金声玉亮2.0模型评测报告

问题

You are an expert Python programmer, and here is your task: Write a function to find the similar elements from the given two tuple lists. Your code should pass these tests:

assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5)
assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4)
assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14)

[BEGIN]
'def similar_elements(test_tup1, test_tup2):
res = tuple(set(test_tup1) & set(test_tup2))
return (res)'
[DONE]

You are an expert Python programmer, and here is your task: Write a python function to identify non-prime numbers. Your code should pass these tests:

assert is_not_prime(2) == False
assert is_not_prime(10) == True
assert is_not_prime(35) == True

[BEGIN]
'import math
def is_not_prime(n):
result = False
for i in range(2,int(math.sqrt(n)) + 1):
if n % i == 0:
result = True
return result'
[DONE]

You are an expert Python programmer, and here is your task: Write a function to find the largest integers from a given list of numbers using heap queue algorithm. Your code should pass these tests:

assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],3)==[85, 75, 65]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],2)==[85, 75]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],5)==[85, 75, 65, 58, 35]

[BEGIN]
'import heapq as hq
def heap_queue_largest(nums,n):
largest_nums = hq.nlargest(n, nums)
return largest_nums'
[DONE]

You are an expert Python programmer, and here is your task: Write a function to perform index wise multiplication of tuple elements in the given two tuples. Your code should pass these tests:

assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30))
assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44))
assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))

[BEGIN]

