| 模型 | 模型答案 | 测试结果 |
|---|---|---|
| 金声玉亮2.0 | ```python def adjacent_num_product(nums): max_product = nums[0] * nums[1] for i in range(1, len(nums) - 1): product = nums[i] * nums[i + 1] if product > max_product: max_product = product return max_product ``` [DONE] |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| deepseekr1 | To solve this problem, we need to find the largest product of adjacent elements in a given list of integers. The solution involves iterating through the list, calculating the product of each pair of adjacent elements, and determining the maximum product from these calculations. ### Approach 1. **Problem Analysis**: The task requires examining each pair of adjacent elements in the list and computing their product. The largest product among these pairs is the desired result. 2. **Intuition**: By iterating through the list and calculating the product of each adjacent pair, we can keep track of the maximum product encountered. This approach ensures that we consider all possible adjacent pairs efficiently. 3. **Algorithm Selection**: Using a list comprehension to generate all adjacent products and then finding the maximum value using Python's built-in `max` function is both concise and efficient. This approach leverages Python's capabilities for clean and readable code. 4. **Edge Cases**: The problem guarantees that the input list will have at least two elements, so we do not need to handle empty lists or single-element lists. ### Solution Code ```python def adjacent_num_product(nums): products = [nums[i] * nums[i + 1] for i in range(len(nums) - 1)] return max(products) ``` ### Explanation 1. **Generating Products**: The list comprehension `[nums[i] * nums[i + 1] for i in range(len(nums) - 1)]` generates a list of products of each adjacent pair in the input list. For example, given the list `[1, 2, 3, 4, 5, 6]`, this comprehension will produce `[2, 6, 12, 20, 30]`. 2. **Finding Maximum**: The `max` function is applied to the generated list of products to find and return the largest value. This ensures that we efficiently determine the maximum product in a single pass through the generated list. This approach is efficient with a time complexity of O(n), where n is the length of the input list, as we iterate through the list once to generate the products and once more to find the maximum. This linear complexity is optimal for the problem at hand. |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| gpto1 | 'def adjacent_num_product(lst): return max(lst[i]*lst[i+1] for i in range(len(lst)-1))' |
failed 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| GPT-4o | Sure, here's the function to find the largest product of a pair of adjacent elements from a given list of integers: ```python def adjacent_num_product(nums): if len(nums) < 2: raise ValueError("The list must contain at least two elements.") max_product = nums[0] * nums[1] for i in range(1, len(nums) - 1): product = nums[i] * nums[i + 1] if product > max_product: max_product = product return max_product # Tests assert adjacent_num_product([1, 2, 3, 4, 5, 6]) == 30 assert adjacent_num_product([1, 2, 3, 4, 5]) == 20 assert adjacent_num_product([2, 3]) == 6 ``` This function iterates through the list, calculates the product of each pair of adjacent elements, and keeps track of the maximum product found. The function will raise an error if the list has fewer than two elements. The provided tests should all pass with this implementation. |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| llama3.1-70B-Instruct | def adjacent_num_product(nums): return max(nums[i] * nums[i+1] for i in range(len(nums)-1)) |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| llama3.1-405B-Instruct | def adjacent_num_product(nums): return max(nums[i] * nums[i+1] for i in range(len(nums)-1)) |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| DeepSeek-Coder-V2 | ```python def adjacent_num_product(nums): max_product = nums[0] * nums[1] for i in range(1, len(nums) - 1): product = nums[i] * nums[i + 1] if product > max_product: max_product = product return max_product ``` [DONE] |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| Qwen2-72B-Instruct | 'def adjacent_num_product(lst): max_product = lst[0] * lst[1] for i in range(1, len(lst) - 1): product = lst[i] * lst[i+1] if product > max_product: max_product = product return max_product' [DONE] Note: This function iterates through the list, calculating the product of each pair of adjacent elements and updating the maximum product found so far. It returns the maximum product found. |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| baichuan4 | To find the largest product of a pair of adjacent elements from a given list of integers, you can use the following function: ```python def adjacent_num_product(nums): max_product = float('-inf') for i in range(len(nums) - 1): product = nums[i] * nums[i + 1] max_product = max(max_product, product) return max_product ``` This function iterates through the list of integers, calculates the product of each pair of adjacent elements, and updates the maximum product if a larger product is found. The initial value of `max_product` is set to negative infinity to ensure that the first product calculated will be larger. Here are the test cases you provided: ```python assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 ``` When you run this function with the given test cases, it should return the expected results. |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| doubao | 'def adjacent_num_product(nums):
