金声玉亮2.0模型评测报告

问题

Complete the following python code:

def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
The order of the list should be ascending by length of each word, and you
should return the list sorted by that rule.
If two words have the same length, sort the list alphabetically.
The function should return a list of strings in sorted order.
You may assume that all words will have the same length.
For example:
assert list_sort(["aa", "a", "aaa"]) => ["aa"]
assert list_sort(["ab", "a", "aaa", "cd"]) => ["ab", "cd"]
"""

答案

模型	模型答案	测试结果
金声玉亮2.0	Sure, here is the complete Python function based on the given description: ```python def sorted_list_sum(lst): """Write a function that accepts a list of strings as a parameter, deletes the strings that have odd lengths from it, and returns the resulted list with a sorted order, The list is always a list of strings and never an array of numbers, and it may contain duplicates. The order of the list should be ascending by length of each word, and you should return the list sorted by that rule. If two words have the same length, sort the list alphabetically. The function should return a list of strings in sorted order. You may assume that all words will have the same length. For example: assert sorted_list_sum(["aa", "a", "aaa"]) => ["aa"] assert sorted_list_sum(["ab", "a", "aaa", "cd"]) => ["ab", "cd"] """ # Filter out strings with odd lengths filtered_lst = [word for word in lst if len(word) % 2 == 0] # Sort the list first alphabetically, then by length sorted_lst = sorted(filtered_lst, key=lambda word: (len(word), word)) return sorted_lst # Example assertions assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"] assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"] ``` This function does the following: 1. Filters out the strings with odd lengths. 2. Sorts the remaining strings first by length and then alphabetically if lengths are the same. 3. Returns the sorted list.	passed
deepseekr1	To solve this problem, we need to filter and sort a list of strings based on specific criteria. The goal is to remove strings with odd lengths and then sort the remaining strings by their length in ascending order. If two strings have the same length, they should be sorted alphabetically. ### Approach 1. Filter the List: First, we iterate through the input list and remove all strings that have an odd length. This is done using a list comprehension that checks if the length of each string is even. 2. Sort the Filtered List: Next, we sort the filtered list. The sorting is done primarily by the length of the strings in ascending order. For strings with the same length, we sort them alphabetically. This is achieved using Python's `sorted` function with a custom key that combines both the length and the string itself. ### Solution Code ```python def sorted_list_sum(lst): filtered = [s for s in lst if len(s) % 2 == 0] return sorted(filtered, key=lambda x: (len(x), x)) ``` ### Explanation 1. Filtering Step: The list comprehension `[s for s in lst if len(s) % 2 == 0]` iterates over each string in the input list and includes it in the new list only if its length is even. This effectively removes all strings with odd lengths. 2. Sorting Step: The `sorted` function is used with a lambda function `lambda x: (len(x), x)` as the key. This key ensures that the primary sorting criterion is the length of the string (ascending order). If two strings have the same length, the secondary criterion is alphabetical order, which is handled by comparing the strings themselves. This approach efficiently combines filtering and sorting to meet the problem requirements, ensuring that the resulting list is both correctly filtered and properly ordered.	passed
gpto1	To complete the given problem, we'll need to follow these steps: 1. Filter out strings with odd lengths from the list. 2. Sort the remaining strings first by their length, and then alphabetically in case of ties. Here's how you can implement it: ```python def list_sort(lst): # Filter out strings with odd lengths lst_even = [s for s in lst if len(s) % 2 == 0] # Sort the list by length and then alphabetically lst_sorted = sorted(lst_even, key=lambda x: (len(x), x)) return lst_sorted ``` Explanation: - We use a list comprehension to create a new list `lst_even` that contains only the strings of even length. - The `sorted()` function is used to sort the list. The `key` parameter is a lambda function that sorts the strings first by their length (`len(x)`) and then alphabetically (`x`) if the lengths are equal. Testing with the examples: ```python assert list_sort(["aa", "a", "aaa"]) == ["aa"] assert list_sort(["ab", "a", "aaa", "cd"]) == ["ab", "cd"] ``` This implementation satisfies all the requirements of the problem, handling any list of strings by removing odd-length strings and sorting the even-length strings appropriately.	failed:
GPT-4o	To complete the function `sorted_list_sum`, we will follow these steps: 1. Filter out the strings that have odd lengths. 2. Sort the remaining strings first by their length and then alphabetically for strings of the same length. 3. Return the sorted list. Here's the complete implementation: ```python def sorted_list_sum(lst): """Write a function that accepts a list of strings as a parameter, deletes the strings that have odd lengths from it, and returns the resulted list with a sorted order, The list is always a list of strings and never an array of numbers, and it may contain duplicates. The order of the list should be ascending by length of each word, and you should return the list sorted by that rule. If two words have the same length, sort the list alphabetically. The function should return a list of strings in sorted order. You may assume that all words will have the same length. For example: assert list_sort(["aa", "a", "aaa"]) => ["aa"] assert list_sort(["ab", "a", "aaa", "cd"]) => ["ab", "cd"] """ # Step 1: Filter out strings with odd lengths even_length_strings = [s for s in lst if len(s) % 2 == 0] # Step 2: Sort the list first by length and then alphabetically sorted_strings = sorted(even_length_strings, key=lambda s: (len(s), s)) return sorted_strings # Example assertions to test the function assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"] assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"] # Additional tests assert sorted_list_sum(["apple", "banana", "cherry", "date"]) == ["banana", "cherry"] assert sorted_list_sum(["even", "odd", "evening", "night"]) == ["even", "night"] ``` In this implementation, the `sorted_list_sum` function: 1. Uses a list comprehension to filter out strings with odd lengths. 2. Sorts the remaining strings by their length and then alphabetically using the `sorted` function with a key that sorts first by length (`len(s)`) and then by the string itself (`s`).	failed:
llama3.1-70B-Instruct	def sorted_list_sum(lst): return sorted([s for s in lst if len(s) % 2 == 0], key=lambda s: (len(s), s))	passed
llama3.1-405B-Instruct	Here is the Python code that meets the requirements: ``` def sorted_list_sum(lst): # Filter out strings with odd lengths filtered_list = [s for s in lst if len(s) % 2 == 0] # Sort the list by length and then alphabetically sorted_list = sorted(filtered_list, key=lambda x: (len(x), x)) return sorted_list ``` Here's an explanation of the code: 1. The first line uses a list comprehension to filter out strings with odd lengths. The condition `len(s) % 2 == 0` checks if the length of the string is even. 2. The second line sorts the filtered list using the `sorted` function. The `key` argument is a lambda function that returns a tuple containing the length of the string and the string itself. This allows the list to be sorted first by length and then alphabetically. 3. The sorted list is returned as the	passed
DeepSeek-Coder-V2	Here's the completed Python function based on the provided description: ```python def sorted_list_sum(lst): # Filter out strings with odd lengths filtered_list = [s for s in lst if len(s) % 2 == 0] # Sort the list first by the length of the strings, then alphabetically sorted_list = sorted(filtered_list, key=lambda x: (len(x), x)) return sorted_list # Example assertions assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"] assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"] ``` This function works as follows: 1. It filters out any strings from the input list that have odd lengths. 2. It sorts the remaining strings first by their length and then alphabetically if they have the same length. 3. It returns the sorted list. The example assertions at the end of the code demonstrate the function's expected behavior.	passed
Qwen2-72B-Instruct	Here is the completed python function: ```python def sorted_list_sum(lst): # Remove strings of odd length lst = [i for i in lst if len(i) % 2 == 0] # Sort list first alphabetically then by length lst = sorted(sorted(lst), key=len) return lst ``` Let's test the function with the examples you provided: ```python print(sorted_list_sum(["aa", "a", "aaa"])) # should return ["aa"] print(sorted_list_sum(["ab", "a", "aaa", "cd"])) # should return ["ab", "cd"] ``` Please note that the function first removes strings of odd length, then sorts the list alphabetically, and finally sorts the list by length. This complies with the instruction to sort the list by length first and alphabetically in case of ties. However, since we assume that all words will have the same length, the alphabetical sorting does not impact the result in the provided examples.	passed
baichuan4	Here's the completed Python function according to your specifications: ```python def sorted_list_sum(lst): """ Accepts a list of strings, deletes strings with odd lengths, and returns a sorted list based on string length and alphabetical order. """ # Filter out strings with odd lengths even_length_strings = [s for s in lst if len(s) % 2 == 0] # Sort the list by string length and then alphabetically sorted_list = sorted(even_length_strings, key=lambda s: (len(s), s)) return sorted_list # Example usage: assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"] assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"] ``` This function first filters out any strings with odd lengths using a list comprehension. It then sorts the remaining strings first by their length and then alphabetically using the `sorted` function with a custom key that is a tuple of string length and the string itself. This ensures that shorter strings come before longer ones, and among strings of the same length, they are sorted alphabetically.	passed
