金声玉亮2.0模型评测报告

问题

You are an expert Python programmer, and here is your task: Write a function to find the similar elements from the given two tuple lists. Your code should pass these tests:

assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5)
assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4)
assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14)

[BEGIN]
'def similar_elements(test_tup1, test_tup2):
res = tuple(set(test_tup1) & set(test_tup2))
return (res)'
[DONE]

You are an expert Python programmer, and here is your task: Write a python function to identify non-prime numbers. Your code should pass these tests:

assert is_not_prime(2) == False
assert is_not_prime(10) == True
assert is_not_prime(35) == True

[BEGIN]
'import math
def is_not_prime(n):
result = False
for i in range(2,int(math.sqrt(n)) + 1):
if n % i == 0:
result = True
return result'
[DONE]

You are an expert Python programmer, and here is your task: Write a function to find the largest integers from a given list of numbers using heap queue algorithm. Your code should pass these tests:

assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],3)==[85, 75, 65]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],2)==[85, 75]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],5)==[85, 75, 65, 58, 35]

[BEGIN]
'import heapq as hq
def heap_queue_largest(nums,n):
largest_nums = hq.nlargest(n, nums)
return largest_nums'
[DONE]

You are an expert Python programmer, and here is your task: Write a function to calculate magic square. Your code should pass these tests:

assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False

[BEGIN]

