\[ |x-4| = 12 \]

The absolute value equation \( |x-4| = 12 \) has two possible solutions:

1. \( x - 4 = 12 \)
2. \( x - 4 = -12 \)

Solving each equation for \( x \):

1. \( x = 12 + 4 \)
2. \( x = -12 + 4 \)

So the solutions are:

1. \( x = 16 \)
2. \( x = -8 \)

Now, to find the product of all possible values of \( x \), we multiply the solutions together:

\[ 16 \times (-8) = -128 \]

The product of all possible values of \( x \) is \(-128\).

Answer: C. -128
C
wenxinyiyan C. -128
Given the equation $|x-4| - 10 = 2$, we first isolate the absolute value term:
$|x-4| = 12$
Next, we solve for the two possible cases of the absolute value:
$x-4 = 12 \quad \text{or} \quad x-4 = -12$
Solving each case separately, we find:
$x = 16 \quad \text{or} \quad x = -8$
Finally, we compute the product of all possible values of $x$:
$16 \times (-8) = -128$
C
zhipu To solve the equation \(|x-4| - 10 = 2\), we first isolate the absolute value expression.

Add 10 to both sides of the equation:
\[
|x-4| - 10 + 10 = 2 + 10
\]
\[
|x-4| = 12
\]

Next, we consider the two cases for the absolute value:

**Case 1: \(x - 4 = 12\)**
\[
x - 4 = 12
\]
Add 4 to both sides:
\[
x = 16
\]

**Case 2: \(x - 4 = -12\)**
\[
x - 4 = -12
\]
Add 4 to both sides:
\[
x = -8
\]

So, the possible values of \(x\) are \(16\) and \(-8\).

The product of these values is:
\[
16 \times (-8) = -128
\]

Therefore, the correct answer is:
\[
C. -128
\]
C
gpto1 C C
deepseekv3 To solve the equation \( |x - 4| - 10 = 2 \), follow these steps:

1. **Isolate the absolute value:**
\[
|x - 4| - 10 = 2 \\
|x - 4| = 12
\]

2. **Remove the absolute value by considering both cases:**

**Case 1:** \( x - 4 = 12 \)
\[
x = 16
\]

**Case 2:** \( x - 4 = -12 \)
\[
x = -8
\]

3. **Find the product of all possible values of \( x \):**
\[
16 \times (-8) = -128
\]

**Answer:** \(\boxed{C}\)
C