doubao	```python def sorted_list_sum(lst): result = [s for s in lst if len(s) % 2 == 0] result.sort(key=lambda x: (len(x), x)) return result ``` ```	passed
minimax	The provided function signature and docstring contain a few inconsistencies. The function is named `sorted_list_sum` but the docstring describes a function that should delete strings with odd lengths and return a sorted list. The docstring also mentions that the function should return a list of strings in sorted order, but the example assertions use `list_sort` as the function name. I will correct the function name to match the docstring and provide the implementation accordingly. Here is the corrected and completed Python code: ```python def sorted_list_sum(lst): """ Write a function that accepts a list of strings as a parameter, deletes the strings that have odd lengths from it, and returns the resulted list with a sorted order. The list is always a list of strings and never an array of numbers, and it may contain duplicates. The order of the list should be ascending by length of each word, and you should return the list sorted by that rule. If two words have the same length, sort the list alphabetically. The function should return a list of strings in sorted order. You may assume that all words will have the same length. For example: assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"] assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"] """ # Filter out strings with odd lengths even_length_strings = [s for s in lst if len(s) % 2 == 0] # Sort the list first by length and then alphabetically even_length_strings.sort(key=lambda s: (len(s), s)) return even_length_strings # Example usage: assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"] assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"] ``` Please note that the example assertions in the docstring have been updated to match the function name `sorted_list_sum`. The function now filters out strings with odd lengths, sorts the remaining strings by their length and alphabetically, and then returns the sorted list.	passed
kimi	Here is the completed Python code for the function `sorted_list_sum`: ```python def sorted_list_sum(lst): """Write a function that accepts a list of strings as a parameter, deletes the strings that have odd lengths from it, and returns the resulted list with a sorted order, The list is always a list of strings and never an array of numbers, and it may contain duplicates. The order of the list should be ascending by length of each word, and you should return the list sorted by that rule. If two words have the same length, sort the list alphabetically. The function should return a list of strings in sorted order. You may assume that all words will have the same length. For example: assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"] assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"] """ # Filter out strings with odd lengths filtered_list = [s for s in lst if len(s) % 2 == 0] # Sort the list by length and then alphabetically sorted_list = sorted(filtered_list, key=lambda x: (len(x), x)) return sorted_list # Test cases assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"] assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"] # You can also print the results to see them print(sorted_list_sum(["aa", "a", "aaa"])) # Output: ['aa'] print(sorted_list_sum(["ab", "a", "aaa", "cd"])) # Output: ['ab', 'cd'] ``` This function first filters out any strings with odd lengths using a list comprehension. Then it sorts the remaining strings first by their length and then alphabetically using the `sorted` function with a custom `key` function. The `key` function returns a tuple where the first element is the length of the string (to sort by length) and the second element is the string itself (to sort alphabetically if lengths are equal).	passed
wenxinyiyan	The code provided has a few issues and inconsistencies that need to be addressed before it can be completed. First, the function name in the docstring (`list_sort`) does not match the actual function name (`sorted_list_sum`). We should correct this to ensure consistency. Second, the docstring mentions "deletes the strings that have odd lengths from it," but the example assertions seem to suggest that only strings with even lengths should be kept. We will assume that the intent is to keep strings with even lengths based on the examples. Here's the corrected and completed code: ```python def sorted_list_sum(lst): """Write a function that accepts a list of strings as a parameter, deletes the strings that have odd lengths from it, and returns the resulted list with a sorted order. The list is always a list of strings and never an array of numbers, and it may contain duplicates. The order of the list should be ascending by length of each word, and you should return the list sorted by that rule. If two words have the same length, sort the list alphabetically. The function should return a list of strings in sorted order. For example: assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"] assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"] """ # Filter out strings with odd lengths filtered_lst = [s for s in lst if len(s) % 2 == 0] # Sort the filtered list by length and then alphabetically sorted_lst = sorted(filtered_lst, key=lambda s: (len(s), s)) return sorted_lst ``` In this code, we