| 模型 | 模型答案 | 测试结果 |
|---|---|---|
| 金声玉亮2.0 | ```python def perimeter_pentagon(side_length): return 5 * side_length ``` [DONE] |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| deepseekr1 | To solve this problem, we need to calculate the perimeter of a regular pentagon given the length of one of its sides. A regular pentagon has all five sides of equal length, which simplifies the calculation of the perimeter. ### Approach The perimeter of a regular pentagon can be determined by multiplying the length of one side by 5. This is because the perimeter is the sum of all the sides of the polygon, and in a regular pentagon, all sides are equal. Therefore, the formula for the perimeter \( P \) of a regular pentagon with side length \( s \) is: \[ P = 5 \times s \] Given this formula, the approach to solve the problem is straightforward: 1. Accept the side length as input. 2. Multiply the side length by 5. 3. Return the result. This approach is efficient with a time complexity of \( O(1) \) since it involves a single multiplication operation. ### Solution Code ```python def perimeter_pentagon(side_length): return 5 * side_length ``` ### Explanation The function `perimeter_pentagon` takes a single parameter `side_length`, which represents the length of one side of the pentagon. The function then calculates the perimeter by multiplying the given side length by 5 and returns the result. This solution efficiently computes the perimeter in constant time, ensuring it works correctly for any valid input as required by the problem constraints. |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| gpto1 | [BEGIN] 'def perimeter_pentagon(side_length): return 5 * side_length' [DONE] |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| GPT-4o | Certainly! Here is the Python function to find the perimeter of a pentagon: ```python def perimeter_pentagon(side_length): return 5 * side_length # Test cases to validate the solution assert perimeter_pentagon(5) == 25 assert perimeter_pentagon(10) == 50 assert perimeter_pentagon(15) == 75 ``` The function `perimeter_pentagon` takes one parameter `side_length`, which represents the length of one side of the pentagon. The perimeter of a pentagon is simply 5 times the length of one of its sides. The provided test cases should pass without any issues. |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| llama3.1-70B-Instruct | def perimeter_pentagon(side_length): return 5 * side_length |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| llama3.1-405B-Instruct | def perimeter_pentagon(side_length): return 5 * side_length |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| DeepSeek-Coder-V2 | 'def perimeter_pentagon(side_length): return 5 * side_length' [DONE] |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| Qwen2-72B-Instruct | 'def perimeter_pentagon(side): return 5 * side' [DONE] |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| baichuan4 | To find the perimeter of a pentagon, we can use the formula: perimeter = 5 * side_length. Here's the function to calculate the perimeter of a pentagon: ```python def perimeter_pentagon(side_length): return 5 * side_length ``` Let's test the function with the given test cases: ```python assert perimeter_pentagon(5) == 25 assert perimeter_pentagon(10) == 50 assert perimeter_pentagon(15) == 75 ``` All the test cases pass, indicating that the function is correct. |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| doubao | 'def perimeter_pentagon(s): return 5 * s' [DONE] |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| minimax | 'def perimeter_pentagon(side_length): perimeter = 5 * side_length return perimeter' |
failed 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| kimi | Here's the Python function to find the perimeter of a pentagon, given the length of each side: ```python def perimeter_pentagon(side_length): return 5 * side_length # Test cases assert perimeter_pentagon(5) == 25 assert perimeter_pentagon(10) == 50 assert perimeter_pentagon(15) == 75 ``` This function simply multiplies the length of one side by 5, since a pentagon has five sides. The test cases check that the function returns the correct perimeter for pentagons with side lengths of 5, 10, and 15. |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| wenxinyiyan | 'def perimeter_pentagon(side_length):
return 5 * side_length' [DONE] Explanation: The perimeter of a pentagon is calculated by multiplying the length of one side by 5, as a pentagon has 5 equal sides. The function `perimeter_pentagon` takes the length of one side as an argument and returns the perimeter of the pentagon. The assertion statements test the function with different side lengths (5, 10, and 15) and check if the returned perimeter is correct. |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| zhipu | To find the perimeter of a pentagon, you simply need to multiply the length of one side by 5, as a pentagon has five equal sides. Here's the function that does this: ```python def perimeter_pentagon(side_length): return 5 * side_length ``` Let's verify that this function passes the given tests: ```python assert perimeter_pentagon(5) == 25 assert perimeter_pentagon(10) == 50 assert perimeter_pentagon(15) == 75 ``` This function should work correctly for the given test cases. Here is the complete code: ```python def perimeter_pentagon(side_length): return 5 * side_length # Test cases assert perimeter_pentagon(5) == 25 assert perimeter_pentagon(10) == 50 assert perimeter_pentagon(15) == 75 print("All tests passed!") ``` When you run this code, it should output "All tests passed!" indicating that the function works as expected for the given test cases. |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| gpto1 | [BEGIN] 'def perimeter_pentagon(side_length): return 5 * side_length' [DONE] |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |
| deepseekv3 | ```python def perimeter_pentagon(side_length): return 5 * side_length ``` ### Explanation: - A regular pentagon has five sides of equal length. - The perimeter of a pentagon is simply the sum of the lengths of all its sides. - Since all sides are equal, the perimeter can be calculated by multiplying the length of one side by 5. ### Tests: - `perimeter_pentagon(5)` returns `25` because \(5 \times 5 = 25\). - `perimeter_pentagon(10)` returns `50` because \(5 \times 10 = 50\). - `perimeter_pentagon(15)` returns `75` because \(5 \times 15 = 75\). This function will correctly calculate the perimeter of a pentagon given the length of one side. |
pass 测试用例:assert perimeter_pentagon(5)==25 assert perimeter_pentagon(10)==50 assert perimeter_pentagon(15)==75 |