金声玉亮2.0模型评测报告

问题

You are an expert Python programmer, and here is your task: Write a function to find the similar elements from the given two tuple lists. Your code should pass these tests:

assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5)
assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4)
assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14)

[BEGIN]
'def similar_elements(test_tup1, test_tup2):
res = tuple(set(test_tup1) & set(test_tup2))
return (res)'
[DONE]

You are an expert Python programmer, and here is your task: Write a python function to identify non-prime numbers. Your code should pass these tests:

assert is_not_prime(2) == False
assert is_not_prime(10) == True
assert is_not_prime(35) == True

[BEGIN]
'import math
def is_not_prime(n):
result = False
for i in range(2,int(math.sqrt(n)) + 1):
if n % i == 0:
result = True
return result'
[DONE]

You are an expert Python programmer, and here is your task: Write a function to find the largest integers from a given list of numbers using heap queue algorithm. Your code should pass these tests:

assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],3)==[85, 75, 65]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],2)==[85, 75]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],5)==[85, 75, 65, 58, 35]

[BEGIN]
'import heapq as hq
def heap_queue_largest(nums,n):
largest_nums = hq.nlargest(n, nums)
return largest_nums'
[DONE]

You are an expert Python programmer, and here is your task: Write a function to sort each sublist of strings in a given list of lists using lambda function. Your code should pass these tests:

assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']]
assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']]
assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]

[BEGIN]

