问题

Complete the following python code:

def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.

Examples:
get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
get_row([], 1) == []
get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
"""

答案

模型 模型答案 测试结果
金声玉亮2.0 Certainly! Below is the completed Python code for the `get_row` function based on the provided requirements:

```python
def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.

Examples:
get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
get_row([], 1) == []
get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
"""
coordinates = []

for i, row in enumerate(lst):
for j, value in enumerate(row):
if value == x:
coordinates.append((i, j))

# Sort coordinates by rows in ascending order, and by columns in descending order
coordinates.sort(key=lambda coord: (coord[0], -coord[1]))

return coordinates

# Examples to test the function
print(get_row([
[1, 2, 3, 4, 5, 6],
[1, 2, 3, 4, 1, 6],
[1, 2, 3, 4, 5, 1]
], 1)) # Output: [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]

print(get_row([], 1)) # Output: []

print(get_row([[], [1], [1, 2, 3]], 3)) # Output: [(2, 2)]
```

This function iterates through the 2D list `lst` to find all occurrences of the integer `x` and collects their coordinates. The coordinates are then sorted first by rows in ascending order and then by columns in descending order, as specified.		 passed
deepseekr1

To solve this problem, we need to find all occurrences of a given integer `x` in a nested list (2D list) and return their coordinates sorted by row in ascending order and by column in descending order within each row.

### Approach
1. **Collect Coordinates**: Traverse each element in the nested list and collect the coordinates (row, column) where the element matches the given integer `x`.
2. **Sort Coordinates**: Sort the collected coordinates first by row in ascending order. For coordinates within the same row, sort them by column in descending order. This is achieved by using a custom sorting key that sorts primarily by row and secondarily by the negative of the column index.

### Solution Code

```python
def get_row(lst, x):
coordinates = []
for i, row in enumerate(lst):
for j, val in enumerate(row):
if val == x:
coordinates.append((i, j))
coordinates.sort(key=lambda t: (t[0], -t[1]))
return coordinates
```

### Explanation
1. **Collecting Coordinates**: The code iterates through each row and each element within the row using nested loops. For each element that matches `x`, the coordinates (row index, column index) are recorded.
2. **Sorting Coordinates**: The collected coordinates are sorted using a custom key. The key is a tuple where the first element is the row index (to ensure ascending order) and the second element is the negative of the column index (to ensure descending order within the same row).

This approach efficiently collects and sorts the coordinates, ensuring the required order is maintained. The solution handles edge cases such as empty lists and rows with varying lengths seamlessly.		 passed
gpto1 Here is the complete Python code for the `get_row` function:

```python
def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.

Examples:
get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
get_row([], 1) == []
get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
"""
result = []
for i in range(len(lst)):
row = lst[i]
columns = [j for j in range(len(row)) if row[j] == x]
if columns:
columns.sort(reverse=True)
coordinates = [(i, j) for j in columns]
result.extend(coordinates)
return result
```		 passed
GPT-4o To complete the implementation of the `get_row` function, you need to iterate through the nested list `lst`, identify the coordinates (row, column) where the integer `x` is found, and then sort these coordinates as described. Here is the complete code:

```python
def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.

Examples:
get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
get_row([], 1) == []
get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
"""
# Initialize an empty list to store the coordinates
coordinates = []

# Iterate through each row in the list
for i, row in enumerate(lst):
# Iterate through each element in the row
for j, value in enumerate(row):
# If the value matches x, add the coordinate (i, j) to the list
if value == x:
coordinates.append((i, j))

# Sort the coordinates first by row in ascending order and then by column in descending order
coordinates.sort(key=lambda coord: (coord[0], -coord[1]))

return coordinates

# Example usage
print(get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1)) # Output: [(0, 0), (1, 4), (1,		 failed: invalid syntax (<string>, line 22)
llama3.1-70B-Instruct

def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.

Examples:
get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
get_row([], 1) == []
get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
"""
# Initialize an empty list to store the coordinates
coordinates = []

# Iterate over the rows in the list
for i, row in enumerate(lst):
# Iterate over the elements in the row
for j, element in enumerate(row):
# Check if the element is equal to x
if element == x:
# If it is, add the coordinates to the list
coordinates.append((i, j))

# Sort the coordinates first by row in ascending order
coordinates.sort(key=lambda x: x[0])

# Then sort the coordinates of each row in descending order
for i in range(len(coordinates)):
if i > 0 and coordinates[i][0] == coordinates[i-1][0]:
coordinates[i-1], coordinates[i] = coordinates[i], coordinates[i-1]

return coordinates		 passed
llama3.1-405B-Instruct

def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.

Examples:
get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1		 failed: unterminated triple-quoted string literal (detected at line 74) (<string>, line 25)
DeepSeek-Coder-V2 Here's the complete Python code for the `get_row` function:

```python
def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.

