金声玉亮2.0模型评测报告

问题

You are an expert Python programmer, and here is your task: Write a function to find the similar elements from the given two tuple lists. Your code should pass these tests:

assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5)
assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4)
assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14)

[BEGIN]
'def similar_elements(test_tup1, test_tup2):
res = tuple(set(test_tup1) & set(test_tup2))
return (res)'
[DONE]

You are an expert Python programmer, and here is your task: Write a python function to identify non-prime numbers. Your code should pass these tests:

assert is_not_prime(2) == False
assert is_not_prime(10) == True
assert is_not_prime(35) == True

[BEGIN]
'import math
def is_not_prime(n):
result = False
for i in range(2,int(math.sqrt(n)) + 1):
if n % i == 0:
result = True
return result'
[DONE]

You are an expert Python programmer, and here is your task: Write a function to find the largest integers from a given list of numbers using heap queue algorithm. Your code should pass these tests:

assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],3)==[85, 75, 65]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],2)==[85, 75]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],5)==[85, 75, 65, 58, 35]

[BEGIN]
'import heapq as hq
def heap_queue_largest(nums,n):
largest_nums = hq.nlargest(n, nums)
return largest_nums'
[DONE]

You are an expert Python programmer, and here is your task: Write a function to shortlist words that are longer than n from a given list of words. Your code should pass these tests:

assert long_words(3,"python is a programming language")==['python','programming','language']
assert long_words(2,"writing a program")==['writing','program']
assert long_words(5,"sorting list")==['sorting']

[BEGIN]

答案

模型	模型答案	测试结果
金声玉亮2.0	```python def long_words(n, sentence): words = sentence.split() return [word for word in words if len(word) > n] ``` [DONE]	pass 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
deepseekr1	To solve this problem, we need to write a function that takes an integer `n` and a string of words, and returns a list of words from the string that are longer than `n` characters. The solution must maintain the order of the words as they appear in the input string. ### Approach 1. Split the Input String: The input string is split into individual words using the `split()` method, which divides the string at whitespace characters. 2. Filter Words by Length: Iterate through each word in the split list and check if its length is greater than `n`. 3. Collect Results: Collect all words that meet the length criteria into a result list while preserving their original order. ### Solution Code ```python def long_words(n, s): words = s.split() return [word for word in words if len(word) > n] ``` ### Explanation - Splitting the String: The `split()` method is used to break the input string into a list of words based on spaces. This handles multiple spaces and ensures each word is processed individually. - Filtering Words: A list comprehension is used to iterate over each word in the split list. For each word, we check if its length is greater than `n`. If it is, the word is included in the result list. - Maintaining Order: The list comprehension processes the words in the order they appear in the original string, thus preserving the order in the result list. This approach efficiently processes the input string in linear time, ensuring both correctness and optimal performance.	pass 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
gpto1	'def long_words(n, s): words = s.split() result = [word for word in words if len(word) > n] return result'	failed 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
GPT-4o	```python def long_words(n, sentence): words = sentence.split() result = [word for word in words if len(word) > n] return result ``` Let's ensure the function passes the given tests: ```python assert long_words(3, "python is a programming language") == ['python', 'programming', 'language'] assert long_words(2, "writing a program") == ['writing', 'program'] assert long_words(5, "sorting list") == ['sorting'] ```	pass 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
llama3.1-70B-Instruct	def long_words(n, sentence): words = sentence.split() long_words = [word for word in words if len(word) > n] return long_words	pass 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
llama3.1-405B-Instruct	def long_words(n, str): word_len = [word for word in str.split() if len(word) > n] return word_len	pass 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
DeepSeek-Coder-V2	```python def long_words(n, sentence): words = sentence.split() return [word for word in words if len(word) > n] ``` [DONE]	pass 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
Qwen2-72B-Instruct	'def long_words(n, sentence): words = sentence.split() long_words_list = [word for word in words if len(word) > n] return long_words_list' [DONE]	pass 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
baichuan4	Here's the function to shortlist words longer than `n` from a given list of words: ```python def long_words(n, sentence): words = sentence.split() # Split the sentence into words long_words = [word for word in words if len(word) > n] # Filter words longer than n return long_words ``` Let's run the tests you provided: ```python assert long_words(3, "python is a programming language") == ['python', 'programming', 'language'] assert long_words(2, "writing a program") == ['writing', 'program'] assert long_words(5, "sorting list") == ['sorting'] ``` All tests should pass successfully with this function.	pass 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
doubao	'def long_words(n, text): words = text.split() return [word for word in words if len(word) > n]' [DONE]	pass 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
minimax	'def long_words(n, sentence): words = sentence.split() long_words = [word for word in words if len(word) > n] return long_words'	failed 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
kimi	```python def long_words(n, text): words = text.split() return [word for word in words if len(word) > n] # Test cases assert long_words(3, "python is a programming language") == ['python', 'programming', 'language'] assert long_words(2, "writing a program") == ['writing', 'program'] assert long_words(5, "sorting list") == ['sorting'] ``` This function `long_words` takes two arguments: `n`, which is the minimum length for words to be considered long, and `text`, which is a string containing words separated by spaces. It splits the text into a list of words, then uses a list comprehension to filter out words that are longer than `n` characters. The resulting list is returned. The test cases check that the function returns the correct list of words for different inputs.	pass 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
wenxinyiyan	'def long_words(n, sentence): words = sentence.split() long_words_list = [word for word in words if len(word) > n] return long_words_list' [DONE] Explanation: The `long_words` function takes two arguments: `n` (an integer) and `sentence` (a string). The function splits the sentence into a list of words using the `split()` method. Then, it uses a list comprehension to iterate over each word in the `words` list and check if the length of the word is greater than `n`. If it is, the word is added to the `long_words_list`. Finally, the function returns the `long_words_list` containing all the words that are longer than `n`. Note: The code assumes that the input sentence does not contain any punctuation marks other than spaces separating the words. If the sentence contains punctuation marks, you may need to modify the code to remove or handle them appropriately before splitting the sentence into words.	pass 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
zhipu	Here's a Python function that fulfills the requirements: ```python def long_words(n, sentence): words = sentence.split() return [word for word in words if len(word) > n] # Test cases assert long_words(3, "python is a programming language") == ['python', 'programming', 'language'] assert long_words(2, "writing a program") == ['writing', 'program'] assert long_words(5, "sorting list") == ['sorting'] ``` ### Explanation: 1. Function Definition: The function `long_words` takes two parameters: `n` (the minimum length of words to be included) and `sentence` (the string containing the words). 2. Splitting the Sentence: The sentence is split into individual words using `sentence.split()`. 3. List Comprehension: A list comprehension is used to filter out words that are longer than `n`. 4. Return: The function returns a list of words that meet the length criterion. ### Test Cases: - The first test case checks if words longer than 3 characters in the sentence "python is a programming language" are correctly identified. - The second test case checks for words longer than 2 characters in "writing a program". - The third test case checks for words longer than 5 characters in "sorting list". This function should pass all the provided test cases.	pass 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
gpto1	'def long_words(n, s): words = s.split() result = [word for word in words if len(word) > n] return result'	failed 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']
deepseekv3	```python def long_words(n, sentence): # Split the sentence into individual words words = sentence.split() # Filter words longer than n long_words_list = [word for word in words if len(word) > n] return long_words_list ``` ### Explanation: 1. Splitting the Sentence: The `split()` method is used to divide the sentence into a list of words based on spaces. 2. Filtering Words: A list comprehension is used to iterate over each word in the list and include it in the result if its length is greater than `n`. 3. Returning the Result: The function returns the list of words that are longer than `n`. ### Tests: - `long_words(3, "python is a programming language")` returns `['python', 'programming', 'language']` because these words have more than 3 characters. - `long_words(2, "writing a program")` returns `['writing', 'program']` because these words have more than 2 characters. - `long_words(5, "sorting list")` returns `['sorting']` because only 'sorting' has more than 5 characters.	pass 测试用例：assert long_words(3,"python is a programming language")==['python','programming','language'] assert long_words(2,"writing a program")==['writing','program'] assert long_words(5,"sorting list")==['sorting']