答案

模型	模型答案	测试结果
金声玉亮2.0	```python def magic_square_test(matrix): n = len(matrix) # Calculate the sum of the first row to use as a reference magic_sum = sum(matrix[0]) # Check rows for row in matrix: if sum(row) != magic_sum: return False # Check columns for col in range(n): if sum(matrix[row][col] for row in range(n)) != magic_sum: return False # Check diagonals if sum(matrix[i][i] for i in range(n)) != magic_sum: return False if sum(matrix[i][n-i-1] for i in range(n)) != magic_sum: return False return True ``` [DONE]	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
deepseekr1	[BEGIN] import math def magic_square_test(matrix): n = len(matrix) if n == 0: return False for row in matrix: if len(row) != n: return False target = sum(matrix[0]) # Check rows for row in matrix: if sum(row) != target: return False # Check columns for j in range(n): if sum(row[j] for row in matrix) != target: return False # Check diagonals diag1 = sum(matrix[i][i] for i in range(n)) diag2 = sum(matrix[i][n-1-i] for i in range(n)) if diag1 != target or diag2 != target: return False return True [DONE]	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
gpto1	Here's a function that tests whether a given square is a magic square: ```python def magic_square_test(square): n = len(square) # Check if the square is not empty and is n x n if n == 0 or any(len(row) != n for row in square): return False # Calculate the magic constant (sum of the first row) magic_constant = sum(square[0]) # Check sums of all rows for row in square: if sum(row) != magic_constant: return False # Check sums of all columns for col in range(n): if sum(square[row][col] for row in range(n)) != magic_constant: return False # Check sum of main diagonal if sum(square[i][i] for i in range(n)) != magic_constant: return False # Check sum of the other diagonal if sum(square[i][n - 1 - i] for i in range(n)) != magic_constant: return False return True ``` Explanation: - Square Dimension Check: - Ensure the provided `square` is not empty and is indeed an `n x n` matrix. - Magic Constant Calculation: - The magic constant is the sum that each row, column, and diagonal should equal. It's calculated using the sum of the first row. - Row Sum Check: - Iterate over each row to verify that its sum equals the magic constant. - Column Sum Check: - For each column index, calculate the sum of that column and compare it to the magic constant. - Diagonal Sum Check: - Calculate the sums of both the main diagonal and the opposite diagonal, ensuring they both equal the magic constant. - Return Value: - If all checks pass, the function returns `True`, indicating the matrix is a magic square. Otherwise, it returns `False`. Usage Example: ```python assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False ``` This function will pass all the provided test cases.	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
GPT-4o	To solve this problem, we need to write a function that checks if a given 2D list (matrix) is a magic square. A magic square is a grid of numbers where the sum of the numbers in each row, each column, and both main diagonals are the same. Let's implement the `magic_square_test` function: ```python def magic_square_test(square): n = len(square) # Check if the square is actually n x n for row in square: if len(row) != n: return False # Calculate the sum of the first row to use as reference magic_sum = sum(square[0]) # Check the sum of each row for row in square: if sum(row) != magic_sum: return False # Check the sum of each column for col in range(n): if sum(square[row][col] for row in range(n)) != magic_sum: return False # Check the sum of the main diagonal if sum(square[i][i] for i in range(n)) != magic_sum: return False # Check the sum of the secondary diagonal if sum(square[i][n-1-i] for i in range(n)) != magic_sum: return False return True # Test cases assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False ``` This function checks: 1. If the matrix is square. 2. If the sum of numbers in each row matches the magic sum. 3. If the sum of numbers in each column matches the magic sum. 4. If the sum of numbers in the main diagonal matches the magic sum. 5. If the sum of numbers in the secondary diagonal matches the magic sum. If all these conditions are satisfied, the function returns `True`, indicating that the given matrix is a magic square. Otherwise, it returns `False`.	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
llama3.1-70B-Instruct	def magic_square_test(square): expected_sum = sum(square[0]) for row in square: if sum(row) != expected_sum: return False for col in range(len(square[0])): if sum(row[col] for row in square) != expected_sum: return False if sum(square[i][i] for i in range(len(square))) != expected_sum: return False if sum(square[i][len(square) - i - 1] for i in range(len(square))) != expected_sum: return False return True	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
llama3.1-405B-Instruct	def magic_square_test(square): # Check if the input is a square matrix if len(square) != len(square[0]): return False # Calculate the expected sum expected_sum = sum(square[0]) # Check rows for row in square: if sum(row) != expected_sum: return False # Check columns for col in range(len(square)): if sum(square[row][col] for row in range(len(square))) != expected_sum: return False # Check diagonals if sum(square[i][i] for i in range(len(square))) != expected_sum: return False if sum(square[i][len(square) - i - 1] for i in range(len(square))) != expected_sum: return False return True	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
DeepSeek-Coder-V2	```python def magic_square_test(matrix): n = len(matrix) # Calculate the sum of the first row to use as a reference magic_sum = sum(matrix[0]) # Check rows for row in matrix: if sum(row) != magic_sum: return False # Check columns for col in range(n): if sum(matrix[row][col] for row in range(n)) != magic_sum: return False # Check diagonals if sum(matrix[i][i] for i in range(n)) != magic_sum: return False if sum(matrix[i][n-i-1] for i in range(n)) != magic_sum: return False return True ``` [DONE]	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
