| 模型 | 模型答案 | 测试结果 |
|---|---|---|
| 金声玉亮2.0 | ```python def index_minimum(records): # Find the tuple with the minimum value in the second position min_record = min(records, key=lambda x: x[1]) # Return the name (first element of the tuple) return min_record[0] ``` [DONE] |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| deepseekr1 | [BEGIN] def index_minimum(lst): min_tuple = min(lst, key=lambda x: x[1]) return min_tuple[0] [DONE] |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| gpto1 | ```python def index_minimum(tuples_list): return min(tuples_list, key=lambda x: x[1])[0] ``` |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| GPT-4o | To solve this task, we need to write a function that finds the tuple with the minimum value in the second element and returns the first element of that tuple. Here's the function that does this: ```python def index_minimum(tuples_list): # Find the tuple with the minimum value in the second element min_tuple = min(tuples_list, key=lambda x: x[1]) # Return the first element of that tuple return min_tuple[0] # Test cases to validate the solution assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' ``` Explanation: 1. We use the `min()` function to find the tuple with the minimum value in the second element. 2. The `key` argument of the `min()` function is a lambda function that extracts the second element of each tuple for comparison. 3. The function returns the first element of the tuple that has the minimum value in the second element. This code is simple and concise, and it will pass the provided test cases. |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| llama3.1-70B-Instruct | def index_minimum(tuples): return min(tuples, key=lambda x: x[1])[0] |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| llama3.1-405B-Instruct | def index_minimum(tuples): return min(tuples, key=lambda x: x[1])[0] |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| DeepSeek-Coder-V2 | ```python def index_minimum(records): # Find the tuple with the minimum value in the second position min_record = min(records, key=lambda x: x[1]) # Return the name (first element of the tuple) return min_record[0] ``` [DONE] |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| Qwen2-72B-Instruct | 'def index_minimum(test_tup):\n return min(test_tup, key = lambda x:x[1])[0]' [DONE] |
failed 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| baichuan4 | To complete this task, you can use the `min` function with a custom key. Here's the code: ```python def index_minimum(tuples): return min(tuples, key=lambda x: x[1])[0] ``` This function finds the tuple with the minimum value in the second element (index 1) and returns the first element (index 0) of that tuple. |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| doubao | 'def index_minimum(tuples):
min_value = min(tuples, key=lambda x: x[1])[1] for tup in tuples: if tup[1] == min_value: return tup[0]' [DONE] |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| minimax | ```python def index_minimum(tuples_list): # Find the tuple with the minimum value using min() and a key function min_value_tuple = min(tuples_list, key=lambda x: x[1]) # Return the first element of the tuple with the minimum value return min_value_tuple[0] # Test cases assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' ``` This function `index_minimum` takes a list of tuples, where each tuple consists of a name and a number. It uses the `min` function with a key argument that specifies to compare the second element of each tuple (the number). The `min` function returns the tuple with the smallest number, and the function then returns the name (the first element of the tuple) associated with that minimum number. The test cases check that the function correctly identifies the name with the minimum number in the list of tuples. |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| kimi | ```python def similar_elements(test_tup1, test_tup2): res = tuple(sorted(set(test_tup1) & set(test_tup2))) return res def is_not_prime(n): if n <= 1: return True for i in range(2, int(n**0.5) + 1): if n % i == 0: return True return False import heapq as hq def heap_queue_largest(nums, n): largest_nums = hq.nlargest(n, nums) return largest_nums def index_minimum(tuples): return min(tuples, key=lambda x: x[1])[0] ``` These functions should pass the tests provided in your task description. Here's a brief explanation of each function: 1. `similar_elements`: This function finds the common elements between two tuples and returns them as a sorted tuple. 2. `is_not_prime`: This function checks if a number is not prime. It returns `True` if the number is not prime, otherwise `False`. 3. `heap_queue_largest`: This function uses the `heapq` module to find the `n` largest numbers in a list. 4. `index_minimum`: This function finds the tuple with the minimum value in the second element (assuming it's the value) and returns the first element of that tuple. |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| wenxinyiyan | 'def index_minimum(lst): return min(lst, key=lambda x: x[1])[0]' [DONE] Explanation: The `index_minimum` function takes a list of tuples as input, where each tuple contains a name and a corresponding value. The function uses the `min` function with a `key` parameter to find the tuple with the minimum value. The `key` parameter is set to a lambda function that extracts the second element (index 1) from each tuple, which represents the value. Finally, the function returns the first element (index 0) of the tuple with the minimum value, which corresponds to the name. Note: The provided code snippets are enclosed in single quotes (' ') to indicate that they are strings. However, in practice, you should remove the quotes and execute the code as Python statements. I have preserved the quotes to maintain the format provided in your question. |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| zhipu | To achieve the task, we need to write a function that iterates through the list of tuples, compares the values, and returns the name associated with the minimum value. Here's the code that accomplishes this: ```python def index_minimum(tuples_list): # Initialize the minimum value and the associated name min_value = float('inf') min_name = None # Iterate through each tuple in the list for name, value in tuples_list: # If the current value is less than the minimum value found so far if value < min_value: min_value = value min_name = name return min_name # Test cases assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' ``` This function works as follows: 1. It initializes `min_value` to infinity and `min_name` to `None`. 2. It iterates through each tuple in the input list. 3. For each tuple, it checks if the value is less than the current `min_value`. 4. If it is, it updates `min_value` and `min_name` with the current tuple's value and name. 5. After iterating through all tuples, it returns the name associated with the minimum value. This code should pass the provided test cases. |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| gpto1 | ```python def index_minimum(tuples_list): return min(tuples_list, key=lambda x: x[1])[0] ``` |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |
| deepseekv3 | To solve this problem, we need to write a function that takes a list of tuples, where each tuple contains a name and a value, and returns the name associated with the minimum value in the list. Here's how you can implement this: ```python def index_minimum(records): # Initialize the minimum value with a large number min_value = float('inf') min_name = "" # Iterate through each tuple in the list for name, value in records: # Check if the current value is less than the minimum value found so far if value < min_value: min_value = value min_name = name return min_name ``` ### Explanation: 1. **Initialization**: We start by initializing `min_value` with `float('inf')` to ensure that any value in the list will be smaller than this initial value. `min_name` is initialized as an empty string to store the name associated with the minimum value. 2. **Iteration**: We loop through each tuple in the list. For each tuple, we compare the value with `min_value`. 3. **Comparison and Update**: If the current value is less than `min_value`, we update `min_value` with the current value and set `min_name` to the corresponding name. 4. **Return**: After the loop completes, we return `min_name`, which is the name associated with the minimum value. This function will correctly identify and return the name associated with the minimum value in the list of tuples. |
pass 测试用例:assert index_minimum([('Rash', 143), ('Manjeet', 200), ('Varsha', 100)]) == 'Varsha' assert index_minimum([('Yash', 185), ('Dawood', 125), ('Sanya', 175)]) == 'Dawood' assert index_minimum([('Sai', 345), ('Salman', 145), ('Ayesha', 96)]) == 'Ayesha' |