问题

You are an expert Python programmer, and here is your task: Write a function to find the similar elements from the given two tuple lists. Your code should pass these tests:

assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5)
assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4)
assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14)

[BEGIN]
'def similar_elements(test_tup1, test_tup2):
res = tuple(set(test_tup1) & set(test_tup2))
return (res)'
[DONE]


You are an expert Python programmer, and here is your task: Write a python function to identify non-prime numbers. Your code should pass these tests:

assert is_not_prime(2) == False
assert is_not_prime(10) == True
assert is_not_prime(35) == True

[BEGIN]
'import math
def is_not_prime(n):
result = False
for i in range(2,int(math.sqrt(n)) + 1):
if n % i == 0:
result = True
return result'
[DONE]


You are an expert Python programmer, and here is your task: Write a function to find the largest integers from a given list of numbers using heap queue algorithm. Your code should pass these tests:

assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],3)==[85, 75, 65]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],2)==[85, 75]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],5)==[85, 75, 65, 58, 35]

[BEGIN]
'import heapq as hq
def heap_queue_largest(nums,n):
largest_nums = hq.nlargest(n, nums)
return largest_nums'
[DONE]


You are an expert Python programmer, and here is your task: Write a python function to find the next perfect square greater than a given number. Your code should pass these tests:

assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16

[BEGIN]

答案

模型 模型答案 测试结果
金声玉亮2.0 ```python
import math

def next_Perfect_Square(num):
next_num = math.floor(math.sqrt(num)) + 1
return next_num ** 2
```
[DONE]		 pass
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
deepseekr1

[BEGIN]
import math

def next_Perfect_Square(N):
next_root = math.isqrt(N) + 1
return next_root ** 2
[DONE]		 pass
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
gpto1 [BEGIN]
'import math
def next_Perfect_Square(n):
k = math.isqrt(n) + 1
return k * k'
[DONE]		 pass
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
GPT-4o Sure, let's define the function to find the next perfect square greater than a given number. We'll start by finding the square root of the given number, then round it up to the next whole number, and finally square that number to get the next perfect square.

Here is the implementation:

```python
import math

def next_Perfect_Square(n):
# Find the square root of the given number
root = math.sqrt(n)
# Find the next whole number greater than the square root
next_root = math.ceil(root)
# Square the next whole number to get the next perfect square
next_perfect_square = next_root ** 2
return next_perfect_square

# Testing the function with the provided test cases
assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
```

This code should pass all the given assertions. Let's break down the logic:
1. Calculate the square root of the given number using `math.sqrt`.
2. Use `math.ceil` to round up the square root to the next whole number.
3. Square this whole number to get the next perfect square.
4. Return the resulting perfect square.		 wrong_answer
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
llama3.1-70B-Instruct

def next_Perfect_Square(n):
i = 1
while True:
perfect_square = i * i
if perfect_square > n:
return perfect_square
i += 1		 pass
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
llama3.1-405B-Instruct

import math

def next_Perfect_Square(n):
root = math.sqrt(n)
if int(root + 0.5) ** 2 == n:
root += 1
else:
root = math.ceil(root)
return root ** 2		 pass
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
DeepSeek-Coder-V2 ```python
import math

def next_Perfect_Square(num):
next_num = math.floor(math.sqrt(num)) + 1
return next_num ** 2
```
[DONE]		 pass
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
Qwen2-72B-Instruct 'def next_Perfect_Square(n):
next_square = ((int(n**0.5)+1)**2)
return next_square'
[DONE]		 pass
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
baichuan4 To find the next perfect square greater than a given number, we can use a simple algorithm that iterates through consecutive squares until finding one that is greater than the input number. Here's the implementation of the `next_Perfect_Square` function:

```python
def next_Perfect_Square(n):
# Start with the square of 3 because 4 is the first perfect square and we need the next one
i = 3
while True:
square = i * i
if square > n:
return square
i += 1
```

Let's test the function with the provided assertions:

```python
assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
```

The function correctly identifies the next perfect square for each of the given numbers.		 pass
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
doubao 'import math
def next_Perfect_Square(n):
root = math.sqrt(n)
if int(root + 0.5) ** 2 == n:
root += 1
return int(root) ** 2'
[DONE]		 wrong_answer
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
minimax ```python
import math

def next_Perfect_Square(n):
root = math.sqrt(n)
next_root = math.ceil(root)
next_perfect_square = next_root ** 2
return next_perfect_square