Qwen2-72B-Instruct	'def magic_square_test(matrix): # Get the size of the matrix size = len(matrix) # Calculate the magic constant magic_constant = sum(matrix[0]) # Check the row sums for row in matrix: if sum(row) != magic_constant: return False # Check the column sums for col in range(size): if sum(matrix[row][col] for row in range(size)) != magic_constant: return False # Check the diagonal sums if sum(matrix[i][i] for i in range(size)) != magic_constant: return False if sum(matrix[i][size-i-1] for i in range(size)) != magic_constant: return False return True' [DONE]	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
baichuan4	To calculate if a matrix is a magic square, we need to check two conditions: 1. Each row, column, and the two main diagonals must sum to the same number. 2. The numbers from 1 to N^2 must all appear exactly once, where N is the size of the square matrix. Here's a Python function that performs these checks: ```python def magic_square_test(matrix): N = len(matrix) expected_sum = N * (N*2 + 1) // 2 # Sum of first N^2 natural numbers # Check row and column sums for i in range(N): if sum(matrix[i]) != expected_sum or sum(row[i] for row in matrix) != expected_sum: return False # Check diagonal sums if sum(matrix[i][i] for i in range(N)) != expected_sum or \ sum(matrix[i][N-1-i] for i in range(N)) != expected_sum: return False # Check if numbers from 1 to N^2 appear exactly once numbers_set = set(range(1, NN + 1)) if set(sum(matrix, [])) != numbers_set: return False return True ``` Let's test the function with the provided test cases: ```python assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False ``` This function first calculates the expected sum of each row, column, and diagonal by using the formula for the sum of the first N^2 natural numbers. Then it checks if each row and column sum to this expected value. Next, it checks the two main diagonals. Finally, it verifies that all numbers from 1 to N^2 are present exactly once in the matrix. If all these conditions are satisfied, the function returns True, indicating that the matrix is a magic square. Otherwise, it returns False.	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
doubao	def magic_square_test(square): n = len(square) target_sum = n * (n**2 + 1) // 2 # Check rows for row in square: if sum(row)!= target_sum: return False # Check columns for j in range(n): col_sum = 0 for i in range(n): col_sum += square[i][j] if col_sum!= target_sum: return False # Check diagonals diag1_sum = 0 diag2_sum = 0 for i in range(n): diag1_sum += square[i][i] diag2_sum += square[i][n - i - 1] if diag1_sum!= target_sum or diag2_sum!= target_sum: return False return True [DONE]	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
minimax	```python def magic_square_test(square): n = len(square) magic_constant = n * (n**2 + 1) // 2 # Check rows and columns for i in range(n): if sum(square[i]) != magic_constant or sum(square[j][i] for j in range(n)) != magic_constant: return False # Check diagonals if sum(square[i][i] for i in range(n)) != magic_constant or sum(square[i][n-i-1] for i in range(n)) != magic_constant: return False return True # Test cases assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False ``` This function `magic_square_test` checks if a given square is a magic square. A magic square is a square grid filled with distinct positive integers such that the sum of the numbers in each row, each column, and both main diagonals are the same. The function calculates the magic constant for the given size of the square and then checks if the sum of the numbers in each row, column, and diagonal equals this magic constant. If all checks pass, the function returns `True`, indicating that the square is a magic square; otherwise, it returns `False`.	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
kimi	Sure, let's tackle these tasks one by one. Task 1: Find similar elements from two tuple lists ```python def similar_elements(test_tup1, test_tup2): res = tuple(sorted(set(test_tup1) & set(test_tup2))) return res ``` Task 2: Identify non-prime numbers ```python import math def is_not_prime(n): if n <= 1: return True for i in range(2, int(math.sqrt(n)) + 1): if n % i == 0: return True return False ``` Task 3: Find the largest integers from a list using heap queue algorithm ```python import heapq def heap_queue_largest(nums, n): largest_nums = heapq.nlargest(n, nums) return largest_nums ``` Task 4: Calculate magic square A magic square is a square grid filled with distinct positive integers in the range of 1 to n^2 such that the sum of the numbers in each row, each column, and both main diagonals of the square is the same. ```python def magic_square_test(square): n = len(square) if not all(len(row) == n for row in square): return False if not all(len(set(row)) == n for row in square): return False target_sum = sum(square[0]) for i in range(n): if sum(square[i]) != target_sum: return False column_sum = sum(square[j][i] for j in range(n)) if column_sum != target_sum: return False diagonal_sum1 = sum(square[i][i] for i in range(n)) if diagonal_sum1 != target_sum: return False diagonal_sum2 = sum(square[i][n - 1 - i] for i in range(n)) if diagonal_sum2 != target_sum: return False return True ``` These functions should pass the tests provided in your tasks.	failed 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