Examples:
get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
get_row([], 1) == []
get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
"""
coordinates = []
for i, row in enumerate(lst):
for j, value in enumerate(row):
if value == x:
coordinates.append((i, j))

# Sort coordinates by rows in ascending order and by columns in descending order within each row
coordinates.sort(key=lambda coord: (coord[0], -coord[1]))

return coordinates

# Example usage:
print(get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1)) # Output: [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]

print(get_row([], 1)) # Output: []

print(get_row([[], [1], [1, 2, 3]], 3)) # Output: [(2, 2)]
```

This function iterates through the nested list `lst` to find all occurrences of the integer `x` and records their coordinates. It then sorts these coordinates first by row in ascending order and then by column in descending order within each row. The sorted list of coordinates is returned.		 passed
Qwen2-72B-Instruct ```python
def get_row(lst, x):
result = []
# Loop through the list to find the integer x
for row_index, row in enumerate(lst):
for col_index, value in enumerate(row):
if value == x:
# Add the coordinates as a tuple to the result list
result.append((row_index, col_index))

# Sort the result list by rows in ascending order and by columns in descending order
result.sort(key=lambda x: (x[0], -x[1]))
return result

# Test cases
print(get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1)) # [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]

print(get_row([], 1)) # []

print(get_row([[], [1], [1, 2, 3]], 3)) # [(2, 2)]
```
This Python function `get_row` takes a nested list `lst` and an integer `x` as input. It searches for the integer `x` in the nested list and returns a list of tuples, where each tuple represents the coordinates (row, column) of the integer `x` in the nested list. The coordinates are sorted initially by rows in ascending order and then by columns in descending order.		 passed
baichuan4 Here's the Python code that completes the `get_row` function according to your specifications:

```python
def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.

Examples:
get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
get_row([], 1) == []
get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
"""
# Find all occurrences of x and their positions
coordinates = []
for row_index, row in enumerate(lst):
for col_index, value in enumerate(row):
if value == x:
coordinates.append((row_index, col_index))

# Sort by rows in ascending order and columns in descending order
coordinates.sort(key=lambda coord: (coord[0], -coord[1]))

return coordinates

# Example usage:
print(get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1)) # Output: [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]

print(get_row([], 1)) # Output: []

print(get_row([[], [1], [1, 2, 3]], 3)) # Output: [(2, 2)]
```

This code defines the `get_row` function which iterates through each row and column of the given 2D list (`lst`) to find all occurrences of the integer `x`. It records the coordinates of these occurrences in a list of tuples. The list of coordinates is then sorted first by the row index in ascending order and then by the column index in descending order. The sorted list of coordinates is then returned.		 passed
doubao Here's the completed Python code:

```python
def get_row(lst, x):
result = []
for i, row in enumerate(lst):
for j, value in enumerate(row):
if value == x:
result.append((i, j))
return sorted(result, key=lambda t: (t[0], -t[1]))
```		 passed
minimax Here's the completed Python function that fulfills the requirements:

```python
def get_row(lst, x):
"""
Find integers x in the list, and return list of tuples,
[(x1, y1), (x2, y2) ...] such that each tuple is a coordinate -
(row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
"""
coordinates = []
for row_index, row in enumerate(lst):
# Find the indices of x in the current row
row_coordinates = [(row_index, col_index) for col_index, value in enumerate(row) if value == x]
# Sort the coordinates of the row by columns in descending order
row_coordinates.sort(key=lambda coord: coord[1], reverse=True)
# Add the row's coordinates to the overall list of coordinates
coordinates.extend(row_coordinates)

# Sort the overall list of coordinates by rows in ascending order
# Since we added the coordinates in reverse order, we need to reverse the list
coordinates.sort(key=lambda coord: coord[0])

return coordinates

# Examples:
print(get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1)) # Output: [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]

print(get_row([], 1)) # Output: []

print(get_row([[], [1], [1, 2, 3]], 3)) # Output: [(2, 2)]
```

This function iterates over each row of the input list `lst`, finds the indices of the integer `x` within each row, and then sorts the coordinates for each row in descending order by columns. After processing all rows, it sorts the overall list of coordinates in ascending order by rows. The function then returns the sorted list of coordinates.		 passed
kimi Here's the completed Python code for the `get_row` function:

```python
def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.

Examples:
get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
get_row([], 1) == []
get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
"""
coordinates = []
for i, row in enumerate(lst):
for j, value in enumerate(row):
if value == x:
coordinates.append((i, j))

# Sort by row in ascending order, then by column in descending order
coordinates.sort(key=lambda coord: (coord[0], -coord[1]))

return coordinates

# Example usage:
print(get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1)) # Output: [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]

print(get_row([], 1)) # Output: []

print(get_row([[], [1], [1, 2, 3]], 3)) # Output: [(2, 2)]
```

