问题

Compute the sample standard deviation of ${4, -19}$. Please put your final answer in a $\\boxed{}$.

答案

模型 模型答案 正确答案
金声玉亮2.0 The sample standard deviation, denoted as \(s\), is calculated using the formula:

\[
s = \sqrt{\frac{1}{n-1} \sum_{i=1}^{n} (x_i - \bar{x})^2}
\]

where \(n\) is the number of observations, \(\bar{x}\) is the sample mean, and \(x_i\) represents each individual observation.

Given the dataset \({4, -19}\):

1. Calculate the mean (\(\bar{x}\)):

\[
\bar{x} = \frac{4 + (-19)}{2} = \frac{-15}{2} = -7.5
\]

2. Calculate the squared deviations from the mean for each observation:

- For \(x_1 = 4\):

\[
(x_1 - \bar{x})^2 = (4 - (-7.5))^2 = (11.5)^2 = 132.25
\]

- For \(x_2 = -19\):

\[
(x_2 - \bar{x})^2 = (-19 - (-7.5))^2 = (-11.5)^2 = 132.25
\]

3. Calculate the sum of these squared deviations:

\[
\sum_{i=1}^{n} (x_i - \bar{x})^2 = 132.25 + 132.25 = 264.5
\]

4. Calculate the sample standard deviation:

\[
s = \sqrt{\frac{1}{n-1} \sum_{i=1}^{n} (x_i - \bar{x})^2} = \sqrt{\frac{1}{2-1} \cdot 264.5} = \sqrt{264.5} \approx 16.26
\]

Thus, the sample standard deviation is approximately \(16.26\).

\[
\boxed{16.26}
\]
\frac{23}{\sqrt{2}}
deepseek-r1

To compute the sample standard deviation of the data set \(\{4, -19\}\), follow these steps:

1. **Calculate the mean**:
\[
\text{Mean} (\bar{x}) = \frac{4 + (-19)}{2} = \frac{-15}{2} = -7.5
\]

2. **Find the deviations from the mean**:
\[
4 - (-7.5) = 11.5 \quad \text{and} \quad -19 - (-7.5) = -11.5
\]

3. **Square each deviation**:
\[
(11.5)^2 = 132.25 \quad \text{and} \quad (-11.5)^2 = 132.25
\]

4. **Sum the squared deviations**:
\[
132.25 + 132.25 = 264.5
\]

5. **Calculate the sample variance**:
\[
\text{Variance} (s^2) = \frac{264.5}{2 - 1} = 264.5
\]

6. **Take the square root to get the sample standard deviation**:
\[
\text{Standard Deviation} (s) = \sqrt{264.5} = \sqrt{\frac{529}{2}} = \frac{23\sqrt{2}}{2}
\]

Thus, the sample standard deviation of the data set is \(\boxed{\dfrac{23\sqrt{2}}{2}}\).
\frac{23}{\sqrt{2}}
gpto1 To compute the sample standard deviation of the data set {4, -19}, we first find the sample mean (\( \bar{x} \)):

\[
\bar{x} = \frac{4 + (-19)}{2} = \frac{-15}{2} = -7.5
\]

Next, we calculate the squared differences from the mean for each data point:

\[
(4 - (-7.5))^2 = (11.5)^2 = 132.25
\]
\[
(-19 - (-7.5))^2 = (-11.5)^2 = 132.25
\]

Sum of squared differences:

\[
\sum (x_i - \bar{x})^2 = 132.25 + 132.25 = 264.5
\]

Since the sample size \( n = 2 \), the sample variance (\( s^2 \)) is:

\[
s^2 = \frac{\sum (x_i - \bar{x})^2}{n - 1} = \frac{264.5}{1} = 264.5
\]

Finally, the sample standard deviation (\( s \)) is:

\[
s = \sqrt{264.5} = \sqrt{\frac{529}{2}} = \frac{\sqrt{529}}{\sqrt{2}} = \frac{23}{\sqrt{2}} = \frac{23\sqrt{2}}{2}
\]

**Answer:**
\boxed{\dfrac{23\sqrt{2}}{2}}
\frac{23}{\sqrt{2}}
gpt-4o-2024-08-06 To compute the sample standard deviation of the data set \(\{4, -19\}\), we follow these steps:

1. **Calculate the sample mean**:
\[
\bar{x} = \frac{4 + (-19)}{2} = \frac{4 - 19}{2} = \frac{-15}{2} = -7.5
\]

2. **Calculate the squared deviations from the mean**:
- For \(x_1 = 4\):
\[
(x_1 - \bar{x})^2 = (4 - (-7.5))^2 = (4 + 7.5)^2 = 11.5^2 = 132.25
\]
- For \(x_2 = -19\):
\[
(x_2 - \bar{x})^2 = (-19 - (-7.5))^2 = (-19 + 7.5)^2 = (-11.5)^2 = 132.25
\]

