问题

You are an expert Python programmer, and here is your task: Write a function to find the similar elements from the given two tuple lists. Your code should pass these tests:

assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5)
assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4)
assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14)

[BEGIN]
'def similar_elements(test_tup1, test_tup2):
res = tuple(set(test_tup1) & set(test_tup2))
return (res)'
[DONE]


You are an expert Python programmer, and here is your task: Write a python function to identify non-prime numbers. Your code should pass these tests:

assert is_not_prime(2) == False
assert is_not_prime(10) == True
assert is_not_prime(35) == True

[BEGIN]
'import math
def is_not_prime(n):
result = False
for i in range(2,int(math.sqrt(n)) + 1):
if n % i == 0:
result = True
return result'
[DONE]


You are an expert Python programmer, and here is your task: Write a function to find the largest integers from a given list of numbers using heap queue algorithm. Your code should pass these tests:

assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],3)==[85, 75, 65]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],2)==[85, 75]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],5)==[85, 75, 65, 58, 35]

[BEGIN]
'import heapq as hq
def heap_queue_largest(nums,n):
largest_nums = hq.nlargest(n, nums)
return largest_nums'
[DONE]


You are an expert Python programmer, and here is your task: Write a function to convert more than one list to nested dictionary. Your code should pass these tests:

assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]

[BEGIN]

答案

模型 模型答案 测试结果
金声玉亮2.0 ```python
def convert_list_dictionary(keys, sub_keys, values):
result = []
for i in range(len(keys)):
nested_dict = {keys[i]: {sub_keys[i]: values[i]}}
result.append(nested_dict)
return result
```
[DONE]		 pass
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
deepseekr1

[BEGIN]
def convert_list_dictionary(keys, values1, values2):
return [{k: {v1: v2}} for k, v1, v2 in zip(keys, values1, values2)]
[DONE]		 pass
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
gpto1 ```python
'def convert_list_dictionary(list1, list2, list3):
result = []
for k, v, val in zip(list1, list2, list3):
result.append({k: {v: val}})
return result'
```		 failed
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
GPT-4o ```python
def convert_list_dictionary(list1, list2, list3):
result = []
for key, sub_key, value in zip(list1, list2, list3):
result.append({key: {sub_key: value}})
return result

# Test cases
assert convert_list_dictionary(["S001", "S002", "S003", "S004"], ["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"], [85, 98, 89, 92]) == [{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"], ["python","program","language","programs"], [100,200,300,400]) == [{'abc': {'python': 100}}, {'def': {'program': 200}}, {'ghi': {'language': 300}}, {'jkl': {'programs': 400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"], ["java","C","C++","DBMS"], [10,20,30,40]) == [{'A1': {'java': 10}}, {'A2': {'C': 20}}, {'A3': {'C++': 30}}, {'A4': {'DBMS': 40}}]
```		 pass
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
llama3.1-70B-Instruct

def convert_list_dictionary(keys, values, scores):
return [{key: {value: score}} for key, value, score in zip(keys, values, scores)]		 pass
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
llama3.1-405B-Instruct

def convert_list_dictionary(keys, values, scores):
result = []
for key, value, score in zip(keys, values, scores):
result.append({key: {value: score}})
return result		 pass
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
DeepSeek-Coder-V2 ```python
def convert_list_dictionary(keys, sub_keys, values):
result = []
for i in range(len(keys)):
nested_dict = {keys[i]: {sub_keys[i]: values[i]}}
result.append(nested_dict)
return result
```
[DONE]		 pass
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
Qwen2-72B-Instruct 'def convert_list_dictionary(keys, subkeys, values):
return [{key: {subkey: value}} for key, subkey, value in zip(keys, subkeys, values)]'
[DONE]		 pass
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
baichuan4 Here's a Python function that converts multiple lists into a nested dictionary, as per your requirement:

```python
def convert_list_dictionary(keys, values, scores):
nested_dict = []
for i in range(len(keys)):
nested_dict.append({keys[i]: {values[i]: scores[i]}})
return nested_dict
```

This function iterates through the provided lists (`keys`, `values`, and `scores`), creating a dictionary for each iteration where the key is an element from the `keys` list, and the value is another dictionary with an element from the `values` list as the key and an element from the `scores` list as the value. These dictionaries are then appended to the `nested_dict` list, which is returned at the end.

