| 模型 | 模型答案 | 测试结果 |
|---|---|---|
| 金声玉亮2.0 | ```python def remove_odd(numbers): return [num for num in numbers if num % 2 == 0] ``` [DONE] |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| deepseekr1 | [BEGIN] def remove_odd(lst): return [num for num in lst if num % 2 == 0] [DONE] |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| gpto1 | ```python def remove_odd(lst): return [x for x in lst if x % 2 == 0] ``` |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| GPT-4o | ```python def remove_odd(nums): return [num for num in nums if num % 2 == 0] # Tests assert remove_odd([1, 2, 3]) == [2] assert remove_odd([2, 4, 6]) == [2, 4, 6] assert remove_odd([10, 20, 3]) == [10, 20] ``` |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| llama3.1-70B-Instruct | def remove_odd(nums): return [num for num in nums if num % 2 == 0] |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| llama3.1-405B-Instruct | def remove_odd(numbers): return [num for num in numbers if num % 2 == 0] |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| DeepSeek-Coder-V2 | ```python def remove_odd(numbers): return [num for num in numbers if num % 2 == 0] ``` [DONE] |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| Qwen2-72B-Instruct | 'def remove_odd(lst): return [num for num in lst if num % 2 == 0]' [DONE] |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| baichuan4 | Here is the Python function to remove odd numbers from a given list: ```python def remove_odd(lst): return [num for num in lst if num % 2 == 0] ``` This function uses list comprehension to iterate through each element in the input list `lst` and includes only the even numbers (i.e., numbers divisible by 2 with no remainder) in the resulting list. Let's run the tests you provided: ```python assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] ``` All tests should pass successfully with this function. |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| doubao | 'def remove_odd(num_list): return [num for num in num_list if num % 2 == 0]' [DONE] |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| minimax | 'def remove_odd(numbers): return [num for num in numbers if num % 2 == 0]' |
failed 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| kimi | ```python def similar_elements(test_tup1, test_tup2): res = tuple(sorted(set(test_tup1) & set(test_tup2))) return res # Test cases assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5) assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4) assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14) def is_not_prime(n): if n <= 1: return True for i in range(2, int(n**0.5) + 1): if n % i == 0: return True return False # Test cases assert is_not_prime(2) == False assert is_not_prime(10) == True assert is_not_prime(35) == True import heapq as hq def heap_queue_largest(nums, n): largest_nums = hq.nlargest(n, nums) return largest_nums # Test cases assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 3) == [85, 75, 65] assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 2) == [85, 75] assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 5) == [85, 75, 65, 58, 35] def remove_odd(nums): return [num for num in nums if num % 2 == 0] # Test cases assert remove_odd([1, 2, 3]) == [2] assert remove_odd([2, 4, 6]) == [2, 4, 6] assert remove_odd([10, 20, 3]) == [10, 20] ``` The above code snippets define the functions `similar_elements`, `is_not_prime`, `heap_queue_largest`, and `remove_odd`. Each function is followed by test cases that validate the correctness of the function. |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| wenxinyiyan | 'def remove_odd(lst): return [num for num in lst if num % 2 == 0]' [DONE] Explanation: The `remove_odd` function takes a list `lst` as input and returns a new list containing only the even numbers from the original list. It uses a list comprehension to iterate over each element `num` in `lst` and checks if `num` is divisible by 2 (i.e., `num % 2 == 0`). If it is, then `num` is added to the new list. Finally, the new list is returned. Note: The code snippets provided in the question already include the correct solutions for finding similar elements from two tuple lists, identifying non-prime numbers, finding the largest integers from a list using a heap queue algorithm, and removing odd numbers from a list. The explanations above are provided for clarity and understanding of the solutions. Additionally, there is a minor typo in the `similar_elements` function provided. The returned value should not be wrapped in an additional tuple, as `res` is already a tuple. Here's the corrected version: ```python def similar_elements(test_tup1, test_tup2): res = tuple(set(test_tup1) & set(test_tup2)) return res ``` This ensures that the function returns a tuple of similar elements from the two input tuples. |
failed 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| zhipu | Here's a Python function that removes odd numbers from a given list and should pass the provided tests: ```python def remove_odd(numbers): return [num for num in numbers if num % 2 == 0] # Test cases assert remove_odd([1, 2, 3]) == [2] assert remove_odd([2, 4, 6]) == [2, 4, 6] assert remove_odd([10, 20, 3]) == [10, 20] ``` Explanation: - The function `remove_odd` takes a list of numbers as input. - It uses a list comprehension to iterate over each number in the input list and includes it in the output list if the number is even (i.e., `num % 2 == 0`). - The test cases verify that the function correctly removes odd numbers from the list. This code should work as expected and pass the given assertions. |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| gpto1 | ```python def remove_odd(lst): return [x for x in lst if x % 2 == 0] ``` |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |
| deepseekv3 | Here is the Python function to remove odd numbers from a given list: ```python def remove_odd(numbers): return [num for num in numbers if num % 2 == 0] ``` ### Explanation: - The function `remove_odd` takes a list of numbers as input. - It uses a list comprehension to iterate over each number in the list. - The condition `num % 2 == 0` checks if the number is even. - Only the even numbers are included in the new list that is returned. ### Tests: 1. `assert remove_odd([1,2,3]) == [2]` → The odd numbers `1` and `3` are removed, leaving `[2]`. 2. `assert remove_odd([2,4,6]) == [2,4,6]` → All numbers are even, so the list remains unchanged. 3. `assert remove_odd([10,20,3]) == [10,20]` → The odd number `3` is removed, leaving `[10, 20]`. |
pass 测试用例：assert remove_odd([1,2,3]) == [2] assert remove_odd([2,4,6]) == [2,4,6] assert remove_odd([10,20,3]) == [10,20] |