金声玉亮2.0模型评测报告

问题

You are an expert Python programmer, and here is your task: Write a function to find the similar elements from the given two tuple lists. Your code should pass these tests:

assert similar_elements((3, 4, 5, 6),(5, 7, 4, 10)) == (4, 5)
assert similar_elements((1, 2, 3, 4),(5, 4, 3, 7)) == (3, 4)
assert similar_elements((11, 12, 14, 13),(17, 15, 14, 13)) == (13, 14)

[BEGIN]
'def similar_elements(test_tup1, test_tup2):
res = tuple(set(test_tup1) & set(test_tup2))
return (res)'
[DONE]

You are an expert Python programmer, and here is your task: Write a python function to identify non-prime numbers. Your code should pass these tests:

assert is_not_prime(2) == False
assert is_not_prime(10) == True
assert is_not_prime(35) == True

[BEGIN]
'import math
def is_not_prime(n):
result = False
for i in range(2,int(math.sqrt(n)) + 1):
if n % i == 0:
result = True
return result'
[DONE]

You are an expert Python programmer, and here is your task: Write a function to find the largest integers from a given list of numbers using heap queue algorithm. Your code should pass these tests:

assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],3)==[85, 75, 65]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],2)==[85, 75]
assert heap_queue_largest( [25, 35, 22, 85, 14, 65, 75, 22, 58],5)==[85, 75, 65, 58, 35]

[BEGIN]
'import heapq as hq
def heap_queue_largest(nums,n):
largest_nums = hq.nlargest(n, nums)
return largest_nums'
[DONE]

You are an expert Python programmer, and here is your task: Write a function to remove specific words from a given list. Your code should pass these tests:

assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']

[BEGIN]