答案

模型	模型答案	测试结果
金声玉亮2.0	```python def index_multiplication(tuple1, tuple2): return tuple((a * b for a, b in zip(sub1, sub2)) for sub1, sub2 in zip(tuple1, tuple2)) ``` [DONE]	wrong_answer 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
deepseekr1	To solve this problem, we need to write a function that performs index-wise multiplication of elements in corresponding tuples from two given tuples of tuples. The result should be a new tuple of tuples where each element is the product of the elements at the same positions in the input tuples. ### Approach 1. Iterate Through Tuples: Use the `zip` function to pair each tuple from the first input tuple with the corresponding tuple from the second input tuple. 2. Element-wise Multiplication: For each pair of tuples, multiply the elements at the same indices. This is done using another `zip` to pair elements from the two tuples and a generator expression to compute the products. 3. Construct Result: Collect all the resulting tuples from the element-wise multiplication into a list and convert this list into a tuple before returning it. ### Solution Code ```python def index_multiplication(tup1, tup2): return tuple(tuple(x * y for x, y in zip(a, b)) for a, b in zip(tup1, tup2)) ``` ### Explanation - Pairing Tuples: The outer `zip(tup1, tup2)` pairs each tuple from `tup1` with the corresponding tuple from `tup2`. - Element-wise Multiplication: For each pair of tuples `(a, b)`, the inner `zip(a, b)` pairs elements from `a` and `b`, and the generator expression `(x * y for x, y in ...)` computes the product of each pair of elements. - Result Construction: The results of the element-wise multiplications are collected into tuples, and all these tuples are combined into a final tuple which is returned as the result. This approach efficiently processes each element exactly once, resulting in a time complexity of O(n*m), where n is the number of tuples and m is the number of elements in each tuple. This ensures the solution is both optimal and easy to understand.	pass 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
gpto1	```python def index_multiplication(tuple1, tuple2): result = tuple((a[0] * b[0], a[1] * b[1]) for a, b in zip(tuple1, tuple2)) return result ```	pass 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
GPT-4o	Sure, here is the function to perform index-wise multiplication of tuple elements in the given two tuples: ```python def index_multiplication(tup1, tup2): result = tuple((a * c, b * d) for (a, b), (c, d) in zip(tup1, tup2)) return result # Test cases assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)), ((6, 7), (3, 9), (1, 1), (7, 3))) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)), ((7, 8), (4, 10), (2, 2), (8, 4))) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)), ((8, 9), (5, 11), (3, 3), (9, 5))) == ((24, 45), (30, 77), (12, 33), (27, 60)) print("All tests passed.") ``` Explanation: - The function `index_multiplication` takes two tuples of tuples `tup1` and `tup2`. - It uses a list comprehension to iterate over pairs of tuples from `tup1` and `tup2` simultaneously (using `zip`). - For each pair of tuples `(a, b)` from `tup1` and `(c, d)` from `tup2`, it computes the product of the first elements (`a * c`) and the product of the second elements (`b * d`). - The results are collected into a new tuple and returned. This code will pass the provided test cases.	pass 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
llama3.1-70B-Instruct	def index_multiplication(tup1, tup2): return tuple((a * b, c * d) for (a, c), (b, d) in zip(tup1, tup2))	pass 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
llama3.1-405B-Instruct	def index_multiplication(tup1, tup2): return tuple((a * c, b * d) for (a, b), (c, d) in zip(tup1, tup2))	pass 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
DeepSeek-Coder-V2	```python def index_multiplication(tuple1, tuple2): return tuple((a * b for a, b in zip(sub1, sub2)) for sub1, sub2 in zip(tuple1, tuple2)) ``` [DONE]	wrong_answer 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
Qwen2-72B-Instruct	'def index_multiplication(tup1, tup2): return tuple((ab, cd) for (a, c), (b, d) in zip(tup1, tup2))' # Test cases assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60)) The function `index_multiplication` takes two tuples of tuples as input. It uses the `zip` function to iterate over corresponding elements of the two tuples simultaneously. For each pair of elements, it multiplies the corresponding values and returns a new tuple with the results.	failed 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
baichuan4	To perform index-wise multiplication of tuple elements in two given tuples, you can use the following function: ```python def index_multiplication(tuple1, tuple2): result = tuple((a * b for a, b in zip(t1, t2))) return result ``` This function takes two tuples as input, iterates through them using the `zip` function to pair up corresponding elements, multiplies each pair of elements together, and finally constructs a new tuple with the results. Let's test it with the provided test cases: ```python assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)), ((6, 7), (3, 9), (1, 1), (7, 3))) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)), ((7, 8), (4, 10), (2, 2), (8, 4))) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)), ((8, 9), (5, 11), (3, 3), (9, 5))) == ((24, 45), (30, 77), (12, 33), (27, 60)) ``` The function should pass these tests successfully.	failed 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
doubao	'def index_multiplication(tup1, tup2): result = [] for i in range(len(tup1)): result.append((tup1[i][0] * tup2[i][0], tup1[i][1] * tup2[i][1])) return tuple(result)' [DONE]	pass 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
minimax	```python def index_multiplication(tup1, tup2): return tuple(tuple(a * b for a, b in zip(t1, t2)) for t1, t2 in zip(tup1, tup2)) # Test cases assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)), ((6, 7), (3, 9), (1, 1), (7, 3))) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)), ((7, 8), (4, 10), (2, 2), (8, 4))) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)), ((8, 9), (5, 11), (3, 3), (9, 5))) == ((24, 45), (30, 77), (12, 33), (27, 60)) ``` This function `index_multiplication` takes two tuples of tuples as input and returns a new tuple of tuples where each element is the product of the corresponding elements from the input tuples. The test cases check that the function works as expected.	pass 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