模型

模型答案

测试结果

金声玉亮2.0

```python
def long_words(n, sentence):
words = sentence.split()
return [word for word in words if len(word) > n]
```
[DONE]

pass
测试用例：assert long_words(3,"python is a programming language")==['python','programming','language']
assert long_words(2,"writing a program")==['writing','program']
assert long_words(5,"sorting list")==['sorting']

deepseekr1

To solve this problem, we need to write a function that takes an integer `n` and a string of words, and returns a list of words from the string that are longer than `n` characters. The solution must maintain the order of the words as they appear in the input string.

### Approach
1. **Split the Input String**: The input string is split into individual words using the `split()` method, which divides the string at whitespace characters.
2. **Filter Words by Length**: Iterate through each word in the split list and check if its length is greater than `n`.
3. **Collect Results**: Collect all words that meet the length criteria into a result list while preserving their original order.

### Solution Code

```python
def long_words(n, s):
words = s.split()
return [word for word in words if len(word) > n]
```

### Explanation
- **Splitting the String**: The `split()` method is used to break the input string into a list of words based on spaces. This handles multiple spaces and ensures each word is processed individually.
- **Filtering Words**: A list comprehension is used to iterate over each word in the split list. For each word, we check if its length is greater than `n`. If it is, the word is included in the result list.
- **Maintaining Order**: The list comprehension processes the words in the order they appear in the original string, thus preserving the order in the result list.