答案

模型	模型答案	测试结果
金声玉亮2.0	```python def remove_words(word_list, words_to_remove): return [word for word in word_list if word not in words_to_remove] ``` [DONE]	pass 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
deepseekr1	[BEGIN] def remove_words(words_list, remove_list): remove_set = set(remove_list) return [word for word in words_list if word not in remove_set] [DONE]	pass 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
gpto1	'def remove_words(words_list, remove_list): result = [word for word in words_list if word not in remove_list] return result'	failed 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
GPT-4o	Sure! Here's the implementation that removes specific words from a given list: ```python def remove_words(word_list, words_to_remove): return [word for word in word_list if word not in words_to_remove] # Test cases assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['white', 'orange']) == ['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['black', 'orange']) == ['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['blue', 'white']) == ['red', 'green', 'black', 'orange'] ``` This function uses list comprehension to create a new list that includes only the words that are not in the `words_to_remove` list. The test cases provided will check if the function behaves as expected.	pass 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
llama3.1-70B-Instruct	def remove_words(word_list, words_to_remove): return [word for word in word_list if word not in words_to_remove]	pass 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
llama3.1-405B-Instruct	def remove_words(word_list, words_to_remove): return [word for word in word_list if word not in words_to_remove]	pass 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
DeepSeek-Coder-V2	```python def remove_words(word_list, words_to_remove): return [word for word in word_list if word not in words_to_remove] ``` [DONE]	pass 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
Qwen2-72B-Instruct	'def remove_words(word_list, words_to_remove): return [word for word in word_list if word not in words_to_remove]' [DONE]	pass 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
baichuan4	Here is a Python function that removes specific words from a given list: ```python def remove_words(word_list, words_to_remove): return [word for word in word_list if word not in words_to_remove] ``` This function uses a list comprehension to iterate through each word in `word_list` and checks if it is in the `words_to_remove` list. If the word is not in the `words_to_remove` list, it is added to the new list. Let's test the function with the provided test cases: ```python assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['white', 'orange']) == ['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['black', 'orange']) == ['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['blue', 'white']) == ['red', 'green', 'black', 'orange'] ``` The function passes all the tests, indicating that it correctly removes the specified words from the list.	pass 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
doubao	'def remove_words(lst, words_to_remove): return [item for item in lst if item not in words_to_remove]' [DONE]	pass 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
minimax	```python def remove_words(words_list, words_to_remove): return [word for word in words_list if word not in words_to_remove] # Test cases assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['white', 'orange']) == ['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['black', 'orange']) == ['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['blue', 'white']) == ['red', 'green', 'black', 'orange'] ``` The function `remove_words` iterates through the `words_list` and includes only those words that are not present in the `words_to_remove` list. The test cases check if the function correctly removes the specified words from the list.	pass 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
kimi	Here's the Python function to remove specific words from a given list: ```python def remove_words(words_list, words_to_remove): return [word for word in words_list if word not in words_to_remove] ``` This function uses a list comprehension to iterate through each word in the `words_list` and includes it in the result if it is not found in the `words_to_remove` list. Now let's test the function with the provided test cases: ```python assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['white', 'orange']) == ['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['black', 'orange']) == ['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['blue', 'white']) == ['red', 'green', 'black', 'orange'] ``` If you run the above code, it should pass without any assertion errors.	pass 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
wenxinyiyan	Here's the solution for each task: Task 1: Finding similar elements from two tuple lists ```python def similar_elements(test_tup1, test_tup2): res = tuple(set(test_tup1) & set(test_tup2)) return res ``` This function takes two tuple lists as input and returns a tuple containing the similar elements from both lists. It converts each tuple list to a set, finds the intersection of the sets using the `&` operator, and then converts the result back to a tuple. Task 2: Identifying non-prime numbers ```python import math def is_not_prime(n): if n < 2: return True for i in range(2, int(math.sqrt(n)) + 1): if n % i == 0: return True return False ``` This function takes an integer `n` as input and returns `True` if `n` is not a prime number, and `False` otherwise. It checks if `n` is less than 2 (which are not considered prime) and then iterates from 2 to the square root of `n` to check for any divisors. If a divisor is found, it returns `True`. If no divisors are found, it returns `False`. Note: There was a small error in your provided code. I fixed it by adding the check `if n < 2` at the beginning of the function. Task 3: Finding the largest integers from a given list using heap queue algorithm ```python import heapq as hq def heap_queue_largest(nums, n): largest_nums = hq.nlargest(n, nums) return largest_nums ``` This function takes a list of numbers `nums` and an integer `n` as input and returns a list containing the `n` largest numbers from `nums`. It uses the `heapq.nlargest()` function from the `heapq` module to find the `n` largest elements efficiently. Task 4: Removing specific words from a given list ```python def remove_words(word_list, words_to_remove): return [word for word in word_list if word not in words_to_remove] ``` This function takes a list of words `word_list` and a list of words to remove `words_to_remove` as input and returns a new list containing the words from `word_list` that are not in `words_to_remove`. It uses a list comprehension to iterate over each word in `word_list` and checks if it is not in `words_to_remove` before adding it to the new list.	failed 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
zhipu	Here is a Python function that removes specific words from a given list. This function will pass the provided tests: ```python def remove_words(original_list, words_to_remove): return [word for word in original_list if word not in words_to_remove] # Test cases assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['white', 'orange']) == ['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['black', 'orange']) == ['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['blue', 'white']) == ['red', 'green', 'black', 'orange'] print("All tests passed!") ``` ### Explanation: 1. Function Definition: - `remove_words(original_list, words_to_remove)`: This function takes two lists as input: - `original_list`: The list from which words need to be removed. - `words_to_remove`: The list of words that should be removed from the `original_list`. 2. List Comprehension: - `[word for word in original_list if word not in words_to_remove]`: This list comprehension iterates over each word in `original_list` and includes it in the resulting list only if it is not present in the `words_to_remove` list. 3. Test Cases: - The `assert` statements are used to verify that the function produces the expected output for the given inputs. ### Running the Code: When you run the above code, it will execute the test cases. If all tests pass, it will print "All tests passed!" indicating that the function works correctly for the provided test cases. If any test fails, an `AssertionError` will be raised, indicating that there is an issue with the function implementation.	pass 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
gpto1	'def remove_words(words_list, remove_list): result = [word for word in words_list if word not in remove_list] return result'	failed 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']
deepseekv3	```python def remove_words(word_list, words_to_remove): return [word for word in word_list if word not in words_to_remove] ``` ### Explanation: - Input: The function takes two arguments: `word_list` (the list of words) and `words_to_remove` (the list of words to be removed). - Output: The function returns a new list that contains all the words from `word_list` except those that are in `words_to_remove`. - List Comprehension: The list comprehension iterates over each word in `word_list` and includes it in the new list only if it is not in `words_to_remove`. ### Example Usage: ```python print(remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['white', 'orange'])) # Output: ['red', 'green', 'blue', 'black'] print(remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['black', 'orange'])) # Output: ['red', 'green', 'blue', 'white'] print(remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['blue', 'white'])) # Output: ['red', 'green', 'black', 'orange'] ``` This function efficiently removes the specified words from the list using a simple and readable list comprehension.	pass 测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white'] assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']

