| 模型 | 模型答案 | 测试结果 |
|---|---|---|
| 金声玉亮2.0 | ```python import re def match(s): pattern = r'[A-Z][a-z]+' if re.search(pattern, s): return 'Yes' else: return 'No' ``` [DONE] |
pass 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| deepseekr1 | [BEGIN] import re def match(text): if re.search(r'[A-Z][a-z]+', text): return 'Yes' else: return 'No' [DONE] |
pass 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| gpto1 | 'import re def match(string): pattern = r"[A-Z][a-z]+" if re.search(pattern, string): return "Yes" else: return "No"' |
failed 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| GPT-4o | ```python import re def match(text): # Define the regex pattern pattern = r'[A-Z][a-z]+' # Search for the pattern in the text if re.search(pattern, text): return 'Yes' else: return 'No' ``` This function uses a regular expression to check for sequences of one uppercase letter followed by one or more lowercase letters in the given string. The `re.search` function is used to search for the pattern in the text. If the pattern is found, it returns 'Yes', otherwise it returns 'No'. Let's ensure it passes the provided tests: ```python assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' ``` |
pass 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| llama3.1-70B-Instruct | import re def match(s): if re.search(r'[A-Z][a-z]+', s): return 'Yes' else: return 'No' |
pass 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| llama3.1-405B-Instruct | import re def match(string): pattern = r'[A-Z][a-z]+' if re.search(pattern, string): return 'Yes' else: return 'No' |
pass 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| DeepSeek-Coder-V2 | ```python import re def match(s): pattern = r'[A-Z][a-z]+' if re.search(pattern, s): return 'Yes' else: return 'No' ``` [DONE] |
pass 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| Qwen2-72B-Instruct | 'reimport re def match(s): if re.search(r"[A-Z][a-z]*", s): return "Yes" else: return "No"' [DONE] |
failed 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| baichuan4 | To find sequences of one upper case letter followed by lower case letters in a given string using regex, you can use the following function: ```python import re def match(s): pattern = r'[A-Z][a-z]+' if re.search(pattern, s): return 'Yes' else: return 'No' ``` This function defines a regex pattern that matches one upper case letter ([A-Z]) followed by one or more lower case letters ([a-z]+). The `re.search()` function is then used to search for this pattern in the given string `s`. If a match is found, the function returns 'Yes', otherwise it returns 'No'. Here are the test cases: ```python assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' ``` |
pass 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| doubao | 'import re def match(s): pattern = r'[A-Z][a-z]+' if re.search(pattern, s): return 'Yes' else: return 'No' ' [DONE] |
pass 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| minimax | ```python import re def match(text): pattern = r'[A-Z][a-z]*' if re.search(pattern, text): return 'Yes' else: return 'No' # Test cases assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' ``` This function uses the `re` module to search for a pattern in the input string. The pattern `[A-Z][a-z]*` matches any sequence that starts with an uppercase letter (`[A-Z]`) followed by zero or more lowercase letters (`[a-z]*`). If such a sequence is found, the function returns 'Yes', otherwise it returns 'No'. |
pass 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| kimi | Certainly! Let's tackle these tasks one by one. 1. **Function to find similar elements from two tuple lists:** ```python def similar_elements(test_tup1, test_tup2): res = tuple(sorted(set(test_tup1) & set(test_tup2))) return res ``` 2. **Function to identify non-prime numbers:** ```python import math def is_not_prime(n): if n <= 1: return True for i in range(2, int(math.sqrt(n)) + 1): if n % i == 0: return True return False ``` 3. **Function to find the largest integers from a given list using heap queue algorithm:** ```python import heapq def heap_queue_largest(nums, n): largest_nums = heapq.nlargest(n, nums) return largest_nums ``` 4. **Function to find sequences of one upper case letter followed by lower case letters using regex:** ```python import re def match(s): pattern = r'^[A-Z][a-z]+' return 'Yes' if re.search(pattern, s) else 'No' ``` Now let's ensure that these functions pass the provided tests. ```python # Test for similar_elements assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5) assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4) assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14) # Test for is_not_prime assert is_not_prime(2) == False assert is_not_prime(10) == True assert is_not_prime(35) == True # Test for heap_queue_largest assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 3) == [85, 75, 65] assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 2) == [85, 75] assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 5) == [85, 75, 65, 58, 35] # Test for match assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' ``` If you run this code, it should not raise any assertion errors, indicating that all tests have passed. |