wenxinyiyan	Here's the solution for the magic square task: ```python def magic_square_test(matrix): size = len(matrix) target_sum = sum(matrix[0]) # Assuming the first row sum is the target sum for the magic square # Check rows for row in matrix[1:]: if sum(row) != target_sum: return False # Check columns for col in range(size): column_sum = 0 for row in matrix: column_sum += row[col] if column_sum != target_sum: return False # Check diagonals diagonal_sum = 0 anti_diagonal_sum = 0 for i in range(size): diagonal_sum += matrix[i][i] anti_diagonal_sum += matrix[i][size - 1 - i] if diagonal_sum != target_sum or anti_diagonal_sum != target_sum: return False return True ``` Now, let's test the function with the provided test cases: ```python assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False ``` All tests should pass successfully. The function checks the sum of each row, column, and both diagonals to determine if the given matrix is a magic square. If any of these sums do not match the target sum (calculated from the first row), the function returns `False`. Otherwise, it returns `True`.	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
zhipu	To create a function that tests whether a given square matrix is a magic square, we need to ensure that the sum of numbers in each row, each column, and both main diagonals are all the same. Here's a Python function that does this: ```python def magic_square_test(matrix): n = len(matrix) if any(len(row) != n for row in matrix): return False # Ensure the matrix is square # Calculate the sum of the first row to use as a reference magic_sum = sum(matrix[0]) # Check rows and columns for i in range(n): if sum(matrix[i]) != magic_sum or sum(matrix[j][i] for j in range(n)) != magic_sum: return False # Check diagonals if sum(matrix[i][i] for i in range(n)) != magic_sum or sum(matrix[i][n-1-i] for i in range(n)) != magic_sum: return False return True # Test cases assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False print("All tests passed!") ``` ### Explanation: 1. Check for Square Matrix: First, we ensure that the matrix is square (i.e., the number of rows and columns are the same). 2. Calculate Magic Sum: We calculate the sum of the first row to use as a reference for what the sum should be for all rows, columns, and diagonals. 3. Check Rows and Columns: We iterate through each row and column to ensure their sums match the magic sum. 4. Check Diagonals: We check the sums of both main diagonals (from top-left to bottom-right and from top-right to bottom-left). 5. Return Result: If all checks pass, the function returns `True`, indicating the matrix is a magic square. Otherwise, it returns `False`. This function should pass the provided test cases and can be used to check any square matrix for being a magic square.	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
gpto1	Here's a function that tests whether a given square is a magic square: ```python def magic_square_test(square): n = len(square) # Check if the square is not empty and is n x n if n == 0 or any(len(row) != n for row in square): return False # Calculate the magic constant (sum of the first row) magic_constant = sum(square[0]) # Check sums of all rows for row in square: if sum(row) != magic_constant: return False # Check sums of all columns for col in range(n): if sum(square[row][col] for row in range(n)) != magic_constant: return False # Check sum of main diagonal if sum(square[i][i] for i in range(n)) != magic_constant: return False # Check sum of the other diagonal if sum(square[i][n - 1 - i] for i in range(n)) != magic_constant: return False return True ``` Explanation: - Square Dimension Check: - Ensure the provided `square` is not empty and is indeed an `n x n` matrix. - Magic Constant Calculation: - The magic constant is the sum that each row, column, and diagonal should equal. It's calculated using the sum of the first row. - Row Sum Check: - Iterate over each row to verify that its sum equals the magic constant. - Column Sum Check: - For each column index, calculate the sum of that column and compare it to the magic constant. - Diagonal Sum Check: - Calculate the sums of both the main diagonal and the opposite diagonal, ensuring they both equal the magic constant. - Return Value: - If all checks pass, the function returns `True`, indicating the matrix is a magic square. Otherwise, it returns `False`. Usage Example: ```python assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False ``` This function will pass all the provided test cases.	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False
deepseekv3	To create a function that tests whether a given square matrix is a magic square, we need to ensure that the sum of the numbers in each row, each column, and both main diagonals are the same. Additionally, the matrix should contain all the numbers from 1 to \( n^2 \) exactly once, where \( n \) is the size of the matrix. Here is the Python function that accomplishes this: ```python def magic_square_test(matrix): n = len(matrix) # Calculate the magic constant magic_constant = n * (n2 + 1) // 2 # Check the sum of each row for row in matrix: if sum(row) != magic_constant: return False # Check the sum of each column for col in range(n): if sum(row[col] for row in matrix) != magic_constant: return False # Check the sum of the main diagonal if sum(matrix[i][i] for i in range(n)) != magic_constant: return False # Check the sum of the secondary diagonal if sum(matrix[i][n - i - 1] for i in range(n)) != magic_constant: return False # Check if all numbers from 1 to n^2 are present exactly once flat_matrix = [num for row in matrix for num in row] if sorted(flat_matrix) != list(range(1, n2 + 1)): return False return True # Test cases assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False ``` ### Explanation: 1. Magic Constant Calculation: The magic constant is calculated as \( n \times (n^2 + 1) / 2 \), where \( n \) is the size of the matrix. 2. Row Sum Check: We iterate through each row and check if the sum of the row equals the magic constant. 3. Column Sum Check: We iterate through each column and check if the sum of the column equals the magic constant. 4. Diagonal Sum Check: We check the sum of the main diagonal and the secondary diagonal. 5. Number Uniqueness Check: We flatten the matrix into a single list and check if it contains all numbers from 1 to \( n^2 \) exactly once. If all checks pass, the matrix is a magic square, and the function returns `True`; otherwise, it returns `False`.	pass 测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False