模型

模型答案

测试结果

金声玉亮2.0

```python
def remove_words(word_list, words_to_remove):
return [word for word in word_list if word not in words_to_remove]
```
[DONE]

pass
测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']

deepseekr1

[BEGIN]
def remove_words(words_list, remove_list):
remove_set = set(remove_list)
return [word for word in words_list if word not in remove_set]
[DONE]

gpto1

'def remove_words(words_list, remove_list):
result = [word for word in words_list if word not in remove_list]
return result'

failed
测试用例：assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['white', 'orange'])==['red', 'green', 'blue', 'black']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['black', 'orange'])==['red', 'green', 'blue', 'white']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'],['blue', 'white'])==['red', 'green', 'black', 'orange']

GPT-4o

Sure! Here's the implementation that removes specific words from a given list:

```python
def remove_words(word_list, words_to_remove):
return [word for word in word_list if word not in words_to_remove]

# Test cases
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['white', 'orange']) == ['red', 'green', 'blue', 'black']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['black', 'orange']) == ['red', 'green', 'blue', 'white']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['blue', 'white']) == ['red', 'green', 'black', 'orange']
```

This function uses list comprehension to create a new list that includes only the words that are not in the `words_to_remove` list. The test cases provided will check if the function behaves as expected.

llama3.1-70B-Instruct

def remove_words(word_list, words_to_remove):
return [word for word in word_list if word not in words_to_remove]

llama3.1-405B-Instruct

def remove_words(word_list, words_to_remove):
return [word for word in word_list if word not in words_to_remove]

DeepSeek-Coder-V2

```python
def remove_words(word_list, words_to_remove):
return [word for word in word_list if word not in words_to_remove]
```
[DONE]

Qwen2-72B-Instruct

'def remove_words(word_list, words_to_remove):
return [word for word in word_list if word not in words_to_remove]'
[DONE]

baichuan4

Here is a Python function that removes specific words from a given list:

```python
def remove_words(word_list, words_to_remove):
return [word for word in word_list if word not in words_to_remove]
```

This function uses a list comprehension to iterate through each word in `word_list` and checks if it is in the `words_to_remove` list. If the word is not in the `words_to_remove` list, it is added to the new list.

Let's test the function with the provided test cases:

```python
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['white', 'orange']) == ['red', 'green', 'blue', 'black']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['black', 'orange']) == ['red', 'green', 'blue', 'white']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['blue', 'white']) == ['red', 'green', 'black', 'orange']
```

The function passes all the tests, indicating that it correctly removes the specified words from the list.

doubao

'def remove_words(lst, words_to_remove):
return [item for item in lst if item not in words_to_remove]'
[DONE]

minimax

```python
def remove_words(words_list, words_to_remove):
return [word for word in words_list if word not in words_to_remove]

# Test cases
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['white', 'orange']) == ['red', 'green', 'blue', 'black']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['black', 'orange']) == ['red', 'green', 'blue', 'white']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['blue', 'white']) == ['red', 'green', 'black', 'orange']
```

The function `remove_words` iterates through the `words_list` and includes only those words that are not present in the `words_to_remove` list. The test cases check if the function correctly removes the specified words from the list.

kimi

Here's the Python function to remove specific words from a given list:

```python
def remove_words(words_list, words_to_remove):
return [word for word in words_list if word not in words_to_remove]
```

This function uses a list comprehension to iterate through each word in the `words_list` and includes it in the result if it is not found in the `words_to_remove` list.

