问题


There is a single choice question about high school mathematics. Answer the question by replying A, B, C or D.
Question: Let $M=4a^2 - 2b^2 +a$. Let $j$ be the value of $M$ when $a=5$ and $b=3$, and let $k$ be the value of $M$ when $a=-1$ and $b=4$. Calculate $j+2k$.
A. 29
B. 28
C. 27
D. 26
Answer:

答案

模型 模型答案 正确答案
金声玉亮2.0 First, calculate $j$:
\[j = 4(5)^2 - 2(3)^2 + 5 = 4(25) - 2(9) + 5 = 100 - 18 + 5 = 87\]

Next, calculate $k$:
\[k = 4(-1)^2 - 2(4)^2 + (-1) = 4(1) - 2(16) - 1 = 4 - 32 - 1 = -29\]

Finally, calculate $j + 2k$:
\[j + 2k = 87 + 2(-29) = 87 - 58 = 29\]

Answer: A. 29
A
deepseekr1

To calculate \( j + 2k \), we first determine the values of \( j \) and \( k \) by substituting the given values into \( M = 4a^2 - 2b^2 + a \).

**Calculating \( j \) when \( a = 5 \) and \( b = 3 \):**
\[
j = 4(5)^2 - 2(3)^2 + 5 = 4(25) - 2(9) + 5 = 100 - 18 + 5 = 87.
\]

**Calculating \( k \) when \( a = -1 \) and \( b = 4 \):**
\[
k = 4(-1)^2 - 2(4)^2 + (-1) = 4(1) - 2(16) - 1 = 4 - 32 - 1 = -29.
\]

**Finding \( j + 2k \):**
\[
j + 2k = 87 + 2(-29) = 87 - 58 = 29.
\]

The final result is **29**, corresponding to option **A**.

**Answer: A**
A
gpto1 To solve this problem, we'll calculate the values step by step.

First, compute \( j \) when \( a = 5 \) and \( b = 3 \):

\[ M = 4a^2 - 2b^2 + a = 4(5)^2 - 2(3)^2 + 5 = 4(25) - 2(9) + 5 = 100 - 18 + 5 = 87 \]

So, \( j = 87 \).

Next, compute \( k \) when \( a = -1 \) and \( b = 4 \):

\[ M = 4(-1)^2 - 2(4)^2 + (-1) = 4(1) - 2(16) - 1 = 4 - 32 - 1 = -29 \]

So, \( k = -29 \).

Finally, compute \( j + 2k \):

\[ j + 2k = 87 + 2(-29) = 87 - 58 = 29 \]

**Answer: A**
A
GPT-4o To solve for \( j + 2k \), we first need to determine the values of \( j \) and \( k \) using the given formula for \( M \).

Given:
\[ M = 4a^2 - 2b^2 + a \]

1. Calculate \( j \) when \( a = 5 \) and \( b = 3 \):
\[ j = 4(5)^2 - 2(3)^2 + 5 \]
\[ j = 4 \cdot 25 - 2 \cdot 9 + 5 \]
\[ j = 100 - 18 + 5 \]
\[ j = 87 \]

2. Calculate \( k \) when \( a = -1 \) and \( b = 4 \):
\[ k = 4(-1)^2 - 2(4)^2 + (-1) \]
\[ k = 4 \cdot 1 - 2 \cdot 16 - 1 \]
\[ k = 4 - 32 - 1 \]
\[ k = -29 \]

Next, calculate \( j + 2k \):
\[ j + 2k = 87 + 2(-29) \]
\[ j + 2k = 87 - 58 \]
\[ j + 2k = 29 \]

The correct answer is:
A. 29
A
llama3.1-70B-Instruct

## Step 1: Substitute the given values of a and b into the equation for M to find j.
We have $j = 4(5)^2 - 2(3)^2 + 5 = 4(25) - 2(9) + 5 = 100 - 18 + 5 = 87$.

## Step 2: Substitute the given values of a and b into the equation for M to find k.
We have $k = 4(-1)^2 - 2(4)^2 + (-1) = 4(1) - 2(16) - 1 = 4 - 32 - 1 = -29$.

## Step 3: Calculate j + 2k.
$j + 2k = 87 + 2(-29) = 87 - 58 = 29$.

The final answer is: $\boxed{29}$
A
llama3.1-405B-Instruct

## Step 1: Substitute the given values of a and b into the equation for M to find j.
$j = 4(5)^2 - 2(3)^2 + 5 = 4(25) - 2(9) + 5 = 100 - 18 + 5 = 87$.