# Test cases
assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
```

This function calculates the square root of the given number `n`, rounds it up to the nearest whole number, and then squares that number to find the next perfect square. The test cases check if the function correctly identifies the next perfect square for the given inputs.		 wrong_answer
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
kimi ```python
import math

def similar_elements(test_tup1, test_tup2):
res = tuple(sorted(set(test_tup1) & set(test_tup2)))
return res

def is_not_prime(n):
if n <= 1:
return True
for i in range(2, int(math.sqrt(n)) + 1):
if n % i == 0:
return True
return False

import heapq as hq

def heap_queue_largest(nums, n):
largest_nums = hq.nlargest(n, nums)
return largest_nums

def next_Perfect_Square(num):
num = abs(int(num)) + 1
root = math.sqrt(num)
if root != int(root):
root = int(root) + 1
return int(root * root)

# Test cases for similar_elements
assert similar_elements((3, 4, 5, 6), (5, 7, 4, 10)) == (4, 5)
assert similar_elements((1, 2, 3, 4), (5, 4, 3, 7)) == (3, 4)
assert similar_elements((11, 12, 14, 13), (17, 15, 14, 13)) == (13, 14)

# Test cases for is_not_prime
assert is_not_prime(2) == False
assert is_not_prime(10) == True
assert is_not_prime(35) == True

# Test cases for heap_queue_largest
assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 3) == [85, 75, 65]
assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 2) == [85, 75]
assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 5) == [85, 75, 65, 58, 35]

# Test cases for next_Perfect_Square
assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
```

This code defines the functions `similar_elements`, `is_not_prime`, `heap_queue_largest`, and `next_Perfect_Square`, and includes test cases to validate their correctness. The `similar_elements` function finds the common elements in two tuples, `is_not_prime` checks if a number is not prime, `heap_queue_largest` finds the largest `n` numbers in a list using the heap queue algorithm, and `next_Perfect_Square` finds the next perfect square greater than a given number.		 pass
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
wenxinyiyan Here's the Python function to find the next perfect square greater than a given number:


```python
import math

def next_Perfect_Square(n):
next_square = math.ceil(math.sqrt(n) + 1) ** 2
return next_square
```
Explanation:

1. We import the `math` module to use mathematical functions.
2. The `next_Perfect_Square` function takes an integer `n` as input.
3. We calculate the square root of `n` using `math.sqrt(n)`.
4. We round up the square root to the nearest integer using `math.ceil()`, and then increment it by 1 to ensure we get the next perfect square.
5. We square the rounded and incremented value to obtain the next perfect square greater than `n`.
6. The function returns the calculated next perfect square.

Now let's test the function with the provided assertions:


```python
assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
```
All assertions should pass, indicating that the function correctly calculates the next perfect square greater than the given number.		 wrong_answer
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
zhipu To create a function that finds the next perfect square greater than a given number, we can follow these steps:

1. Compute the integer square root of the given number.
2. Increment this square root by 1 to get the next integer.
3. Square this new integer to get the next perfect square.

Here's the Python function that implements this logic:

```python
def next_Perfect_Square(n):
# Calculate the integer square root of the given number
sqrt_n = int(n**0.5)

# Increment to get the next integer
next_sqrt = sqrt_n + 1

# Return the square of the next integer
return next_sqrt**2

# Test cases
assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16

print("All tests passed!")
```

This function should pass the provided test cases. The `**0.5` operation computes the square root, and `int()` converts it to the nearest lower integer. By incrementing this integer and squaring it, we obtain the next perfect square. The assertions ensure that the function behaves as expected. If no assertion error is raised, the "All tests passed!" message will be printed.		 pass
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
gpto1 [BEGIN]
'import math
def next_Perfect_Square(n):
k = math.isqrt(n) + 1
return k * k'
[DONE]		 pass
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
deepseekv3 Here is the Python function to find the next perfect square greater than a given number:

```python
import math

def next_Perfect_Square(n):
# Calculate the square root of the given number
sqrt = math.sqrt(n)

# Round up to the nearest integer
next_int = math.ceil(sqrt)

# If the given number is already a perfect square, move to the next integer
if next_int == sqrt:
next_int += 1

# Calculate the next perfect square
next_square = next_int ** 2

return next_square
```

### Explanation:
1. **Square Root Calculation**: The function first calculates the square root of the input number `n` using `math.sqrt()`.
2. **Rounding Up**: It then rounds up the square root to the nearest integer using `math.ceil()`.
3. **Check for Perfect Square**: If the rounded-up integer is equal to the square root, it means `n` is already a perfect square, so it increments the integer by 1 to find the next perfect square.
4. **Calculate Next Perfect Square**: Finally, it calculates the next perfect square by squaring the rounded-up integer.

### Test Cases:
```python
assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16
```

These test cases should pass successfully with the provided function.		 pass
测试用例：assert next_Perfect_Square(35) == 36
assert next_Perfect_Square(6) == 9
assert next_Perfect_Square(9) == 16