模型

模型答案

测试结果

金声玉亮2.0

```python
def magic_square_test(matrix):
n = len(matrix)
# Calculate the sum of the first row to use as a reference
magic_sum = sum(matrix[0])

# Check rows
for row in matrix:
if sum(row) != magic_sum:
return False

# Check columns
for col in range(n):
if sum(matrix[row][col] for row in range(n)) != magic_sum:
return False

# Check diagonals
if sum(matrix[i][i] for i in range(n)) != magic_sum:
return False
if sum(matrix[i][n-i-1] for i in range(n)) != magic_sum:
return False

return True
```
[DONE]

pass
测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False

deepseekr1

[BEGIN]
import math

def magic_square_test(matrix):
n = len(matrix)
if n == 0:
return False
for row in matrix:
if len(row) != n:
return False
target = sum(matrix[0])
# Check rows
for row in matrix:
if sum(row) != target:
return False
# Check columns
for j in range(n):
if sum(row[j] for row in matrix) != target:
return False
# Check diagonals
diag1 = sum(matrix[i][i] for i in range(n))
diag2 = sum(matrix[i][n-1-i] for i in range(n))
if diag1 != target or diag2 != target:
return False
return True
[DONE]

gpto1

Here's a function that tests whether a given square is a magic square:

```python
def magic_square_test(square):
n = len(square)
# Check if the square is not empty and is n x n
if n == 0 or any(len(row) != n for row in square):
return False

# Calculate the magic constant (sum of the first row)
magic_constant = sum(square[0])

# Check sums of all rows
for row in square:
if sum(row) != magic_constant:
return False

# Check sums of all columns
for col in range(n):
if sum(square[row][col] for row in range(n)) != magic_constant:
return False

# Check sum of main diagonal
if sum(square[i][i] for i in range(n)) != magic_constant:
return False

# Check sum of the other diagonal
if sum(square[i][n - 1 - i] for i in range(n)) != magic_constant:
return False

return True
```

**Explanation:**

- **Square Dimension Check:**
- Ensure the provided `square` is not empty and is indeed an `n x n` matrix.
- **Magic Constant Calculation:**
- The magic constant is the sum that each row, column, and diagonal should equal. It's calculated using the sum of the first row.
- **Row Sum Check:**
- Iterate over each row to verify that its sum equals the magic constant.
- **Column Sum Check:**
- For each column index, calculate the sum of that column and compare it to the magic constant.
- **Diagonal Sum Check:**
- Calculate the sums of both the main diagonal and the opposite diagonal, ensuring they both equal the magic constant.
- **Return Value:**
- If all checks pass, the function returns `True`, indicating the matrix is a magic square. Otherwise, it returns `False`.

**Usage Example:**

```python
assert magic_square_test([[7, 12, 1, 14],
[2, 13, 8, 11],
[16, 3, 10, 5],
[9, 6, 15, 4]]) == True

assert magic_square_test([[2, 7, 6],
[9, 5, 1],
[4, 3, 8]]) == True

assert magic_square_test([[2, 7, 6],
[9, 5, 1],
[4, 3, 7]]) == False
```

This function will pass all the provided test cases.