max_product = float("-inf") for i in range(len(nums) - 1): product = nums[i] * nums[i + 1] if product > max_product: max_product = product return max_product' [DONE] |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| minimax | ```python def adjacent_num_product(lst): return max(a * b for a, b in zip(lst, lst[1:])) # Test cases assert adjacent_num_product([1, 2, 3, 4, 5, 6]) == 30 assert adjacent_num_product([1, 2, 3, 4, 5]) == 20 assert adjacent_num_product([2, 3]) == 6 ``` This function `adjacent_num_product` calculates the product of each pair of adjacent elements in the list by using a generator expression within the `max` function. The `zip` function pairs each element with its subsequent neighbor, and the `max` function finds the largest product from these pairs. The provided test cases should pass with this implementation. |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| kimi | ```python def similar_elements(test_tup1, test_tup2): res = tuple(sorted(set(test_tup1) & set(test_tup2))) return res def is_not_prime(n): if n <= 1: return True for i in range(2, int(n**0.5) + 1): if n % i == 0: return True return False import heapq as hq def heap_queue_largest(nums, n): largest_nums = hq.nlargest(n, nums) return largest_nums def adjacent_num_product(lst): max_product = float('-inf') for i in range(len(lst) - 1): product = lst[i] * lst[i + 1] max_product = max(max_product, product) return max_product ``` This code defines the functions required to pass the tests you've provided: 1. `similar_elements` finds the similar elements between two tuples. 2. `is_not_prime` checks if a number is not prime. 3. `heap_queue_largest` finds the largest `n` integers from a list using the heap queue algorithm. 4. `adjacent_num_product` finds the largest product of a pair of adjacent elements from a list of integers. |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| wenxinyiyan | 'def adjacent_num_product(lst): if len(lst) < 2: return None # Or raise an exception, depending on how you want to handle an empty or single-element list max_product = float('-inf') for i in range(len(lst) - 1): product = lst[i] * lst[i + 1] if product > max_product: max_product = product return max_product' [DONE] Explanation: The function `adjacent_num_product` takes a list `lst` as input and initializes a variable `max_product` to negative infinity. This variable will keep track of the maximum product found so far. The function then iterates over the indices of the list, excluding the last index, since we need pairs of adjacent elements. For each index `i`, it calculates the product of the element at index `i` and the element at index `i + 1`. If this product is greater than the current `max_product`, it updates `max_product` with the new value. After iterating through all the pairs of adjacent elements, the function returns the `max_product`. Note: If the input list has fewer than 2 elements, the function returns `None`. You can modify this behavior based on your specific requirements, such as raising an exception or returning a default value. |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| zhipu | To solve this task, we need to iterate through the list of integers and calculate the product of each pair of adjacent elements. We then keep track of the largest product found during this iteration. Here's the Python function that accomplishes this: ```python def adjacent_num_product(nums): if len(nums) < 2: raise ValueError("List must contain at least two elements.") max_product = nums[0] * nums[1] for i in range(1, len(nums) - 1): current_product = nums[i] * nums[i + 1] if current_product > max_product: max_product = current_product return max_product # Test cases assert adjacent_num_product([1, 2, 3, 4, 5, 6]) == 30 assert adjacent_num_product([1, 2, 3, 4, 5]) == 20 assert adjacent_num_product([2, 3]) == 6 ``` Explanation: 1. **Input Validation**: The function first checks if the input list `nums` has at least two elements. If not, it raises a `ValueError`. 2. **Initial Maximum Product**: It initializes `max_product` with the product of the first two elements. 3. **Iteration**: The function then iterates through the list starting from the second element up to the second-to-last element. 4. **Current Product Calculation**: For each element at index `i`, it calculates the product with the next element (`nums[i + 1]`). 5. **Update Maximum Product**: If the current product is greater than the `max_product`, it updates `max_product`. 6. **Return Result**: Finally, it returns the `max_product`. This function should pass the provided test cases. |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| gpto1 | 'def adjacent_num_product(lst): return max(lst[i]*lst[i+1] for i in range(len(lst)-1))' |
failed 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |
| deepseekv3 | To find the largest product of the pair of adjacent elements from a given list of integers, you can iterate through the list and calculate the product of each pair of adjacent elements. Then, you can keep track of the maximum product found. Here's the Python function to achieve this: ```python def adjacent_num_product(nums): if len(nums) < 2: return None # Return None if the list has fewer than 2 elements max_product = nums[0] * nums[1] for i in range(1, len(nums) - 1): current_product = nums[i] * nums[i + 1] if current_product > max_product: max_product = current_product return max_product # Test cases assert adjacent_num_product([1, 2, 3, 4, 5, 6]) == 30 assert adjacent_num_product([1, 2, 3, 4, 5]) == 20 assert adjacent_num_product([2, 3]) == 6 ``` ### Explanation: 1. **Check List Length**: The function first checks if the list has fewer than 2 elements. If so, it returns `None` because there are no adjacent pairs to compare. 2. **Initialize Maximum Product**: It initializes `max_product` with the product of the first two elements. 3. **Iterate Through List**: The function then iterates through the list from the second element to the second-to-last element, calculating the product of each pair of adjacent elements. 4. **Update Maximum Product**: If the current product is greater than `max_product`, it updates `max_product`. 5. **Return Result**: Finally, the function returns `max_product`. This approach ensures that you efficiently find the largest product of adjacent elements in the list. |
pass 测试用例：assert adjacent_num_product([1,2,3,4,5,6]) == 30 assert adjacent_num_product([1,2,3,4,5]) == 20 assert adjacent_num_product([2,3]) == 6 |