| 模型 | 模型答案 | 测试结果 |
|---|---|---|
| 金声玉亮2.0 | ```python def hexagonal_num(n): return n * (2 * n - 1) ``` [DONE] |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| deepseekr1 | [BEGIN] def hexagonal_num(n): return n * (2 * n - 1) [DONE] |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| gpto1 | [BEGIN] 'def hexagonal_num(n): return n * (2 * n - 1)' [DONE] |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| GPT-4o | ```python def hexagonal_num(n): return n * (2 * n - 1) ``` Here is the explanation of the function `hexagonal_num`: A hexagonal number for a given n can be calculated using the formula: \[ H_n = n \times (2n - 1) \] Where \( H_n \) is the nth hexagonal number. Let's verify the function with the given test cases: ```python assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 ``` The function should pass all these tests. |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| llama3.1-70B-Instruct | def hexagonal_num(n): return n * (2 * n - 1) |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| llama3.1-405B-Instruct | def hexagonal_num(n): return n * (2 * n - 1) |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| DeepSeek-Coder-V2 | ```python def hexagonal_num(n): return n * (2 * n - 1) ``` [DONE] |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| Qwen2-72B-Instruct | 'def hexagonal_num(n): return n * (2*n - 1)' [DONE] |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| baichuan4 | The nth hexagonal number can be calculated using the formula: H_n = n * (2 * n - 1). Here's the implementation of the function: ```python def hexagonal_num(n): return n * (2 * n - 1) ``` Let's test the function with the provided test cases: ```python assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 ``` All the test cases pass successfully, indicating that the function is correct. |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| doubao | 'def hexagonal_num(n): return n * (2 * n - 1)' [DONE] |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| minimax | ```python def hexagonal_num(n): return n * (2 * n - 1) # Test cases assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 ``` This function calculates the nth hexagonal number using the formula `n * (2 * n - 1)`, where `n` is the position in the hexagonal number sequence. The test cases check if the function returns the correct hexagonal numbers for the given positions. |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| kimi | Certainly! Let's tackle each task one by one. ### Task 1: Find similar elements from two tuple lists ```python def similar_elements(test_tup1, test_tup2): res = tuple(sorted(set(test_tup1) & set(test_tup2))) return res ``` ### Task 2: Identify non-prime numbers ```python import math def is_not_prime(n): if n <= 1: return True for i in range(2, int(math.sqrt(n)) + 1): if n % i == 0: return True return False ``` ### Task 3: Find the largest integers from a list using heap queue algorithm ```python import heapq def heap_queue_largest(nums, n): largest_nums = heapq.nlargest(n, nums) return largest_nums ``` ### Task 4: Find the nth hexagonal number The nth hexagonal number can be calculated using the formula: `H(n) = n * (2n - 1)`. Here's the function: ```python def hexagonal_num(n): return n * (2 * n - 1) ``` Now, let's put these functions to the test: ```python # Task 1 tests assert similar_elements((3, 4, 5, 6), (5, 7, 4, 10)) == (4, 5) assert similar_elements((1, 2, 3, 4), (5, 4, 3, 7)) == (3, 4) assert similar_elements((11, 12, 14, 13), (17, 15, 14, 13)) == (13, 14) # Task 2 tests assert is_not_prime(2) == False assert is_not_prime(10) == True assert is_not_prime(35) == True # Task 3 tests assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 3) == [85, 75, 65] assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 2) == [85, 75] assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 5) == [85, 75, 65, 58, 35] # Task 4 tests assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 ``` If you run these tests, they should all pass without any assertion errors. |
failed 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| wenxinyiyan | 'def hexagonal_num(n): return n * (2 * n - 1) ' [DONE] Explanation: A hexagonal number is a figurate number that represents a hexagon. The nth hexagonal number is given by the formula: n * (2 * n - 1). This formula arises from the geometric arrangement of dots in a hexagonal pattern. In this pattern, each subsequent layer adds an additional side of dots, resulting in a sequence of hexagonal numbers. The given function `hexagonal_num` takes an integer `n` as input and returns the nth hexagonal number by applying the formula n * (2 * n - 1). The function can be used to calculate any hexagonal number by providing the corresponding value of `n`. The provided test cases assert that the function correctly calculates the hexagonal numbers for different values of `n`. For example, `hexagonal_num(10)` should return 190, `hexagonal_num(5)` should return 45, and `hexagonal_num(7)` should return 91. |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| zhipu | To find the nth hexagonal number, we can use the formula for the nth hexagonal number, which is given by: \[ H_n = n(2n - 1) \] Here's the Python function to calculate the nth hexagonal number: ```python def hexagonal_num(n): return n * (2 * n - 1) # Test cases assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 print("All tests passed!") ``` This function takes an integer `n` as input and returns the nth hexagonal number by applying the formula. The provided test cases verify that the function works correctly. If you run this code, it should output "All tests passed!" indicating that all assertions are true. |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| gpto1 | [BEGIN] 'def hexagonal_num(n): return n * (2 * n - 1)' [DONE] |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |
| deepseekv3 | To find the nth hexagonal number, we can use the formula for hexagonal numbers, which is given by: \[ H_n = n \times (2n - 1) \] Here’s the Python function that implements this formula: ```python def hexagonal_num(n): return n * (2 * n - 1) # Test cases assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 ``` ### Explanation: - The function `hexagonal_num` takes an integer `n` as input. - It calculates the nth hexagonal number using the formula \( H_n = n \times (2n - 1) \). - The function returns the computed hexagonal number. ### Test Cases: - For `n = 10`, the hexagonal number is \( 10 \times (2 \times 10 - 1) = 10 \times 19 = 190 \). - For `n = 5`, the hexagonal number is \( 5 \times (2 \times 5 - 1) = 5 \times 9 = 45 \). - For `n = 7`, the hexagonal number is \( 7 \times (2 \times 7 - 1) = 7 \times 13 = 91 \). The function passes all the provided test cases. |
pass 测试用例:assert hexagonal_num(10) == 190 assert hexagonal_num(5) == 45 assert hexagonal_num(7) == 91 |