GPT-4o

To solve this problem, we need to write a function that checks if a given 2D list (matrix) is a magic square. A magic square is a grid of numbers where the sum of the numbers in each row, each column, and both main diagonals are the same.

Let's implement the `magic_square_test` function:

```python
def magic_square_test(square):
n = len(square)

# Check if the square is actually n x n
for row in square:
if len(row) != n:
return False

# Calculate the sum of the first row to use as reference
magic_sum = sum(square[0])

# Check the sum of each row
for row in square:
if sum(row) != magic_sum:
return False

# Check the sum of each column
for col in range(n):
if sum(square[row][col] for row in range(n)) != magic_sum:
return False

# Check the sum of the main diagonal
if sum(square[i][i] for i in range(n)) != magic_sum:
return False

# Check the sum of the secondary diagonal
if sum(square[i][n-1-i] for i in range(n)) != magic_sum:
return False

return True

# Test cases
assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False
```

This function checks:
1. If the matrix is square.
2. If the sum of numbers in each row matches the magic sum.
3. If the sum of numbers in each column matches the magic sum.
4. If the sum of numbers in the main diagonal matches the magic sum.
5. If the sum of numbers in the secondary diagonal matches the magic sum.

If all these conditions are satisfied, the function returns `True`, indicating that the given matrix is a magic square. Otherwise, it returns `False`.

llama3.1-70B-Instruct

def magic_square_test(square):
expected_sum = sum(square[0])
for row in square:
if sum(row) != expected_sum:
return False
for col in range(len(square[0])):
if sum(row[col] for row in square) != expected_sum:
return False
if sum(square[i][i] for i in range(len(square))) != expected_sum:
return False
if sum(square[i][len(square) - i - 1] for i in range(len(square))) != expected_sum:
return False
return True

llama3.1-405B-Instruct

def magic_square_test(square):
# Check if the input is a square matrix
if len(square) != len(square[0]):
return False

# Calculate the expected sum
expected_sum = sum(square[0])

# Check rows
for row in square:
if sum(row) != expected_sum:
return False

# Check columns
for col in range(len(square)):
if sum(square[row][col] for row in range(len(square))) != expected_sum:
return False

# Check diagonals
if sum(square[i][i] for i in range(len(square))) != expected_sum:
return False
if sum(square[i][len(square) - i - 1] for i in range(len(square))) != expected_sum:
return False

return True

DeepSeek-Coder-V2

Qwen2-72B-Instruct

'def magic_square_test(matrix):
# Get the size of the matrix
size = len(matrix)

# Calculate the magic constant
magic_constant = sum(matrix[0])

# Check the row sums
for row in matrix:
if sum(row) != magic_constant:
return False

# Check the column sums
for col in range(size):
if sum(matrix[row][col] for row in range(size)) != magic_constant:
return False

# Check the diagonal sums
if sum(matrix[i][i] for i in range(size)) != magic_constant:
return False
if sum(matrix[i][size-i-1] for i in range(size)) != magic_constant:
return False

return True'
[DONE]

baichuan4

To calculate if a matrix is a magic square, we need to check two conditions:
1. Each row, column, and the two main diagonals must sum to the same number.
2. The numbers from 1 to N^2 must all appear exactly once, where N is the size of the square matrix.

Here's a Python function that performs these checks:

```python
def magic_square_test(matrix):
N = len(matrix)
expected_sum = N * (N**2 + 1) // 2 # Sum of first N^2 natural numbers

# Check row and column sums
for i in range(N):
if sum(matrix[i]) != expected_sum or sum(row[i] for row in matrix) != expected_sum:
return False

# Check diagonal sums
if sum(matrix[i][i] for i in range(N)) != expected_sum or \
sum(matrix[i][N-1-i] for i in range(N)) != expected_sum:
return False

# Check if numbers from 1 to N^2 appear exactly once
numbers_set = set(range(1, N*N + 1))
if set(sum(matrix, [])) != numbers_set:
return False

return True
```

Let's test the function with the provided test cases:

```python
assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False
```