kimi	Here's the Python code for each task: 1. Function to find similar elements from two tuple lists: ```python def similar_elements(test_tup1, test_tup2): res = tuple(sorted(set(test_tup1) & set(test_tup2))) return res ``` 2. Function to identify non-prime numbers: ```python import math def is_not_prime(n): if n <= 1: return True for i in range(2, int(math.sqrt(n)) + 1): if n % i == 0: return True return False ``` 3. Function to find the largest integers from a given list of numbers using heap queue algorithm: ```python import heapq def heap_queue_largest(nums, n): largest_nums = heapq.nlargest(n, nums) return largest_nums ``` 4. Function to perform index wise multiplication of tuple elements in the given two tuples: ```python def index_multiplication(tup1, tup2): return tuple((a * b for a, b in zip(tup1, tup2))) ``` Each function should pass the provided tests.	failed 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
wenxinyiyan	Here's the code for the `index_multiplication` function that performs index-wise multiplication of tuple elements in the given two tuples: ```python def index_multiplication(tuple1, tuple2): result = [] for t1, t2 in zip(tuple1, tuple2): multiplied = tuple(a * b for a, b in zip(t1, t2)) result.append(multiplied) return tuple(result) ``` This function iterates over the tuples in `tuple1` and `tuple2` using the `zip` function, which pairs corresponding elements from both tuples. For each pair of tuples `(t1, t2)`, it performs element-wise multiplication using a generator expression `(a * b for a, b in zip(t1, t2))` and converts the result to a tuple. The multiplied tuples are then appended to the `result` list. Finally, the `result` list is converted to a tuple and returned as the output. Now let's test the function with the provided test cases: ```python assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)), ((6, 7), (3, 9), (1, 1), (7, 3))) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)), ((7, 8), (4, 10), (2, 2), (8, 4))) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)), ((8, 9), (5, 11), (3, 3), (9, 5))) == ((24, 45), (30, 77), (12, 33), (27, 60)) ``` All the tests should pass, indicating that the function works correctly.	pass 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
zhipu	To perform index-wise multiplication of tuple elements in the given two tuples, we can iterate through the tuples and multiply corresponding elements. Here's the function that accomplishes this: ```python def index_multiplication(tup1, tup2): # Ensure both tuples have the same length if len(tup1) != len(tup2): raise ValueError("Both tuples must have the same length") # Perform index-wise multiplication result = tuple((a * b for a, b in zip(tup1[i], tup2[i])) for i in range(len(tup1))) return result # Test cases assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)), ((6, 7), (3, 9), (1, 1), (7, 3))) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)), ((7, 8), (4, 10), (2, 2), (8, 4))) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)), ((8, 9), (5, 11), (3, 3), (9, 5))) == ((24, 45), (30, 77), (12, 33), (27, 60)) print("All tests passed!") ``` ### Explanation: 1. Input Validation: The function first checks if both input tuples have the same length. If not, it raises a `ValueError`. 2. Index-wise Multiplication: The function uses a nested comprehension to iterate over the indices and elements of the tuples. The `zip` function is used to pair corresponding elements from the sub-tuples, and these pairs are multiplied. 3. Result Construction: The result is constructed as a tuple of tuples, where each inner tuple contains the products of the corresponding elements from the input tuples. This function should pass the provided test cases, ensuring that the index-wise multiplication is correctly implemented.	wrong_answer 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
gpto1	```python def index_multiplication(tuple1, tuple2): result = tuple((a[0] * b[0], a[1] * b[1]) for a, b in zip(tuple1, tuple2)) return result ```	pass 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))
deepseekv3	To solve the problem of performing index-wise multiplication of tuple elements in two given tuples, we can write a Python function that iterates through each pair of tuples and multiplies their corresponding elements. Here's the implementation: ```python def index_multiplication(tup1, tup2): result = [] for t1, t2 in zip(tup1, tup2): multiplied_tuple = tuple(a * b for a, b in zip(t1, t2)) result.append(multiplied_tuple) return tuple(result) # Test cases assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)), ((6, 7), (3, 9), (1, 1), (7, 3))) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)), ((7, 8), (4, 10), (2, 2), (8, 4))) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)), ((8, 9), (5, 11), (3, 3), (9, 5))) == ((24, 45), (30, 77), (12, 33), (27, 60)) print("All test cases passed!") ``` ### Explanation: 1. Function Definition: The function `index_multiplication` takes two tuples `tup1` and `tup2` as input. 2. Iteration and Multiplication: It iterates through each pair of tuples using `zip(tup1, tup2)`. For each pair of tuples, it multiplies the corresponding elements using a list comprehension. 3. Result Construction: The multiplied elements are converted back into a tuple and appended to the result list. 4. Return Result: Finally, the result list is converted into a tuple and returned. ### Test Cases: The provided test cases ensure that the function works correctly by comparing the output of the function with the expected results. This approach ensures that the function is both efficient and easy to understand, leveraging Python's capabilities for handling tuples and list comprehensions.	pass 测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30)) assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44)) assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))