This approach efficiently processes the input string in linear time, ensuring both correctness and optimal performance.

gpto1

'def long_words(n, s):
words = s.split()
result = [word for word in words if len(word) > n]
return result'

failed
测试用例：assert long_words(3,"python is a programming language")==['python','programming','language']
assert long_words(2,"writing a program")==['writing','program']
assert long_words(5,"sorting list")==['sorting']

GPT-4o

```python
def long_words(n, sentence):
words = sentence.split()
result = [word for word in words if len(word) > n]
return result
```

Let's ensure the function passes the given tests:

```python
assert long_words(3, "python is a programming language") == ['python', 'programming', 'language']
assert long_words(2, "writing a program") == ['writing', 'program']
assert long_words(5, "sorting list") == ['sorting']
```

llama3.1-70B-Instruct

def long_words(n, sentence):
words = sentence.split()
long_words = [word for word in words if len(word) > n]
return long_words

llama3.1-405B-Instruct

def long_words(n, str):
word_len = [word for word in str.split() if len(word) > n]
return word_len

DeepSeek-Coder-V2

```python
def long_words(n, sentence):
words = sentence.split()
return [word for word in words if len(word) > n]
```
[DONE]

Qwen2-72B-Instruct

'def long_words(n, sentence):
words = sentence.split()
long_words_list = [word for word in words if len(word) > n]
return long_words_list'
[DONE]

baichuan4

Here's the function to shortlist words longer than `n` from a given list of words:

```python
def long_words(n, sentence):
words = sentence.split() # Split the sentence into words
long_words = [word for word in words if len(word) > n] # Filter words longer than n
return long_words
```

Let's run the tests you provided:

```python
assert long_words(3, "python is a programming language") == ['python', 'programming', 'language']
assert long_words(2, "writing a program") == ['writing', 'program']
assert long_words(5, "sorting list") == ['sorting']
```

All tests should pass successfully with this function.

doubao

'def long_words(n, text):
words = text.split()
return [word for word in words if len(word) > n]'
[DONE]

minimax

'def long_words(n, sentence):
words = sentence.split()
long_words = [word for word in words if len(word) > n]
return long_words'

kimi

```python
def long_words(n, text):
words = text.split()
return [word for word in words if len(word) > n]

# Test cases
assert long_words(3, "python is a programming language") == ['python', 'programming', 'language']
assert long_words(2, "writing a program") == ['writing', 'program']
assert long_words(5, "sorting list") == ['sorting']
```

This function `long_words` takes two arguments: `n`, which is the minimum length for words to be considered long, and `text`, which is a string containing words separated by spaces. It splits the text into a list of words, then uses a list comprehension to filter out words that are longer than `n` characters. The resulting list is returned. The test cases check that the function returns the correct list of words for different inputs.

wenxinyiyan

'def long_words(n, sentence):
words = sentence.split()
long_words_list = [word for word in words if len(word) > n]
return long_words_list'
[DONE]

Explanation:
The `long_words` function takes two arguments: `n` (an integer) and `sentence` (a string). The function splits the sentence into a list of words using the `split()` method. Then, it uses a list comprehension to iterate over each word in the `words` list and check if the length of the word is greater than `n`. If it is, the word is added to the `long_words_list`. Finally, the function returns the `long_words_list` containing all the words that are longer than `n`.

Note: The code assumes that the input sentence does not contain any punctuation marks other than spaces separating the words. If the sentence contains punctuation marks, you may need to modify the code to remove or handle them appropriately before splitting the sentence into words.

zhipu

Here's a Python function that fulfills the requirements:

```python
def long_words(n, sentence):
words = sentence.split()
return [word for word in words if len(word) > n]

# Test cases
assert long_words(3, "python is a programming language") == ['python', 'programming', 'language']
assert long_words(2, "writing a program") == ['writing', 'program']
assert long_words(5, "sorting list") == ['sorting']
```

### Explanation:
1. **Function Definition**: The function `long_words` takes two parameters: `n` (the minimum length of words to be included) and `sentence` (the string containing the words).
2. **Splitting the Sentence**: The sentence is split into individual words using `sentence.split()`.
3. **List Comprehension**: A list comprehension is used to filter out words that are longer than `n`.
4. **Return**: The function returns a list of words that meet the length criterion.

### Test Cases:
- The first test case checks if words longer than 3 characters in the sentence "python is a programming language" are correctly identified.
- The second test case checks for words longer than 2 characters in "writing a program".
- The third test case checks for words longer than 5 characters in "sorting list".

This function should pass all the provided test cases.

gpto1

'def long_words(n, s):
words = s.split()
result = [word for word in words if len(word) > n]
return result'

deepseekv3

```python
def long_words(n, sentence):
# Split the sentence into individual words
words = sentence.split()
# Filter words longer than n
long_words_list = [word for word in words if len(word) > n]
return long_words_list
```

### Explanation:
1. **Splitting the Sentence**: The `split()` method is used to divide the sentence into a list of words based on spaces.
2. **Filtering Words**: A list comprehension is used to iterate over each word in the list and include it in the result if its length is greater than `n`.
3. **Returning the Result**: The function returns the list of words that are longer than `n`.

### Tests:
- `long_words(3, "python is a programming language")` returns `['python', 'programming', 'language']` because these words have more than 3 characters.
- `long_words(2, "writing a program")` returns `['writing', 'program']` because these words have more than 2 characters.
- `long_words(5, "sorting list")` returns `['sorting']` because only 'sorting' has more than 5 characters.