This function first calculates the expected sum of each row, column, and diagonal by using the formula for the sum of the first N^2 natural numbers. Then it checks if each row and column sum to this expected value. Next, it checks the two main diagonals. Finally, it verifies that all numbers from 1 to N^2 are present exactly once in the matrix. If all these conditions are satisfied, the function returns True, indicating that the matrix is a magic square. Otherwise, it returns False.

doubao

def magic_square_test(square):
n = len(square)
target_sum = n * (n**2 + 1) // 2

# Check rows
for row in square:
if sum(row)!= target_sum:
return False

# Check columns
for j in range(n):
col_sum = 0
for i in range(n):
col_sum += square[i][j]
if col_sum!= target_sum:
return False

# Check diagonals
diag1_sum = 0
diag2_sum = 0
for i in range(n):
diag1_sum += square[i][i]
diag2_sum += square[i][n - i - 1]
if diag1_sum!= target_sum or diag2_sum!= target_sum:
return False

return True
[DONE]

minimax

```python
def magic_square_test(square):
n = len(square)
magic_constant = n * (n**2 + 1) // 2

# Check rows and columns
for i in range(n):
if sum(square[i]) != magic_constant or sum(square[j][i] for j in range(n)) != magic_constant:
return False

# Check diagonals
if sum(square[i][i] for i in range(n)) != magic_constant or sum(square[i][n-i-1] for i in range(n)) != magic_constant:
return False

return True

# Test cases
assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False
```

This function `magic_square_test` checks if a given square is a magic square. A magic square is a square grid filled with distinct positive integers such that the sum of the numbers in each row, each column, and both main diagonals are the same. The function calculates the magic constant for the given size of the square and then checks if the sum of the numbers in each row, column, and diagonal equals this magic constant. If all checks pass, the function returns `True`, indicating that the square is a magic square; otherwise, it returns `False`.

kimi

Sure, let's tackle these tasks one by one.

**Task 1: Find similar elements from two tuple lists**

```python
def similar_elements(test_tup1, test_tup2):
res = tuple(sorted(set(test_tup1) & set(test_tup2)))
return res
```

**Task 2: Identify non-prime numbers**

```python
import math

def is_not_prime(n):
if n <= 1:
return True
for i in range(2, int(math.sqrt(n)) + 1):
if n % i == 0:
return True
return False
```

**Task 3: Find the largest integers from a list using heap queue algorithm**

```python
import heapq

def heap_queue_largest(nums, n):
largest_nums = heapq.nlargest(n, nums)
return largest_nums
```

**Task 4: Calculate magic square**

A magic square is a square grid filled with distinct positive integers in the range of 1 to n^2 such that the sum of the numbers in each row, each column, and both main diagonals of the square is the same.

```python
def magic_square_test(square):
n = len(square)
if not all(len(row) == n for row in square):
return False
if not all(len(set(row)) == n for row in square):
return False

target_sum = sum(square[0])

for i in range(n):
if sum(square[i]) != target_sum:
return False
column_sum = sum(square[j][i] for j in range(n))
if column_sum != target_sum:
return False

diagonal_sum1 = sum(square[i][i] for i in range(n))
if diagonal_sum1 != target_sum:
return False
diagonal_sum2 = sum(square[i][n - 1 - i] for i in range(n))
if diagonal_sum2 != target_sum:
return False

return True
```

These functions should pass the tests provided in your tasks.

failed
测试用例：assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]])==True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]])==True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]])==False

wenxinyiyan

Here's the solution for the magic square task:

```python
def magic_square_test(matrix):
size = len(matrix)
target_sum = sum(matrix[0]) # Assuming the first row sum is the target sum for the magic square

# Check rows
for row in matrix[1:]:
if sum(row) != target_sum:
return False

# Check columns
for col in range(size):
column_sum = 0
for row in matrix:
column_sum += row[col]
if column_sum != target_sum:
return False

# Check diagonals
diagonal_sum = 0
anti_diagonal_sum = 0
for i in range(size):
diagonal_sum += matrix[i][i]
anti_diagonal_sum += matrix[i][size - 1 - i]
if diagonal_sum != target_sum or anti_diagonal_sum != target_sum:
return False

return True
```
Now, let's test the function with the provided test cases:

```python
assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False
```
All tests should pass successfully. The function checks the sum of each row, column, and both diagonals to determine if the given matrix is a magic square. If any of these sums do not match the target sum (calculated from the first row), the function returns `False`. Otherwise, it returns `True`.

