金声玉亮2.0模型评测报告

Complete the following python code:

def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]

"""

答案

模型	模型答案	测试结果
金声玉亮2.0	Certainly! Below is the complete implementation of the `common` function based on the provided specification: ```python def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ # Convert both lists to sets to get unique elements set1 = set(l1) set2 = set(l2) # Find the intersection of the two sets common_elements = set1.intersection(set2) # Convert the set to a sorted list and return return sorted(common_elements) ``` This function uses sets to find the unique common elements between the two lists and then sorts the result before returning it. The provided examples in the docstring show how the function works.	passed
deepseekr1	To solve this problem, we need to find the common elements between two lists, ensure these elements are unique, and return them in sorted order. ### Approach 1. Convert Lists to Sets: By converting each list to a set, we automatically remove any duplicate elements and allow for efficient computation of common elements using set intersection. 2. Compute Intersection: The intersection of two sets gives us elements that are present in both sets, which corresponds to the common elements of the original lists. 3. Sort the Result: Convert the resulting set of common elements into a sorted list to meet the requirement of returning elements in ascending order. ### Solution Code ```python def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ return sorted(set(l1) & set(l2)) ``` ### Explanation - Conversion to Sets: Converting `l1` and `l2` to sets removes duplicates and allows the use of set operations. - Intersection: Using the `&` operator on the sets derived from `l1` and `l2` efficiently finds common elements. - Sorting: The `sorted()` function converts the resulting set into a sorted list, ensuring the output is in ascending order. This approach ensures that we efficiently find unique common elements and return them in the required sorted order.	passed
gpto1	Here's the completed Python code for the `common` function: ```python def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ # Convert both lists to sets to remove duplicates and allow set operations set1 = set(l1) set2 = set(l2) # Find the intersection of the two sets common_elements = set1 & set2 # or set1.intersection(set2) # Return the sorted list of common elements return sorted(common_elements) ``` Explanation: - Convert lists to sets: By converting the lists `l1` and `l2` to sets (`set1` and `set2`), we eliminate any duplicate elements within each list. - Find common elements: The intersection of `set1` and `set2` (`set1 & set2`) gives us the unique elements that are common to both sets. - Sort the result: We convert the set of common elements back to a list and sort it using the `sorted()` function to get the final result. Example Usage: ```python print(common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])) # Output: [1, 5, 653] print(common([5, 3, 2, 8], [3, 2])) # Output: [2, 3] ```	passed
GPT-4o	Certainly! Here is the complete implementation of the `common` function that returns the sorted unique common elements for two lists: ```python def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ # Convert both lists to sets to remove duplicates and find the intersection set1 = set(l1) set2 = set(l2) # Find the common elements using set intersection common_elements = set1.intersection(set2) # Convert the set to a sorted list and return it return sorted(common_elements) # Example usages: if __name__ == "__main__": print(common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])) # Output: [1, 5, 653] print(common([5, 3, 2, 8], [3, 2])) # Output: [2, 3] ``` This function uses sets to remove duplicates and find the intersection of the two input lists. The resulting set of common elements is then converted to a sorted list before being returned.	passed
llama3.1-70B-Instruct	def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ return sorted(set(l1) & set(l2))	passed
llama3.1-405B-Instruct	Here is the completed Python code: ```python def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ return sorted(set(l1) & set(l2)) ``` Explanation: * We use the `set` data structure to find the common elements between the two lists. The `&` operator is used to find the intersection of two sets, which returns a new set containing only the elements that are present in both sets. * We use the `sorted` function to sort the resulting set of common	passed
DeepSeek-Coder-V2	Here's the completed Python function that returns sorted unique common elements for two lists: ```python def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ # Use set intersection to find common elements and convert back to list common_elements = list(set(l1) & set(l2)) # Sort the list before returning return sorted(common_elements) # Test cases if __name__ == "__main__": import doctest doctest.testmod() ``` This function works as follows: 1. It converts both lists to sets to eliminate duplicates and find the intersection of these sets, which gives the common elements. 2. It converts the result back to a list. 3. It sorts the list of common elements. 4. It returns the sorted list of common elements. The `doctest` module is used to run the test cases provided in the docstring to ensure the function works as expected.	passed
Qwen2-72B-Instruct	Here is a possible solution for the given problem: ```python def common(l1: list, l2: list): return sorted(list(set(l1) & set(l2))) print(common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])) # [1, 5, 653] print(common([5, 3, 2, 8], [3, 2])) # [2, 3] ``` The function `common` first converts both lists to sets with `set(l1)` and `set(l2)`. The `&` operator is then used to find the intersection of these two sets, i.e., the elements that are common to both sets. This result is then converted back to a list with `list()`, and finally sorted with `sorted()`. This function will return a sorted list of the unique common elements of the two input lists.	passed
