金声玉亮2.0模型评测报告

问题

You are an expert Python programmer, and here is your task: Write a function to find the similar elements from the given two tuple lists. Your code should pass these tests:

assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5)
assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4)
assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14)

[BEGIN]
'def similar_elements(test_tup1, test_tup2):
res = tuple(set(test_tup1) & set(test_tup2))
return (res)'
[DONE]

You are an expert Python programmer, and here is your task: Write a python function to identify non-prime numbers. Your code should pass these tests:

assert is_not_prime(2) == False
assert is_not_prime(10) == True
assert is_not_prime(35) == True

[BEGIN]
'import math
def is_not_prime(n):
result = False
for i in range(2,int(math.sqrt(n)) + 1):
if n % i == 0:
result = True
return result'
[DONE]

You are an expert Python programmer, and here is your task: Write a function to find the largest integers from a given list of numbers using heap queue algorithm. Your code should pass these tests:

assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],3)==[85, 75, 65]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],2)==[85, 75]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],5)==[85, 75, 65, 58, 35]

[BEGIN]
'import heapq as hq
def heap_queue_largest(nums,n):
largest_nums = hq.nlargest(n, nums)
return largest_nums'
[DONE]

You are an expert Python programmer, and here is your task: Write a function to check if a substring is present in a given list of string values. Your code should pass these tests:

assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True
assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False
assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True

[BEGIN]