模型

模型答案

测试结果

金声玉亮2.0

```python
def index_multiplication(tuple1, tuple2):
return tuple((a * b for a, b in zip(sub1, sub2)) for sub1, sub2 in zip(tuple1, tuple2))
```
[DONE]

wrong_answer
测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30))
assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44))
assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))

deepseekr1

To solve this problem, we need to write a function that performs index-wise multiplication of elements in corresponding tuples from two given tuples of tuples. The result should be a new tuple of tuples where each element is the product of the elements at the same positions in the input tuples.

### Approach
1. **Iterate Through Tuples**: Use the `zip` function to pair each tuple from the first input tuple with the corresponding tuple from the second input tuple.
2. **Element-wise Multiplication**: For each pair of tuples, multiply the elements at the same indices. This is done using another `zip` to pair elements from the two tuples and a generator expression to compute the products.
3. **Construct Result**: Collect all the resulting tuples from the element-wise multiplication into a list and convert this list into a tuple before returning it.

### Solution Code

```python
def index_multiplication(tup1, tup2):
return tuple(tuple(x * y for x, y in zip(a, b)) for a, b in zip(tup1, tup2))
```

### Explanation
- **Pairing Tuples**: The outer `zip(tup1, tup2)` pairs each tuple from `tup1` with the corresponding tuple from `tup2`.
- **Element-wise Multiplication**: For each pair of tuples `(a, b)`, the inner `zip(a, b)` pairs elements from `a` and `b`, and the generator expression `(x * y for x, y in ...)` computes the product of each pair of elements.
- **Result Construction**: The results of the element-wise multiplications are collected into tuples, and all these tuples are combined into a final tuple which is returned as the result.

This approach efficiently processes each element exactly once, resulting in a time complexity of O(n*m), where n is the number of tuples and m is the number of elements in each tuple. This ensures the solution is both optimal and easy to understand.

pass
测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30))
assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44))
assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))

gpto1

```python
def index_multiplication(tuple1, tuple2):
result = tuple((a[0] * b[0], a[1] * b[1]) for a, b in zip(tuple1, tuple2))
return result
```

GPT-4o

Sure, here is the function to perform index-wise multiplication of tuple elements in the given two tuples:

```python
def index_multiplication(tup1, tup2):
result = tuple((a * c, b * d) for (a, b), (c, d) in zip(tup1, tup2))
return result

# Test cases
assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)), ((6, 7), (3, 9), (1, 1), (7, 3))) == ((6, 21), (12, 45), (2, 9), (7, 30))
assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)), ((7, 8), (4, 10), (2, 2), (8, 4))) == ((14, 32), (20, 60), (6, 20), (16, 44))
assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)), ((8, 9), (5, 11), (3, 3), (9, 5))) == ((24, 45), (30, 77), (12, 33), (27, 60))

print("All tests passed.")
```

Explanation:
- The function `index_multiplication` takes two tuples of tuples `tup1` and `tup2`.
- It uses a list comprehension to iterate over pairs of tuples from `tup1` and `tup2` simultaneously (using `zip`).
- For each pair of tuples `(a, b)` from `tup1` and `(c, d)` from `tup2`, it computes the product of the first elements (`a * c`) and the product of the second elements (`b * d`).
- The results are collected into a new tuple and returned.

This code will pass the provided test cases.

llama3.1-70B-Instruct

def index_multiplication(tup1, tup2):
return tuple((a * b, c * d) for (a, c), (b, d) in zip(tup1, tup2))

llama3.1-405B-Instruct

def index_multiplication(tup1, tup2):
return tuple((a * c, b * d) for (a, b), (c, d) in zip(tup1, tup2))

DeepSeek-Coder-V2

```python
def index_multiplication(tuple1, tuple2):
return tuple((a * b for a, b in zip(sub1, sub2)) for sub1, sub2 in zip(tuple1, tuple2))
```
[DONE]

Qwen2-72B-Instruct

'def index_multiplication(tup1, tup2):
return tuple((a*b, c*d) for (a, c), (b, d) in zip(tup1, tup2))'

# Test cases
assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30))
assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44))
assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))