baichuan4	To complete the Python code for the `common` function, we need to find the unique common elements between two lists and return them in a sorted order. We can achieve this by converting each list into a set, which automatically removes duplicates, and then performing an intersection of these sets. Finally, we convert the resulting set back into a list and sort it before returning. Here's how you can complete the function: ```python def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ # Convert both lists into sets to remove duplicates and perform intersection common_elements = set(l1).intersection(set(l2)) # Convert the set of common elements back into a list and sort it return sorted(list(common_elements)) ``` This function first converts `l1` and `l2` into sets using `set(l1)` and `set(l2)`. Then, it finds the intersection of these sets with `.intersection()`, which gives us the common elements. The result is a set, so we convert it into a list with `list(common_elements)` and sort it with `sorted()` before returning. This ensures that the returned list is sorted and contains only unique common elements.	passed
doubao	Here's the completed Python code: ```python def common(l1: list, l2: list): return sorted(set(l1) & set(l2)) ```	passed
minimax	To complete the function `common`, we need to find the common elements between the two lists `l1` and `l2`. We can do this by converting both lists to sets and then finding the intersection of these sets. After finding the common elements, we need to return them as a sorted list. Here's the completed function: ```python def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ # Convert lists to sets to remove duplicates and find the intersection common_elements = set(l1).intersection(set(l2)) # Return the sorted list of common elements return sorted(common_elements) # Example usage: print(common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])) # Output: [1, 5, 653] print(common([5, 3, 2, 8], [3, 2])) # Output: [2, 3] ``` This function will work as expected for the provided examples and any other pair of lists. It's worth noting that the order of the elements in the input lists does not matter, as sets do not preserve order. The `sorted` function is used to return the common elements in ascending order.	passed
kimi	Here's the completed Python code for the `common` function that returns sorted unique common elements for two lists: ```python def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ # Find the common elements using set intersection common_elements = set(l1).intersection(l2) # Convert the set to a sorted list return sorted(list(common_elements)) # Example usage: if __name__ == "__main__": print(common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])) print(common([5, 3, 2, 8], [3, 2])) ``` This function uses set operations to find the common elements between the two lists and then sorts the result. The `set.intersection()` method is used to find the common elements, and `sorted()` is used to sort the resulting list.	passed
wenxinyiyan	Here's the completed code for the `common` function that returns sorted unique common elements for two lists: ```python def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ # Convert lists to sets to remove duplicates set1 = set(l1) set2 = set(l2) # Find the intersection of the two sets common_elements = set1.intersection(set2) # Convert the set of common elements back to a list and sort it sorted_common_elements = sorted(list(common_elements)) return sorted_common_elements ``` You can use this function to find the sorted unique common elements between two lists by passing them as arguments to the `common` function. The function first converts the lists to sets to remove any duplicate elements. Then, it finds the intersection of the two sets using the `intersection` method. Finally, it converts the set of common elements back to a list, sorts it using the `sorted` function, and returns the result.	passed
zhipu	Certainly! Here's the complete Python code for the `common` function that returns sorted unique common elements from two lists: ```python def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ # Find the intersection of the two lists to get common elements common_elements = set(l1).intersection(l2) # Convert the set to a sorted list sorted_common_elements = sorted(list(common_elements)) return sorted_common_elements # Example usage: if __name__ == "__main__": import doctest doctest.testmod() ``` ### Explanation: 1. Intersection of Sets: The `set(l1).intersection(l2)` operation finds the common elements between the two lists by converting them to sets and then finding their intersection. This automatically removes duplicates. 2. Sorting: The `sorted` function is used to sort the resulting set of common elements. 3. Doctest: The `if __name__ == "__main__":` block with `doctest.testmod()` is used to run the examples provided in the docstring as tests. This code will work as expected based on the given examples in the docstring. You can run this script directly, and it will validate the examples using doctest.	passed
gpto1	Here's the completed Python code for the `common` function: ```python def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ # Convert both lists to sets to remove duplicates and allow set operations set1 = set(l1) set2 = set(l2) # Find the intersection of the two sets common_elements = set1 & set2 # or set1.intersection(set2) # Return the sorted list of common elements return sorted(common_elements) ``` Explanation: - Convert lists to sets: By converting the lists `l1` and `l2` to sets (`set1` and `set2`), we eliminate any duplicate elements within each list. - Find common elements: The intersection of `set1` and `set2` (`set1 & set2`) gives us the unique elements that are common to both sets. - Sort the result: We convert the set of common elements back to a list and sort it using the `sorted()` function to get the final result. Example Usage: ```python print(common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])) # Output: [1, 5, 653] print(common([5, 3, 2, 8], [3, 2])) # Output: [2, 3] ```	passed
deepseekv3	To complete the `common` function, we need to find the unique common elements between two lists, sort them, and return the result. Here’s the implementation: ```python def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """ # Convert both lists to sets to find the intersection (common elements) common_elements = set(l1) & set(l2) # Sort the common elements and return them as a list return sorted(common_elements) # Example usage: print(common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])) # Output: [1, 5, 653] print(common([5, 3, 2, 8], [3, 2])) # Output: [2, 3] ``` ### Explanation: 1. Convert Lists to Sets: By converting `l1` and `l2` to sets, we can use the `&` operator to find the intersection of the two sets, which gives us the common elements. 2. Sort the Common Elements: The `sorted()` function is used to sort the common elements in ascending order. 3. Return the Result: The sorted list of common elements is returned. This implementation ensures that the result is both unique and sorted, as required by the function's docstring.	passed

