问题

### Instructions: You are an expert Python programmer. You will be given a question (problem specification) and the first lines of Python solution to this problem, and will write in Python the remaining lines of the program to produce a correct Python program that matches the specification and passes all tests. You will NOT return anything except for the second part of the program that you wrote.
### Question:
You are given a string word and an integer k.
A substring s of word is complete if:

Each character in s occurs exactly k times.
The difference between two adjacent characters is at most 2. That is, for any two adjacent characters c1 and c2 in s, the absolute difference in their positions in the alphabet is at most 2.

Return the number of complete substrings of word.
A substring is a non-empty contiguous sequence of characters in a string.

Example 1:

Input: word = "igigee", k = 2
Output: 3
Explanation: The complete substrings where each character appears exactly twice and the difference between adjacent characters is at most 2 are: igigee, igigee, igigee.

Example 2:

Input: word = "aaabbbccc", k = 3
Output: 6
Explanation: The complete substrings where each character appears exactly three times and the difference between adjacent characters is at most 2 are: aaabbbccc, aaabbbccc, aaabbbccc, aaabbbccc, aaabbbccc, aaabbbccc.


Constraints:

1 <= word.length <= 10^5
word consists only of lowercase English letters.
1 <= k <= word.length

### Format: You will use the following starter code to write the solution to the problem and enclose your code within delimiters.
```python
class Solution(object):
def countCompleteSubstrings(self, word, k):
"""
:type word: str
:type k: int
:rtype: int
"""
result = valid = 0
cnt = [0]*26
for c in range(1, len(set(word))+1):
left = 0
for right in range(len(word)):
cnt[ord(word[right])-ord('a')] += 1
curr = cnt[ord(word[right])-ord('a')]
valid += 1 if curr == k else -1 if curr == k+1 else 0
if right-left+1 == c*k+1:
curr = cnt[ord(word[left])-ord('a')]
valid -= 1 if curr == k else -1 if curr == k+1 else 0
cnt[ord(word[left])-ord('a')] -= 1
left += 1
if valid == c:
result += 1
if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2:
while left < right+1:
```

### Answer: (enclose your partial completion in backticks. Only write the missing portion of the code, not the entire code. Be very careful to match the appropriate indentation. Directly appending your code after the partial code should produce a correct completion solution.)

