金声玉亮2.0模型评测报告

问题

Complete the following python code:

def unique_digits(x):
"""Given a list of positive integers x. return a sorted list of all
elements that hasn't any even digit.

Note: Returned list should be sorted in increasing order.

For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10])
[]
"""

答案

模型	模型答案	测试结果
金声玉亮2.0	Certainly! Below is the completed Python code for the `unique_digits` function: ```python def unique_digits(x): """Given a list of positive integers x, return a sorted list of all elements that haven't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> unique_digits([15, 33, 1422, 1]) [1, 15, 33] >>> unique_digits([152, 323, 1422, 10]) [] """ def has_even_digit(num): """Helper function to check if a number has any even digit.""" return any(int(digit) % 2 == 0 for digit in str(num)) result = [num for num in x if not has_even_digit(num)] return sorted(result) # Example usage: print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33] print(unique_digits([152, 323, 1422, 10])) # Output: [] ``` Explanation: 1. The `has_even_digit` function is a helper function that takes a single number and checks if it has any even digit. It converts the number to a string, iterates through each digit, converts it back to an integer, and checks if it is even. 2. The `unique_digits` function uses a list comprehension to filter out numbers that have any even digit using the `has_even_digit` function. 3. The filtered list is then sorted in increasing order and returned.	passed
deepseekr1	To solve this problem, we need to filter a list of positive integers to find those numbers that consist entirely of odd digits. The result should be a sorted list in increasing order. ### Approach 1. Filter Numbers with All Odd Digits: For each number in the input list, check if all its digits are odd. This can be done by converting the number to a string, iterating over each character (digit), converting it back to an integer, and checking if it is odd. 2. Sort the Result: After filtering out the numbers that contain even digits, sort the remaining numbers in increasing order. ### Solution Code ```python def unique_digits(x): return sorted([n for n in x if all(int(d) % 2 != 0 for d in str(n))]) ``` ### Explanation 1. Filtering Process: The list comprehension `[n for n in x if all(int(d) % 2 != 0 for d in str(n))]` iterates over each number `n` in the input list `x`. For each number, it converts the number to a string to iterate over each digit. Each digit is converted back to an integer and checked if it is odd using `int(d) % 2 != 0`. The `all()` function ensures that all digits meet this condition. 2. Sorting: The `sorted()` function is used to sort the filtered list of numbers in increasing order. This approach efficiently combines filtering and sorting in a concise manner, ensuring clarity and correctness.	passed
gpto1	```python def unique_digits(x): res = [] for n in x: n_str = str(n) for digit in n_str: if digit in '02468': break else: res.append(n) return sorted(res) ```	passed
GPT-4o	Certainly! To complete the function `unique_digits`, we need to iterate through the given list of integers, check each integer for the presence of even digits, and collect those that have only odd digits. Finally, we'll return the sorted list of these integers. Here's the completed function: ```python def unique_digits(x): """Given a list of positive integers x, return a sorted list of all elements that haven't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> unique_digits([15, 33, 1422, 1]) [1, 15, 33] >>> unique_digits([152, 323, 1422, 10]) [] """ def has_even_digit(n): """Check if the number n has any even digit""" while n > 0: digit = n % 10 if digit % 2 == 0: return True n //= 10 return False # Filter out numbers with even digits result = [num for num in x if not has_even_digit(num)] # Return the sorted result return sorted(result) # Test cases print(unique_digits([15, 33, 1422, 1])) # [1, 15, 33] print(unique_digits([152, 323, 1422, 10])) # [] ``` Explanation of the function: 1. Helper Function `has_even_digit(n)`: This function checks if the given number `n` contains any even digits. It does so by iterating through each digit of the number. 2. Filtering: Using a list comprehension, we filter the list `x` to include only those numbers that do not have even digits. 3. Sorting: The filtered list is then sorted in increasing order before being returned. This approach ensures that the function works correctly and efficiently.	passed
llama3.1-70B-Instruct	def unique_digits(x): """Given a list of positive integers x. return a sorted list of all elements that hasn't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> unique_digits([15, 33, 1422, 1]) [1, 15, 33] >>> unique_digits([152, 323, 1422, 10]) [] """ def has_even_digit(n): return any(int(digit) % 2 == 0 for digit in str(n)) return sorted([num for num in x if not has_even_digit(num)])	passed
llama3.1-405B-Instruct	def unique_digits(x): def has_even_digit(n): return any(int(digit) % 2 == 0 for digit in str(n)) return sorted([num for num in x if not has_even_digit(num)])	passed