模型

模型答案

测试结果

金声玉亮2.0

Certainly! Below is the complete implementation of the `common` function based on the provided specification:

```python
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
# Convert both lists to sets to get unique elements
set1 = set(l1)
set2 = set(l2)

# Find the intersection of the two sets
common_elements = set1.intersection(set2)

# Convert the set to a sorted list and return
return sorted(common_elements)
```

This function uses sets to find the unique common elements between the two lists and then sorts the result before returning it. The provided examples in the docstring show how the function works.

passed

deepseekr1

To solve this problem, we need to find the common elements between two lists, ensure these elements are unique, and return them in sorted order.

### Approach
1. **Convert Lists to Sets**: By converting each list to a set, we automatically remove any duplicate elements and allow for efficient computation of common elements using set intersection.
2. **Compute Intersection**: The intersection of two sets gives us elements that are present in both sets, which corresponds to the common elements of the original lists.
3. **Sort the Result**: Convert the resulting set of common elements into a sorted list to meet the requirement of returning elements in ascending order.

### Solution Code
```python
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
return sorted(set(l1) & set(l2))
```

### Explanation
- **Conversion to Sets**: Converting `l1` and `l2` to sets removes duplicates and allows the use of set operations.
- **Intersection**: Using the `&` operator on the sets derived from `l1` and `l2` efficiently finds common elements.
- **Sorting**: The `sorted()` function converts the resulting set into a sorted list, ensuring the output is in ascending order.