答案

模型	模型答案	测试结果
金声玉亮2.0	```python def sort_sublists(list_of_lists): return [sorted(sublist, key=lambda x: x.strip().lower()) for sublist in list_of_lists] ``` [DONE]	wrong_answer 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
deepseekr1	To solve this problem, we need to write a function that sorts each sublist of strings in a given list of lists using a lambda function. The goal is to return a new list of lists where each sublist is sorted in lexicographical order. ### Approach The approach involves using Python's built-in `sorted()` function to sort each sublist. To adhere to the problem's requirement of using a lambda function, we utilize the `map()` function along with a lambda expression. The `map()` function applies the lambda to each sublist in the input, which in turn sorts the sublist. The result is then converted to a list to meet the expected output format. ### Solution Code ```python def sort_sublists(input_list): return list(map(lambda sub: sorted(sub), input_list)) ``` ### Explanation 1. Input Handling: The function takes an `input_list`, which can be a list or a tuple of lists. Each element in `input_list` is a sublist of strings. 2. Sorting with Lambda: The `map()` function iterates over each sublist in `input_list`. For each sublist, the lambda function `lambda sub: sorted(sub)` is applied, which sorts the sublist using the default lexicographical order. 3. Conversion to List: The result of `map()` is a map object, which is converted to a list using `list()` to produce the final list of sorted sublists. This approach efficiently sorts each sublist using a combination of `map()` and `sorted()`, ensuring clarity and adherence to the problem constraints.	pass 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
gpto1	```python def sort_sublists(list_of_lists): sorted_sublists = [sorted(sublist, key=lambda s: s) for sublist in list_of_lists] return sorted_sublists ```	pass 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
GPT-4o	Here's the implementation of the function to sort each sublist of strings in a given list of lists using a lambda function: ```python def sort_sublists(list_of_lists): return [sorted(sublist, key=lambda x: x.strip()) for sublist in list_of_lists] # Test cases assert sort_sublists([["green", "orange"], ["black", "white"], ["white", "black", "orange"]]) == [['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists([[" red ", "green"], ["blue ", " black"], [" orange", "brown"]]) == [[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists([["zilver", "gold"], ["magnesium", "aluminium"], ["steel", "bronze"]]) == [['gold', 'zilver'], ['aluminium', 'magnesium'], ['bronze', 'steel']] ``` Explanation: - The `sort_sublists` function takes a list of lists (`list_of_lists`) as input. - It returns a new list where each sublist is sorted. - The sorting is done using the `sorted` function with a `lambda` function as the key. - The `lambda` function uses `strip()` to remove any leading or trailing whitespace from the strings during comparison. This implementation ensures that the sublists are sorted correctly and will pass the provided test cases.	wrong_answer 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
llama3.1-70B-Instruct	def sort_sublists(lists): return sorted(lists, key=lambda x: x[0].lower())	wrong_answer 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
llama3.1-405B-Instruct	def sort_sublists(lst): return [sorted(sublist) for sublist in lst]	pass 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
DeepSeek-Coder-V2	```python def sort_sublists(list_of_lists): return [sorted(sublist, key=lambda x: x.strip().lower()) for sublist in list_of_lists] ``` [DONE]	wrong_answer 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
Qwen2-72B-Instruct	'def sort_sublists(test_list):\n res = list(map(lambda sub: sorted(sub), test_list))\n return res' [DONE]	failed 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
baichuan4	Here's the function to sort each sublist of strings in a given list of lists using a lambda function: ```python def sort_sublists(list_of_lists): return [sorted(sublist, key=lambda x: x.strip()) for sublist in list_of_lists] ``` This function iterates through each sublist in the input `list_of_lists`, sorting each one using Python's built-in `sorted` function. The `key` parameter is set to a lambda function that strips any leading or trailing whitespace from each string before comparing them. This ensures that strings with different amounts of whitespace are correctly sorted based on their actual content. Let's run the tests you provided: ```python assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"])) == [['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"])) == [[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"])) == [['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']] ``` All tests should pass without any assertion errors.	wrong_answer 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
doubao	'def sort_sublists(lst): return [sorted(sublist, key=lambda x: x) for sublist in lst]' [DONE]	pass 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
minimax	```python def sort_sublists(list_of_lists): return [sorted(sublist, key=lambda x: x.strip().lower()) for sublist in list_of_lists] # Test cases assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"])) == [['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ", "green"], ["blue ", " black"], [" orange", "brown"])) == [[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver", "gold"], ["magnesium", "aluminium"], ["steel", "bronze"])) == [['gold', 'zilver'], ['aluminium', 'magnesium'], ['bronze', 'steel']] ``` This function `sort_sublists` takes a list of lists as input and returns a new list of lists with each sublist sorted. The sorting is case-insensitive and ignores leading and trailing whitespace, as it uses a lambda function to strip and convert strings to lowercase for comparison purposes. The test cases check that the function correctly sorts the sublists as specified.	wrong_answer 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
kimi	Here's the Python code for each of the tasks you've provided: 1. Function to find similar elements from two tuple lists: ```python def similar_elements(test_tup1, test_tup2): res = tuple(sorted(set(test_tup1) & set(test_tup2))) return res ``` 2. Function to identify non-prime numbers: ```python import math def is_not_prime(n): if n <= 1: return True for i in range(2, int(math.sqrt(n)) + 1): if n % i == 0: return True return False ``` 3. Function to find the largest integers from a given list of numbers using heap queue algorithm: ```python import heapq def heap_queue_largest(nums, n): largest_nums = heapq.nlargest(n, nums) return largest_nums ``` 4. Function to sort each sublist of strings in a given list of lists using lambda function: ```python def sort_sublists(list_of_lists): return [sorted(sublist, key=lambda s: s.strip().lower()) for sublist in list_of_lists] ``` Each function is designed to pass the tests you've provided. Here's how you can use them: ```python # Test similar_elements function assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5) assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4) assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14) # Test is_not_prime function assert is_not_prime(2) == False assert is_not_prime(10) == True assert is_not_prime(35) == True # Test heap_queue_largest function assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 3) == [85, 75, 65] assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 2) == [85, 75] assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 5) == [85, 75, 65, 58, 35] # Test sort_sublists function assert sort_sublists(["green", "orange"]) == ['green', 'orange'] assert sort_sublists([" red ","green" ]) == [' green', 'green'] assert sort_sublists(["zilver","gold"]) == ['gold', 'zilver'] ``` Note that the `similar_elements` function now returns the result as a sorted tuple to ensure the order is consistent. The `is_not_prime` function has been updated to handle the case when `n` is less than or equal to 1, which are not prime numbers.	failed 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
wenxinyiyan	'def sort_sublists(lst): return [sorted(sublst) for sublst in lst]' [DONE] Explanation for the last task: The given task is to sort each sublist of strings in a list of lists. The `sort_sublists` function takes a list of lists (`lst`) as input. It uses a list comprehension to iterate over each sublist (`sublst`) in the input list. For each sublist, it applies the `sorted` function, which returns a new sorted list. The sorted sublists are then collected into a new list, which is returned as the output of the function. Note: The original code snippet provided in the question uses a lambda function, but it's not necessary for this task. The `sorted` function can be used directly without a lambda function since we are sorting strings, and the default sorting order for strings is lexicographical, which is what we need in this case. However, if you want to use a lambda function explicitly to define the sorting key, you can modify the code as follows: ```python def sort_sublists(lst): return [sorted(sublst, key=lambda x: x) for sublst in lst] ``` In this modified version, the `key` parameter of the `sorted` function is set to a lambda function that takes an element `x` from the sublist and returns it as the sorting key. Since the lambda function simply returns the element itself, the sorting order will be the same as the default lexicographical order for strings. But again, this is not necessary for the given task, and the simpler version without the lambda function is preferred.	pass 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
zhipu	To achieve the task of sorting each sublist of strings in a given list of lists using a lambda function, we can use the `sorted` function along with a lambda function to define the sorting criteria. Here is the implementation of the `sort_sublists` function: ```python def sort_sublists(list_of_lists): return [sorted(sublist, key=lambda x: x) for sublist in list_of_lists] # Test cases assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"])) == [['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ", "green"], ["blue ", " black"], [" orange", "brown"])) == [[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver", "gold"], ["magnesium", "aluminium"], ["steel", "bronze"])) == [['gold', 'zilver'], ['aluminium', 'magnesium'], ['bronze', 'steel']] print("All tests passed!") ``` ### Explanation: 1. Function Definition: The function `sort_sublists` takes a list of lists (`list_of_lists`) as input. 2. List Comprehension: We use a list comprehension to iterate over each sublist in the input list. 3. Sorting: For each sublist, we apply the `sorted` function. The `key` parameter of the `sorted` function is set to a lambda function `lambda x: x`, which means the sorting is based on the natural order of the strings. 4. Return: The function returns a new list of lists where each sublist is sorted. ### Test Cases: - The provided test cases are used to ensure that the function behaves as expected. Each test case asserts that the output of the function matches the expected sorted list of lists. This implementation should pass all the given tests.	pass 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
gpto1	```python def sort_sublists(list_of_lists): sorted_sublists = [sorted(sublist, key=lambda s: s) for sublist in list_of_lists] return sorted_sublists ```	pass 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
deepseekv3	```python def sort_sublists(lst): return [sorted(sublist, key=lambda x: x.strip()) for sublist in lst] # Test cases assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"])) == [['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"])) == [[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"])) == [['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']] ``` ### Explanation: 1. Function Definition: The function `sort_sublists` takes a list of lists (where each sublist contains strings) as input. 2. Sorting Sublists: For each sublist in the input list, the `sorted` function is used to sort the strings. The `key=lambda x: x.strip()` ensures that the sorting is case-insensitive and ignores leading/trailing whitespace. 3. Return Statement: The function returns a new list where each sublist is sorted. 4. Test Cases: The provided test cases validate that the function works as expected. This approach ensures that each sublist is sorted correctly, and the lambda function handles any potential issues with whitespace or case sensitivity.	wrong_answer 测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']] assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']] assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]