first use a list comprehension to create a new list (`filtered_lst`) that contains only the strings from the input list (`lst`) that have even lengths. We achieve this by checking if the length of each string (`len(s)`) is divisible by 2 without a remainder (`len(s) % 2 == 0`). Next, we use the `sorted` function to sort the filtered list. We pass a `key` parameter to the `sorted` function, which is a lambda function that specifies the sorting criteria. The lambda function takes a string `s` as input and returns a tuple `(len(s), s)`. This means that the list will be sorted first by the length of the strings and then alphabetically if two strings have the same length. Finally, we return the sorted list (`sorted_lst`). Note that I have also corrected the assertion statements in the docstring to use the `==` operator instead of `=>` to check for equality.	passed
zhipu	Certainly! Here's the complete Python code for the function `sorted_list_sum` that meets the specified requirements: ```python def sorted_list_sum(lst): """ Write a function that accepts a list of strings as a parameter, deletes the strings that have odd lengths from it, and returns the resulted list with a sorted order. The list is always a list of strings and never an array of numbers, and it may contain duplicates. The order of the list should be ascending by length of each word, and you should return the list sorted by that rule. If two words have the same length, sort the list alphabetically. The function should return a list of strings in sorted order. You may assume that all words will have the same length. For example: assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"] assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"] """ # Filter out strings with odd lengths filtered_list = [s for s in lst if len(s) % 2 == 0] # Sort the list by length of strings, and then alphabetically sorted_list = sorted(filtered_list, key=lambda x: (len(x), x)) return sorted_list # Example usage: print(sorted_list_sum(["aa", "a", "aaa"])) # Output: ["aa"] print(sorted_list_sum(["ab", "a", "aaa", "cd"])) # Output: ["ab", "cd"] ``` ### Explanation: 1. Filtering Odd Length Strings: - The list comprehension `[s for s in lst if len(s) % 2 == 0]` filters out all strings in the list `lst` that have an odd length. 2. Sorting the List: - The `sorted` function is used with a custom key. The key is a lambda function `lambda x: (len(x), x)` that sorts the strings first by their length and then alphabetically if they have the same length. 3. Return the Sorted List: - The filtered and sorted list is returned. ### Assertions: - The provided examples are used to demonstrate the function's correctness. You can also use assertions to test the function: ```python assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"] assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"] ``` This ensures that the function behaves as expected for the given test cases.	passed
gpto1	To complete the given problem, we'll need to follow these steps: 1. Filter out strings with odd lengths from the list. 2. Sort the remaining strings first by their length, and then alphabetically in case of ties. Here's how you can implement it: ```python def list_sort(lst): # Filter out strings with odd lengths lst_even = [s for s in lst if len(s) % 2 == 0] # Sort the list by length and then alphabetically lst_sorted = sorted(lst_even, key=lambda x: (len(x), x)) return lst_sorted ``` Explanation: - We use a list comprehension to create a new list `lst_even` that contains only the strings of even length. - The `sorted()` function is used to sort the list. The `key` parameter is a lambda function that sorts the strings first by their length (`len(x)`) and then alphabetically (`x`) if the lengths are equal. Testing with the examples: ```python assert list_sort(["aa", "a", "aaa"]) == ["aa"] assert list_sort(["ab", "a", "aaa", "cd"]) == ["ab", "cd"] ``` This implementation satisfies all the requirements of the problem, handling any list of strings by removing odd-length strings and sorting the even-length strings appropriately.	failed:
deepseekv3	Here is the completed Python function based on the given requirements: ```python def sorted_list_sum(lst): # Filter out strings with odd lengths filtered_lst = [word for word in lst if len(word) % 2 == 0] # Sort the filtered list first by length, then alphabetically sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x)) return sorted_lst # Example usage: print(sorted_list_sum(["aa", "a", "aaa"])) # Output: ["aa"] print(sorted_list_sum(["ab", "a", "aaa", "cd"])) # Output: ["ab", "cd"] ``` ### Explanation: 1. Filtering: The list comprehension `[word for word in lst if len(word) % 2 == 0]` removes all strings with odd lengths. 2. Sorting: The `sorted` function is used with a custom key that sorts primarily by the length of the string (`len(x)`) and secondarily by the string itself (`x`) in alphabetical order. 3. Return: The function returns the sorted and filtered list. ### Example Outputs: - `sorted_list_sum(["aa", "a", "aaa"])` returns `["aa"]` because "a" and "aaa" have odd lengths and are removed. - `sorted_list_sum(["ab", "a", "aaa", "cd"])` returns `["ab", "cd"]` because "a" and "aaa" have odd lengths and are removed, and "ab" and "cd" are sorted by length and alphabetically.	passed