This approach ensures that we efficiently find unique common elements and return them in the required sorted order.

passed

gpto1

Here's the completed Python code for the `common` function:

```python
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
# Convert both lists to sets to remove duplicates and allow set operations
set1 = set(l1)
set2 = set(l2)

# Find the intersection of the two sets
common_elements = set1 & set2 # or set1.intersection(set2)

# Return the sorted list of common elements
return sorted(common_elements)
```

**Explanation:**

- **Convert lists to sets:** By converting the lists `l1` and `l2` to sets (`set1` and `set2`), we eliminate any duplicate elements within each list.

- **Find common elements:** The intersection of `set1` and `set2` (`set1 & set2`) gives us the unique elements that are common to both sets.

- **Sort the result:** We convert the set of common elements back to a list and sort it using the `sorted()` function to get the final result.

**Example Usage:**

```python
print(common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]))
# Output: [1, 5, 653]

print(common([5, 3, 2, 8], [3, 2]))
# Output: [2, 3]
```

passed

GPT-4o

Certainly! Here is the complete implementation of the `common` function that returns the sorted unique common elements for two lists:

```python
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
# Convert both lists to sets to remove duplicates and find the intersection
set1 = set(l1)
set2 = set(l2)

# Find the common elements using set intersection
common_elements = set1.intersection(set2)

# Convert the set to a sorted list and return it
return sorted(common_elements)

# Example usages:
if __name__ == "__main__":
print(common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])) # Output: [1, 5, 653]
print(common([5, 3, 2, 8], [3, 2])) # Output: [2, 3]
```

This function uses sets to remove duplicates and find the intersection of the two input lists. The resulting set of common elements is then converted to a sorted list before being returned.

passed

llama3.1-70B-Instruct

def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]

"""
return sorted(set(l1) & set(l2))

passed

llama3.1-405B-Instruct

Here is the completed Python code:

```python
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
return sorted(set(l1) & set(l2))
```

Explanation:

* We use the `set` data structure to find the common elements between the two lists. The `&` operator is used to find the intersection of two sets, which returns a new set containing only the elements that are present in both sets.
* We use the `sorted` function to sort the resulting set of common

passed

DeepSeek-Coder-V2

Here's the completed Python function that returns sorted unique common elements for two lists:

```python
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
# Use set intersection to find common elements and convert back to list
common_elements = list(set(l1) & set(l2))
# Sort the list before returning
return sorted(common_elements)

# Test cases
if __name__ == "__main__":
import doctest
doctest.testmod()
```

This function works as follows:
1. It converts both lists to sets to eliminate duplicates and find the intersection of these sets, which gives the common elements.
2. It converts the result back to a list.
3. It sorts the list of common elements.
4. It returns the sorted list of common elements.

The `doctest` module is used to run the test cases provided in the docstring to ensure the function works as expected.

passed

Qwen2-72B-Instruct

Here is a possible solution for the given problem:

```python
def common(l1: list, l2: list):
return sorted(list(set(l1) & set(l2)))

print(common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])) # [1, 5, 653]
print(common([5, 3, 2, 8], [3, 2])) # [2, 3]
```

The function `common` first converts both lists to sets with `set(l1)` and `set(l2)`. The `&` operator is then used to find the intersection of these two sets, i.e., the elements that are common to both sets. This result is then converted back to a list with `list()`, and finally sorted with `sorted()`. This function will return a sorted list of the unique common elements of the two input lists.

passed

baichuan4

To complete the Python code for the `common` function, we need to find the unique common elements between two lists and return them in a sorted order. We can achieve this by converting each list into a set, which automatically removes duplicates, and then performing an intersection of these sets. Finally, we convert the resulting set back into a list and sort it before returning. Here's how you can complete the function:

```python
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
# Convert both lists into sets to remove duplicates and perform intersection
common_elements = set(l1).intersection(set(l2))
# Convert the set of common elements back into a list and sort it
return sorted(list(common_elements))
```

This function first converts `l1` and `l2` into sets using `set(l1)` and `set(l2)`. Then, it finds the intersection of these sets with `.intersection()`, which gives us the common elements. The result is a set, so we convert it into a list with `list(common_elements)` and sort it with `sorted()` before returning. This ensures that the returned list is sorted and contains only unique common elements.

