| 模型 | 模型答案 | 测试结果 |
|---|---|---|
| 金声玉亮2.0 | ```python def filter_oddnumbers(numbers): return list(filter(lambda x: x % 2 != 0, numbers)) ``` [DONE] |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| deepseekr1 | To solve this problem, we need to write a Python function that filters out odd numbers from a given list using a lambda function. The solution should efficiently check each number in the list and return a new list containing only the odd numbers. ### Approach 1. **Understanding Odd Numbers**: An odd number is any integer that is not divisible by 2. This can be checked using the modulus operator `%`, where a number `x` is odd if `x % 2 != 0`. 2. **Lambda Function**: We will use a lambda function to define the condition for filtering odd numbers. This lambda function will be used as the predicate for the `filter` function. 3. **Filter Function**: The `filter` function in Python applies the lambda function to each element of the list, returning an iterator that includes only the elements for which the lambda function returns `True`. 4. **Conversion to List**: Since the `filter` function returns an iterator, we convert the result to a list to get the final output. ### Solution Code ```python def filter_oddnumbers(numbers): return list(filter(lambda x: x % 2 != 0, numbers)) ``` ### Explanation - **Lambda Function**: The lambda function `lambda x: x % 2 != 0` checks if a number `x` is odd. If `x` modulo 2 is not zero, the function returns `True`, indicating that `x` should be included in the result. - **Filter Application**: The `filter` function processes each element of the input list with the lambda function. It efficiently iterates through the list and applies the condition. - **Conversion**: The result from `filter` is an iterator, so we convert it to a list using `list()` to get the final list of odd numbers. This approach ensures that we efficiently filter out the odd numbers using a concise and readable implementation, leveraging Python's built-in functions for clarity and performance. |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| gpto1 | ```python def filter_oddnumbers(nums): return list(filter(lambda x: x % 2 != 0, nums)) ``` |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| GPT-4o | Sure, here's the function to filter odd numbers using a lambda function: ```python def filter_oddnumbers(numbers): return list(filter(lambda x: x % 2 != 0, numbers)) # Tests assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9] assert filter_oddnumbers([10, 20, 45, 67, 84, 93]) == [45, 67, 93] assert filter_oddnumbers([5, 7, 9, 8, 6, 4, 3]) == [5, 7, 9, 3] ``` This function uses the `filter` function along with a lambda function to filter out odd numbers from the given list. The lambda function checks if a number is odd by using the modulus operator (`%`). If the number is odd (i.e., `x % 2 != 0`), it is included in the filtered list. The `filter` function returns an iterator, so we convert it to a list before returning the result. |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| llama3.1-70B-Instruct | def filter_oddnumbers(numbers): return list(filter(lambda x: x % 2 != 0, numbers)) |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| llama3.1-405B-Instruct | def filter_oddnumbers(numbers): return list(filter(lambda x: x % 2 != 0, numbers)) |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| DeepSeek-Coder-V2 | ```python def filter_oddnumbers(numbers): return list(filter(lambda x: x % 2 != 0, numbers)) ``` [DONE] |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| Qwen2-72B-Instruct | 'filter_oddnumbers = lambda nums: list(filter(lambda x: x % 2 != 0, nums))' [DONE] |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| baichuan4 | To filter odd numbers using a lambda function in Python, you can use the `filter()` function along with a lambda expression. Here's the function that does that: ```python def filter_oddnumbers(numbers): return list(filter(lambda x: x % 2 != 0, numbers)) ``` This function takes a list of numbers as input and returns a new list containing only the odd numbers from the original list. The `filter()` function is used to filter out the even numbers, and the lambda function `lambda x: x % 2 != 0` checks if a number is odd by verifying that the remainder of dividing the number by 2 is not zero. Let's test the function with the provided test cases: ```python assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9] assert filter_oddnumbers([10, 20, 45, 67, 84, 93]) == [45, 67, 93] assert filter_oddnumbers([5, 7, 9, 8, 6, 4, 3]) == [5, 7, 9, 3] ``` If you run this code, no assertion errors will be raised, indicating that the function passes all the tests. |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| doubao | 'filter_oddnumbers = lambda nums: [num for num in nums if num % 2!