Now let's test the function with the provided test cases:

```python
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['white', 'orange']) == ['red', 'green', 'blue', 'black']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['black', 'orange']) == ['red', 'green', 'blue', 'white']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['blue', 'white']) == ['red', 'green', 'black', 'orange']
```

If you run the above code, it should pass without any assertion errors.

wenxinyiyan

Here's the solution for each task:

Task 1: Finding similar elements from two tuple lists

```python
def similar_elements(test_tup1, test_tup2):
res = tuple(set(test_tup1) & set(test_tup2))
return res
```
This function takes two tuple lists as input and returns a tuple containing the similar elements from both lists. It converts each tuple list to a set, finds the intersection of the sets using the `&` operator, and then converts the result back to a tuple.

Task 2: Identifying non-prime numbers

```python
import math

def is_not_prime(n):
if n < 2:
return True
for i in range(2, int(math.sqrt(n)) + 1):
if n % i == 0:
return True
return False
```
This function takes an integer `n` as input and returns `True` if `n` is not a prime number, and `False` otherwise. It checks if `n` is less than 2 (which are not considered prime) and then iterates from 2 to the square root of `n` to check for any divisors. If a divisor is found, it returns `True`. If no divisors are found, it returns `False`.

Note: There was a small error in your provided code. I fixed it by adding the check `if n < 2` at the beginning of the function.

Task 3: Finding the largest integers from a given list using heap queue algorithm

```python
import heapq as hq

def heap_queue_largest(nums, n):
largest_nums = hq.nlargest(n, nums)
return largest_nums
```
This function takes a list of numbers `nums` and an integer `n` as input and returns a list containing the `n` largest numbers from `nums`. It uses the `heapq.nlargest()` function from the `heapq` module to find the `n` largest elements efficiently.

Task 4: Removing specific words from a given list

```python
def remove_words(word_list, words_to_remove):
return [word for word in word_list if word not in words_to_remove]
```
This function takes a list of words `word_list` and a list of words to remove `words_to_remove` as input and returns a new list containing the words from `word_list` that are not in `words_to_remove`. It uses a list comprehension to iterate over each word in `word_list` and checks if it is not in `words_to_remove` before adding it to the new list.

zhipu

Here is a Python function that removes specific words from a given list. This function will pass the provided tests:

```python
def remove_words(original_list, words_to_remove):
return [word for word in original_list if word not in words_to_remove]

# Test cases
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['white', 'orange']) == ['red', 'green', 'blue', 'black']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['black', 'orange']) == ['red', 'green', 'blue', 'white']
assert remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['blue', 'white']) == ['red', 'green', 'black', 'orange']

print("All tests passed!")
```

### Explanation:
1. **Function Definition**:
- `remove_words(original_list, words_to_remove)`: This function takes two lists as input:
- `original_list`: The list from which words need to be removed.
- `words_to_remove`: The list of words that should be removed from the `original_list`.

2. **List Comprehension**:
- `[word for word in original_list if word not in words_to_remove]`: This list comprehension iterates over each word in `original_list` and includes it in the resulting list only if it is not present in the `words_to_remove` list.

3. **Test Cases**:
- The `assert` statements are used to verify that the function produces the expected output for the given inputs.

### Running the Code:
When you run the above code, it will execute the test cases. If all tests pass, it will print "All tests passed!" indicating that the function works correctly for the provided test cases. If any test fails, an `AssertionError` will be raised, indicating that there is an issue with the function implementation.

gpto1

'def remove_words(words_list, remove_list):
result = [word for word in words_list if word not in remove_list]
return result'

deepseekv3

```python
def remove_words(word_list, words_to_remove):
return [word for word in word_list if word not in words_to_remove]
```

### Explanation:
- **Input**: The function takes two arguments: `word_list` (the list of words) and `words_to_remove` (the list of words to be removed).
- **Output**: The function returns a new list that contains all the words from `word_list` except those that are in `words_to_remove`.
- **List Comprehension**: The list comprehension iterates over each word in `word_list` and includes it in the new list only if it is not in `words_to_remove`.

### Example Usage:
```python
print(remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['white', 'orange']))
# Output: ['red', 'green', 'blue', 'black']

print(remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['black', 'orange']))
# Output: ['red', 'green', 'blue', 'white']

print(remove_words(['red', 'green', 'blue', 'white', 'black', 'orange'], ['blue', 'white']))
# Output: ['red', 'green', 'black', 'orange']
```

This function efficiently removes the specified words from the list using a simple and readable list comprehension.