| 模型 | 模型答案 | 测试结果 |
|---|---|---|
| 金声玉亮2.0 | ```python def remove_empty(lst): return [item for item in lst if not isinstance(item, list) or len(item) > 0] ``` [DONE] |
pass 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| deepseekr1 | To solve this problem, we need to write a function that removes all empty lists from a given list of lists. The input list may contain elements of various types, including both lists and non-list elements. Our task is to filter out any elements that are empty lists while preserving all other elements. ### Approach 1. **Understand the Input and Output**: The input is a list that can contain elements of any type, including other lists. The output should be a new list that excludes all empty lists but retains all other elements. 2. **Identify Empty Lists**: For each element in the input list, check if it is a list and if it is empty. This can be done using the `isinstance` function to check if the element is a list and the `len` function to check if its length is zero. 3. **Filter Elements**: Use a list comprehension to iterate through each element in the input list. Include an element in the result if it is either not a list or is a non-empty list. ### Solution Code ```python def remove_empty(lst): return [x for x in lst if not (isinstance(x, list) and len(x) == 0)] ``` ### Explanation - **List Comprehension**: The solution uses a list comprehension to iterate over each element in the input list. This is an efficient and concise way to create the resulting list. - **Type and Length Check**: The condition `isinstance(x, list) and len(x) == 0` checks if an element is an empty list. If this condition is true, the element is excluded from the result. - **Non-List Elements**: Elements that are not lists are included in the result as they are, ensuring that strings, numbers, and other non-list elements are preserved. This approach efficiently filters out empty lists while maintaining the order of the remaining elements, ensuring the solution is both correct and optimal. |
pass 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| gpto1 | 'def remove_empty(lst): return [x for x in lst if x != []]' |
failed 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| GPT-4o | ```python def remove_empty(lst_of_lsts): return [item for item in lst_of_lsts if item != []] # Test cases assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []]) == ['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], [], [], 'Green', [1,2], 'Blue', [], []]) == ['Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python', [], [], 'programming', 'language', [], [], [], [], []]) == ['Python', 'programming', 'language'] ``` |
pass 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| llama3.1-70B-Instruct | def remove_empty(lst): return [i for i in lst if i != []] |
pass 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| llama3.1-405B-Instruct | def remove_empty(input_list): return [x for x in input_list if x != []] |
pass 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| DeepSeek-Coder-V2 | ```python def remove_empty(lst): return [item for item in lst if not isinstance(item, list) or len(item) > 0] ``` [DONE] |
pass 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| Qwen2-72B-Instruct | 'def remove_empty(lst): return [i for i in lst if i != []] assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language']' |
failed 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| baichuan4 | Here's the Python function to remove empty lists from a given list of lists: ```python def remove_empty(lists): return [item for item in lists if item] ``` This function uses a list comprehension to iterate over each item in the `lists` input. The `if item` condition checks if the item is truthy, which means it filters out empty lists (since they are falsy in Python). The remaining items are collected into a new list, which is then returned. Let's run the provided tests: ```python assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []]) == ['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []]) == ['Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []]) == ['Python', 'programming', 'language'] ``` All tests should pass without any assertion errors, confirming that the function works as expected. |
pass 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| doubao | 'def remove_empty(lst): return [x for x in lst if x!= []]' [DONE] |
pass 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| minimax | ```python def remove_empty(list_of_lists): return [item for item in list_of_lists if item] # Test cases assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []]) == ['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Green', [1,2], 'Blue', [], []]) == ['Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python', [], [], 'programming', 'language', [], [], [], [], []]) == ['Python', 'programming', 'language'] ``` [DONE] |