DeepSeek-Coder-V2	Here's the completed Python function `unique_digits` that meets the specified requirements: ```python def unique_digits(x): """Given a list of positive integers x, return a sorted list of all elements that hasn't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> unique_digits([15, 33, 1422, 1]) [1, 15, 33] >>> unique_digits([152, 323, 1422, 10]) [] """ def has_even_digit(num): for digit in str(num): if int(digit) % 2 == 0: return True return False result = [num for num in x if not has_even_digit(num)] return sorted(result) # Example usage: print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33] print(unique_digits([152, 323, 1422, 10])) # Output: [] ``` This function works as follows: 1. It defines a helper function `has_even_digit` that checks if a given number contains any even digit. 2. It uses a list comprehension to filter out numbers that have even digits. 3. It sorts the resulting list of numbers that do not have any even digits and returns it.	passed
Qwen2-72B-Instruct	Here is the completed Python function: ```python def unique_digits(x): result = [] for num in x: if not any(int(digit) % 2 == 0 for digit in str(num)): result.append(num) return sorted(result) ``` This function goes through each number in the input list, converts it to a string, and checks if any digit is even. If no even digit is found, the number is added to the result list. Finally, the result list is sorted and returned.	passed
baichuan4	To complete the Python code for the `unique_digits` function, we need to iterate through each integer in the input list `x`, check if it contains any even digits, and if not, add it to a new list. Finally, we sort and return this new list. Here's the completed function: ```python def unique_digits(x): """Given a list of positive integers x. return a sorted list of all elements that hasn't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> unique_digits([15, 33, 1422, 1]) [1, 15, 33] >>> unique_digits([152, 323, 1422, 10]) [] """ # Initialize an empty list to store integers without even digits result = [] # Iterate through each integer in the input list for num in x: # Assume the number does not have any even digits until proven otherwise has_even_digit = False # Convert the integer to a string to easily access its digits digits = str(num) # Check each digit of the current integer for digit in digits: # If the digit is even, set the flag to True and break the loop if int(digit) % 2 == 0: has_even_digit = True break # If no even digits were found, add the integer to the result list if not has_even_digit: result.append(num) # Sort the result list in increasing order result.sort() # Return the sorted list return result # Example usage: print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33] print(unique_digits([152, 323, 1422, 10])) # Output: [] ``` This function first initializes an empty list called `result`. It then iterates over each integer in the input list `x`. For each integer, it converts the integer to a string to easily access its individual digits. It then checks each digit to determine if it is even. If an even digit is found, the flag `has_even_digit` is set to `True`, and the loop breaks, moving on to the next integer in `x`. If no even digits are found, the integer is appended to the `result` list. After checking all integers in `x`, the `result` list is sorted and returned.	passed
doubao	Here's the completed Python code: ```python def unique_digits(x): result = [] for num in x: has_even = False for digit in str(num): if int(digit) % 2 == 0: has_even = True break if not has_even: result.append(num) return sorted(result) ```	passed
minimax	To complete the function `unique_digits`, we need to iterate through the list of integers, check each number for even digits, and if a number has no even digits, we add it to a result list. Finally, we return a sorted version of this result list. Here's the completed function: ```python def unique_digits(x): """Given a list of positive integers x, return a sorted list of all elements that haven't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> unique_digits([15, 33, 1422, 1]) [1, 15, 33] >>> unique_digits([152, 323, 1422, 10]) [] """ def has_even_digit(n): """Helper function to check if a number has an even digit.""" while n > 0: if n % 10 % 2 == 0: # Check if the last digit is even return True n //= 10 # Remove the last digit return False # Filter out numbers with even digits and sort the result return sorted([num for num in x if not has_even_digit(num)]) # Example usage: print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33] print(unique_digits([152, 323, 1422, 10])) # Output: [] ``` The `has_even_digit` helper function checks if a number has any even digits by repeatedly taking the last digit of the number and checking if it's even. If it finds an even digit, it returns `True`; otherwise, it returns `False`. The main function uses a list comprehension to filter out numbers that have even digits and then sorts the resulting list before returning it.	passed