模型

模型答案

测试结果

金声玉亮2.0

```python
def sort_sublists(list_of_lists):
return [sorted(sublist, key=lambda x: x.strip().lower()) for sublist in list_of_lists]
```
[DONE]

wrong_answer
测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']]
assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']]
assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]

deepseekr1

To solve this problem, we need to write a function that sorts each sublist of strings in a given list of lists using a lambda function. The goal is to return a new list of lists where each sublist is sorted in lexicographical order.

### Approach
The approach involves using Python's built-in `sorted()` function to sort each sublist. To adhere to the problem's requirement of using a lambda function, we utilize the `map()` function along with a lambda expression. The `map()` function applies the lambda to each sublist in the input, which in turn sorts the sublist. The result is then converted to a list to meet the expected output format.

### Solution Code
```python
def sort_sublists(input_list):
return list(map(lambda sub: sorted(sub), input_list))
```

### Explanation
1. **Input Handling**: The function takes an `input_list`, which can be a list or a tuple of lists. Each element in `input_list` is a sublist of strings.
2. **Sorting with Lambda**: The `map()` function iterates over each sublist in `input_list`. For each sublist, the lambda function `lambda sub: sorted(sub)` is applied, which sorts the sublist using the default lexicographical order.
3. **Conversion to List**: The result of `map()` is a map object, which is converted to a list using `list()` to produce the final list of sorted sublists.