答案

模型	模型答案	测试结果
金声玉亮2.0	```python def find_substring(str_list, substring): for string in str_list: if substring in string: return True return False ``` [DONE]	pass 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
deepseekr1	To solve this problem, we need to determine if a given substring is present in any of the strings within a provided list. The solution involves iterating through each string in the list and checking for the presence of the substring using straightforward string operations. ### Approach 1. Iterate Through Each String: For each string in the input list, check if the substring exists within it. 2. Check Substring Presence: Use Python's `in` operator to check if the substring is part of the current string in the iteration. 3. Return Result Immediately: If any string contains the substring, return `True` immediately. If the loop completes without finding any occurrence, return `False`. This approach ensures that we efficiently check each string and return as soon as we find a match, minimizing unnecessary iterations. ### Solution Code ```python def find_substring(string_list, substring): for s in string_list: if substring in s: return True return False ``` ### Explanation - Iteration: The function iterates through each string in the provided list. - Substring Check: For each string, it checks if the substring is present using the `in` operator, which efficiently checks for substring presence. - Early Termination: The function returns `True` immediately upon finding the first occurrence of the substring, ensuring optimal performance. If no substring is found after checking all strings, it returns `False`. This method is efficient with a time complexity of O(n*m), where n is the number of strings in the list and m is the average length of the strings. This is because each string is checked in linear time relative to its length for the presence of the substring. The early termination ensures that in the best case, where the substring is found in the first string, the complexity is O(1).	pass 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
gpto1	[BEGIN] ```python def find_substring(str_list, substr): for s in str_list: if substr in s: return True return False ``` [DONE]	failed 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
GPT-4o	Sure, here is the function to check if a substring is present in a given list of string values: ```python def find_substring(str_list, substring): return any(substring in s for s in str_list) # Tests assert find_substring(["red", "black", "white", "green", "orange"],"ack") == True assert find_substring(["red", "black", "white", "green", "orange"],"abc") == False assert find_substring(["red", "black", "white", "green", "orange"],"ange") == True ``` This function uses the `any` function together with a generator expression to check if the `substring` is present in any of the strings in the `str_list`. If the `substring` is found in any string, `any` will return `True`; otherwise, it will return `False`.	pass 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
llama3.1-70B-Instruct	def find_substring(lst, sub): for string in lst: if sub in string: return True return False	pass 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
llama3.1-405B-Instruct	def find_substring(lst, sub): for string in lst: if sub in string: return True return False	pass 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
DeepSeek-Coder-V2	```python def find_substring(str_list, substring): for string in str_list: if substring in string: return True return False ``` [DONE]	pass 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
Qwen2-72B-Instruct	'def find_substring(str_list, substr): return any(substr in s for s in str_list)' [DONE]	pass 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
baichuan4	To check if a substring is present in a given list of string values, you can use the `any()` function along with a generator expression that checks each string in the list for the presence of the substring using the `in` operator. Here's the implementation: ```python def find_substring(string_list, substring): return any(substring in s for s in string_list) ``` Let's test it with the provided assertions: ```python assert find_substring(["red", "black", "white", "green", "orange"], "ack") == True assert find_substring(["red", "black", "white", "green", "orange"], "abc") == False assert find_substring(["red", "black", "white", "green", "orange"], "ange") == True ``` The `find_substring` function will return `True` if the `substring` is found within any of the strings in `string_list`, otherwise, it will return `False`.	pass 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
doubao	def find_substring(str_list, sub): for s in str_list: if sub in s: return True return False [DONE]	pass 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
minimax	```python def find_substring(str_list, sub): return any(sub in s for s in str_list) # Test cases assert find_substring(["red", "black", "white", "green", "orange"], "ack") == True assert find_substring(["red", "black", "white", "green", "orange"], "abc") == False assert find_substring(["red", "black", "white", "green", "orange"], "ange") == True ``` [DONE]	pass 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
kimi	```python def similar_elements(test_tup1, test_tup2): res = tuple(sorted(set(test_tup1) & set(test_tup2))) return res def is_not_prime(n): if n <= 1: return True for i in range(2, int(n**0.5) + 1): if n % i == 0: return True return False import heapq as hq def heap_queue_largest(nums, n): largest_nums = hq.nlargest(n, nums) return largest_nums def find_substring(strings, substring): return any(substring in s for s in strings) ``` These functions should pass the tests you provided: 1. `similar_elements` finds the common elements between two tuples and returns them as a sorted tuple. 2. `is_not_prime` checks if a number is not prime by trying to divide it by all numbers up to its square root. 3. `heap_queue_largest` finds the largest `n` numbers in a list using the heap queue algorithm. 4. `find_substring` checks if a substring is present in any of the strings in a list.	pass 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
wenxinyiyan	'def find_substring(lst, substring): for string in lst: if substring in string: return True return False' [DONE] Explanation: The function `find_substring` takes two arguments: a list of strings `lst` and a substring `substring` to search for. It iterates through each string in the list using a for loop. If the substring is found in any of the strings (using the `in` operator), it immediately returns `True`. If the loop completes without finding the substring, it returns `False`. Note: The code provided in the [BEGIN] and [DONE] sections should be copied and pasted without the surrounding single quotes. The single quotes are only used here to display the code as a string for explanation purposes. Here's the corrected code without the single quotes: ```python def find_substring(lst, substring): for string in lst: if substring in string: return True return False ``` This code will correctly pass the given tests: ```python assert find_substring(["red", "black", "white", "green", "orange"], "ack") == True assert find_substring(["red", "black", "white", "green", "orange"], "abc") == False assert find_substring(["red", "black", "white", "green", "orange"], "ange") == True ```	failed 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
zhipu	Here is a Python function that checks if a substring is present in any of the string values within a given list. The function iterates through each string in the list and checks if the substring is present using the `in` keyword. ```python def find_substring(string_list, substring): for string in string_list: if substring in string: return True return False # Test cases assert find_substring(["red", "black", "white", "green", "orange"], "ack") == True assert find_substring(["red", "black", "white", "green", "orange"], "abc") == False assert find_substring(["red", "black", "white", "green", "orange"], "ange") == True print("All tests passed!") ``` This function will return `True` if the substring is found in any of the strings in the list, and `False` otherwise. The provided test cases are used to validate the correctness of the function. If the function passes all the assertions, it will print "All tests passed!" indicating that it works as expected.	pass 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
gpto1	[BEGIN] ```python def find_substring(str_list, substr): for s in str_list: if substr in s: return True return False ``` [DONE]	failed 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True
deepseekv3	```python def find_substring(strings, substring): for s in strings: if substring in s: return True return False ``` ### Explanation: - Function Definition: The function `find_substring` takes two arguments: `strings` (a list of strings) and `substring` (the substring to search for). - Loop Through Strings: The function loops through each string in the list `strings`. - Check for Substring: For each string, it checks if the `substring` is present using the `in` operator. - Return Result: If the substring is found in any of the strings, the function returns `True`. If the loop completes without finding the substring, it returns `False`. ### Test Cases: 1. `find_substring(["red", "black", "white", "green", "orange"], "ack")` should return `True` because "ack" is a substring of "black". 2. `find_substring(["red", "black", "white", "green", "orange"], "abc")` should return `False` because "abc" is not a substring of any string in the list. 3. `find_substring(["red", "black", "white", "green", "orange"], "ange")` should return `True` because "ange" is a substring of "orange".	pass 测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True