kimi	Here's the complete Python code for the function `unique_digits`: ```python def unique_digits(x): """Given a list of positive integers x. return a sorted list of all elements that haven't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> unique_digits([15, 33, 1422, 1]) [1, 15, 33] >>> unique_digits([152, 323, 1422, 10]) [] """ def has_no_even_digits(n): # Check if a number has no even digits return all(int(digit) % 2 != 0 for digit in str(n)) # Filter the list to include only numbers with no even digits filtered_list = [num for num in x if has_no_even_digits(num)] # Sort the filtered list in increasing order filtered_list.sort() return filtered_list # Example usage: print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33] print(unique_digits([152, 323, 1422, 10])) # Output: [] ``` This function defines a nested function `has_no_even_digits` that checks if a number has no even digits by converting each digit to an integer and checking if it's not divisible by 2. It then uses a list comprehension to filter out the numbers with even digits from the input list `x`, sorts the remaining numbers, and returns the sorted list.	passed
wenxinyiyan	Here's the completed Python code for the `unique_digits` function: ```python def unique_digits(x): result = [] for num in x: if all(int(digit) % 2 != 0 for digit in str(num)): result.append(num) return sorted(result) ``` Explanation: 1. We initialize an empty list called `result` to store the elements that satisfy the condition. 2. We iterate over each element `num` in the input list `x`. 3. Inside the loop, we use a generator expression with the `all` function to check if all digits in the current number `num` are odd. We convert `num` to a string using `str(num)` and iterate over each character (digit) in the string. We convert the character back to an integer using `int(digit)` and check if it's odd by computing `int(digit) % 2 != 0`. If all digits are odd, the condition is `True`. 4. If the condition is `True`, we append the current number `num` to the `result` list. 5. Finally, we return the sorted version of the `result` list using the `sorted` function. Now you can call the `unique_digits` function with a list of positive integers, and it will return a sorted list of elements that don't have any even digits.	passed
zhipu	To complete the function `unique_digits`, we need to implement the following steps: 1. Iterate through each number in the list `x`. 2. For each number, check if it contains any even digit. 3. If a number does not contain any even digit, add it to a result list. 4. Finally, return the sorted result list. Here is the complete Python code: ```python def unique_digits(x): """Given a list of positive integers x, return a sorted list of all elements that hasn't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> unique_digits([15, 33, 1422, 1]) [1, 15, 33] >>> unique_digits([152, 323, 1422, 10]) [] """ def has_even_digit(n): """Helper function to check if the number n has any even digit.""" while n > 0: digit = n % 10 if digit % 2 == 0: return True n //= 10 return False # Filter the list to include only numbers without any even digits result = [num for num in x if not has_even_digit(num)] # Return the sorted list return sorted(result) # Example usage: print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33] print(unique_digits([152, 323, 1422, 10])) # Output: [] ``` ### Explanation: - Helper Function `has_even_digit(n)`: - This function takes an integer `n` and checks if it contains any even digit. - It does this by repeatedly taking the last digit of `n` (`n % 10`) and checking if it is even (`digit % 2 == 0`). - If an even digit is found, it returns `True`. - If no even digits are found after checking all digits, it returns `False`. - Main Function `unique_digits(x)`: - It uses a list comprehension to filter out numbers from `x` that do not have any even digits by using the `has_even_digit` function. - The resulting list is then sorted in increasing order using the `sorted()` function. - Finally, the sorted list is returned. This implementation ensures that the function works as specified and handles the examples provided correctly.	passed
gpto1	```python def unique_digits(x): res = [] for n in x: n_str = str(n) for digit in n_str: if digit in '02468': break else: res.append(n) return sorted(res) ```	passed
deepseekv3	To complete the `unique_digits` function, we need to filter out all numbers that contain even digits and then return the remaining numbers sorted in increasing order. Here's the implementation: ```python def unique_digits(x): """Given a list of positive integers x. return a sorted list of all elements that hasn't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> unique_digits([15, 33, 1422, 1]) [1, 15, 33] >>> unique_digits([152, 323, 1422, 10]) [] """ def has_even_digit(n): """Helper function to check if a number has any even digits.""" while n > 0: digit = n % 10 if digit % 2 == 0: return True n = n // 10 return False # Filter out numbers that have even digits result = [num for num in x if not has_even_digit(num)] # Return the sorted result return sorted(result) # Example usage: print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33] print(unique_digits([152, 323, 1422, 10])) # Output: [] ``` ### Explanation: 1. Helper Function (`has_even_digit`): - This function checks if a number has any even digits by iterating through each digit of the number. - If any digit is even, it returns `True`; otherwise, it returns `False`. 2. Filtering: - We use a list comprehension to filter out numbers that have even digits by calling the `has_even_digit` function. 3. Sorting: - The filtered list is then sorted in increasing order using the `sorted()` function. This implementation ensures that only numbers without any even digits are included in the result, and the final list is sorted as required.	passed