This approach efficiently sorts each sublist using a combination of `map()` and `sorted()`, ensuring clarity and adherence to the problem constraints.

pass
测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']]
assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']]
assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]

gpto1

```python
def sort_sublists(list_of_lists):
sorted_sublists = [sorted(sublist, key=lambda s: s) for sublist in list_of_lists]
return sorted_sublists
```

GPT-4o

Here's the implementation of the function to sort each sublist of strings in a given list of lists using a lambda function:

```python
def sort_sublists(list_of_lists):
return [sorted(sublist, key=lambda x: x.strip()) for sublist in list_of_lists]

# Test cases
assert sort_sublists([["green", "orange"], ["black", "white"], ["white", "black", "orange"]]) == [['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']]
assert sort_sublists([[" red ", "green"], ["blue ", " black"], [" orange", "brown"]]) == [[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']]
assert sort_sublists([["zilver", "gold"], ["magnesium", "aluminium"], ["steel", "bronze"]]) == [['gold', 'zilver'], ['aluminium', 'magnesium'], ['bronze', 'steel']]
```

Explanation:
- The `sort_sublists` function takes a list of lists (`list_of_lists`) as input.
- It returns a new list where each sublist is sorted.
- The sorting is done using the `sorted` function with a `lambda` function as the key.
- The `lambda` function uses `strip()` to remove any leading or trailing whitespace from the strings during comparison.

This implementation ensures that the sublists are sorted correctly and will pass the provided test cases.

llama3.1-70B-Instruct

def sort_sublists(lists):
return sorted(lists, key=lambda x: x[0].lower())

llama3.1-405B-Instruct

def sort_sublists(lst):
return [sorted(sublist) for sublist in lst]

DeepSeek-Coder-V2

```python
def sort_sublists(list_of_lists):
return [sorted(sublist, key=lambda x: x.strip().lower()) for sublist in list_of_lists]
```
[DONE]

Qwen2-72B-Instruct

'def sort_sublists(test_list):\n res = list(map(lambda sub: sorted(sub), test_list))\n return res'
[DONE]

failed
测试用例：assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"]))==[['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']]
assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"]))==[[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']]
assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"]))==[['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]

baichuan4

Here's the function to sort each sublist of strings in a given list of lists using a lambda function:

```python
def sort_sublists(list_of_lists):
return [sorted(sublist, key=lambda x: x.strip()) for sublist in list_of_lists]
```

This function iterates through each sublist in the input `list_of_lists`, sorting each one using Python's built-in `sorted` function. The `key` parameter is set to a lambda function that strips any leading or trailing whitespace from each string before comparing them. This ensures that strings with different amounts of whitespace are correctly sorted based on their actual content.

Let's run the tests you provided:

```python
assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"])) == [['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']]
assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"])) == [[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']]
assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"])) == [['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
```

All tests should pass without any assertion errors.

doubao

'def sort_sublists(lst):
return [sorted(sublist, key=lambda x: x) for sublist in lst]'
[DONE]

minimax

```python
def sort_sublists(list_of_lists):
return [sorted(sublist, key=lambda x: x.strip().lower()) for sublist in list_of_lists]

# Test cases
assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"])) == [['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']]
assert sort_sublists(([" red ", "green"], ["blue ", " black"], [" orange", "brown"])) == [[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']]
assert sort_sublists((["zilver", "gold"], ["magnesium", "aluminium"], ["steel", "bronze"])) == [['gold', 'zilver'], ['aluminium', 'magnesium'], ['bronze', 'steel']]
```

This function `sort_sublists` takes a list of lists as input and returns a new list of lists with each sublist sorted. The sorting is case-insensitive and ignores leading and trailing whitespace, as it uses a lambda function to strip and convert strings to lowercase for comparison purposes. The test cases check that the function correctly sorts the sublists as specified.

kimi

Here's the Python code for each of the tasks you've provided:

1. Function to find similar elements from two tuple lists:

```python
def similar_elements(test_tup1, test_tup2):
res = tuple(sorted(set(test_tup1) & set(test_tup2)))
return res
```

2. Function to identify non-prime numbers:

```python
import math

def is_not_prime(n):
if n <= 1:
return True
for i in range(2, int(math.sqrt(n)) + 1):
if n % i == 0:
return True
return False
```

3. Function to find the largest integers from a given list of numbers using heap queue algorithm:

```python
import heapq

def heap_queue_largest(nums, n):
largest_nums = heapq.nlargest(n, nums)
return largest_nums
```

4. Function to sort each sublist of strings in a given list of lists using lambda function:

```python
def sort_sublists(list_of_lists):
return [sorted(sublist, key=lambda s: s.strip().lower()) for sublist in list_of_lists]
```

Each function is designed to pass the tests you've provided. Here's how you can use them:

```python
# Test similar_elements function
assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5)
assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4)
assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14)

# Test is_not_prime function
assert is_not_prime(2) == False
assert is_not_prime(10) == True
assert is_not_prime(35) == True

# Test heap_queue_largest function
assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 3) == [85, 75, 65]
assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 2) == [85, 75]
assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 5) == [85, 75, 65, 58, 35]

# Test sort_sublists function
assert sort_sublists(["green", "orange"]) == ['green', 'orange']
assert sort_sublists([" red ","green" ]) == [' green', 'green']
assert sort_sublists(["zilver","gold"]) == ['gold', 'zilver']
```