模型

模型答案

测试结果

金声玉亮2.0

Sure, here is the complete Python function based on the given description:

```python
def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
The order of the list should be ascending by length of each word, and you
should return the list sorted by that rule.
If two words have the same length, sort the list alphabetically.
The function should return a list of strings in sorted order.
You may assume that all words will have the same length.
For example:
assert sorted_list_sum(["aa", "a", "aaa"]) => ["aa"]
assert sorted_list_sum(["ab", "a", "aaa", "cd"]) => ["ab", "cd"]
"""
# Filter out strings with odd lengths
filtered_lst = [word for word in lst if len(word) % 2 == 0]

# Sort the list first alphabetically, then by length
sorted_lst = sorted(filtered_lst, key=lambda word: (len(word), word))

return sorted_lst

# Example assertions
assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"]
assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
```

This function does the following:
1. Filters out the strings with odd lengths.
2. Sorts the remaining strings first by length and then alphabetically if lengths are the same.
3. Returns the sorted list.

passed

deepseekr1

To solve this problem, we need to filter and sort a list of strings based on specific criteria. The goal is to remove strings with odd lengths and then sort the remaining strings by their length in ascending order. If two strings have the same length, they should be sorted alphabetically.

### Approach
1. **Filter the List**: First, we iterate through the input list and remove all strings that have an odd length. This is done using a list comprehension that checks if the length of each string is even.
2. **Sort the Filtered List**: Next, we sort the filtered list. The sorting is done primarily by the length of the strings in ascending order. For strings with the same length, we sort them alphabetically. This is achieved using Python's `sorted` function with a custom key that combines both the length and the string itself.

### Solution Code
```python
def sorted_list_sum(lst):
filtered = [s for s in lst if len(s) % 2 == 0]
return sorted(filtered, key=lambda x: (len(x), x))
```

### Explanation
1. **Filtering Step**: The list comprehension `[s for s in lst if len(s) % 2 == 0]` iterates over each string in the input list and includes it in the new list only if its length is even. This effectively removes all strings with odd lengths.
2. **Sorting Step**: The `sorted` function is used with a lambda function `lambda x: (len(x), x)` as the key. This key ensures that the primary sorting criterion is the length of the string (ascending order). If two strings have the same length, the secondary criterion is alphabetical order, which is handled by comparing the strings themselves.

This approach efficiently combines filtering and sorting to meet the problem requirements, ensuring that the resulting list is both correctly filtered and properly ordered.

passed

gpto1

To complete the given problem, we'll need to follow these steps:
1. Filter out strings with odd lengths from the list.
2. Sort the remaining strings first by their length, and then alphabetically in case of ties.

Here's how you can implement it:

```python
def list_sort(lst):
# Filter out strings with odd lengths
lst_even = [s for s in lst if len(s) % 2 == 0]
# Sort the list by length and then alphabetically
lst_sorted = sorted(lst_even, key=lambda x: (len(x), x))
return lst_sorted
```

**Explanation:**
- We use a list comprehension to create a new list `lst_even` that contains only the strings of even length.
- The `sorted()` function is used to sort the list. The `key` parameter is a lambda function that sorts the strings first by their length (`len(x)`) and then alphabetically (`x`) if the lengths are equal.