= 0]' [DONE] |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| minimax | ```python def filter_oddnumbers(numbers): return list(filter(lambda x: x % 2 != 0, numbers)) # Test cases assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9] assert filter_oddnumbers([10, 20, 45, 67, 84, 93]) == [45, 67, 93] assert filter_oddnumbers([5, 7, 9, 8, 6, 4, 3]) == [5, 7, 9, 3] ``` The function `filter_oddnumbers` uses a lambda function to filter out the odd numbers from the given list. The lambda function checks if a number is odd by using the modulo operator `%`. If the number is odd (i.e., `x % 2 != 0`), it is included in the resulting list. The `filter` function returns an iterator, so we convert it to a list before returning it. The provided test cases should pass with this implementation. |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| kimi | Here's the Python code for each of the tasks: 1. Function to find similar elements from two tuple lists: ```python def similar_elements(test_tup1, test_tup2): res = tuple(sorted(set(test_tup1) & set(test_tup2))) return res ``` 2. Function to identify non-prime numbers: ```python import math def is_not_prime(n): if n <= 1: return True for i in range(2, int(math.sqrt(n)) + 1): if n % i == 0: return True return False ``` 3. Function to find the largest integers from a given list using heap queue algorithm: ```python import heapq def heap_queue_largest(nums, n): largest_nums = heapq.nlargest(n, nums) return largest_nums ``` 4. Function to filter odd numbers using a lambda function: ```python def filter_oddnumbers(numbers): return list(filter(lambda x: x % 2 != 0, numbers)) ``` Now, let's make sure the functions pass the provided tests: ```python # Test for similar_elements function assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5) assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4) assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14) # Test for is_not_prime function assert is_not_prime(2) == False assert is_not_prime(10) == True assert is_not_prime(35) == True # Test for heap_queue_largest function assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 3) == [85, 75, 65] assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 2) == [85, 75] assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 5) == [85, 75, 65, 58, 35] # Test for filter_oddnumbers function assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9] assert filter_oddnumbers([10, 20, 45, 67, 84, 93]) == [45, 67, 93] assert filter_oddnumbers([5, 7, 9, 8, 6, 4, 3]) == [5, 7, 9, 3] ``` If you run the above tests, they should all pass without any assertion errors. |
failed 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| wenxinyiyan | 'def filter_oddnumbers(lst): return list(filter(lambda x: x % 2 != 0, lst))' [DONE] Explanation: The `filter_oddnumbers` function takes a list `lst` as input. It uses the `filter` function from Python's built-in functions, along with a lambda function, to filter out the odd numbers from the list. The lambda function `lambda x: x % 2 != 0` takes an element `x` from the list and checks if it is odd by computing `x % 2 != 0`. If the remainder of `x` divided by 2 is not equal to 0, it means `x` is an odd number. The `filter` function applies the lambda function to each element of the list `lst` and returns an iterator containing only the elements that satisfy the condition (i.e., the odd numbers). Finally, the iterator is converted to a list using the `list()` function and returned as the output of the `filter_oddnumbers` function. |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| zhipu | To achieve the task of filtering odd numbers using a lambda function, you can use the `filter` function in Python, which takes a function and an iterable as arguments. The lambda function will be used to check if each number in the list is odd. Here's the code that accomplishes this: ```python def filter_oddnumbers(numbers): return list(filter(lambda x: x % 2 != 0, numbers)) # Test cases assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9] assert filter_oddnumbers([10, 20, 45, 67, 84, 93]) == [45, 67, 93] assert filter_oddnumbers([5, 7, 9, 8, 6, 4, 3]) == [5, 7, 9, 3] ``` Explanation: 1. The `filter_oddnumbers` function takes a list of numbers as input. 2. The `filter` function is used with a lambda function `lambda x: x % 2 != 0` to filter out the odd numbers. The lambda function returns `True` for odd numbers and `False` for even numbers. 3. The `filter` function returns a filter object, which is then converted to a list using `list()`. 4. The function returns the list of odd numbers. This code should pass the provided test cases. |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| gpto1 | ```python def filter_oddnumbers(nums): return list(filter(lambda x: x % 2 != 0, nums)) ``` |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |
| deepseekv3 | ```python def filter_oddnumbers(numbers): return list(filter(lambda x: x % 2 != 0, numbers)) ``` ### Explanation: - **Lambda Function**: The lambda function `lambda x: x % 2 != 0` is used to check if a number is odd. It returns `True` if the number is odd and `False` otherwise. - **Filter Function**: The `filter()` function applies the lambda function to each element in the `numbers` list and returns an iterator that includes only those elements for which the lambda function returns `True`. - **List Conversion**: The `list()` function is used to convert the iterator returned by `filter()` into a list. ### Example Usage: ```python print(filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])) # Output: [1, 3, 5, 7, 9] print(filter_oddnumbers([10, 20, 45, 67, 84, 93])) # Output: [45, 67, 93] print(filter_oddnumbers([5, 7, 9, 8, 6, 4, 3])) # Output: [5, 7, 9, 3] ``` This function will correctly filter out and return the odd numbers from the given lists, passing all the provided test cases. |
pass 测试用例：assert filter_oddnumbers([1, 2, 3, 4, 5, 6, 7, 8, 9, 10])==[1,3,5,7,9] assert filter_oddnumbers([10,20,45,67,84,93])==[45,67,93] assert filter_oddnumbers([5,7,9,8,6,4,3])==[5,7,9,3] |