问题


There is a single choice question about high school mathematics. Answer the question by replying A, B, C or D.
Question: If 3^(x – 3) + 10 = 19, then x =
A. 3
B. 4
C. 5
D. 6
Answer:

答案

模型 模型答案 正确答案
金声玉亮2.0

To solve the equation 3^(x - 3) + 10 = 19, we first isolate the exponential term by subtracting 10 from both sides:

3^(x - 3) = 19 - 10
3^(x - 3) = 9

Since 9 is 3^2, we can rewrite the equation as:

3^(x - 3) = 3^2

This means that x - 3 = 2, because the bases are the same. Solving for x, we add 3 to both sides:

x = 2 + 3
x = 5

Therefore, the correct answer is:

C. 5
C
deepseekr1

To solve the equation \(3^{x – 3} + 10 = 19\), start by isolating the exponential term. Subtract 10 from both sides:

\[
3^{x – 3} = 19 - 10 \implies 3^{x – 3} = 9.
\]

Recognize that \(9 = 3^2\), so rewrite the equation as:

\[
3^{x – 3} = 3^2.
\]

Since the bases are equal, the exponents must also be equal:

\[
x – 3 = 2.
\]

Solving for \(x\) gives:

\[
x = 2 + 3 = 5.
\]

Verify by substituting \(x = 5\) back into the original equation: \(3^{5-3} + 10 = 3^2 + 10 = 9 + 10 = 19\), which is correct.

Answer: **C**
C
gpto1 C C
GPT-4o To solve the equation \(3^{(x - 3)} + 10 = 19\), we first isolate the exponential term:

\[3^{(x - 3)} + 10 = 19\]

Subtract 10 from both sides:

\[3^{(x - 3)} = 9\]

We know that 9 can be written as a power of 3:

\[9 = 3^2\]

Thus, we have:

\[3^{(x - 3)} = 3^2\]

Since the bases are the same, we can set the exponents equal to each other:

\[x - 3 = 2\]

Solving for \(x\):

\[x = 2 + 3\]
\[x = 5\]

So, the answer is:

C. 5
C
llama3.1-70B-Instruct

B
C
llama3.1-405B-Instruct

To solve the equation 3^(x - 3) + 10 = 19, we first isolate the exponential term by subtracting 10 from both sides:

3^(x - 3) = 19 - 10
3^(x - 3) = 9

Now, we notice that 9 is a power of 3, specifically 3^2. Therefore, we can equate the exponents:

x - 3 = 2

To solve for x, we add 3 to both sides:

x = 2 + 3
x = 5

So, the correct answer is:

C. 5
C
DeepSeek-Coder-V2 B. 4 C
Qwen2-72B-Instruct B. 4 C
baichuan4 C C
doubao First, subtract 10 from both sides of the equation: 3^(x – 3) = 19 - 10 = 9.

Then 3^(x – 3) = 3^2, so x - 3 = 2, and x = 2 + 3 = 5.

So the answer is C.
C
minimax To solve for x, we first isolate the term with the exponent:

3^(x – 3) + 10 = 19

Subtract 10 from both sides:

3^(x – 3) = 9

Now we recognize that 9 is a power of 3, specifically 3^2:

3^(x – 3) = 3^2

Since the bases are the same, we can set the exponents equal to each other:

x – 3 = 2

Now solve for x:

x = 2 + 3
x = 5

The correct answer is:

C. 5
C
kimi To solve for x, we start with the given equation:

\[ 3^{x - 3} + 10 = 19 \]

First, we subtract 10 from both sides to isolate the exponential term:

\[ 3^{x - 3} = 19 - 10 \]
\[ 3^{x - 3} = 9 \]

Next, we recognize that 9 is a power of 3:

\[ 3^2 = 9 \]

So, we can set the exponents equal to each other:

\[ x - 3 = 2 \]

Finally, we solve for x by adding 3 to both sides:

\[ x = 2 + 3 \]
\[ x = 5 \]

The correct answer is C. 5.
C
wenxinyiyan C
Explanation:
Given the equation $3^{x - 3} + 10 = 19$, we can subtract 10 from both sides to get:
$3^{x - 3} = 9$
Since $3^2 = 9$, we can write:
$3^{x - 3} = 3^2$
Comparing the exponents, we get:
$x - 3 = 2$
Solving for x, we have:
$x = 5$
C
zhipu To solve the equation \( 3^{(x - 3)} + 10 = 19 \), we need to isolate \( x \). Here are the steps:

1. Subtract 10 from both sides of the equation:
\[
3^{(x - 3)} + 10 - 10 = 19 - 10
\]
Simplifying this, we get:
\[
3^{(x - 3)} = 9
\]

2. Recognize that \( 9 \) can be written as \( 3^2 \):
\[
3^{(x - 3)} = 3^2
\]

3. Since the bases are the same, we can equate the exponents:
\[
x - 3 = 2
\]

4. Solve for \( x \) by adding 3 to both sides:
\[
x - 3 + 3 = 2 + 3
\]
Simplifying this, we get:
\[
x = 5
\]

Therefore, the correct answer is \( \boxed{C} \).
C
gpto1 C C
deepseekv3 To solve the equation \( 3^{x - 3} + 10 = 19 \), follow these steps:

1. Subtract 10 from both sides:
\[
3^{x - 3} = 19 - 10
\]
\[
3^{x - 3} = 9
\]

2. Recognize that \( 9 \) can be written as \( 3^2 \):
\[
3^{x - 3} = 3^2
\]

3. Since the bases are the same, set the exponents equal to each other:
\[
x - 3 = 2
\]

4. Solve for \( x \):
\[
x = 2 + 3
\]
\[
x = 5
\]

Therefore, the correct answer is \( C. 5 \).
C