pass 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| kimi | Here's the Python code for each of the tasks you've described: 1. Function to find similar elements from two tuple lists: ```python def similar_elements(test_tup1, test_tup2): res = tuple(sorted(set(test_tup1) & set(test_tup2))) return res ``` 2. Function to identify non-prime numbers: ```python import math def is_not_prime(n): if n <= 1: return True for i in range(2, int(math.sqrt(n)) + 1): if n % i == 0: return True return False ``` 3. Function to find the largest integers from a given list using heap queue algorithm: ```python import heapq def heap_queue_largest(nums, n): largest_nums = heapq.nlargest(n, nums) return largest_nums ``` 4. Function to remove empty lists from a given list of lists: ```python def remove_empty(list_of_lists): return [item for item in list_of_lists if item] ``` Each function should pass the tests you've provided. You can use these functions in your Python environment to perform the required tasks. |
failed 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| wenxinyiyan | Here are the solutions for the given tasks: 1. Finding similar elements from two tuple lists: ```python def similar_elements(test_tup1, test_tup2): res = tuple(set(test_tup1) & set(test_tup2)) return res ``` The code uses the set intersection operation (`&`) to find the common elements between the two tuples. The result is then converted back to a tuple and returned. 2. Identifying non-prime numbers: ```python import math def is_not_prime(n): if n <= 1: return True for i in range(2, int(math.sqrt(n)) + 1): if n % i == 0: return True return False ``` The code checks if the number `n` is less than or equal to 1, in which case it is not prime. Then, it iterates from 2 to the square root of `n` and checks if `n` is divisible by any of those numbers. If it is, the function returns `True` indicating that `n` is not prime. Otherwise, it returns `False`. Note: The provided code snippet had a minor issue where it was returning `True` for prime numbers and `False` for non-prime numbers. I modified it to match the expected behavior based on the test cases. 3. Finding the largest integers from a given list using the heap queue algorithm: ```python import heapq as hq def heap_queue_largest(nums, n): largest_nums = hq.nlargest(n, nums) return largest_nums ``` The code uses the `heapq.nlargest()` function from the `heapq` module to find the `n` largest elements in the given list `nums`. The result is returned as a list. 4. Removing empty lists from a given list of lists: ```python def remove_empty(lst): return [item for item in lst if isinstance(item, list) and item or not isinstance(item, list)] ``` The code uses a list comprehension to iterate over each item in the given list `lst`. It checks if the item is a list and not empty (`item` evaluates to `True` when the list is not empty) or if the item is not a list. If either condition is met, the item is included in the new list. The resulting list is then returned. Note: The provided code snippet had a syntax error in the list comprehension. I modified it to fix the error and achieve the desired functionality. With these modifications, all the test cases should pass for each task. |
failed 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| zhipu | Here's a Python function that removes empty lists from a given list of lists. This function will pass the provided tests: ```python def remove_empty(list_of_lists): return [item for item in list_of_lists if item != []] # Test cases assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []]) == ['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []]) == ['Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []]) == ['Python', 'programming', 'language'] print("All tests passed!") ``` Explanation: - The function `remove_empty` uses a list comprehension to iterate over each element in the input list `list_of_lists`. - It includes the element in the resulting list only if the element is not an empty list (`item != []`). - The provided test cases are then used to verify that the function behaves as expected. When you run this code, it should output "All tests passed!" indicating that all assertions are true. |
pass 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| gpto1 | 'def remove_empty(lst): return [x for x in lst if x != []]' |
failed 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |
| deepseekv3 | ```python def remove_empty(lst): return [item for item in lst if item != []] # Test cases assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []]) == ['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []]) == ['Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []]) == ['Python', 'programming', 'language'] ``` ### Explanation: - The function `remove_empty` takes a list `lst` as input. - It uses a list comprehension to iterate through each item in `lst`. - It includes the item in the new list only if the item is not an empty list (`item != []`). - The function then returns the new list without any empty lists. This implementation is concise and efficiently removes all empty lists from the given list of lists. |
pass 测试用例:assert remove_empty([[], [], [], 'Red', 'Green', [1,2], 'Blue', [], []])==['Red', 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [],[],[], 'Green', [1,2], 'Blue', [], []])==[ 'Green', [1, 2], 'Blue'] assert remove_empty([[], [], [], 'Python',[],[], 'programming', 'language',[],[],[], [], []])==['Python', 'programming', 'language'] |