failed 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| wenxinyiyan | 'import re
def match(s): pattern = "[A-Z][a-z]+" if re.search(pattern, s): return "Yes" else: return "No"' [DONE] Explanation: The function `match` takes a string `s` as input and uses regular expressions (regex) to search for sequences of one uppercase letter followed by lowercase letters. The regex pattern `[A-Z][a-z]+` is used, where `[A-Z]` matches any uppercase letter and `[a-z]+` matches one or more lowercase letters. If the pattern is found in the string `s`, the function returns "Yes"; otherwise, it returns "No". The provided tests check if the function correctly identifies the presence or absence of the specified pattern in different strings. For example, the string "Geeks" contains the pattern (uppercase 'G' followed by lowercase 'eeks'), so the function returns "Yes". The string "geeks" does not contain the pattern, so the function returns "No". |
pass 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| zhipu | To achieve this task, we can use the `re` module in Python, which provides support for regular expressions. The function will use a regular expression pattern to search for sequences of one uppercase letter followed by one or more lowercase letters in the given string. Here's the code for the function: ```python import re def match(s): # Define the regex pattern: one uppercase letter followed by one or more lowercase letters pattern = r'[A-Z][a-z]+' # Use re.search to check if the pattern exists in the string if re.search(pattern, s): return 'Yes' else: return 'No' # Test cases assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' ``` Explanation: 1. **Pattern Explanation**: - `[A-Z]`: Matches any single uppercase letter. - `[a-z]+`: Matches one or more lowercase letters. - The combination `[A-Z][a-z]+` ensures that we are looking for a sequence starting with an uppercase letter followed by lowercase letters. 2. **re.search**: - `re.search(pattern, s)` searches for the first occurrence of the pattern in the string `s`. - If the pattern is found, `re.search` returns a match object; otherwise, it returns `None`. 3. **Return Value**: - If a match is found (`re.search` returns a match object), the function returns 'Yes'. - If no match is found (`re.search` returns `None`), the function returns 'No'. This function should pass the provided test cases as it correctly identifies strings that contain at least one sequence of an uppercase letter followed by lowercase letters. |
pass 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| gpto1 | 'import re def match(string): pattern = r"[A-Z][a-z]+" if re.search(pattern, string): return "Yes" else: return "No"' |
failed 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |
| deepseekv3 | To solve the task of finding sequences of one uppercase letter followed by lowercase letters in a given string using regular expressions, we can use Python's `re` module. The regular expression pattern `^[A-Z][a-z]*$` will match strings that start with an uppercase letter followed by zero or more lowercase letters. Here’s the function that accomplishes this: ```python import re def match(s): if re.match(r'^[A-Z][a-z]*$', s): return 'Yes' else: return 'No' # Test cases assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' ``` ### Explanation: - **`re.match(r'^[A-Z][a-z]*$', s)`**: - `^` asserts the position at the start of the string. - `[A-Z]` matches any uppercase letter. - `[a-z]*` matches zero or more lowercase letters. - `$` asserts the position at the end of the string. - The `re.match` function checks if the entire string matches the pattern. - If a match is found, the function returns `'Yes'`; otherwise, it returns `'No'`. This function will pass the provided test cases. |
wrong_answer 测试用例:assert match("Geeks") == 'Yes' assert match("geeksforGeeks") == 'Yes' assert match("geeks") == 'No' |