问题

### Instructions: You are an expert Python programmer. You will be given a question (problem specification) and will generate a correct Python program that matches the specification and passes all tests. You will NOT return anything except for the program.
### Question:
An ant is on a boundary. It sometimes goes left and sometimes right.
You are given an array of non-zero integers nums. The ant starts reading nums from the first element of it to its end. At each step, it moves according to the value of the current element:

If nums[i] < 0, it moves left by -nums[i] units.
If nums[i] > 0, it moves right by nums[i] units.

Return the number of times the ant returns to the boundary.
Notes:

There is an infinite space on both sides of the boundary.
We check whether the ant is on the boundary only after it has moved |nums[i]| units. In other words, if the ant crosses the boundary during its movement, it does not count.


Example 1:

Input: nums = [2,3,-5]
Output: 1
Explanation: After the first step, the ant is 2 steps to the right of the boundary.
After the second step, the ant is 5 steps to the right of the boundary.
After the third step, the ant is on the boundary.
So the answer is 1.

Example 2:

Input: nums = [3,2,-3,-4]
Output: 0
Explanation: After the first step, the ant is 3 steps to the right of the boundary.
After the second step, the ant is 5 steps to the right of the boundary.
After the third step, the ant is 2 steps to the right of the boundary.
After the fourth step, the ant is 2 steps to the left of the boundary.
The ant never returned to the boundary, so the answer is 0.


Constraints:

1 <= nums.length <= 100
-10 <= nums[i] <= 10
nums[i] != 0

### Format: You will use the following starter code to write the solution to the problem and enclose your code within delimiters.
```python
class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:

```

### Answer: (use the provided format with backticks)

答案

模型 模型答案 正确答案
金声玉亮2.0 ```python
from typing import List

class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0
count = 0

for num in nums:
position += num
if position == 0:
count += 1

return count
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
deepseek-r1

```python
from typing import List

class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0
count = 0
for num in nums:
position += num
if position == 0:
count += 1
return count
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
gpto1 ```python
class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0
count = 0
for num in nums:
position += num
if position == 0:
count += 1
return count
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
gpt-4o-2024-08-06 ```python
class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0
boundary_count = 0

for move in nums:
position += move
if position == 0:
boundary_count += 1

return boundary_count
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
DeepSeek-Coder-V2-Lite-Instruct ```python
from typing import List

class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0
boundary_crossings = 0

for num in nums:
position += num
if position == 0 or position == len(nums):
boundary_crossings += 1

return boundary_crossings
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
Meta-Llama-3.1-405B-Instruct-Turbo ```python
from typing import List

class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0
count = 0
for num in nums:
position += num
if position == 0:
count += 1
return count
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
Meta-Llama-3.1-70B-Instruct-Turbo ```python
class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0
count = 0
for num in nums:
position += num
if position == 0:
count += 1
return count
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
Qwen2-72B-Instruct ```python
class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0
count = 0

for num in nums:
position += num

if position == 0:
count += 1

return count
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
baichuan4 ```python
class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0
count = 0
for move in nums:
position += move
if position == 0:
count += 1
return count
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
doubao ```python
class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0
count = 0
for num in nums:
if num > 0:
position += num
elif num < 0:
position -= num
if position == 0:
count += 1
return count
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
gpto1 ```python
class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0
count = 0
for num in nums:
position += num
if position == 0:
count += 1
return count
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
kimi ```python
class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
pos = 0
count = 0
for num in nums:
if num > 0:
pos += num
else:
pos += num
if pos == 0:
count += 1
elif pos == 0:
count += 1
return count
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
minimax ```python
from typing import List

class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0 # Start at the boundary
boundary_crossings = 0

for step in nums:
# Move the ant according to the value of the current element
position += step

# Check if the ant has crossed the boundary
if position == 0:
boundary_crossings += 1
# Reset the position to the boundary
position = 0

return boundary_crossings

# Example usage:
# sol = Solution()
# print(sol.returnToBoundaryCount([2,3,-5])) # Output: 1
# print(sol.returnToBoundaryCount([3,2,-3,-4])) # Output: 0
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
wenxinyiyan ```python
class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
count = 0 # Initialize the count of returns to the boundary
position = 0 # Initialize the ant's position on the boundary

for num in nums:
position += num # Move the ant according to the current element

# Check if the ant is on the boundary after moving
if position == 0:
count += 1

return count
```
This program defines a class `Solution` with a method `returnToBoundaryCount` that takes an array of non-zero integers `nums` as input and returns the number of times the ant returns to the boundary. The program uses a `count` variable to keep track of the number of returns and a `position` variable to track the ant's current position. It iterates over the elements of `nums`, updates the ant's position accordingly, and checks if the ant is on the boundary after each move. If the ant is on the boundary, it increments the `count` variable. Finally, it returns the total count of returns to the boundary.		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
zhipu ```python
class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0
boundary_count = 0

for num in nums:
position += num
if position == 0:
boundary_count += 1

return boundary_count
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]
deepseek-v3 ```python
class Solution:
def returnToBoundaryCount(self, nums: List[int]) -> int:
position = 0
count = 0
for num in nums:
position += num
if position == 0:
count += 1
return count
```		 [{"input": "[2, 3, -5]", "output": "1", "testtype": "functional"}, {"input": "[3, 2, -3, -4]", "output": "0", "testtype": "functional"}]