3. **Calculate the sample variance**:
\[
s^2 = \frac{1}{n-1} \sum_{i=1}^{n} (x_i - \bar{x})^2 = \frac{1}{2-1} (132.25 + 132.25) = \frac{1}{1} \times 264.5 = 264.5
\]

4. **Calculate the sample standard deviation**:
\[
s = \sqrt{s^2} = \sqrt{264.5}
\]

5. **Compute the square root**:
\[
\sqrt{264.5} \approx 16.26
\]

Thus, the sample standard deviation is \(\boxed{16.26}\).
\frac{23}{\sqrt{2}}
DeepSeek-Coder-V2-Lite-Instruct To compute the sample standard deviation of the data set \(\{4, -19\}\), we follow these steps:

1. **Calculate the mean (average) of the data set:**
\[
\text{Mean} = \frac{4 + (-19)}{2} = \frac{4 - 19}{2} = \frac{-15}{2} = -7.5
\]

2. **Calculate the variance:**
The variance is the average of the squared differences from the mean. First, find the squared differences from the mean:
\[
(4 - (-7.5))^2 = (4 + 7.5)^2 = 11.5^2 = 132.25
\]
\[
(-19 - (-7.5))^2 = (-19 + 7.5)^2 = -11.5^2 = 132.25
\]
Now, average these squared differences:
\[
\text{Variance} = \frac{132.25 + 132.25}{2} = \frac{264.5}{2} = 132.25
\]

3. **Calculate the standard deviation:**
The standard deviation is the square root of the variance:
\[
\text{Standard Deviation} = \sqrt{132.25} = 11.5
\]

Thus, the sample standard deviation of \(\{4, -19\}\) is \(\boxed{11.5}\).
\frac{23}{\sqrt{2}}
Meta-Llama-3.1-405B-Instruct-Turbo ## Step 1: Calculate the mean of the given numbers
To find the sample standard deviation, we first need to calculate the mean of the given numbers. The mean is calculated by adding all the numbers together and then dividing by the total count of numbers. In this case, the numbers are 4 and -19. So, the mean is (4 + (-19)) / 2 = -15 / 2 = -7.5.

## Step 2: Calculate the deviations from the mean
Next, we need to calculate the deviations of each number from the mean. This is done by subtracting the mean from each number. So, the deviations are (4 - (-7.5)) and (-19 - (-7.5)), which simplifies to 11.5 and -11.5.

## Step 3: Calculate the squared deviations
Now, we need to square each deviation. Squaring the deviations gives us (11.5)^2 and (-11.5)^2, which both equal 132.25.

## Step 4: Calculate the sum of the squared deviations
We then calculate the sum of these squared deviations, which is 132.25 + 132.25 = 264.5.

## Step 5: Calculate the variance
To find the sample variance, we divide the sum of the squared deviations by the total count of numbers minus one. In this case, we divide by 2 - 1 = 1. So, the variance is 264.5 / 1 = 264.5.

## Step 6: Calculate the sample standard deviation
Finally, we find the sample standard deviation by taking the square root of the variance. The square root of 264.5 is approximately 16.27.

The final answer is: $\boxed{16.27}$
\frac{23}{\sqrt{2}}
Meta-Llama-3.1-70B-Instruct-Turbo ## Step 1: Calculate the mean of the given numbers
To find the sample standard deviation, we first need to calculate the mean of the given numbers. The mean is calculated by summing all the numbers and then dividing by the total count of numbers. In this case, the numbers are 4 and -19. So, the mean is (4 + (-19)) / 2 = -15 / 2 = -7.5.

## Step 2: Subtract the mean from each number to find the deviations
Next, we subtract the mean from each number to find the deviations from the mean. For 4, the deviation is 4 - (-7.5) = 11.5. For -19, the deviation is -19 - (-7.5) = -11.5.

## Step 3: Square each deviation
Now, we square each deviation. The squared deviation for 4 is (11.5)^2 = 132.25. The squared deviation for -19 is (-11.5)^2 = 132.25.

## Step 4: Calculate the average of the squared deviations
We then calculate the average of the squared deviations. Since we are calculating the sample standard deviation, we divide by the number of items minus one (n-1), which in this case is 2-1 = 1. So, the average of the squared deviations is (132.25 + 132.25) / 1 = 264.5.

## Step 5: Take the square root of the average of the squared deviations
Finally, we take the square root of the average of the squared deviations to find the sample standard deviation. The square root of 264.5 is approximately 16.26.