## Step 2: Substitute the given values of a and b into the equation for M to find k.
$k = 4(-1)^2 - 2(4)^2 + (-1) = 4(1) - 2(16) - 1 = 4 - 32 - 1 = -29$.

## Step 3: Calculate j + 2k.
$j + 2k = 87 + 2(-29) = 87 - 58 = 29$.

The final answer is: $\boxed{29}$
A
DeepSeek-Coder-V2 To solve the problem, we need to calculate the values of \(j\) and \(k\) and then find \(j + 2k\).

First, let's find \(j\):
\[ M = 4a^2 - 2b^2 + a \]
When \(a = 5\) and \(b = 3\):
\[ M = 4(5^2) - 2(3^2) + 5 \]
\[ M = 4(25) - 2(9) + 5 \]
\[ M = 100 - 18 + 5 \]
\[ M = 87 \]
So, \(j = 87\).

Next, let's find \(k\):
When \(a = -1\) and \(b = 4\):
\[ M = 4(-1)^2 - 2(4^2) + (-1) \]
\[ M = 4(1) - 2(16) - 1 \]
\[ M = 4 - 32 - 1 \]
\[ M = -29 \]
So, \(k = -29\).

Now, we need to calculate \(j + 2k\):
\[ j + 2k = 87 + 2(-29) \]
\[ j + 2k = 87 - 58 \]
\[ j + 2k = 29 \]

Thus, the answer is:
\[ \boxed{A} \]
A
Qwen2-72B-Instruct First, we calculate $j$ and $k$.
When $a=5$ and $b=3$, $M=4(5)^2 - 2(3)^2 + 5 = 100 - 18 + 5 = 87$. So $j=87$.
When $a=-1$ and $b=4$, $M=4(-1)^2 - 2(4)^2 + (-1) = 4 - 32 - 1 = -29$. So $k=-29$.
Then, $j+2k = 87 + 2*(-29) = 87 - 58 = 29$.
The answer is A. 29.
A
baichuan4 First, let's calculate $j$, the value of $M$ when $a=5$ and $b=3$:

$$M = 4a^2 - 2b^2 + a$$
$$M = 4(5)^2 - 2(3)^2 + 5$$
$$M = 100 - 18 + 5$$
$$M = 87$$

So, $j = 87$.

Next, let's calculate $k$, the value of $M$ when $a=-1$ and $b=4$:

$$M = 4(-1)^2 - 2(4)^2 + (-1)$$
$$M = 4 - 32 - 1$$
$$M = -29$$

So, $k = -29$.

Now, we can calculate $j+2k$:

$$j+2k = 87 + 2(-29)$$
$$j+2k = 87 - 58$$
$$j+2k = 29$$

Answer: A. 29
A
doubao When a=5 and b=3, M=4×5²-2×3²+5=4×25-2×9+5=100-18+5=87, so j=87.
When a=-1 and b=4, M=4×(-1)²-2×4²-1=4-2×16-1=4-32-1=-29, so k=-29.
j+2k=87+2×(-29)=87-58=29.
So the answer is A.
A
minimax First, let's calculate $j$ by substituting $a=5$ and $b=3$ into the expression for $M$:

$j = 4(5)^2 - 2(3)^2 + 5$
$j = 4(25) - 2(9) + 5$
$j = 100 - 18 + 5$
$j = 82 + 5$
$j = 87$

Next, let's calculate $k$ by substituting $a=-1$ and $b=4$ into the expression for $M$:

$k = 4(-1)^2 - 2(4)^2 - 1$
$k = 4(1) - 2(16) - 1$
$k = 4 - 32 - 1$
$k = -28 - 1$
$k = -29$

Now, we can calculate $j + 2k$:

$j + 2k = 87 + 2(-29)$
$j + 2k = 87 - 58$
$j + 2k = 29$

The answer is A. 29.
A
kimi First, let's calculate the value of \( j \) when \( a = 5 \) and \( b = 3 \):

\( M = 4a^2 - 2b^2 + a \)
\( j = 4(5)^2 - 2(3)^2 + 5 \)
\( j = 4(25) - 2(9) + 5 \)
\( j = 100 - 18 + 5 \)
\( j = 87 \)

Next, let's calculate the value of \( k \) when \( a = -1 \) and \( b = 4 \):

\( M = 4a^2 - 2b^2 + a \)
\( k = 4(-1)^2 - 2(4)^2 + (-1) \)
\( k = 4(1) - 2(16) - 1 \)
\( k = 4 - 32 - 1 \)
\( k = -29 \)

Now, we calculate \( j + 2k \):

\( j + 2k = 87 + 2(-29) \)
\( j + 2k = 87 - 58 \)
\( j + 2k = 29 \)

So the answer is A. 29.
A
wenxinyiyan A

Explanation:
Given $M = 4a^{2} - 2b^{2} + a$.

