问题

### Instructions: You are an expert Python programmer. You will be given a question (problem specification) and will generate a correct Python program that matches the specification and passes all tests. You will NOT return anything except for the program.
### Question:
You are given a 0-indexed integer array nums of size n, and a 0-indexed integer array pattern of size m consisting of integers -1, 0, and 1.
A subarray nums[i..j] of size m + 1 is said to match the pattern if the following conditions hold for each element pattern[k]:

nums[i + k + 1] > nums[i + k] if pattern[k] == 1.
nums[i + k + 1] == nums[i + k] if pattern[k] == 0.
nums[i + k + 1] < nums[i + k] if pattern[k] == -1.

Return the count of subarrays in nums that match the pattern.

Example 1:

Input: nums = [1,2,3,4,5,6], pattern = [1,1]
Output: 4
Explanation: The pattern [1,1] indicates that we are looking for strictly increasing subarrays of size 3. In the array nums, the subarrays [1,2,3], [2,3,4], [3,4,5], and [4,5,6] match this pattern.
Hence, there are 4 subarrays in nums that match the pattern.

Example 2:

Input: nums = [1,4,4,1,3,5,5,3], pattern = [1,0,-1]
Output: 2
Explanation: Here, the pattern [1,0,-1] indicates that we are looking for a sequence where the first number is smaller than the second, the second is equal to the third, and the third is greater than the fourth. In the array nums, the subarrays [1,4,4,1], and [3,5,5,3] match this pattern.
Hence, there are 2 subarrays in nums that match the pattern.


Constraints:

2 <= n == nums.length <= 100
1 <= nums[i] <= 10^9
1 <= m == pattern.length < n
-1 <= pattern[i] <= 1

### Format: You will use the following starter code to write the solution to the problem and enclose your code within delimiters.
```python
class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:

```

### Answer: (use the provided format with backticks)

答案

模型 模型答案 正确答案
金声玉亮2.0 ```python
from typing import List

class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
m = len(pattern)
count = 0

for i in range(len(nums) - m):
match = True
for k in range(m):
if pattern[k] == 1 and nums[i + k + 1] <= nums[i + k]:
match = False
break
if pattern[k] == 0 and nums[i + k + 1] != nums[i + k]:
match = False
break
if pattern[k] == -1 and nums[i + k + 1] >= nums[i + k]:
match = False
break
if match:
count += 1