模型

模型答案

测试结果

金声玉亮2.0

Certainly! Below is the completed Python code for the `unique_digits` function:

```python
def unique_digits(x):
"""Given a list of positive integers x, return a sorted list of all
elements that haven't any even digit.

Note: Returned list should be sorted in increasing order.

For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10])
[]
"""
def has_even_digit(num):
"""Helper function to check if a number has any even digit."""
return any(int(digit) % 2 == 0 for digit in str(num))

result = [num for num in x if not has_even_digit(num)]
return sorted(result)

# Example usage:
print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33]
print(unique_digits([152, 323, 1422, 10])) # Output: []
```

Explanation:
1. The `has_even_digit` function is a helper function that takes a single number and checks if it has any even digit. It converts the number to a string, iterates through each digit, converts it back to an integer, and checks if it is even.
2. The `unique_digits` function uses a list comprehension to filter out numbers that have any even digit using the `has_even_digit` function.
3. The filtered list is then sorted in increasing order and returned.

passed

deepseekr1

To solve this problem, we need to filter a list of positive integers to find those numbers that consist entirely of odd digits. The result should be a sorted list in increasing order.

### Approach
1. **Filter Numbers with All Odd Digits**: For each number in the input list, check if all its digits are odd. This can be done by converting the number to a string, iterating over each character (digit), converting it back to an integer, and checking if it is odd.
2. **Sort the Result**: After filtering out the numbers that contain even digits, sort the remaining numbers in increasing order.

### Solution Code
```python
def unique_digits(x):
return sorted([n for n in x if all(int(d) % 2 != 0 for d in str(n))])
```

### Explanation
1. **Filtering Process**: The list comprehension `[n for n in x if all(int(d) % 2 != 0 for d in str(n))]` iterates over each number `n` in the input list `x`. For each number, it converts the number to a string to iterate over each digit. Each digit is converted back to an integer and checked if it is odd using `int(d) % 2 != 0`. The `all()` function ensures that all digits meet this condition.
2. **Sorting**: The `sorted()` function is used to sort the filtered list of numbers in increasing order.