The function `index_multiplication` takes two tuples of tuples as input. It uses the `zip` function to iterate over corresponding elements of the two tuples simultaneously. For each pair of elements, it multiplies the corresponding values and returns a new tuple with the results.

failed
测试用例：assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)),((6, 7), (3, 9), (1, 1), (7, 3)) ) == ((6, 21), (12, 45), (2, 9), (7, 30))
assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)),((7, 8), (4, 10), (2, 2), (8, 4)) ) == ((14, 32), (20, 60), (6, 20), (16, 44))
assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)),((8, 9), (5, 11), (3, 3), (9, 5)) ) == ((24, 45), (30, 77), (12, 33), (27, 60))

baichuan4

To perform index-wise multiplication of tuple elements in two given tuples, you can use the following function:

```python
def index_multiplication(tuple1, tuple2):
result = tuple((a * b for a, b in zip(t1, t2)))
return result
```

This function takes two tuples as input, iterates through them using the `zip` function to pair up corresponding elements, multiplies each pair of elements together, and finally constructs a new tuple with the results.

Let's test it with the provided test cases:

```python
assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)), ((6, 7), (3, 9), (1, 1), (7, 3))) == ((6, 21), (12, 45), (2, 9), (7, 30))
assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)), ((7, 8), (4, 10), (2, 2), (8, 4))) == ((14, 32), (20, 60), (6, 20), (16, 44))
assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)), ((8, 9), (5, 11), (3, 3), (9, 5))) == ((24, 45), (30, 77), (12, 33), (27, 60))
```

The function should pass these tests successfully.

doubao

'def index_multiplication(tup1, tup2):
result = []
for i in range(len(tup1)):
result.append((tup1[i][0] * tup2[i][0], tup1[i][1] * tup2[i][1]))
return tuple(result)'
[DONE]

minimax

```python
def index_multiplication(tup1, tup2):
return tuple(tuple(a * b for a, b in zip(t1, t2)) for t1, t2 in zip(tup1, tup2))

# Test cases
assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)), ((6, 7), (3, 9), (1, 1), (7, 3))) == ((6, 21), (12, 45), (2, 9), (7, 30))
assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)), ((7, 8), (4, 10), (2, 2), (8, 4))) == ((14, 32), (20, 60), (6, 20), (16, 44))
assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)), ((8, 9), (5, 11), (3, 3), (9, 5))) == ((24, 45), (30, 77), (12, 33), (27, 60))
```

This function `index_multiplication` takes two tuples of tuples as input and returns a new tuple of tuples where each element is the product of the corresponding elements from the input tuples. The test cases check that the function works as expected.

kimi

Here's the Python code for each task:

1. Function to find similar elements from two tuple lists:

```python
def similar_elements(test_tup1, test_tup2):
res = tuple(sorted(set(test_tup1) & set(test_tup2)))
return res
```

2. Function to identify non-prime numbers:

```python
import math

def is_not_prime(n):
if n <= 1:
return True
for i in range(2, int(math.sqrt(n)) + 1):
if n % i == 0:
return True
return False
```

3. Function to find the largest integers from a given list of numbers using heap queue algorithm:

```python
import heapq

def heap_queue_largest(nums, n):
largest_nums = heapq.nlargest(n, nums)
return largest_nums
```

4. Function to perform index wise multiplication of tuple elements in the given two tuples:

```python
def index_multiplication(tup1, tup2):
return tuple((a * b for a, b in zip(tup1, tup2)))
```

Each function should pass the provided tests.

wenxinyiyan

Here's the code for the `index_multiplication` function that performs index-wise multiplication of tuple elements in the given two tuples:

```python
def index_multiplication(tuple1, tuple2):
result = []
for t1, t2 in zip(tuple1, tuple2):
multiplied = tuple(a * b for a, b in zip(t1, t2))
result.append(multiplied)
return tuple(result)
```
This function iterates over the tuples in `tuple1` and `tuple2` using the `zip` function, which pairs corresponding elements from both tuples. For each pair of tuples `(t1, t2)`, it performs element-wise multiplication using a generator expression `(a * b for a, b in zip(t1, t2))` and converts the result to a tuple. The multiplied tuples are then appended to the `result` list. Finally, the `result` list is converted to a tuple and returned as the output.