The final answer is: $\boxed{16.26}$
\frac{23}{\sqrt{2}}
Qwen2-72B-Instruct To compute the sample standard deviation of a set of numbers, we follow these steps:

1. Calculate the mean (average) of the numbers.
2. Subtract the mean from each number to find the deviation of each number.
3. Square each deviation.
4. Find the average of these squared deviations (this is called the variance).
5. Take the square root of the variance to get the standard deviation.

Given the set ${4, -19}$:

1. The mean is $\frac{4 + (-19)}{2} = \frac{-15}{2} = -7.5$.
2. The deviations are $4 - (-7.5) = 11.5$ and $-19 - (-7.5) = -11.5$.
3. Squaring the deviations gives $11.5^2 = 132.25$ and $(-11.5)^2 = 132.25$.
4. The average of these squared deviations (variance) is $\frac{132.25 + 132.25}{2} = 132.25$.
5. The square root of the variance (standard deviation) is $\sqrt{132.25} \approx 11.5$.

Therefore, the sample standard deviation of ${4, -19}$ is approximately $11.5$.

\[
\boxed{11.5}
\]
\frac{23}{\sqrt{2}}
baichuan4 To compute the sample standard deviation of a set of numbers, we first need to calculate the mean (average) of the numbers, then find the squared differences between each number and the mean, take the average of those squared differences, and finally take the square root of that average.

Given the two numbers in the set: 4 and -19, we can proceed with the steps:

1. Calculate the mean:
Mean = (4 + (-19)) / 2 = -15 / 2 = -7.5

2. Find the squared differences between each number and the mean:
For 4: (4 - (-7.5))^2 = (4 + 7.5)^2 = 11.5^2 = 132.25
For -19: (-19 - (-7.5))^2 = (-19 + 7.5)^2 = (-11.5)^2 = 132.25

3. Take the average of the squared differences:
Average of squared differences = (132.25 + 132.25) / 2 = 264.5 / 2 = 132.25

4. Take the square root of the average of the squared differences to get the sample standard deviation:
Sample standard deviation = √132.25 ≈ 11.5

Therefore, the sample standard deviation of the set {4, -19} is approximately 11.5.

Final answer: $ \boxed{11.5} $
\frac{23}{\sqrt{2}}
doubao First find the mean: $(4 + (-19)) \div 2 = (-15) \div 2 = -7.5$.

Then find the deviations from the mean: $4 - (-7.5) = 11.5$ and $-19 - (-7.5) = -11.5$.

Square the deviations: $11.5^2 = 132.25$ and $(-11.5)^2 = 132.25$.

Find the mean of the squared deviations: $(132.25 + 132.25) \div 2 = 132.25$.

The sample standard deviation is the square root of the mean of the squared deviations: $\sqrt{132.25} = 11.5$.

So the answer is $\boxed{11.5}$.
\frac{23}{\sqrt{2}}
gpto1 To compute the sample standard deviation of the data set {4, -19}, we first find the sample mean (\( \bar{x} \)):

\[
\bar{x} = \frac{4 + (-19)}{2} = \frac{-15}{2} = -7.5
\]

Next, we calculate the squared differences from the mean for each data point:

\[
(4 - (-7.5))^2 = (11.5)^2 = 132.25
\]
\[
(-19 - (-7.5))^2 = (-11.5)^2 = 132.25
\]

Sum of squared differences:

\[
\sum (x_i - \bar{x})^2 = 132.25 + 132.25 = 264.5
\]

Since the sample size \( n = 2 \), the sample variance (\( s^2 \)) is:

\[
s^2 = \frac{\sum (x_i - \bar{x})^2}{n - 1} = \frac{264.5}{1} = 264.5
\]

Finally, the sample standard deviation (\( s \)) is:

\[
s = \sqrt{264.5} = \sqrt{\frac{529}{2}} = \frac{\sqrt{529}}{\sqrt{2}} = \frac{23}{\sqrt{2}} = \frac{23\sqrt{2}}{2}
\]

**Answer:**
\boxed{\dfrac{23\sqrt{2}}{2}}
\frac{23}{\sqrt{2}}
kimi To compute the sample standard deviation of the dataset \(\{4, -19\}\), we will follow these steps:

1. **Calculate the mean (\(\bar{x}\))**:
The mean is the sum of all the values divided by the number of values.
\[
\bar{x} = \frac{4 + (-19)}{2} = \frac{4 - 19}{2} = \frac{-15}{2} = -7.5
\]

2. **Calculate the squared differences from the mean**:
For each value \(x_i\), compute \((x_i - \bar{x})^2\).
\[
(4 - (-7.5))^2 = (4 + 7.5)^2 = 11.5^2 = 132.25
\]
\[
(-19 - (-7.5))^2 = (-19 + 7.5)^2 = (-11.5)^2 = 132.25
\]