This approach efficiently combines filtering and sorting in a concise manner, ensuring clarity and correctness.

passed

gpto1

```python
def unique_digits(x):
res = []
for n in x:
n_str = str(n)
for digit in n_str:
if digit in '02468':
break
else:
res.append(n)
return sorted(res)
```

passed

GPT-4o

Certainly! To complete the function `unique_digits`, we need to iterate through the given list of integers, check each integer for the presence of even digits, and collect those that have only odd digits. Finally, we'll return the sorted list of these integers.

Here's the completed function:

```python
def unique_digits(x):
"""Given a list of positive integers x, return a sorted list of all
elements that haven't any even digit.

Note: Returned list should be sorted in increasing order.

For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10])
[]
"""
def has_even_digit(n):
"""Check if the number n has any even digit"""
while n > 0:
digit = n % 10
if digit % 2 == 0:
return True
n //= 10
return False

# Filter out numbers with even digits
result = [num for num in x if not has_even_digit(num)]

# Return the sorted result
return sorted(result)

# Test cases
print(unique_digits([15, 33, 1422, 1])) # [1, 15, 33]
print(unique_digits([152, 323, 1422, 10])) # []
```

Explanation of the function:
1. **Helper Function `has_even_digit(n)`**: This function checks if the given number `n` contains any even digits. It does so by iterating through each digit of the number.
2. **Filtering**: Using a list comprehension, we filter the list `x` to include only those numbers that do not have even digits.
3. **Sorting**: The filtered list is then sorted in increasing order before being returned.

This approach ensures that the function works correctly and efficiently.

passed

llama3.1-70B-Instruct

def unique_digits(x):
"""Given a list of positive integers x. return a sorted list of all
elements that hasn't any even digit.

Note: Returned list should be sorted in increasing order.

For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10])
[]
"""
def has_even_digit(n):
return any(int(digit) % 2 == 0 for digit in str(n))

return sorted([num for num in x if not has_even_digit(num)])

passed

llama3.1-405B-Instruct

def unique_digits(x):
def has_even_digit(n):
return any(int(digit) % 2 == 0 for digit in str(n))

return sorted([num for num in x if not has_even_digit(num)])

passed

DeepSeek-Coder-V2

Here's the completed Python function `unique_digits` that meets the specified requirements:

```python
def unique_digits(x):
"""Given a list of positive integers x, return a sorted list of all
elements that hasn't any even digit.

Note: Returned list should be sorted in increasing order.

For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10])
[]
"""
def has_even_digit(num):
for digit in str(num):
if int(digit) % 2 == 0:
return True
return False

result = [num for num in x if not has_even_digit(num)]
return sorted(result)

# Example usage:
print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33]
print(unique_digits([152, 323, 1422, 10])) # Output: []
```

This function works as follows:
1. It defines a helper function `has_even_digit` that checks if a given number contains any even digit.
2. It uses a list comprehension to filter out numbers that have even digits.
3. It sorts the resulting list of numbers that do not have any even digits and returns it.

passed

Qwen2-72B-Instruct

Here is the completed Python function:

```python
def unique_digits(x):
result = []
for num in x:
if not any(int(digit) % 2 == 0 for digit in str(num)):
result.append(num)
return sorted(result)
```
This function goes through each number in the input list, converts it to a string, and checks if any digit is even. If no even digit is found, the number is added to the result list. Finally, the result list is sorted and returned.

