| 模型 | 模型答案 | 测试结果 |
|---|---|---|
| 金声玉亮2.0 | ```python def same_order(list1, list2): common_elements = [element for element in list1 if element in list2] if not common_elements: return True # No common elements, so trivially in order index_list1 = [list1.index(element) for element in common_elements] index_list2 = [list2.index(element) for element in common_elements] return index_list1 == sorted(index_list1) and index_list2 == sorted(index_list2) # Test cases assert same_order(["red", "green", "black", "orange"], ["red", "pink", "green", "white", "black"]) == True assert same_order(["red", "pink", "green", "white", "black"], ["white", "orange", "pink", "black"]) == False assert same_order(["red", "green", "black", "orange"], ["red", "pink", "green", "white", "black"]) == True ``` [DONE] |
pass 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| deepseekr1 | [BEGIN] def same_order(list1, list2): common = set(list1) & set(list2) sublist1 = [x for x in list1 if x in common] sublist2 = [x for x in list2 if x in common] return sublist1 == sublist2 [DONE] |
pass 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| gpto1 | ```python def same_order(list1, list2): common = set(list1) & set(list2) seq1 = [item for item in list1 if item in common] seq2 = [item for item in list2 if item in common] return seq1 == seq2 ``` |
pass 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| GPT-4o | To solve this task, we need to find the common elements between two lists and then check if these common elements are in the same order in both lists. Here's how we can implement this: 1. Extract common elements from both lists. 2. Check if the order of these common elements is the same in both lists. Here's the implementation: ```python def same_order(list1, list2): # Extract common elements common_elements = [element for element in list1 if element in list2] # Create the ordered list of common elements from list2 ordered_common_elements = [element for element in list2 if element in common_elements] # Check if the order is the same return common_elements == ordered_common_elements # Test cases assert same_order(["red","green","black","orange"],["red","pink","green","white","black"]) == True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"]) == False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"]) == True ``` Explanation: - We first extract the common elements from `list1` that are also present in `list2`. - We then create a list of these common elements from `list2` to ensure the order is preserved as in `list2`. - Finally, we check if the order of common elements in `list1` is the same as in `list2`. This code should pass all the provided test cases. |
pass 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| llama3.1-70B-Instruct | def same_order(list1, list2): common_elements = set(list1) & set(list2) index_list1 = [list1.index(element) for element in common_elements] index_list2 = [list2.index(element) for element in common_elements] return index_list1 == index_list2 |
wrong_answer 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| llama3.1-405B-Instruct | def same_order(list1, list2): common_elements = [element for element in list1 if element in list2] list2_index = 0 for element in list2: if element in common_elements: if list2.index(element) < list2_index: return False list2_index = list2.index(element) return True |
wrong_answer 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| DeepSeek-Coder-V2 | ```python def same_order(list1, list2): common_elements = [element for element in list1 if element in list2] if not common_elements: return True # No common elements, so trivially in order index_list1 = [list1.index(element) for element in common_elements] index_list2 = [list2.index(element) for element in common_elements] return index_list1 == sorted(index_list1) and index_list2 == sorted(index_list2) # Test cases assert same_order(["red", "green", "black", "orange"], ["red", "pink", "green", "white", "black"]) == True assert same_order(["red", "pink", "green", "white", "black"], ["white", "orange", "pink", "black"]) == False assert same_order(["red", "green", "black", "orange"], ["red", "pink", "green", "white", "black"]) == True ``` [DONE] |
pass 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| Qwen2-72B-Instruct | 'def same_order(list1, list2): index = 0 for i in list1: try: index_list2 = list2.index(i) except ValueError: return False if index_list2 < index: return False index = index_list2 + 1 return True' [DONE] |
wrong_answer 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| baichuan4 | To check if the common elements between two given lists are in the same order or not, you can use the following function: ```python def same_order(list1, list2): it1 = iter(list1) it2 = iter(list2) try: while True: val1 = next(it1) val2 = next(it2) if val1 == val2: continue elif val2 in list1: # Shift the second iterator back to the start it2 = iter(list2) while next(it2) != val2: pass else: return False except StopIteration: return True ``` This function uses two iterators to traverse through both lists simultaneously. If a common element is found, it continues to the next element. If a mismatch is found, it resets the second iterator and tries to match the element again. If the second element is not found in the first list, it returns False. If the end of both lists is reached without any mismatches, it returns True. Let's test the function with the provided test cases: ```python assert same_order(["red","green","black","orange"],["red","pink","green","white","black"]) == True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"]) == False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"]) == True ``` The function should pass these tests successfully. |
wrong_answer 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| doubao | def same_order(list1, list2): i = j = 0 while i < len(list1) and j < len(list2): if list1[i] == list2[j]: i += 1 j += 1 else: j += 1 return i == len(list1) [DONE] |
wrong_answer 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| minimax | ```python def same_order(list1, list2): # Find the common elements and their indices in list1 common_elements = [element for element in list1 if element in list2] common_indices = [list1.index(element) for element in common_elements] # Find the indices of the common elements in list2 list2_indices = [list2.index(element) for element in common_elements] # Check if the indices are the same in both lists return common_indices == list2_indices # Test cases assert same_order(["red", "green", "black", "orange"], ["red", "pink", "green", "white", "black"]) == True assert same_order(["red", "pink", "green", "white", "black"], ["white", "orange", "pink", "black"]) == False assert same_order(["red", "green", "black", "orange"], ["red", "pink", "green", "white", "black"]) == True ``` This function `same_order` takes two lists as input and returns `True` if the common elements between the two lists are in the same order in both lists, and `False` otherwise. The test cases check for this functionality. |