Now let's test the function with the provided test cases:

```python
assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)), ((6, 7), (3, 9), (1, 1), (7, 3))) == ((6, 21), (12, 45), (2, 9), (7, 30))
assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)), ((7, 8), (4, 10), (2, 2), (8, 4))) == ((14, 32), (20, 60), (6, 20), (16, 44))
assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)), ((8, 9), (5, 11), (3, 3), (9, 5))) == ((24, 45), (30, 77), (12, 33), (27, 60))
```
All the tests should pass, indicating that the function works correctly.

zhipu

To perform index-wise multiplication of tuple elements in the given two tuples, we can iterate through the tuples and multiply corresponding elements. Here's the function that accomplishes this:

```python
def index_multiplication(tup1, tup2):
# Ensure both tuples have the same length
if len(tup1) != len(tup2):
raise ValueError("Both tuples must have the same length")

# Perform index-wise multiplication
result = tuple((a * b for a, b in zip(tup1[i], tup2[i])) for i in range(len(tup1)))
return result

# Test cases
assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)), ((6, 7), (3, 9), (1, 1), (7, 3))) == ((6, 21), (12, 45), (2, 9), (7, 30))
assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)), ((7, 8), (4, 10), (2, 2), (8, 4))) == ((14, 32), (20, 60), (6, 20), (16, 44))
assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)), ((8, 9), (5, 11), (3, 3), (9, 5))) == ((24, 45), (30, 77), (12, 33), (27, 60))

print("All tests passed!")
```

### Explanation:
1. **Input Validation**: The function first checks if both input tuples have the same length. If not, it raises a `ValueError`.
2. **Index-wise Multiplication**: The function uses a nested comprehension to iterate over the indices and elements of the tuples. The `zip` function is used to pair corresponding elements from the sub-tuples, and these pairs are multiplied.
3. **Result Construction**: The result is constructed as a tuple of tuples, where each inner tuple contains the products of the corresponding elements from the input tuples.

This function should pass the provided test cases, ensuring that the index-wise multiplication is correctly implemented.

gpto1

```python
def index_multiplication(tuple1, tuple2):
result = tuple((a[0] * b[0], a[1] * b[1]) for a, b in zip(tuple1, tuple2))
return result
```

deepseekv3

To solve the problem of performing index-wise multiplication of tuple elements in two given tuples, we can write a Python function that iterates through each pair of tuples and multiplies their corresponding elements. Here's the implementation:

```python
def index_multiplication(tup1, tup2):
result = []
for t1, t2 in zip(tup1, tup2):
multiplied_tuple = tuple(a * b for a, b in zip(t1, t2))
result.append(multiplied_tuple)
return tuple(result)

# Test cases
assert index_multiplication(((1, 3), (4, 5), (2, 9), (1, 10)), ((6, 7), (3, 9), (1, 1), (7, 3))) == ((6, 21), (12, 45), (2, 9), (7, 30))
assert index_multiplication(((2, 4), (5, 6), (3, 10), (2, 11)), ((7, 8), (4, 10), (2, 2), (8, 4))) == ((14, 32), (20, 60), (6, 20), (16, 44))
assert index_multiplication(((3, 5), (6, 7), (4, 11), (3, 12)), ((8, 9), (5, 11), (3, 3), (9, 5))) == ((24, 45), (30, 77), (12, 33), (27, 60))

print("All test cases passed!")
```

### Explanation:
1. **Function Definition**: The function `index_multiplication` takes two tuples `tup1` and `tup2` as input.
2. **Iteration and Multiplication**: It iterates through each pair of tuples using `zip(tup1, tup2)`. For each pair of tuples, it multiplies the corresponding elements using a list comprehension.
3. **Result Construction**: The multiplied elements are converted back into a tuple and appended to the result list.
4. **Return Result**: Finally, the result list is converted into a tuple and returned.

### Test Cases:
The provided test cases ensure that the function works correctly by comparing the output of the function with the expected results.

This approach ensures that the function is both efficient and easy to understand, leveraging Python's capabilities for handling tuples and list comprehensions.