Note that the `similar_elements` function now returns the result as a sorted tuple to ensure the order is consistent. The `is_not_prime` function has been updated to handle the case when `n` is less than or equal to 1, which are not prime numbers.

wenxinyiyan

'def sort_sublists(lst):
return [sorted(sublst) for sublst in lst]'
[DONE]

Explanation for the last task:
The given task is to sort each sublist of strings in a list of lists. The `sort_sublists` function takes a list of lists (`lst`) as input. It uses a list comprehension to iterate over each sublist (`sublst`) in the input list. For each sublist, it applies the `sorted` function, which returns a new sorted list. The sorted sublists are then collected into a new list, which is returned as the output of the function.

Note: The original code snippet provided in the question uses a lambda function, but it's not necessary for this task. The `sorted` function can be used directly without a lambda function since we are sorting strings, and the default sorting order for strings is lexicographical, which is what we need in this case.

However, if you want to use a lambda function explicitly to define the sorting key, you can modify the code as follows:

```python
def sort_sublists(lst):
return [sorted(sublst, key=lambda x: x) for sublst in lst]
```
In this modified version, the `key` parameter of the `sorted` function is set to a lambda function that takes an element `x` from the sublist and returns it as the sorting key. Since the lambda function simply returns the element itself, the sorting order will be the same as the default lexicographical order for strings. But again, this is not necessary for the given task, and the simpler version without the lambda function is preferred.

zhipu

To achieve the task of sorting each sublist of strings in a given list of lists using a lambda function, we can use the `sorted` function along with a lambda function to define the sorting criteria. Here is the implementation of the `sort_sublists` function:

```python
def sort_sublists(list_of_lists):
return [sorted(sublist, key=lambda x: x) for sublist in list_of_lists]

# Test cases
assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"])) == [['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']]
assert sort_sublists(([" red ", "green"], ["blue ", " black"], [" orange", "brown"])) == [[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']]
assert sort_sublists((["zilver", "gold"], ["magnesium", "aluminium"], ["steel", "bronze"])) == [['gold', 'zilver'], ['aluminium', 'magnesium'], ['bronze', 'steel']]

print("All tests passed!")
```

### Explanation:
1. **Function Definition**: The function `sort_sublists` takes a list of lists (`list_of_lists`) as input.
2. **List Comprehension**: We use a list comprehension to iterate over each sublist in the input list.
3. **Sorting**: For each sublist, we apply the `sorted` function. The `key` parameter of the `sorted` function is set to a lambda function `lambda x: x`, which means the sorting is based on the natural order of the strings.
4. **Return**: The function returns a new list of lists where each sublist is sorted.

### Test Cases:
- The provided test cases are used to ensure that the function behaves as expected. Each test case asserts that the output of the function matches the expected sorted list of lists.

This implementation should pass all the given tests.

gpto1

```python
def sort_sublists(list_of_lists):
sorted_sublists = [sorted(sublist, key=lambda s: s) for sublist in list_of_lists]
return sorted_sublists
```

deepseekv3

```python
def sort_sublists(lst):
return [sorted(sublist, key=lambda x: x.strip()) for sublist in lst]

# Test cases
assert sort_sublists((["green", "orange"], ["black", "white"], ["white", "black", "orange"])) == [['green', 'orange'], ['black', 'white'], ['black', 'orange', 'white']]
assert sort_sublists(([" red ","green" ],["blue "," black"],[" orange","brown"])) == [[' red ', 'green'], [' black', 'blue '], [' orange', 'brown']]
assert sort_sublists((["zilver","gold"], ["magnesium","aluminium"], ["steel", "bronze"])) == [['gold', 'zilver'],['aluminium', 'magnesium'], ['bronze', 'steel']]
```

### Explanation:
1. **Function Definition**: The function `sort_sublists` takes a list of lists (where each sublist contains strings) as input.
2. **Sorting Sublists**: For each sublist in the input list, the `sorted` function is used to sort the strings. The `key=lambda x: x.strip()` ensures that the sorting is case-insensitive and ignores leading/trailing whitespace.
3. **Return Statement**: The function returns a new list where each sublist is sorted.
4. **Test Cases**: The provided test cases validate that the function works as expected.

This approach ensures that each sublist is sorted correctly, and the lambda function handles any potential issues with whitespace or case sensitivity.