return count
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
deepseek-r1

```python
from typing import List

class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
# Generate the differences array
diff = []
for j in range(len(nums) - 1):
a, b = nums[j], nums[j+1]
if b > a:
diff.append(1)
elif b == a:
diff.append(0)
else:
diff.append(-1)

m = len(pattern)
if m > len(diff):
return 0

count = 0
# Check each possible starting index in the differences array
for i in range(len(diff) - m + 1):
# Extract the subarray of length m
current = diff[i:i+m]
if current == pattern:
count += 1

return count
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
gpto1 ```python
class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
count = 0
n = len(nums)
m = len(pattern)
for i in range(n - m):
match = True
for k in range(m):
if pattern[k] == 1:
if nums[i + k + 1] <= nums[i + k]:
match = False
break
elif pattern[k] == 0:
if nums[i + k + 1] != nums[i + k]:
match = False
break
elif pattern[k] == -1:
if nums[i + k + 1] >= nums[i + k]:
match = False
break
if match:
count += 1
return count
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
gpt-4o-2024-08-06 ```python
from typing import List

class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
n = len(nums)
m = len(pattern)
count = 0

for i in range(n - m):
match = True
for k in range(m):
if pattern[k] == 1 and not (nums[i + k + 1] > nums[i + k]):
match = False
break
elif pattern[k] == 0 and not (nums[i + k + 1] == nums[i + k]):
match = False
break
elif pattern[k] == -1 and not (nums[i + k + 1] < nums[i + k]):
match = False
break
if match:
count += 1

return count
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
DeepSeek-Coder-V2-Lite-Instruct ```python
from typing import List

class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
n = len(nums)
m = len(pattern)
count = 0

for i in range(n - m):
match = True
for j in range(m):
if (pattern[j] == 1 and nums[i + j + 1] <= nums[i + j]) or \
(pattern[j] == 0 and nums[i + j + 1] != nums[i + j]) or \
(pattern[j] == -1 and nums[i + j + 1] >= nums[i + j]):
match = False
break
if match:
count += 1

return count
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
Meta-Llama-3.1-405B-Instruct-Turbo ```python
from typing import List

class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
n, m = len(nums), len(pattern)
count = 0

for i in range(n - m):
match = True
for j in range(m):
if (pattern[j] == 1 and nums[i + j + 1] <= nums[i + j]) or \
(pattern[j] == 0 and nums[i + j + 1] != nums[i + j]) or \
(pattern[j] == -1 and nums[i + j + 1] >= nums[i + j]):
match = False
break
if match:
count += 1

return count
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
Meta-Llama-3.1-70B-Instruct-Turbo ```python
class Solution:
def numSub(self, nums: List[int], pattern: List[int]) -> int:
n, m = len(nums), len(pattern)
res = 0
for i in range(n - m + 1):
match = True
for j in range(m):
if pattern[j] == 1 and nums[i + j] >= nums[i + j + 1]:
match = False
break
elif pattern[j] == 0 and nums[i + j] != nums[i + j + 1]:
match = False
break
elif pattern[j] == -1 and nums[i + j] <= nums[i + j + 1]:
match = False
break
if match:
res += 1
return res
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
Qwen2-72B-Instruct ```python
class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
n, m = len(nums), len(pattern)
count = 0

for i in range(n-m):
match = True
for j in range(m):
if pattern[j] == 1 and not nums[i+j+1] > nums[i+j]:
match = False
break
elif pattern[j] == 0 and not nums[i+j+1] == nums[i+j]:
match = False
break
elif pattern[j] == -1 and not nums[i+j+1] < nums[i+j]:
match = False
break
if match:
count += 1

return count
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
baichuan4 ```python
from typing import List

class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
m = len(pattern)
count = 0

for i in range(len(nums) - m):
match = True
for j in range(m):
if pattern[j] == 1 and nums[i + j] >= nums[i + j + 1]:
match = False
break
elif pattern[j] == 0 and nums[i + j] != nums[i + j + 1]:
match = False
break
elif pattern[j] == -1 and nums[i + j] <= nums[i + j + 1]:
match = False
break
if match:
count += 1

return count
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
doubao ```python
class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
n = len(nums)
m = len(pattern)
count = 0
for i in range(n - m):
match = True
for j in range(m):
if pattern[j] == 1 and nums[i + j + 1] <= nums[i + j]:
match = False
break
if pattern[j] == -1 and nums[i + j + 1] >= nums[i + j]:
match = False
break
if pattern[j] == 0 and nums[i + j + 1]!= nums[i + j]:
match = False
break
if match:
count += 1
return count
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
gpto1 ```python
class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
count = 0
n = len(nums)
m = len(pattern)
for i in range(n - m):
match = True
for k in range(m):
if pattern[k] == 1:
if nums[i + k + 1] <= nums[i + k]:
match = False
break
elif pattern[k] == 0:
if nums[i + k + 1] != nums[i + k]:
match = False
break
elif pattern[k] == -1:
if nums[i + k + 1] >= nums[i + k]:
match = False
break
if match:
count += 1
return count
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
kimi ```python
class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
n, m = len(nums), len(pattern)
res = 0
for i in range(n - m):
match = True
for j in range(m):
if pattern[j] == 1 and nums[i + j + 1] <= nums[i + j]:
match = False
elif pattern[j] == 0 and nums[i + j + 1] != nums[i + j]:
match = False
elif pattern[j] == -1 and nums[i + j + 1] >= nums[i + j]:
match = False
if match:
res += 1
return res
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
minimax ```python
from typing import List

class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
n = len(nums)
m = len(pattern)
count = 0

# Iterate over the array to find all possible subarrays of size m+1
for i in range(n - m):
# Check if the current subarray matches the pattern
if all(
(nums[i + k + 1] > nums[i + k] if pattern[k] == 1 else
nums[i + k + 1] == nums[i + k] if pattern[k] == 0 else
nums[i + k + 1] < nums[i + k]) for k in range(m)
):
count += 1

return count

# Example usage:
# sol = Solution()
# print(sol.countMatchingSubarrays([1,2,3,4,5,6], [1,1])) # Output: 4
# print(sol.countMatchingSubarrays([1,4,4,1,3,5,5,3], [1,0,-1])) # Output: 2
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
wenxinyiyan ```python
from typing import List

class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
n = len(nums)
m = len(pattern)
count = 0

for i in range(n - m):
match = True
for j in range(m):
if pattern[j] == 1 and nums[i + j + 1] <= nums[i + j]:
match = False
break
elif pattern[j] == 0 and nums[i + j + 1] != nums[i + j]:
match = False
break
elif pattern[j] == -1 and nums[i + j + 1] >= nums[i + j]:
match = False
break
if match:
count += 1

return count
```
This solution iterates over the `nums` array using a sliding window approach. For each starting index `i` from 0 to `n - m - 1`, it checks if the subarray `nums[i:i+m+1]` matches the given `pattern`. The inner loop iterates over the `pattern` array and compares the corresponding elements in the `nums` subarray according to the conditions specified in the problem statement. If any condition is violated, the `match` flag is set to `False` and the inner loop is exited using `break`. If the `match` flag remains `True` after the inner loop, it means the subarray matches the pattern, and the `count` variable is incremented. Finally, the function returns the total count of matching subarrays.		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
zhipu ```python
class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
count = 0
n = len(nums)
m = len(pattern)

for i in range(n - m - 1):
match = True
for k in range(m):
if pattern[k] == 1 and nums[i + k + 1] <= nums[i + k]:
match = False
break
elif pattern[k] == 0 and nums[i + k + 1] != nums[i + k]:
match = False
break
elif pattern[k] == -1 and nums[i + k + 1] >= nums[i + k]:
match = False
break
if match:
count += 1

return count
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]
deepseek-v3 ```python
class Solution:
def countMatchingSubarrays(self, nums: List[int], pattern: List[int]) -> int:
n = len(nums)
m = len(pattern)
count = 0

for i in range(n - m):
match = True
for k in range(m):
if pattern[k] == 1:
if nums[i + k + 1] <= nums[i + k]:
match = False
break
elif pattern[k] == 0:
if nums[i + k + 1] != nums[i + k]:
match = False
break
elif pattern[k] == -1:
if nums[i + k + 1] >= nums[i + k]:
match = False
break
if match:
count += 1

return count
```		 [{"input": "[1, 2, 3, 4, 5, 6]\n[1, 1]", "output": "4", "testtype": "functional"}, {"input": "[1, 4, 4, 1, 3, 5, 5, 3]\n[1, 0, -1]", "output": "2", "testtype": "functional"}]