模型

模型答案

测试结果

金声玉亮2.0

```python
def find_substring(str_list, substring):
for string in str_list:
if substring in string:
return True
return False
```
[DONE]

pass
测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True
assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False
assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True

deepseekr1

To solve this problem, we need to determine if a given substring is present in any of the strings within a provided list. The solution involves iterating through each string in the list and checking for the presence of the substring using straightforward string operations.

### Approach
1. **Iterate Through Each String**: For each string in the input list, check if the substring exists within it.
2. **Check Substring Presence**: Use Python's `in` operator to check if the substring is part of the current string in the iteration.
3. **Return Result Immediately**: If any string contains the substring, return `True` immediately. If the loop completes without finding any occurrence, return `False`.

This approach ensures that we efficiently check each string and return as soon as we find a match, minimizing unnecessary iterations.

### Solution Code
```python
def find_substring(string_list, substring):
for s in string_list:
if substring in s:
return True
return False
```

### Explanation
- **Iteration**: The function iterates through each string in the provided list.
- **Substring Check**: For each string, it checks if the substring is present using the `in` operator, which efficiently checks for substring presence.
- **Early Termination**: The function returns `True` immediately upon finding the first occurrence of the substring, ensuring optimal performance. If no substring is found after checking all strings, it returns `False`.

This method is efficient with a time complexity of O(n*m), where n is the number of strings in the list and m is the average length of the strings. This is because each string is checked in linear time relative to its length for the presence of the substring. The early termination ensures that in the best case, where the substring is found in the first string, the complexity is O(1).

gpto1

[BEGIN]
```python
def find_substring(str_list, substr):
for s in str_list:
if substr in s:
return True
return False
```
[DONE]

failed
测试用例：assert find_substring(["red", "black", "white", "green", "orange"],"ack")==True
assert find_substring(["red", "black", "white", "green", "orange"],"abc")==False
assert find_substring(["red", "black", "white", "green", "orange"],"ange")==True

GPT-4o

Sure, here is the function to check if a substring is present in a given list of string values:

```python
def find_substring(str_list, substring):
return any(substring in s for s in str_list)

# Tests
assert find_substring(["red", "black", "white", "green", "orange"],"ack") == True
assert find_substring(["red", "black", "white", "green", "orange"],"abc") == False
assert find_substring(["red", "black", "white", "green", "orange"],"ange") == True
```

This function uses the `any` function together with a generator expression to check if the `substring` is present in any of the strings in the `str_list`. If the `substring` is found in any string, `any` will return `True`; otherwise, it will return `False`.

llama3.1-70B-Instruct

def find_substring(lst, sub):
for string in lst:
if sub in string:
return True
return False

llama3.1-405B-Instruct

def find_substring(lst, sub):
for string in lst:
if sub in string:
return True
return False

DeepSeek-Coder-V2

```python
def find_substring(str_list, substring):
for string in str_list:
if substring in string:
return True
return False
```
[DONE]

Qwen2-72B-Instruct

'def find_substring(str_list, substr):
return any(substr in s for s in str_list)'
[DONE]

baichuan4

To check if a substring is present in a given list of string values, you can use the `any()` function along with a generator expression that checks each string in the list for the presence of the substring using the `in` operator. Here's the implementation:

```python
def find_substring(string_list, substring):
return any(substring in s for s in string_list)
```

Let's test it with the provided assertions:

```python
assert find_substring(["red", "black", "white", "green", "orange"], "ack") == True
assert find_substring(["red", "black", "white", "green", "orange"], "abc") == False
assert find_substring(["red", "black", "white", "green", "orange"], "ange") == True
```

The `find_substring` function will return `True` if the `substring` is found within any of the strings in `string_list`, otherwise, it will return `False`.

