问题

### Instructions: You are an expert Python programmer. You will be given a question (problem specification) and the first lines of Python solution to this problem, and will write in Python the remaining lines of the program to produce a correct Python program that matches the specification and passes all tests. You will NOT return anything except for the second part of the program that you wrote.
### Question:
You are given a 0-indexed array nums consisting of positive integers.
A partition of an array into one or more contiguous subarrays is called good if no two subarrays contain the same number.
Return the total number of good partitions of nums.
Since the answer may be large, return it modulo 10^9 + 7.

Example 1:

Input: nums = [1,2,3,4]
Output: 8
Explanation: The 8 possible good partitions are: ([1], [2], [3], [4]), ([1], [2], [3,4]), ([1], [2,3], [4]), ([1], [2,3,4]), ([1,2], [3], [4]), ([1,2], [3,4]), ([1,2,3], [4]), and ([1,2,3,4]).

Example 2:

Input: nums = [1,1,1,1]
Output: 1
Explanation: The only possible good partition is: ([1,1,1,1]).

Example 3:

Input: nums = [1,2,1,3]
Output: 2
Explanation: The 2 possible good partitions are: ([1,2,1], [3]) and ([1,2,1,3]).


Constraints:

1 <= nums.length <= 10^5
1 <= nums[i] <= 10^9

### Format: You will use the following starter code to write the solution to the problem and enclose your code within delimiters.
```python
class Solution(object):
def numberOfGoodPartitions(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
MOD = 10**9+7
lookup = {x:i for i, x in enumerate(nums)}
result = 1
right = cnt = 0
for left, x in enumerate(nums):
if left == right+1:
```

### Answer: (enclose your partial completion in backticks. Only write the missing portion of the code, not the entire code. Be very careful to match the appropriate indentation. Directly appending your code after the partial code should produce a correct completion solution.)

答案

模型 模型答案 正确答案
金声玉亮2.0 ```python
cnt += 1
right = max(right, lookup[x])
if left == right:
result = (result * (cnt + 1)) % MOD
cnt = 0
return result
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
deepseek-r1

```python
result = (result * 2) % MOD
right = max(right, lookup[x])
if left == right:
cnt +=1
return pow(2, cnt-1, MOD)
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
gpto1 ```python
result = result * 2 % MOD
right = max(right, lookup[x])
return result
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
gpt-4o-2024-08-06 ```python
result = (result * cnt) % MOD
cnt = 0
right = max(right, lookup[x])
cnt += 1
return result
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
Meta-Llama-3.1-405B-Instruct-Turbo ```python
right = left
if x in lookup and lookup[x] > right:
right = lookup[x]
cnt += 1
else:
result = (result * (cnt + 1)) % MOD
cnt = 0
return (result * (cnt + 1)) % MOD
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
Meta-Llama-3.1-70B-Instruct-Turbo ```python
right = left
cnt = 1
while right + 1 < len(nums) and nums[right + 1] == x:
right += 1
cnt += 1
if cnt > 1:
result = result * cnt % MOD
else:
result = result * (right - left + 1) % MOD
return result
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
DeepSeek-Coder-V2-Lite-Instruct ```python
class Solution(object):
def numberOfGoodPartitions(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
MOD = 10**9+7
lookup = {x:i for i, x in enumerate(nums)}
result = 1
right = cnt = 0
for left, x in enumerate(nums):
if left == right+1:
result = (result * 2) % MOD
right = lookup[x]
elif lookup[x] > right:
right = lookup[x]
cnt += 1
return pow(2, cnt, MOD)
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
Qwen2-72B-Instruct ```python
right = lookup[x]
cnt += 1
else:
while right < len(nums)-1 and nums[right+1] not in nums[left:right+1]:
right += 1
cnt += right - left + 1
result = (result * 2) % MOD if cnt > 1 else result
return result
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
baichuan4 ```python
if x == nums[left-1]:
cnt += 1
else:
result = (result * (cnt+1)) % MOD
cnt = 1
right = lookup[x]
else:
result = (result * (cnt+1)) % MOD
cnt = 1
right = lookup[x]
result = (result * (cnt+1)) % MOD
return result
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
doubao ```python
right = lookup[x]
cnt += 1
result = (result * cnt) % MOD
return result
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
gpto1 ```python
result = result * 2 % MOD
right = max(right, lookup[x])
return result
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
kimi ```python
cnt = cnt | 1 << lookup[x]
while right < len(nums) and (cnt & 1 << lookup[nums[right]]):
cnt &= ~(1 << lookup[nums[right]])
right += 1
result = (result + pow(2, left - right, MOD)) % MOD
return result - 1
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
minimax ```python
class Solution(object):
def numberOfGoodPartitions(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
MOD = 10**9+7
lookup = {x:i for i, x in enumerate(nums)}
result = 1
right = cnt = 0
for left, x in enumerate(nums):
if left == right+1:
right = lookup[x]
cnt = 1
else:
cnt += 1
result = (result * (cnt + 1)) % MOD
return result
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
wenxinyiyan ```python
right += 1
cnt = 1
else:
cnt += 1
last_idx = lookup[x]
lookup[x] = left
if last_idx >= right:
result = (result * cnt) % MOD
right = left + 1
cnt = 1
result = (result * cnt) % MOD
return result
```

### Explanation:

The provided solution uses a sliding window approach to count the number of good partitions. The `lookup` dictionary keeps track of the last seen index for each number in `nums`. The variables `left` and `right` represent the current boundaries of the sliding window, while `cnt` keeps track of the number of elements in the current partition.

The loop iterates over `nums` using the `left` pointer. If `left` is equal to `right + 1`, it means we are starting a new partition, so we increment `right` and reset `cnt` to 1. Otherwise, we increment `cnt` to account for the new element in the current partition.

We then update the `last_idx` for the current number `x` in the `lookup` dictionary and check if it falls within the current partition (i.e., `last_idx >= right`). If it does, it means we have encountered a duplicate number in the current partition, so we need to start a new partition. In this case, we multiply the `result` by `cnt` (the number of elements in the current partition) and update `right` and `cnt` accordingly.

Finally, after the loop, we multiply the `result` by the remaining elements in the last partition (represented by `cnt`) and return the `result` modulo `10^9 + 7` to satisfy the constraint.

Note: The provided solution assumes that the input list `nums` is passed as a parameter to the `numberOfGoodPartitions` method of the `Solution` class, as indicated by the method signature.		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
zhipu ```
result = result * cnt % MOD
cnt = 1
right = max(right, lookup[x])
cnt += 1
return result * cnt % MOD
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)
deepseek-v3 ```python
cnt += 1
right = max(right, lookup[x])
return pow(2, cnt, MOD)
```		 class Solution(object): def numberOfGoodPartitions(self, nums): """ :type nums: List[int] :rtype: int """ MOD = 10**9+7 lookup = {x:i for i, x in enumerate(nums)} result = 1 right = cnt = 0 for left, x in enumerate(nums): if left == right+1: cnt += 1 right = max(right, lookup[x]) return pow(2, cnt, MOD)