passed

baichuan4

To complete the Python code for the `unique_digits` function, we need to iterate through each integer in the input list `x`, check if it contains any even digits, and if not, add it to a new list. Finally, we sort and return this new list. Here's the completed function:

```python
def unique_digits(x):
"""Given a list of positive integers x. return a sorted list of all
elements that hasn't any even digit.

Note: Returned list should be sorted in increasing order.

For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10])
[]
"""
# Initialize an empty list to store integers without even digits
result = []

# Iterate through each integer in the input list
for num in x:
# Assume the number does not have any even digits until proven otherwise
has_even_digit = False

# Convert the integer to a string to easily access its digits
digits = str(num)

# Check each digit of the current integer
for digit in digits:
# If the digit is even, set the flag to True and break the loop
if int(digit) % 2 == 0:
has_even_digit = True
break

# If no even digits were found, add the integer to the result list
if not has_even_digit:
result.append(num)

# Sort the result list in increasing order
result.sort()

# Return the sorted list
return result

# Example usage:
print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33]
print(unique_digits([152, 323, 1422, 10])) # Output: []
```

This function first initializes an empty list called `result`. It then iterates over each integer in the input list `x`. For each integer, it converts the integer to a string to easily access its individual digits. It then checks each digit to determine if it is even. If an even digit is found, the flag `has_even_digit` is set to `True`, and the loop breaks, moving on to the next integer in `x`. If no even digits are found, the integer is appended to the `result` list. After checking all integers in `x`, the `result` list is sorted and returned.

passed

doubao

Here's the completed Python code:

```python
def unique_digits(x):
result = []
for num in x:
has_even = False
for digit in str(num):
if int(digit) % 2 == 0:
has_even = True
break
if not has_even:
result.append(num)
return sorted(result)
```

passed

minimax

To complete the function `unique_digits`, we need to iterate through the list of integers, check each number for even digits, and if a number has no even digits, we add it to a result list. Finally, we return a sorted version of this result list. Here's the completed function:

```python
def unique_digits(x):
"""Given a list of positive integers x, return a sorted list of all
elements that haven't any even digit.

Note: Returned list should be sorted in increasing order.

For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10])
[]
"""
def has_even_digit(n):
"""Helper function to check if a number has an even digit."""
while n > 0:
if n % 10 % 2 == 0: # Check if the last digit is even
return True
n //= 10 # Remove the last digit
return False

# Filter out numbers with even digits and sort the result
return sorted([num for num in x if not has_even_digit(num)])

# Example usage:
print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33]
print(unique_digits([152, 323, 1422, 10])) # Output: []
```

The `has_even_digit` helper function checks if a number has any even digits by repeatedly taking the last digit of the number and checking if it's even. If it finds an even digit, it returns `True`; otherwise, it returns `False`. The main function uses a list comprehension to filter out numbers that have even digits and then sorts the resulting list before returning it.

passed

kimi

Here's the complete Python code for the function `unique_digits`:

```python
def unique_digits(x):
"""Given a list of positive integers x. return a sorted list of all
elements that haven't any even digit.

Note: Returned list should be sorted in increasing order.

For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10])
[]
"""
def has_no_even_digits(n):
# Check if a number has no even digits
return all(int(digit) % 2 != 0 for digit in str(n))

# Filter the list to include only numbers with no even digits
filtered_list = [num for num in x if has_no_even_digits(num)]

# Sort the filtered list in increasing order
filtered_list.sort()

return filtered_list

# Example usage:
print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33]
print(unique_digits([152, 323, 1422, 10])) # Output: []
```

This function defines a nested function `has_no_even_digits` that checks if a number has no even digits by converting each digit to an integer and checking if it's not divisible by 2. It then uses a list comprehension to filter out the numbers with even digits from the input list `x`, sorts the remaining numbers, and returns the sorted list.

passed

wenxinyiyan

Here's the completed Python code for the `unique_digits` function:

```python
def unique_digits(x):
result = []
for num in x:
if all(int(digit) % 2 != 0 for digit in str(num)):
result.append(num)
return sorted(result)
```
Explanation:

1. We initialize an empty list called `result` to store the elements that satisfy the condition.
2. We iterate over each element `num` in the input list `x`.
3. Inside the loop, we use a generator expression with the `all` function to check if all digits in the current number `num` are odd. We convert `num` to a string using `str(num)` and iterate over each character (digit) in the string. We convert the character back to an integer using `int(digit)` and check if it's odd by computing `int(digit) % 2 != 0`. If all digits are odd, the condition is `True`.
4. If the condition is `True`, we append the current number `num` to the `result` list.
5. Finally, we return the sorted version of the `result` list using the `sorted` function.