zhipu

To create a function that tests whether a given square matrix is a magic square, we need to ensure that the sum of numbers in each row, each column, and both main diagonals are all the same. Here's a Python function that does this:

```python
def magic_square_test(matrix):
n = len(matrix)
if any(len(row) != n for row in matrix):
return False # Ensure the matrix is square

# Calculate the sum of the first row to use as a reference
magic_sum = sum(matrix[0])

# Check rows and columns
for i in range(n):
if sum(matrix[i]) != magic_sum or sum(matrix[j][i] for j in range(n)) != magic_sum:
return False

# Check diagonals
if sum(matrix[i][i] for i in range(n)) != magic_sum or sum(matrix[i][n-1-i] for i in range(n)) != magic_sum:
return False

return True

# Test cases
assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False

print("All tests passed!")
```

### Explanation:
1. **Check for Square Matrix**: First, we ensure that the matrix is square (i.e., the number of rows and columns are the same).
2. **Calculate Magic Sum**: We calculate the sum of the first row to use as a reference for what the sum should be for all rows, columns, and diagonals.
3. **Check Rows and Columns**: We iterate through each row and column to ensure their sums match the magic sum.
4. **Check Diagonals**: We check the sums of both main diagonals (from top-left to bottom-right and from top-right to bottom-left).
5. **Return Result**: If all checks pass, the function returns `True`, indicating the matrix is a magic square. Otherwise, it returns `False`.

This function should pass the provided test cases and can be used to check any square matrix for being a magic square.

gpto1

deepseekv3

To create a function that tests whether a given square matrix is a magic square, we need to ensure that the sum of the numbers in each row, each column, and both main diagonals are the same. Additionally, the matrix should contain all the numbers from 1 to \( n^2 \) exactly once, where \( n \) is the size of the matrix.

Here is the Python function that accomplishes this:

```python
def magic_square_test(matrix):
n = len(matrix)

# Calculate the magic constant
magic_constant = n * (n**2 + 1) // 2

# Check the sum of each row
for row in matrix:
if sum(row) != magic_constant:
return False

# Check the sum of each column
for col in range(n):
if sum(row[col] for row in matrix) != magic_constant:
return False

# Check the sum of the main diagonal
if sum(matrix[i][i] for i in range(n)) != magic_constant:
return False

# Check the sum of the secondary diagonal
if sum(matrix[i][n - i - 1] for i in range(n)) != magic_constant:
return False

# Check if all numbers from 1 to n^2 are present exactly once
flat_matrix = [num for row in matrix for num in row]
if sorted(flat_matrix) != list(range(1, n**2 + 1)):
return False

return True

# Test cases
assert magic_square_test([[7, 12, 1, 14], [2, 13, 8, 11], [16, 3, 10, 5], [9, 6, 15, 4]]) == True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 8]]) == True
assert magic_square_test([[2, 7, 6], [9, 5, 1], [4, 3, 7]]) == False
```

### Explanation:
1. **Magic Constant Calculation**: The magic constant is calculated as \( n \times (n^2 + 1) / 2 \), where \( n \) is the size of the matrix.
2. **Row Sum Check**: We iterate through each row and check if the sum of the row equals the magic constant.
3. **Column Sum Check**: We iterate through each column and check if the sum of the column equals the magic constant.
4. **Diagonal Sum Check**: We check the sum of the main diagonal and the secondary diagonal.
5. **Number Uniqueness Check**: We flatten the matrix into a single list and check if it contains all numbers from 1 to \( n^2 \) exactly once.

If all checks pass, the matrix is a magic square, and the function returns `True`; otherwise, it returns `False`.