1. When $a = 5$ and $b = 3$:
$j = 4(5^{2}) - 2(3^{2}) + 5$
$= 4(25) - 2(9) + 5$
$= 100 - 18 + 5$
$= 87$ (This is an intermediate value, not the final answer to the question.)
However, upon rechecking, we find that:
$j = 4(5^{2}) - 2(3^{2}) + 5$
$= 100 - 18 + 5$
$= 87$ is incorrect. The correct calculation is:
$j = 4(5^{2}) - 2(3^{2}) + 5$
$= 100 - 18 + 5$
$= 82 + 5$
$= 87$ (corrected, but still an intermediate value)
Actually, this step is redundant because the first calculation was already correct. The value of $j$ is 87.
2. When $a = -1$ and $b = 4$:
$k = 4(-1^{2}) - 2(4^{2}) - 1$
$= 4(1) - 2(16) - 1$
$= 4 - 32 - 1$
$= -29$ (This is an intermediate value, not the final answer to the question.)
3. Calculate $j + 2k$:
$j + 2k = 87 + 2(-29)$
$= 87 - 58$
$= 29$
A
zhipu First, we need to find the value of \( j \) and \( k \).

**Calculate \( j \):**
Given \( a = 5 \) and \( b = 3 \), substitute these values into the expression for \( M \):
\[
M = 4a^2 - 2b^2 + a
\]
\[
j = 4(5)^2 - 2(3)^2 + 5
\]
\[
j = 4 \cdot 25 - 2 \cdot 9 + 5
\]
\[
j = 100 - 18 + 5
\]
\[
j = 87
\]

**Calculate \( k \):**
Given \( a = -1 \) and \( b = 4 \), substitute these values into the expression for \( M \):
\[
M = 4a^2 - 2b^2 + a
\]
\[
k = 4(-1)^2 - 2(4)^2 + (-1)
\]
\[
k = 4 \cdot 1 - 2 \cdot 16 - 1
\]
\[
k = 4 - 32 - 1
\]
\[
k = -29
\]

**Calculate \( j + 2k \):**
\[
j + 2k = 87 + 2(-29)
\]
\[
j + 2k = 87 - 58
\]
\[
j + 2k = 29
\]

Thus, the correct answer is:
**A. 29**
A
gpto1 To solve this problem, we'll calculate the values step by step.

First, compute \( j \) when \( a = 5 \) and \( b = 3 \):

\[ M = 4a^2 - 2b^2 + a = 4(5)^2 - 2(3)^2 + 5 = 4(25) - 2(9) + 5 = 100 - 18 + 5 = 87 \]

So, \( j = 87 \).

Next, compute \( k \) when \( a = -1 \) and \( b = 4 \):

\[ M = 4(-1)^2 - 2(4)^2 + (-1) = 4(1) - 2(16) - 1 = 4 - 32 - 1 = -29 \]

So, \( k = -29 \).

Finally, compute \( j + 2k \):

\[ j + 2k = 87 + 2(-29) = 87 - 58 = 29 \]

**Answer: A**
A
deepseekv3 To solve the problem, we first calculate the values of \( j \) and \( k \) using the given expression \( M = 4a^2 - 2b^2 + a \).

1. **Calculate \( j \) when \( a = 5 \) and \( b = 3 \):**
\[
j = 4(5)^2 - 2(3)^2 + 5 = 4 \times 25 - 2 \times 9 + 5 = 100 - 18 + 5 = 87
\]

2. **Calculate \( k \) when \( a = -1 \) and \( b = 4 \):**
\[
k = 4(-1)^2 - 2(4)^2 + (-1) = 4 \times 1 - 2 \times 16 - 1 = 4 - 32 - 1 = -29
\]

3. **Calculate \( j + 2k \):**
\[
j + 2k = 87 + 2(-29) = 87 - 58 = 29
\]

Therefore, the correct answer is:

\boxed{A}
A