**Testing with the examples:**

```python
assert list_sort(["aa", "a", "aaa"]) == ["aa"]
assert list_sort(["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
```

This implementation satisfies all the requirements of the problem, handling any list of strings by removing odd-length strings and sorting the even-length strings appropriately.

failed:

GPT-4o

To complete the function `sorted_list_sum`, we will follow these steps:

1. Filter out the strings that have odd lengths.
2. Sort the remaining strings first by their length and then alphabetically for strings of the same length.
3. Return the sorted list.

Here's the complete implementation:

```python
def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
The order of the list should be ascending by length of each word, and you
should return the list sorted by that rule.
If two words have the same length, sort the list alphabetically.
The function should return a list of strings in sorted order.
You may assume that all words will have the same length.
For example:
assert list_sort(["aa", "a", "aaa"]) => ["aa"]
assert list_sort(["ab", "a", "aaa", "cd"]) => ["ab", "cd"]
"""

# Step 1: Filter out strings with odd lengths
even_length_strings = [s for s in lst if len(s) % 2 == 0]

# Step 2: Sort the list first by length and then alphabetically
sorted_strings = sorted(even_length_strings, key=lambda s: (len(s), s))

return sorted_strings

# Example assertions to test the function
assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"]
assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"]

# Additional tests
assert sorted_list_sum(["apple", "banana", "cherry", "date"]) == ["banana", "cherry"]
assert sorted_list_sum(["even", "odd", "evening", "night"]) == ["even", "night"]
```

In this implementation, the `sorted_list_sum` function:

1. Uses a list comprehension to filter out strings with odd lengths.
2. Sorts the remaining strings by their length and then alphabetically using the `sorted` function with a key that sorts first by length (`len(s)`) and then by the string itself (`s`).

failed:

llama3.1-70B-Instruct

def sorted_list_sum(lst):
return sorted([s for s in lst if len(s) % 2 == 0], key=lambda s: (len(s), s))

passed

llama3.1-405B-Instruct

Here is the Python code that meets the requirements:
```
def sorted_list_sum(lst):
# Filter out strings with odd lengths
filtered_list = [s for s in lst if len(s) % 2 == 0]

# Sort the list by length and then alphabetically
sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))

return sorted_list
```
Here's an explanation of the code:

1. The first line uses a list comprehension to filter out strings with odd lengths. The condition `len(s) % 2 == 0` checks if the length of the string is even.
2. The second line sorts the filtered list using the `sorted` function. The `key` argument is a lambda function that returns a tuple containing the length of the string and the string itself. This allows the list to be sorted first by length and then alphabetically.
3. The sorted list is returned as the

passed

DeepSeek-Coder-V2

Here's the completed Python function based on the provided description:

```python
def sorted_list_sum(lst):
# Filter out strings with odd lengths
filtered_list = [s for s in lst if len(s) % 2 == 0]

# Sort the list first by the length of the strings, then alphabetically
sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))

return sorted_list

# Example assertions
assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"]
assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
```

This function works as follows:
1. It filters out any strings from the input list that have odd lengths.
2. It sorts the remaining strings first by their length and then alphabetically if they have the same length.
3. It returns the sorted list.

The example assertions at the end of the code demonstrate the function's expected behavior.

passed

Qwen2-72B-Instruct

Here is the completed python function:

```python
def sorted_list_sum(lst):
# Remove strings of odd length
lst = [i for i in lst if len(i) % 2 == 0]
# Sort list first alphabetically then by length
lst = sorted(sorted(lst), key=len)
return lst
```

Let's test the function with the examples you provided:

```python
print(sorted_list_sum(["aa", "a", "aaa"])) # should return ["aa"]
print(sorted_list_sum(["ab", "a", "aaa", "cd"])) # should return ["ab", "cd"]
```

Please note that the function first removes strings of odd length, then sorts the list alphabetically, and finally sorts the list by length. This complies with the instruction to sort the list by length first and alphabetically in case of ties. However, since we assume that all words will have the same length, the alphabetical sorting does not impact the result in the provided examples.

