| 模型 | 模型答案 | 正确答案 |
|---|---|---|
| 金声玉亮2.0 | A. 6 Explanation: The degrees of freedom for a chi-squared test of independence is calculated as (r-1) × (c-1), where r is the number of rows and c is the number of columns in the contingency table. In this case, the table has 3 rows and 4 columns, so the degrees of freedom is (3-1) × (4-1) = 2 × 3 = 6. |
A |
| deepseekr1 | The degrees of freedom for a chi-squared test of independence in a contingency table are calculated as \((\text{rows} - 1) \times (\text{columns} - 1)\). For a 3×4 table, this is \((3-1) \times (4-1) = 2 \times 3 = 6\). **Answer:** A. 6 |
A |
| gpto1 | A | A |
| GPT-4o | B. 8 | A |
| llama3.1-70B-Instruct | A |
A |
| llama3.1-405B-Instruct | A. 6 The degrees of freedom for a chi-squared test of independence on a contingency table is calculated as (number of rows - 1) × (number of columns - 1). In this case, the table has 3 rows and 4 columns, so the degrees of freedom is (3 - 1) × (4 - 1) = 2 × 3 = 6. |
A |
| DeepSeek-Coder-V2 | A | A |
| Qwen2-72B-Instruct | B. 8 | A |
| baichuan4 | C | A |
| doubao | A For a contingency table with r rows and c columns, the degrees of freedom for a chi-squared test of independence is (r - 1) * (c - 1). In this case, for a 3 × 4 contingency table, it is (3 - 1) * (4 - 1) = 2 * 3 = 6 degrees of freedom. |
A |
| minimax | The degrees of freedom for a chi-squared test of independence in a contingency table are calculated by the formula: Degrees of freedom (df) = (number of rows - 1) * (number of columns - 1) For a 3 × 4 contingency table: df = (3 - 1) * (4 - 1) df = 2 * 3 df = 6 So the correct answer is: A. 6 |
A |
| kimi | The degrees of freedom for a chi-squared test of independence can be calculated using the formula: Degrees of freedom = (number of rows - 1) * (number of columns - 1) For a 3 × 4 contingency table, the calculation would be: Degrees of freedom = (3 - 1) * (4 - 1) = 2 * 3 = 6 Answer: A. 6 |
A |
| wenxinyiyan | A chi-squared test of independence for a contingency table has degrees of freedom calculated as (r - 1) * (c - 1), where r is the number of rows and c is the number of columns in the table. Given a 3 × 4 contingency table, we have: r = 3 (number of rows) c = 4 (number of columns) Degrees of freedom = (3 - 1) * (4 - 1) = 2 * 3 = 6 So, the chi-squared test of independence for this 3 × 4 contingency table has 6 degrees of freedom. The answer is A. 6. |
A |
| zhipu | The degrees of freedom for a chi-squared test of independence in a contingency table is calculated using the formula: \[ \text{Degrees of Freedom} = (r - 1) \times (c - 1) \] where \( r \) is the number of rows and \( c \) is the number of columns. For a 3 × 4 contingency table: - \( r = 3 \) - \( c = 4 \) Plugging these values into the formula: \[ \text{Degrees of Freedom} = (3 - 1) \times (4 - 1) = 2 \times 3 = 6 \] So, the correct answer is: A. 6 |
A |
| gpto1 | A | A |
| deepseekv3 | The degrees of freedom for a chi-squared test of independence on a contingency table is calculated using the formula: \[ \text{Degrees of freedom} = (r - 1) \times (c - 1) \] where \( r \) is the number of rows and \( c \) is the number of columns. For a 3 × 4 contingency table: \[ \text{Degrees of freedom} = (3 - 1) \times (4 - 1) = 2 \times 3 = 6 \] The correct answer is: **A. 6** |
A |