wrong_answer 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| kimi | Here's the Python code for each task: 1. Function to find similar elements from two tuple lists: ```python def similar_elements(test_tup1, test_tup2): res = tuple(sorted(set(test_tup1) & set(test_tup2))) return res ``` 2. Function to identify non-prime numbers: ```python import math def is_not_prime(n): if n <= 1: return True for i in range(2, int(math.sqrt(n)) + 1): if n % i == 0: return True return False ``` 3. Function to find the largest integers from a given list of numbers using heap queue algorithm: ```python import heapq def heap_queue_largest(nums, n): largest_nums = heapq.nlargest(n, nums) return largest_nums ``` 4. Function to check if the common elements between two given lists are in the same order or not: ```python def same_order(list1, list2): for item in list1: if item in list2: list2 = list2[list2.index(item) + 1:] if not list2: break else: return False return True ``` Each function is designed to pass the provided test cases. |
failed 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| wenxinyiyan | Here's the code to check if the common elements between two given lists are in the same order: ```python def same_order(list1, list2): common_elements = [x for x in list1 if x in list2] i = 0 for elem in list2: if elem in common_elements: if common_elements[i] != elem: return False i += 1 if i == len(common_elements): break return True ``` However, there's a small issue with the provided test cases. The third test case is a duplicate of the first one, and it should be modified to include a different scenario. Let's assume the third test case should be: ```python assert same_order(["red", "green", "black", "orange"], ["green", "red", "black", "orange"]) == False ``` In this case, the common elements are in a different order in the second list compared to the first list. Now, let's test the function with the updated test cases: ```python assert same_order(["red", "green", "black", "orange"], ["red", "pink", "green", "white", "black"]) == True assert same_order(["red", "pink", "green", "white", "black"], ["white", "orange", "pink", "black"]) == False assert same_order(["red", "green", "black", "orange"], ["green", "red", "black", "orange"]) == False ``` The function should return `True` for the first test case because the common elements `"red"`, `"green"`, and `"black"` appear in the same order in both lists. It should return `False` for the second and third test cases because the common elements are not in the same order. Note: The function assumes that the common elements between the two lists are unique and don't repeat within each list. If there can be duplicate common elements, the function would need to be modified accordingly. |
pass 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| zhipu | To solve this task, we need to write a function `same_order` that checks if the common elements between two given lists appear in the same order in both lists. Here's the implementation: ```python def same_order(list1, list2): # Find the common elements common_elements = set(list1) & set(list2) # Extract the order of common elements in both lists ordered_common_list1 = [item for item in list1 if item in common_elements] ordered_common_list2 = [item for item in list2 if item in common_elements] # Check if the order of common elements is the same return ordered_common_list1 == ordered_common_list2 # Test cases assert same_order(["red","green","black","orange"],["red","pink","green","white","black"]) == True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"]) == False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"]) == True print("All tests passed!") ``` ### Explanation: 1. **Find Common Elements**: We use set intersection to find the common elements between `list1` and `list2`. 2. **Extract Ordered Common Elements**: We create two new lists, `ordered_common_list1` and `ordered_common_list2`, which contain the common elements in the order they appear in `list1` and `list2`, respectively. 3. **Compare Orders**: We compare the two ordered lists to check if the common elements appear in the same order in both lists. This function should pass the provided test cases. You can run the code to verify that all tests pass. |
pass 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| gpto1 | ```python def same_order(list1, list2): common = set(list1) & set(list2) seq1 = [item for item in list1 if item in common] seq2 = [item for item in list2 if item in common] return seq1 == seq2 ``` |
pass 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |
| deepseekv3 | ```python def same_order(list1, list2): # Extract common elements from both lists while preserving order common1 = [item for item in list1 if item in list2] common2 = [item for item in list2 if item in list1] # Check if the order of common elements is the same in both lists return common1 == common2 ``` ### Explanation: 1. **Extract Common Elements**: We first extract the common elements from both lists while preserving their original order. This is done using list comprehensions that filter out only the elements that are present in both lists. 2. **Compare Order**: After extracting the common elements, we simply compare the two lists of common elements to see if they are the same. If they are, it means the common elements appear in the same order in both original lists. ### Example Walkthrough: - For the first test case: - `list1 = ["red","green","black","orange"]` - `list2 = ["red","pink","green","white","black"]` - Common elements in order from `list1`: `["red", "green", "black"]` - Common elements in order from `list2`: `["red", "green", "black"]` - Since both lists of common elements are the same, the function returns `True`. - For the second test case: - `list1 = ["red","pink","green","white","black"]` - `list2 = ["white","orange","pink","black"]` - Common elements in order from `list1`: `["pink", "white", "black"]` - Common elements in order from `list2`: `["white", "pink", "black"]` - Since the order of common elements is different, the function returns `False`. This function ensures that the common elements between the two lists are compared in the order they appear in each list. |
pass 测试用例：assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True assert same_order(["red","pink","green","white","black"],["white","orange","pink","black"])==False assert same_order(["red","green","black","orange"],["red","pink","green","white","black"])==True |