passed

baichuan4

Here's the completed Python function according to your specifications:

```python
def sorted_list_sum(lst):
"""
Accepts a list of strings, deletes strings with odd lengths,
and returns a sorted list based on string length and alphabetical order.
"""
# Filter out strings with odd lengths
even_length_strings = [s for s in lst if len(s) % 2 == 0]

# Sort the list by string length and then alphabetically
sorted_list = sorted(even_length_strings, key=lambda s: (len(s), s))

return sorted_list

# Example usage:
assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"]
assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
```

This function first filters out any strings with odd lengths using a list comprehension. It then sorts the remaining strings first by their length and then alphabetically using the `sorted` function with a custom key that is a tuple of string length and the string itself. This ensures that shorter strings come before longer ones, and among strings of the same length, they are sorted alphabetically.

passed

doubao

```python
def sorted_list_sum(lst):
result = [s for s in lst if len(s) % 2 == 0]
result.sort(key=lambda x: (len(x), x))
return result
```
```

passed

minimax

The provided function signature and docstring contain a few inconsistencies. The function is named `sorted_list_sum` but the docstring describes a function that should delete strings with odd lengths and return a sorted list. The docstring also mentions that the function should return a list of strings in sorted order, but the example assertions use `list_sort` as the function name. I will correct the function name to match the docstring and provide the implementation accordingly.

Here is the corrected and completed Python code:

```python
def sorted_list_sum(lst):
"""
Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order.
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
The order of the list should be ascending by length of each word, and you
should return the list sorted by that rule.
If two words have the same length, sort the list alphabetically.
The function should return a list of strings in sorted order.
You may assume that all words will have the same length.
For example:
assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"]
assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
"""
# Filter out strings with odd lengths
even_length_strings = [s for s in lst if len(s) % 2 == 0]

# Sort the list first by length and then alphabetically
even_length_strings.sort(key=lambda s: (len(s), s))

return even_length_strings

# Example usage:
assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"]
assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
```

Please note that the example assertions in the docstring have been updated to match the function name `sorted_list_sum`. The function now filters out strings with odd lengths, sorts the remaining strings by their length and alphabetically, and then returns the sorted list.

passed

kimi

Here is the completed Python code for the function `sorted_list_sum`:

```python
def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order,
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
The order of the list should be ascending by length of each word, and you
should return the list sorted by that rule.
If two words have the same length, sort the list alphabetically.
The function should return a list of strings in sorted order.
You may assume that all words will have the same length.
For example:
assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"]
assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
"""
# Filter out strings with odd lengths
filtered_list = [s for s in lst if len(s) % 2 == 0]

# Sort the list by length and then alphabetically
sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))

return sorted_list

# Test cases
assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"]
assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"]

# You can also print the results to see them
print(sorted_list_sum(["aa", "a", "aaa"])) # Output: ['aa']
print(sorted_list_sum(["ab", "a", "aaa", "cd"])) # Output: ['ab', 'cd']
```

This function first filters out any strings with odd lengths using a list comprehension. Then it sorts the remaining strings first by their length and then alphabetically using the `sorted` function with a custom `key` function. The `key` function returns a tuple where the first element is the length of the string (to sort by length) and the second element is the string itself (to sort alphabetically if lengths are equal).

passed

wenxinyiyan

The code provided has a few issues and inconsistencies that need to be addressed before it can be completed. First, the function name in the docstring (`list_sort`) does not match the actual function name (`sorted_list_sum`). We should correct this to ensure consistency. Second, the docstring mentions "deletes the strings that have odd lengths from it," but the example assertions seem to suggest that only strings with even lengths should be kept. We will assume that the intent is to keep strings with even lengths based on the examples.

Here's the corrected and completed code:

```python
def sorted_list_sum(lst):
"""Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order.
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
The order of the list should be ascending by length of each word, and you
should return the list sorted by that rule.
If two words have the same length, sort the list alphabetically.
The function should return a list of strings in sorted order.
For example:
assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"]
assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
"""
# Filter out strings with odd lengths
filtered_lst = [s for s in lst if len(s) % 2 == 0]