passed

doubao

Here's the completed Python code:

```python
def common(l1: list, l2: list):
return sorted(set(l1) & set(l2))
```

passed

minimax

To complete the function `common`, we need to find the common elements between the two lists `l1` and `l2`. We can do this by converting both lists to sets and then finding the intersection of these sets. After finding the common elements, we need to return them as a sorted list. Here's the completed function:

```python
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
# Convert lists to sets to remove duplicates and find the intersection
common_elements = set(l1).intersection(set(l2))
# Return the sorted list of common elements
return sorted(common_elements)

# Example usage:
print(common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])) # Output: [1, 5, 653]
print(common([5, 3, 2, 8], [3, 2])) # Output: [2, 3]
```

This function will work as expected for the provided examples and any other pair of lists. It's worth noting that the order of the elements in the input lists does not matter, as sets do not preserve order. The `sorted` function is used to return the common elements in ascending order.

passed

kimi

Here's the completed Python code for the `common` function that returns sorted unique common elements for two lists:

```python
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
# Find the common elements using set intersection
common_elements = set(l1).intersection(l2)
# Convert the set to a sorted list
return sorted(list(common_elements))

# Example usage:
if __name__ == "__main__":
print(common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]))
print(common([5, 3, 2, 8], [3, 2]))
```

This function uses set operations to find the common elements between the two lists and then sorts the result. The `set.intersection()` method is used to find the common elements, and `sorted()` is used to sort the resulting list.

passed

wenxinyiyan

Here's the completed code for the `common` function that returns sorted unique common elements for two lists:

```python
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]

"""
# Convert lists to sets to remove duplicates
set1 = set(l1)
set2 = set(l2)

# Find the intersection of the two sets
common_elements = set1.intersection(set2)

# Convert the set of common elements back to a list and sort it
sorted_common_elements = sorted(list(common_elements))

return sorted_common_elements
```
You can use this function to find the sorted unique common elements between two lists by passing them as arguments to the `common` function. The function first converts the lists to sets to remove any duplicate elements. Then, it finds the intersection of the two sets using the `intersection` method. Finally, it converts the set of common elements back to a list, sorts it using the `sorted` function, and returns the result.

passed

zhipu

Certainly! Here's the complete Python code for the `common` function that returns sorted unique common elements from two lists:

```python
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
# Find the intersection of the two lists to get common elements
common_elements = set(l1).intersection(l2)

# Convert the set to a sorted list
sorted_common_elements = sorted(list(common_elements))

return sorted_common_elements

# Example usage:
if __name__ == "__main__":
import doctest
doctest.testmod()
```

### Explanation:
1. **Intersection of Sets**: The `set(l1).intersection(l2)` operation finds the common elements between the two lists by converting them to sets and then finding their intersection. This automatically removes duplicates.
2. **Sorting**: The `sorted` function is used to sort the resulting set of common elements.
3. **Doctest**: The `if __name__ == "__main__":` block with `doctest.testmod()` is used to run the examples provided in the docstring as tests.

This code will work as expected based on the given examples in the docstring. You can run this script directly, and it will validate the examples using doctest.

passed

gpto1

passed

deepseekv3

To complete the `common` function, we need to find the unique common elements between two lists, sort them, and return the result. Here’s the implementation:

```python
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
# Convert both lists to sets to find the intersection (common elements)
common_elements = set(l1) & set(l2)

# Sort the common elements and return them as a list
return sorted(common_elements)

# Example usage:
print(common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])) # Output: [1, 5, 653]
print(common([5, 3, 2, 8], [3, 2])) # Output: [2, 3]
```

### Explanation:
1. **Convert Lists to Sets**: By converting `l1` and `l2` to sets, we can use the `&` operator to find the intersection of the two sets, which gives us the common elements.
2. **Sort the Common Elements**: The `sorted()` function is used to sort the common elements in ascending order.
3. **Return the Result**: The sorted list of common elements is returned.

This implementation ensures that the result is both unique and sorted, as required by the function's docstring.

passed

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