| 模型 | 模型答案 | 测试结果 |
|---|---|---|
| 金声玉亮2.0 | ```python def sort_tuple(tuples_list): return sorted(tuples_list, key=lambda x: x[-1]) ``` [DONE] |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| deepseekr1 | To solve this problem, we need to write a function that sorts a list of tuples based on the last element of each tuple in increasing order. ### Approach The key insight here is to utilize Python's built-in sorting capabilities with a custom key function. The sorted() function in Python allows specifying a key parameter, which determines the value used for comparison during sorting. By using a lambda function that extracts the last element of each tuple, we can sort the list of tuples based on these values. The sorted() function will return a new list sorted in ascending order by default, which meets our requirement of sorting in increasing order by the last element. ### Solution Code ```python def sort_tuple(lst): return sorted(lst, key=lambda x: x[-1]) ``` ### Explanation 1. **sorted() Function**: The sorted() function is used to sort the elements of a list. It returns a new list and does not modify the original list. 2. **Key Parameter**: The key parameter is set to a lambda function `lambda x: x[-1]`, which extracts the last element of each tuple. This ensures that the sorting is based on the last element of the tuples. 3. **Ascending Order**: By default, sorted() arranges elements in ascending order, which is exactly what we need for this problem. This approach efficiently sorts the list of tuples using Python's built-in functions, ensuring clarity and optimal performance. The time complexity of the sorting operation is O(n log n), where n is the number of tuples in the list, which is typical for comparison-based sorting algorithms. |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| gpto1 | ```python def sort_tuple(lst): return sorted(lst, key=lambda x: x[1]) ``` |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| GPT-4o | Sure, here is the function to sort a list of tuples in increasing order by the last element in each tuple: ```python def sort_tuple(tuples_list): # Sort the list of tuples using the last element of each tuple as the key sorted_list = sorted(tuples_list, key=lambda x: x[-1]) return sorted_list # Test cases assert sort_tuple([(1, 3), (3, 2), (2, 1)]) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)]) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)]) == [(4, 3), (6, 7), (3, 9)] ``` This function uses the `sorted` function with a `lambda` to specify that the sorting should be done based on the last element in each tuple. The test cases provided confirm that the function works as expected. |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| llama3.1-70B-Instruct | def sort_tuple(tuples): return sorted(tuples, key=lambda x: x[-1]) |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| llama3.1-405B-Instruct | def sort_tuple(tuples): return sorted(tuples, key=lambda x: x[-1]) |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| DeepSeek-Coder-V2 | ```python def sort_tuple(tuples_list): return sorted(tuples_list, key=lambda x: x[-1]) ``` [DONE] |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| Qwen2-72B-Instruct | 'def sort_tuple(tuples): return sorted(tuples, key=lambda x: x[1])' [DONE] |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| baichuan4 | To sort a list of tuples in increasing order by the last element in each tuple, you can use the built-in `sorted` function with a custom key. Here's the function that does that: ```python def sort_tuple(tuple_list): return sorted(tuple_list, key=lambda x: x[-1]) ``` This function takes a list of tuples `tuple_list` and returns a new list sorted based on the last element of each tuple. The `key=lambda x: x[-1]` argument specifies the sorting criteria, which in this case is the last element of each tuple. Let's test it with the provided test cases: ```python assert sort_tuple([(1, 3), (3, 2), (2, 1)]) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)]) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)]) == [(4, 3), (6, 7), (3, 9)] ``` All tests should pass successfully, indicating that the function works correctly. |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| doubao | 'def sort_tuple(lst): return sorted(lst, key=lambda x: x[-1])' [DONE] |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| minimax | ```python def sort_tuple(tuples_list): return sorted(tuples_list, key=lambda x: x[1]) # Test cases assert sort_tuple([(1, 3), (3, 2), (2, 1)]) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)]) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)]) == [(4, 3), (6, 7), (3, 9)] ``` This function `sort_tuple` takes a list of tuples and sorts them in increasing order based on the last element of each tuple. The `sorted` function is used with a key that specifies to sort by the second element of each tuple (index 1). The test cases check that the function correctly sorts the tuples as required. |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| kimi | ```python # Function to find similar elements from two tuple lists def similar_elements(test_tup1, test_tup2): res = tuple(sorted(set(test_tup1) & set(test_tup2))) return res # Function to identify non-prime numbers import math def is_not_prime(n): if n <= 1: return True for i in range(2, int(math.sqrt(n)) + 1): if n % i == 0: return True return False # Function to find the largest integers from a list using heap queue algorithm import heapq as hq def heap_queue_largest(nums, n): largest_nums = hq.nlargest(n, nums) return largest_nums # Function to sort a list of tuples in increasing order by the last element def sort_tuple(tuples_list): return sorted(tuples_list, key=lambda x: x[1]) # Test cases assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5) assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4) assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14) assert is_not_prime(2) == False assert is_not_prime(10) == True assert is_not_prime(35) == True assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 3) == [85, 75, 65] assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 2) == [85, 75] assert heap_queue_largest([25, 35, 22, 85, 14, 65, 75, 22, 58], 5) == [85, 75, 65, 58, 35] assert sort_tuple([(1, 3), (3, 2), (2, 1)]) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)]) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)]) == [(4, 3), (6, 7), (3, 9)] ``` This code defines the functions required for each task and includes the test cases to validate the functions. If any test case fails, an `AssertionError` will be raised. |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| wenxinyiyan | 'def sort_tuple(lst): return sorted(lst, key=lambda x: x[-1])' [DONE] Explanation: The `sort_tuple` function takes a list of tuples as input and returns a new list with the tuples sorted in increasing order based on the last element in each tuple. To achieve this, we use the `sorted` function from the Python standard library. The `sorted` function takes an iterable (in this case, the list of tuples) and returns a new sorted list. The key to sorting the tuples based on the last element is the `key` parameter of the `sorted` function. We pass a lambda function to the `key` parameter, which extracts the last element from each tuple using the index `-1`. The `sorted` function then uses this extracted value to compare and sort the tuples. Finally, the sorted list of tuples is returned as the output of the `sort_tuple` function. |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| zhipu | To achieve the task of sorting a list of tuples based on the last element in each tuple, we can use Python's built-in `sorted` function with a custom key. The `key` parameter of the `sorted` function allows us to specify a function that returns the element to be used for sorting purposes. Here is the implementation of the `sort_tuple` function: ```python def sort_tuple(tuples_list): # Sort the list of tuples based on the last element of each tuple return sorted(tuples_list, key=lambda x: x[-1]) # Test cases assert sort_tuple([(1, 3), (3, 2), (2, 1)]) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)]) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)]) == [(4, 3), (6, 7), (3, 9)] print("All tests passed!") ``` ### Explanation: 1. **Function Definition**: The `sort_tuple` function takes a list of tuples as input. 2. **Sorting Mechanism**: - `sorted(tuples_list, key=lambda x: x[-1])`: This line sorts the `tuples_list`. - The `key` parameter is set to a lambda function `lambda x: x[-1]`, which returns the last element of each tuple. This tells the `sorted` function to sort the tuples based on their last elements. 3. **Test Cases**: The `assert` statements are used to verify that the function produces the expected output for given inputs. When you run this code, it should pass all the provided test cases and print "All tests passed!" indicating that the function works as expected. |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| gpto1 | ```python def sort_tuple(lst): return sorted(lst, key=lambda x: x[1]) ``` |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |
| deepseekv3 | To sort a list of tuples in increasing order by the last element in each tuple, you can use the `sorted()` function with a custom key that extracts the last element of each tuple. Here's the function that accomplishes this: ```python def sort_tuple(tuples_list): return sorted(tuples_list, key=lambda x: x[-1]) ``` ### Explanation: - `sorted(tuples_list, key=lambda x: x[-1])`: The `sorted()` function sorts the list of tuples. The `key` parameter is set to a lambda function that returns the last element (`x[-1]`) of each tuple. This ensures that the sorting is based on the last element of each tuple. ### Test Cases: ```python assert sort_tuple([(1, 3), (3, 2), (2, 1)]) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)]) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)]) == [(4, 3), (6, 7), (3, 9)] ``` These test cases verify that the function correctly sorts the tuples based on their last element in increasing order. |
pass 测试用例：assert sort_tuple([(1, 3), (3, 2), (2, 1)] ) == [(2, 1), (3, 2), (1, 3)] assert sort_tuple([(2, 4), (3, 3), (1, 1)] ) == [(1, 1), (3, 3), (2, 4)] assert sort_tuple([(3, 9), (6, 7), (4, 3)] ) == [(4, 3), (6, 7), (3, 9)] |