3. **Calculate the sum of the squared differences**:
Add the squared differences together.
\[
132.25 + 132.25 = 264.5
\]

4. **Calculate the sample variance**:
The sample variance \(s^2\) is the sum of the squared differences divided by \(n-1\) (where \(n\) is the number of values).
\[
s^2 = \frac{264.5}{2-1} = \frac{264.5}{1} = 264.5
\]

5. **Calculate the sample standard deviation**:
The sample standard deviation \(s\) is the square root of the sample variance.
\[
s = \sqrt{264.5}
\]

To find the exact value:
\[
s \approx 16.26
\]

Therefore, the sample standard deviation of the dataset \(\{4, -19\}\) is \(\boxed{16.26}\).
\frac{23}{\sqrt{2}}
minimax To compute the sample standard deviation of the set ${4, -19}$, we will follow these steps:

1. Find the mean (average) of the numbers.
2. Subtract the mean from each number to find the deviation of each number from the mean.
3. Square each of these deviations.
4. Find the mean of these squared deviations.
5. Take the square root of this mean to get the sample standard deviation.

Let's go through these steps:

1. Calculate the mean:
$$ \text{mean} = \frac{4 + (-19)}{2} = \frac{-15}{2} = -7.5 $$

2. Calculate the deviations from the mean and square them:
$$ (4 - (-7.5))^2 = (4 + 7.5)^2 = (11.5)^2 = 132.25 $$
$$ (-19 - (-7.5))^2 = (-19 + 7.5)^2 = (-11.5)^2 = 132.25 $$

3. Calculate the mean of these squared deviations:
$$ \text{mean of squared deviations} = \frac{132.25 +
\frac{23}{\sqrt{2}}
wenxinyiyan 计算样本标准差,我们首先需要找到样本均值。对于给定的两个数$4$和$-19$,样本均值$\bar{x}$为:

$\bar{x} = \frac{4 + (-19)}{2} = \frac{-15}{2} = -7.5$

接着,我们计算每个数据与样本均值的差的平方,然后求这些平方差的均值。这里只有两个数据点,所以计算如下:

$\frac{(4 - (-7.5))^2 + ((-19) - (-7.5))^2}{2} = \frac{(11.5)^2 + (-11.5)^2}{2}$

$= \frac{132.25 + 132.25}{2} = \frac{264.5}{2} = 132.25$

最后,样本标准差$s$是这个平方差均值的平方根:

$s = \sqrt{132.25} \approx 11.5$

所以,样本标准差为$11.5$。
\frac{23}{\sqrt{2}}
zhipu 1. **Calculate the mean of the sample**:
\[
\text{Mean} = \frac{4 + (-19)}{2} = \frac{-15}{2} = -7.5
\]

2. **Compute the squared deviations from the mean**:
- For $4$:
\[
(4 - (-7.5))^2 = (4 + 7.5)^2 = 11.5^2 = 132.25
\]
- For $-19$:
\[
(-19 - (-7.5))^2 = (-19 + 7.5)^2 = -11.5^2 = 132.25
\]

3. **Calculate the average of these squared deviations (variance)**:
\[
\text{Variance} = \frac{132.25 + 132.25}{2} = \frac{264.5}{2} = 132.25
\]

4. **Take the square root of the variance to get the standard deviation**:
\[
\text{Standard Deviation} = \sqrt{132.25} = 11.5
\]

Therefore, the sample standard deviation is ${\\boxed{11.5}}$.
\frac{23}{\sqrt{2}}
deepseek-v3 To compute the **sample standard deviation** of the dataset \({4, -19}\), follow these steps:

### Step 1: Calculate the Mean (\(\mu\))
First, find the average of the numbers.

\[
\mu = \frac{4 + (-19)}{2} = \frac{-15}{2} = -7.5
\]

### Step 2: Compute the Squared Deviations from the Mean
Next, subtract the mean from each data point and square the result.

\[
\begin{align*}
(4 - (-7.5))^2 &= (11.5)^2 = 132.25 \\
(-19 - (-7.5))^2 &= (-11.5)^2 = 132.25 \\
\end{align*}
\]

### Step 3: Calculate the Variance (\(s^2\))
Sum the squared deviations and divide by the number of data points minus one (since it's a sample).

\[
s^2 = \frac{132.25 + 132.25}{2 - 1} = \frac{264.5}{1} = 264.5
\]

### Step 4: Determine the Standard Deviation (\(s\))
Take the square root of the variance to find the standard deviation.

\[
s = \sqrt{264.5} \approx 16.26
\]

### Final Answer
\[
\boxed{16.26}
\]
\frac{23}{\sqrt{2}}