答案

模型 模型答案 正确答案
金声玉亮2.0 ```python
curr = cnt[ord(word[left])-ord('a')]
valid -= 1 if curr == k else -1 if curr == k+1 else 0
cnt[ord(word[left])-ord('a')] -= 1
left += 1
left = right + 1
return result
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
deepseek-r1

```
curr = cnt[ord(word[left]) - ord('a')]
valid -= 1 if curr == k else (-1 if curr == k+1 else 0)
cnt[ord(word[left]) - ord('a')] -= 1
left += 1
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
gpto1 ```python
while left < right + 1:
curr = cnt[ord(word[left]) - ord('a')]
valid -= 1 if curr == k else -1 if curr == k + 1 else 0
cnt[ord(word[left]) - ord('a')] -= 1
left += 1
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
gpt-4o-2024-08-06 ```python
curr = cnt[ord(word[left])-ord('a')]
valid -= 1 if curr == k else -1 if curr == k+1 else 0
cnt[ord(word[left])-ord('a')] -= 1
left += 1
cnt = [0]*26
valid = 0
return result
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
Meta-Llama-3.1-405B-Instruct-Turbo ```python
curr = cnt[ord(word[left])-ord('a')]
valid -= 1 if curr == k else -1 if curr == k+1 else 0
cnt[ord(word[left])-ord('a')] -= 1
left += 1
valid = 0
return result
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
Meta-Llama-3.1-70B-Instruct-Turbo ```python
cnt[ord(word[left])-ord('a')] -= 1
left += 1
valid = 0
return result
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
DeepSeek-Coder-V2-Lite-Instruct ```python
class Solution(object):
def countCompleteSubstrings(self, word, k):
"""
:type word: str
:type k: int
:rtype: int
"""
result = valid = 0
cnt = [0]*26
for c in range(1, len(set(word))+1):
left = 0
for right in range(len(word)):
cnt[ord(word[right])-ord('a')] += 1
curr = cnt[ord(word[right])-ord('a')]
valid += 1 if curr == k else -1 if curr == k+1 else 0
if right-left+1 == c*k+1:
curr = cnt[ord(word[left])-ord('a')]
valid -= 1 if curr == k else -1 if curr == k+1 else 0
cnt[ord(word[left])-ord('a')] -= 1
left += 1
if valid == c:
result += 1
if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2:
while left < right+1:
cnt[ord(word[left])-ord('a')] -= 1
left += 1
valid = 0
return result
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
Qwen2-72B-Instruct ```python
curr = cnt[ord(word[left])-ord('a')]
valid -= 1 if curr == k else -1 if curr == k+1 else 0
cnt[ord(word[left])-ord('a')] -= 1
left += 1
valid = 0
return result
```
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
baichuan4 ```python
curr = cnt[ord(word[left])-ord('a')]
valid -= 1 if curr == k else -1 if curr == k+1 else 0
cnt[ord(word[left])-ord('a')] -= 1
left += 1
if valid == c:
result += 1
if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2:
while left < right+1:
curr = cnt[ord(word[left])-ord('a')]
valid -= 1 if curr == k else -1 if curr == k+1 else 0
cnt[ord(word[left])-ord('a')] -= 1
left += 1
if valid == c:
result += 1
return result
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
doubao ```python
cnt[ord(word[left])-ord('a')] -= 1
left += 1
valid -= 1 if cnt[ord(word[left-1])-ord('a')] == k else -1 if cnt[ord(word[left-1])-ord('a')] == k+1 else 0
}
}
}
}
return result
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
gpto1 ```python
while left < right + 1:
curr = cnt[ord(word[left]) - ord('a')]
valid -= 1 if curr == k else -1 if curr == k + 1 else 0
cnt[ord(word[left]) - ord('a')] -= 1
left += 1
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
kimi ```python
curr = cnt[ord(word[left])-ord('a')]
valid -= 1 if curr == k else -1 if curr == k+1 else 0
cnt[ord(word[left])-ord('a')] -= 1
left += 1
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
minimax ```python
cnt[ord(word[left])-ord('a')] -= 1
valid -= 1 if cnt[ord(word[left])-ord('a')] == k else -1 if cnt[ord(word[left])-ord('a')] == k+1 else 0
left += 1
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
wenxinyiyan ```python
curr = cnt[ord(word[left])-ord('a')]
valid -= 1 if curr == k else -1 if curr == k+1 else 0
cnt[ord(word[left])-ord('a')] -= 1
left += 1
valid = 0
cnt = [0]*26
return result
```

### Explanation:

The given starter code attempts to solve the problem using a sliding window approach, but it's incomplete. The missing portion handles the case where the difference between adjacent characters exceeds 2, which requires resetting the window and starting over.

Here's a step-by-step explanation of the missing code:

1. After the inner loop (iterating over `right`) finishes processing a character, we check if the next character (if it exists) has a difference greater than 2 with the current character. This condition is given by `abs(ord(word[right+1])-ord(word[right])) > 2`.

2. If the condition is true, we need to reset the window because the substring we're currently considering cannot be extended further while satisfying the given constraints.

3. To reset the window, we need to:
- Move the `left` pointer forward until it reaches the `right+1` position. This effectively discards all the characters in the current window.
- Decrement the count of each discarded character in the `cnt` array.
- Update the `valid` variable accordingly. If a character's count becomes `k` or `k+1` during this process, we need to adjust `valid` to reflect the change in the number of valid characters.

4. After resetting the window, we set `valid` to 0 and `cnt` to a new array of 26 zeros to prepare for the next substring.

5. Finally, we return the `result`, which represents the total number of complete substrings found.

Note: The provided solution assumes that the input string `word` contains only lowercase English letters, as stated in the constraints. If the input can contain other characters, additional checks or modifications may be necessary.		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
zhipu ```python
curr = cnt[ord(word[left])-ord('a')]
valid -= 1 if curr == k else -1 if curr == k+1 else 0
cnt[ord(word[left])-ord('a')] -= 1
left += 1
valid = 0
cnt = [0]*26
return result
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result
deepseek-v3 ```python
cnt[ord(word[left])-ord('a')] -= 1
left += 1
cnt = [0]*26
valid = 0
return result
```		 class Solution(object): def countCompleteSubstrings(self, word, k): """ :type word: str :type k: int :rtype: int """ result = valid = 0 cnt = [0]*26 for c in range(1, len(set(word))+1): left = 0 for right in range(len(word)): cnt[ord(word[right])-ord('a')] += 1 curr = cnt[ord(word[right])-ord('a')] valid += 1 if curr == k else -1 if curr == k+1 else 0 if right-left+1 == c*k+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 if valid == c: result += 1 if right+1 == len(word) or abs(ord(word[right+1])-ord(word[right])) > 2: while left < right+1: curr = cnt[ord(word[left])-ord('a')] valid -= 1 if curr == k else -1 if curr == k+1 else 0 cnt[ord(word[left])-ord('a')] -= 1 left += 1 return result