# Sort the filtered list by length and then alphabetically
sorted_lst = sorted(filtered_lst, key=lambda s: (len(s), s))

return sorted_lst
```
In this code, we first use a list comprehension to create a new list (`filtered_lst`) that contains only the strings from the input list (`lst`) that have even lengths. We achieve this by checking if the length of each string (`len(s)`) is divisible by 2 without a remainder (`len(s) % 2 == 0`).

Next, we use the `sorted` function to sort the filtered list. We pass a `key` parameter to the `sorted` function, which is a lambda function that specifies the sorting criteria. The lambda function takes a string `s` as input and returns a tuple `(len(s), s)`. This means that the list will be sorted first by the length of the strings and then alphabetically if two strings have the same length.

Finally, we return the sorted list (`sorted_lst`).

Note that I have also corrected the assertion statements in the docstring to use the `==` operator instead of `=>` to check for equality.

passed

zhipu

Certainly! Here's the complete Python code for the function `sorted_list_sum` that meets the specified requirements:

```python
def sorted_list_sum(lst):
"""
Write a function that accepts a list of strings as a parameter,
deletes the strings that have odd lengths from it,
and returns the resulted list with a sorted order.
The list is always a list of strings and never an array of numbers,
and it may contain duplicates.
The order of the list should be ascending by length of each word, and you
should return the list sorted by that rule.
If two words have the same length, sort the list alphabetically.
The function should return a list of strings in sorted order.
You may assume that all words will have the same length.

For example:
assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"]
assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
"""
# Filter out strings with odd lengths
filtered_list = [s for s in lst if len(s) % 2 == 0]

# Sort the list by length of strings, and then alphabetically
sorted_list = sorted(filtered_list, key=lambda x: (len(x), x))

return sorted_list

# Example usage:
print(sorted_list_sum(["aa", "a", "aaa"])) # Output: ["aa"]
print(sorted_list_sum(["ab", "a", "aaa", "cd"])) # Output: ["ab", "cd"]
```

### Explanation:
1. **Filtering Odd Length Strings**:
- The list comprehension `[s for s in lst if len(s) % 2 == 0]` filters out all strings in the list `lst` that have an odd length.

2. **Sorting the List**:
- The `sorted` function is used with a custom key. The key is a lambda function `lambda x: (len(x), x)` that sorts the strings first by their length and then alphabetically if they have the same length.

3. **Return the Sorted List**:
- The filtered and sorted list is returned.

### Assertions:
- The provided examples are used to demonstrate the function's correctness. You can also use assertions to test the function:

```python
assert sorted_list_sum(["aa", "a", "aaa"]) == ["aa"]
assert sorted_list_sum(["ab", "a", "aaa", "cd"]) == ["ab", "cd"]
```

This ensures that the function behaves as expected for the given test cases.

passed

gpto1

failed:

deepseekv3

Here is the completed Python function based on the given requirements:

```python
def sorted_list_sum(lst):
# Filter out strings with odd lengths
filtered_lst = [word for word in lst if len(word) % 2 == 0]

# Sort the filtered list first by length, then alphabetically
sorted_lst = sorted(filtered_lst, key=lambda x: (len(x), x))

return sorted_lst

# Example usage:
print(sorted_list_sum(["aa", "a", "aaa"])) # Output: ["aa"]
print(sorted_list_sum(["ab", "a", "aaa", "cd"])) # Output: ["ab", "cd"]
```

### Explanation:
1. **Filtering**: The list comprehension `[word for word in lst if len(word) % 2 == 0]` removes all strings with odd lengths.
2. **Sorting**: The `sorted` function is used with a custom key that sorts primarily by the length of the string (`len(x)`) and secondarily by the string itself (`x`) in alphabetical order.
3. **Return**: The function returns the sorted and filtered list.

### Example Outputs:
- `sorted_list_sum(["aa", "a", "aaa"])` returns `["aa"]` because "a" and "aaa" have odd lengths and are removed.
- `sorted_list_sum(["ab", "a", "aaa", "cd"])` returns `["ab", "cd"]` because "a" and "aaa" have odd lengths and are removed, and "ab" and "cd" are sorted by length and alphabetically.

passed