Let's test the function with the provided test cases:

```python
assert convert_list_dictionary(["S001", "S002", "S003", "S004"], ["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"], [85, 98, 89, 92]) == [{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc", "def", "ghi", "jkl"], ["python", "program", "language", "programs"], [100, 200, 300, 400]) == [{'abc': {'python': 100}}, {'def': {'program': 200}}, {'ghi': {'language': 300}}, {'jkl': {'programs': 400}}]
assert convert_list_dictionary(["A1", "A2", "A3", "A4"], ["java", "C", "C++", "DBMS"], [10, 20, 30, 40]) == [{'A1': {'java': 10}}, {'A2': {'C': 20}}, {'A3': {'C++': 30}}, {'A4': {'DBMS': 40}}]
```

All the assertions should pass without any errors, indicating that the function works correctly for the given test cases.		 pass
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
doubao def convert_list_dictionary(keys1, keys2, values):
result = []
for i in range(len(keys1)):
result.append({keys1[i]: {keys2[i]: values[i]}})
return result
[DONE]		 pass
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
minimax ```python
def convert_list_dictionary(keys, names, values):
return [{k: {n: v}} for k, n, v in zip(keys, names, values)]

# Test cases
assert convert_list_dictionary(["S001", "S002", "S003", "S004"], ["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"], [85, 98, 89, 92]) == [{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc", "def", "ghi", "jkl"], ["python", "program", "language", "programs"], [100, 200, 300, 400]) == [{'abc': {'python': 100}}, {'def': {'program': 200}}, {'ghi': {'language': 300}}, {'jkl': {'programs': 400}}]
assert convert_list_dictionary(["A1", "A2", "A3", "A4"], ["java", "C", "C++", "DBMS"], [10, 20, 30, 40]) == [{'A1': {'java': 10}}, {'A2': {'C': 20}}, {'A3': {'C++': 30}}, {'A4': {'DBMS': 40}}]
```

This function `convert_list_dictionary` takes three lists as input and returns a list of dictionaries, where each dictionary is a combination of one element from each list, with the first list as the outer key, the second list as the inner key, and the third list as the value. The test cases check that the function works as expected.		 pass
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
kimi Here's the Python code for each of the tasks you've described:

1. Function to find similar elements from two tuple lists:

```python
def similar_elements(test_tup1, test_tup2):
res = tuple(sorted(set(test_tup1) & set(test_tup2)))
return res
```

2. Function to identify non-prime numbers:

```python
import math

def is_not_prime(n):
if n <= 1:
return True
for i in range(2, int(math.sqrt(n)) + 1):
if n % i == 0:
return True
return False
```

3. Function to find the largest integers from a given list using heap queue algorithm:

```python
import heapq

def heap_queue_largest(nums, n):
largest_nums = heapq.nlargest(n, nums)
return largest_nums
```

4. Function to convert more than one list to a nested dictionary:

```python
def convert_list_dictionary(keys, values, scores):
nested_dict = []
for i in range(len(keys)):
temp_dict = {keys[i]: {values[i]: scores[i]}}
nested_dict.append(temp_dict)
return nested_dict
```

Each function should pass the provided tests. Here's how you can test them:

```python
# Test for similar_elements
assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5)
assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4)
assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14)

# Test for is_not_prime
assert is_not_prime(2) == False
assert is_not_prime(10) == True
assert is_not_prime(35) == True

# Test for heap_queue_largest
assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 3) == [85, 75, 65]
assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 2) == [85, 75]
assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 5) == [85, 75, 65, 58, 35]

# Test for convert_list_dictionary
assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92]) == [{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400]) == [{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40]) == [{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
```

If you run these tests, they should all pass without any assertion errors.		 failed
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
wenxinyiyan 'def convert_list_dictionary(keys1, keys2, values):
result = []
for i in range(len(keys1)):
temp_dict = {keys1[i]: {keys2[i]: values[i]}}
result.append(temp_dict)
return result'
[DONE]

Explanation:
The `convert_list_dictionary` function takes three lists as input: `keys1`, `keys2`, and `values`. It creates a nested dictionary for each index of the lists and appends it to the `result` list. The outer dictionary has a key from `keys1` and the inner dictionary has a key from `keys2` with the corresponding value from `values`. Finally, it returns the `result` list containing all the nested dictionaries.

Note: The code assumes that the lengths of `keys1`, `keys2`, and `values` are the same, and it does not include any error handling for cases where the lengths are different. You can add error handling if needed.

Also, the indentation in the provided code snippet is incorrect. I have fixed the indentation in my explanation. Make sure to use correct indentation when writing Python code, as it is crucial for defining the structure of the code.		 failed
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
zhipu To achieve the desired functionality, we need to write a function `convert_list_dictionary` that takes three lists as input and converts them into a nested dictionary. Each element from the first list will be a key in the outer dictionary, each element from the second list will be a key in the inner dictionary, and each element from the third list will be the value in the inner dictionary.

Here is the implementation of the function:

```python
def convert_list_dictionary(keys, inner_keys, values):
result = []
for key, inner_key, value in zip(keys, inner_keys, values):
result.append({key: {inner_key: value}})
return result

# Test cases
assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92]) == [{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400]) == [{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40]) == [{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]

print("All tests passed!")
```

### Explanation:
1. **Function Definition**: The function `convert_list_dictionary` takes three parameters: `keys`, `inner_keys`, and `values`.
2. **Result Initialization**: An empty list `result` is initialized to store the final nested dictionaries.
3. **Loop through Lists**: Using the `zip` function, we iterate through the three lists simultaneously.
4. **Create Nested Dictionary**: For each set of elements from the lists, we create a nested dictionary where the element from `keys` is the outer key, the element from `inner_keys` is the inner key, and the element from `values` is the value.
5. **Append to Result**: The created nested dictionary is appended to the `result` list.
6. **Return Result**: Finally, the `result` list containing all the nested dictionaries is returned.

### Test Cases:
The provided test cases are used to ensure that the function works as expected. If any of the assertions fail, an `AssertionError` will be raised. If all tests pass, the message "All tests passed!" will be printed.

This implementation should meet the requirements and pass the given tests.		 pass
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
gpto1 ```python
'def convert_list_dictionary(list1, list2, list3):
result = []
for k, v, val in zip(list1, list2, list3):
result.append({k: {v: val}})
return result'
```		 failed
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]
deepseekv3 ```python
def convert_list_dictionary(keys, names, values):
nested_dicts = []
for key, name, value in zip(keys, names, values):
nested_dict = {key: {name: value}}
nested_dicts.append(nested_dict)
return nested_dicts


# Test cases
assert convert_list_dictionary(["S001", "S002", "S003", "S004"], ["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"], [85, 98, 89, 92]) == [{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc", "def", "ghi", "jkl"], ["python", "program", "language", "programs"], [100, 200, 300, 400]) == [{'abc': {'python': 100}}, {'def': {'program': 200}}, {'ghi': {'language': 300}}, {'jkl': {'programs': 400}}]
assert convert_list_dictionary(["A1", "A2", "A3", "A4"], ["java", "C", "C++", "DBMS"], [10, 20, 30, 40]) == [{'A1': {'java': 10}}, {'A2': {'C': 20}}, {'A3': {'C++': 30}}, {'A4': {'DBMS': 40}}]

print("All test cases passed!")
```

### Explanation:
1. **Function Definition**: The function `convert_list_dictionary` takes three lists as arguments: `keys`, `names`, and `values`.
2. **List Comprehension**: We use a loop to iterate over the three lists simultaneously using the `zip` function.
3. **Nested Dictionary Construction**: For each iteration, we construct a nested dictionary where the key from the `keys` list maps to another dictionary that maps the name from the `names` list to the corresponding value from the `values` list.
4. **Appending to Result List**: Each nested dictionary is appended to the `nested_dicts` list.
5. **Return Statement**: Finally, the function returns the list of nested dictionaries.

This approach ensures that the function correctly converts the input lists into the desired nested dictionary structure.		 pass
测试用例：assert convert_list_dictionary(["S001", "S002", "S003", "S004"],["Adina Park", "Leyton Marsh", "Duncan Boyle", "Saim Richards"] ,[85, 98, 89, 92])==[{'S001': {'Adina Park': 85}}, {'S002': {'Leyton Marsh': 98}}, {'S003': {'Duncan Boyle': 89}}, {'S004': {'Saim Richards': 92}}]
assert convert_list_dictionary(["abc","def","ghi","jkl"],["python","program","language","programs"],[100,200,300,400])==[{'abc':{'python':100}},{'def':{'program':200}},{'ghi':{'language':300}},{'jkl':{'programs':400}}]
assert convert_list_dictionary(["A1","A2","A3","A4"],["java","C","C++","DBMS"],[10,20,30,40])==[{'A1':{'java':10}},{'A2':{'C':20}},{'A3':{'C++':30}},{'A4':{'DBMS':40}}]