Now you can call the `unique_digits` function with a list of positive integers, and it will return a sorted list of elements that don't have any even digits.

passed

zhipu

To complete the function `unique_digits`, we need to implement the following steps:

1. Iterate through each number in the list `x`.
2. For each number, check if it contains any even digit.
3. If a number does not contain any even digit, add it to a result list.
4. Finally, return the sorted result list.

Here is the complete Python code:

```python
def unique_digits(x):
"""Given a list of positive integers x, return a sorted list of all
elements that hasn't any even digit.

Note: Returned list should be sorted in increasing order.

For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10])
[]
"""
def has_even_digit(n):
"""Helper function to check if the number n has any even digit."""
while n > 0:
digit = n % 10
if digit % 2 == 0:
return True
n //= 10
return False

# Filter the list to include only numbers without any even digits
result = [num for num in x if not has_even_digit(num)]

# Return the sorted list
return sorted(result)

# Example usage:
print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33]
print(unique_digits([152, 323, 1422, 10])) # Output: []
```

### Explanation:
- **Helper Function `has_even_digit(n)`**:
- This function takes an integer `n` and checks if it contains any even digit.
- It does this by repeatedly taking the last digit of `n` (`n % 10`) and checking if it is even (`digit % 2 == 0`).
- If an even digit is found, it returns `True`.
- If no even digits are found after checking all digits, it returns `False`.

- **Main Function `unique_digits(x)`**:
- It uses a list comprehension to filter out numbers from `x` that do not have any even digits by using the `has_even_digit` function.
- The resulting list is then sorted in increasing order using the `sorted()` function.
- Finally, the sorted list is returned.

This implementation ensures that the function works as specified and handles the examples provided correctly.

passed

gpto1

```python
def unique_digits(x):
res = []
for n in x:
n_str = str(n)
for digit in n_str:
if digit in '02468':
break
else:
res.append(n)
return sorted(res)
```

passed

deepseekv3

To complete the `unique_digits` function, we need to filter out all numbers that contain even digits and then return the remaining numbers sorted in increasing order. Here's the implementation:

```python
def unique_digits(x):
"""Given a list of positive integers x. return a sorted list of all
elements that hasn't any even digit.

Note: Returned list should be sorted in increasing order.

For example:
>>> unique_digits([15, 33, 1422, 1])
[1, 15, 33]
>>> unique_digits([152, 323, 1422, 10])
[]
"""
def has_even_digit(n):
"""Helper function to check if a number has any even digits."""
while n > 0:
digit = n % 10
if digit % 2 == 0:
return True
n = n // 10
return False

# Filter out numbers that have even digits
result = [num for num in x if not has_even_digit(num)]

# Return the sorted result
return sorted(result)

# Example usage:
print(unique_digits([15, 33, 1422, 1])) # Output: [1, 15, 33]
print(unique_digits([152, 323, 1422, 10])) # Output: []
```

### Explanation:
1. **Helper Function (`has_even_digit`)**:
- This function checks if a number has any even digits by iterating through each digit of the number.
- If any digit is even, it returns `True`; otherwise, it returns `False`.

2. **Filtering**:
- We use a list comprehension to filter out numbers that have even digits by calling the `has_even_digit` function.

3. **Sorting**:
- The filtered list is then sorted in increasing order using the `sorted()` function.

This implementation ensures that only numbers without any even digits are included in the result, and the final list is sorted as required.

passed