doubao

def find_substring(str_list, sub):
for s in str_list:
if sub in s:
return True
return False
[DONE]

minimax

```python
def find_substring(str_list, sub):
return any(sub in s for s in str_list)

# Test cases
assert find_substring(["red", "black", "white", "green", "orange"], "ack") == True
assert find_substring(["red", "black", "white", "green", "orange"], "abc") == False
assert find_substring(["red", "black", "white", "green", "orange"], "ange") == True
```
[DONE]

kimi

```python
def similar_elements(test_tup1, test_tup2):
res = tuple(sorted(set(test_tup1) & set(test_tup2)))
return res

def is_not_prime(n):
if n <= 1:
return True
for i in range(2, int(n**0.5) + 1):
if n % i == 0:
return True
return False

import heapq as hq
def heap_queue_largest(nums, n):
largest_nums = hq.nlargest(n, nums)
return largest_nums

def find_substring(strings, substring):
return any(substring in s for s in strings)
```

These functions should pass the tests you provided:

1. `similar_elements` finds the common elements between two tuples and returns them as a sorted tuple.
2. `is_not_prime` checks if a number is not prime by trying to divide it by all numbers up to its square root.
3. `heap_queue_largest` finds the largest `n` numbers in a list using the heap queue algorithm.
4. `find_substring` checks if a substring is present in any of the strings in a list.

wenxinyiyan

'def find_substring(lst, substring):
for string in lst:
if substring in string:
return True
return False'
[DONE]

Explanation:
The function `find_substring` takes two arguments: a list of strings `lst` and a substring `substring` to search for. It iterates through each string in the list using a for loop. If the substring is found in any of the strings (using the `in` operator), it immediately returns `True`. If the loop completes without finding the substring, it returns `False`.

Note: The code provided in the [BEGIN] and [DONE] sections should be copied and pasted without the surrounding single quotes. The single quotes are only used here to display the code as a string for explanation purposes.

Here's the corrected code without the single quotes:

```python
def find_substring(lst, substring):
for string in lst:
if substring in string:
return True
return False
```
This code will correctly pass the given tests:

```python
assert find_substring(["red", "black", "white", "green", "orange"], "ack") == True
assert find_substring(["red", "black", "white", "green", "orange"], "abc") == False
assert find_substring(["red", "black", "white", "green", "orange"], "ange") == True
```

zhipu

Here is a Python function that checks if a substring is present in any of the string values within a given list. The function iterates through each string in the list and checks if the substring is present using the `in` keyword.

```python
def find_substring(string_list, substring):
for string in string_list:
if substring in string:
return True
return False

# Test cases
assert find_substring(["red", "black", "white", "green", "orange"], "ack") == True
assert find_substring(["red", "black", "white", "green", "orange"], "abc") == False
assert find_substring(["red", "black", "white", "green", "orange"], "ange") == True

print("All tests passed!")
```

This function will return `True` if the substring is found in any of the strings in the list, and `False` otherwise. The provided test cases are used to validate the correctness of the function. If the function passes all the assertions, it will print "All tests passed!" indicating that it works as expected.

gpto1

[BEGIN]
```python
def find_substring(str_list, substr):
for s in str_list:
if substr in s:
return True
return False
```
[DONE]

deepseekv3

```python
def find_substring(strings, substring):
for s in strings:
if substring in s:
return True
return False
```

### Explanation:
- **Function Definition**: The function `find_substring` takes two arguments: `strings` (a list of strings) and `substring` (the substring to search for).
- **Loop Through Strings**: The function loops through each string in the list `strings`.
- **Check for Substring**: For each string, it checks if the `substring` is present using the `in` operator.
- **Return Result**: If the substring is found in any of the strings, the function returns `True`. If the loop completes without finding the substring, it returns `False`.

### Test Cases:
1. `find_substring(["red", "black", "white", "green", "orange"], "ack")` should return `True` because "ack" is a substring of "black".
2. `find_substring(["red", "black", "white", "green", "orange"], "abc")` should return `False` because "abc" is not a substring of any string in the list.
3. `find_substring(["red", "black", "white", "green", "orange"], "ange")` should return `True` because "ange" is a substring of "orange".