This function iterates through each row and column of the given 2D list `lst`, checks if the value at the current position is equal to `x`, and if so, appends the coordinate `(row, column)` to the `coordinates` list. After collecting all the coordinates, it sorts them by row in ascending order and by column in descending order using the `sort` method with a custom `key` function.		 passed
wenxinyiyan Here's the completed Python code for the `get_row` function:


```python
def get_row(lst, x):
result = []
for i, row in enumerate(lst):
coordinates = [(i, j) for j, val in enumerate(row) if val == x]
coordinates.sort(key=lambda coord: coord[1], reverse=True)
result.extend(coordinates)
return sorted(result, key=lambda coord: coord[0])
```
Explanation:

1. Initialize an empty list `result` to store the coordinates of the found integers.
2. Use a `for` loop to iterate over each row in the given nested list `lst`. The `enumerate` function is used to get both the index `i` (representing the row) and the actual row `row`.
3. For each row, create a list comprehension that generates tuples `(i, j)` where `i` is the row index and `j` is the column index for each element in the row that matches the given integer `x`.
4. Sort the generated tuples for the current row by their column index `j` in descending order using the `sort` method with a lambda function as the key.
5. Extend the `result` list with the sorted tuples for the current row using the `extend` method.
6. Finally, return the `result` list, but first sort it by the row index `i` in ascending order using the `sorted` function with a lambda function as the key.

This code will produce the expected output for the given examples.		 passed
zhipu To complete the given Python function `get_row` as per the specifications, you need to iterate through each row and column of the nested list, identify the positions where the integer `x` occurs, and then store these positions as tuples in a list. Finally, you need to sort this list of tuples first by the row index in ascending order and then by the column index in descending order within the same row.

Here's the completed code:

```python
def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.

Examples:
get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
get_row([], 1) == []
get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
"""
coordinates = []

# Iterate through each row and column to find the integer x
for row_index, row in enumerate(lst):
for col_index, value in enumerate(row):
if value == x:
coordinates.append((row_index, col_index))

# Sort the coordinates by row index in ascending order
# and by column index in descending order within the same row
coordinates.sort(key=lambda coord: (coord[0], -coord[1]))

return coordinates

# Example usage:
print(get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1)) # Output: [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
print(get_row([], 1)) # Output: []
print(get_row([[], [1], [1, 2, 3]], 3)) # Output: [(2, 2)]
```

### Explanation:
1. **Initialization**: A list `coordinates` is initialized to store the tuples of coordinates.
2. **Nested Loops**: Two nested loops are used to iterate through each element of the nested list. The outer loop iterates over each row, and the inner loop iterates over each element within the row.
3. **Condition Check**: If the current element matches the integer `x`, a tuple `(row_index, col_index)` is appended to the `coordinates` list.
4. **Sorting**: The `coordinates` list is sorted using the `sort` method with a custom key. The key is a lambda function that sorts primarily by the row index in ascending order and secondarily by the column index in descending order.
5. **Return**: The sorted list of coordinates is returned.

This implementation ensures that the function behaves as specified in the problem statement.		 passed
gpto1 Here is the complete Python code for the `get_row` function:

```python
def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.

Examples:
get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
get_row([], 1) == []
get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
"""
result = []
for i in range(len(lst)):
row = lst[i]
columns = [j for j in range(len(row)) if row[j] == x]
if columns:
columns.sort(reverse=True)
coordinates = [(i, j) for j in columns]
result.extend(coordinates)
return result
```		 passed
deepseekv3 Here is the completed Python code for the `get_row` function:

```python
def get_row(lst, x):
"""
Finds all occurrences of integer x in the 2D list lst and returns their coordinates
as a list of tuples. Coordinates are sorted first by row in ascending order, and then
by column in descending order.
"""
result = []

for row_idx, row in enumerate(lst):
for col_idx, value in enumerate(row):
if value == x:
result.append((row_idx, col_idx))

# Sort the result first by row in ascending order, then by column in descending order
result.sort(key=lambda coord: (coord[0], -coord[1]))

return result

# Test cases
print(get_row([
[1, 2, 3, 4, 5, 6],
[1, 2, 3, 4, 1, 6],
[1, 2, 3, 4, 5, 1]
], 1)) # Output: [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]

print(get_row([], 1)) # Output: []

print(get_row([[], [1], [1, 2, 3]], 3)) # Output: [(2, 2)]
```

### Explanation:
1. **Iterate through the 2D list**: The outer loop iterates through each row, and the inner loop iterates through each element in the row.
2. **Check for the target value**: If the element matches the target value `x`, its coordinates `(row_idx, col_idx)` are added to the result list.
3. **Sort the result**: The result list is sorted first by the row index in ascending order, and then by the column index in descending order using the `sort` method with a custom key.
4. **Return the result**: The sorted list of coordinates is returned.

### Example Walkthrough:
For the first test case:
```python
lst = [
[1, 2, 3, 4, 5, 6],
[1, 2, 3, 4, 1, 6],
[1, 2, 3, 4, 5, 1]
]
x = 1
```
- The function finds `1` at positions `(0, 0)`, `(1, 4)`, `(1, 0)`, `(2, 5)`, and `(2, 0)`.
- After sorting, the output is `[(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]`.

This implementation ensures that the coordinates are returned in the required order.		 passed